I'm using pluck to get the datetime.
ModelName.where("created_at >= ? ", Time.zone.now).pluck(:created_at)
it is giving me output in this format [[17 Jan 2022 18:03:20 IST +05:30], [20 Jan 2022 13:06:25 IST +05:30]]
Is there way to convert this DateTime in epochtime, or use pluck in such a way to get epochtime instead of getting DateTime like this?
Is there a way to convert epochtime into this "17 Jan 2022 18:03:20 IST +05:30" DateTime format?
I need to compare params[:created_at] which is in epochtime from the data which I'm getting from DB.
To compare dates, you can convert the epochtime in params to time object using Time.at function as follows.
2.7.3 :011 > Time.at(1641658419)
=> 2022-01-08 21:43:39 +0530
2.7.3 :011 > Time.at(1641658419) > DateTime.parse("2021-12-01")
=> true
If you prefer comparing both dates in epoch time, you can select the created_at as epoch time from database itself and then you can compare it through your code. For MySQL database, you can try
ModelName.where("created_at >=?",Time.zone.now)
.select("UNIX_TIMESTAMP(created_at) as epoch_time")
.map(&:epoch_time)
Convert to Time with .to_time and then to Unix Time with to_i. For example:
created_at = ModelName.where("created_at >= ? ", Time.zone.now).pluck(:created_at)
created_at.to_time.to_i
Related
How do I convert UTC timestamp in the format '2009-02-02 00:00:00' to EST/EDT in Ruby? Note that I am not using Rails, instead it is a simple Ruby script.
1If the date range falls between EST (usually Jan-Mid March) it needs to to UTC-5hrs. For EDT it is UTC-4hrs.
So far I have the following function to convert UTC to EST/EDT.
def utc_to_eastern(utc)
eastern = Time.parse(utc) # 2009-02-02 00:00:00 -0500
offset_num = eastern.to_s.split(" -")[1][1].to_i # 5
eastern_without_offset = (eastern-offset_num*60*60).strftime("%F %T") # 2009-02-01 19:00:00
return eastern_without_offset
end
puts utc_to_eastern("2009-02-02 00:00:00") # 2009-02-01 19:00:00
puts utc_to_eastern("2009-04-02 00:00:00") # 2009-04-01 20:00:00
The above code does what I want, however there's two issues with my solution:
I do not want to reinvent the wheel, meaning I do not wish to write the time conversion functionality instead use existing methods provided by Ruby. Is there a more intuitive way to do this?
The parsing uses my local timezone to convert UTC to EST/EDT, however I would like to explicitly define the timezone conversion ("America/New_York"). Because this means someone running this on a machine on central time would not be using EST/EDT.
The best approach would be to use TZInfo.
require 'tzinfo'
require 'time'
def utc_to_eastern utc
tz = TZInfo::Timezone.get("America/New_York")
tz.to_local(Time.parse(utc)).strftime('%Y-%m-%d %H:%M:%S')
end
utc_to_eastern "2020-02-02 00:00:00 UTC" => "2020-02-01 19:00:00"
utc_to_eastern "2020-04-02 00:00:00 UTC" => "2020-04-01 20:00:00"
I've got a bunch of user-inputted dates and times like so:
date = "01:00pm 06/03/2015"
I'm trying to submit them to a datetime column in a database, and I'm trying to systemize them like this:
DateTime.strptime(date, '%m/%d/%Y %H:%M')
But I consistently get an invalid date error. What am I doing wrong? If I submit the string without strptime the record will save but it sometimes gets the date wrong.
Also, how can I append a timezone to a DateTime object?
Edit:
So .to_datetime and DateTime.parse(date) work for the date string and fail for date2. What's going on?
date2 = "03:30pm 05/28/2015"
Try using to_datetime:
date.to_datetime
# => Fri, 06 Mar 2015 13:00:00 +0000
Also if you read the documentation for DateTime#strptime, here. It states:
Parses the given representation of date and time with the given
template, and creates a date object.
Its important to note that the template sequence must match to that of input string sequence, which don't in your case - leading to error.
Update
Using to_datetime over second example will generate
ArgumentError: invalid date
This is because it expects the date to be in dd-mm-yy format. Same error will be raised for DateTime.parse as to_datetime is nothing but an api for the later. You should use strptime in-case of non-standard custom date formats. Here:
date2 = "03:30pm 05/28/2015"
DateTime.strptime(date2, "%I:%M%p %m/%d/%Y")
# => Thu, 28 May 2015 15:30:00 +0000
date = "01:00pm 06/03/2015"
DateTime.parse(date)
=> Fri, 06 Mar 2015 13:00:00 +0000
You haven't got your parameters in the correct order.
DateTime.strptime(date, '%H:%M%p %m/%d/%Y')
You'll also need to add %p for the am/pm suffix
How to get previous day on UTC time using ruby?
Currently I'm using Time.now.utc.iso8601 to get UTC time format in ruby, I need previous day in same UTC format. Can someone help me with sample code to get previous day?
> Time.now.utc
=> 2015-03-22 19:00:46 UTC
> Time.now.utc - 86400
=> 2015-03-21 19:00:51 UTC
> (Time.now.utc - 86400).iso8601
=> "2015-03-21T19:00:59Z"
By using XML API, I got date-time as "2008-02-05T12:50:00Z". Now I wanna convert this text format into different format like "2008-02-05 12:50:00". But I am getting proper way.
I have tried this one :: #a = "2008-02-05T12:50:00Z"
Steps
1. #a.to_date
=> Tue, 05 Feb 2008
2. #a.to_date.strftime('%Y')
=> "2008"
3. #a.to_date.strftime('%Y-%m-%d %H:%M:%S')
=> "2008-02-05 00:00:00
Suggest some thing ?
The to_date method converts your string to a date but dates don't have hours, minutes, or seconds. You want to use DateTime:
require 'date'
d = DateTime.parse('2008-02-05T12:50:00Z')
d.strftime('%Y-%m-%d %H:%M:%S')
# 2008-02-05 12:50:00
Use Ruby's DateTime:
DateTime.parse("2008-02-05T12:50:00Z") #=> #<DateTime: 2008-02-05T12:50:00+00:00 (353448293/144,0/1,2299161)>
From there you can output the value in any format you want using strftime. See Time#strftime for more info.
I need to parse following String into a DateTime Object:
30/Nov/2009:16:29:30 +0100
Is there an easy way to do this?
PS: I want to convert the string above as is. The colon after the year is not a typo. I also want to solve the problem with Ruby and not RoR.
Shouldn't this also work for Rails?
"30/Nov/2009 16:29:30 +0100".to_datetime
DateTime.strptime allows you to specify the format and convert a String to a DateTime.
I have had success with:
require 'time'
t = Time.parse(some_string)
This will convert the string in date to datetime, if using Rails:
"05/05/2012".to_time
Doc Reference: https://apidock.com/rails/String/to_time
I used Time.parse("02/07/1988"), like some of the other posters.
An interesting gotcha was that Time was loaded by default when I opened up IRB, but Time.parse was not defined. I had to require 'time' to get it to work.
That's with Ruby 2.2.
convert string to date:
# without timezone
DateTime.strptime('2012-12-09 00:01:36', '%Y-%m-%d %H:%M:%S')
=> Sun, 09 Dec 2012 00:01:36 +0000
# with specified timezone
DateTime.strptime('2012-12-09 00:01:36 +8', '%Y-%m-%d %H:%M:%S %z')
=> Sun, 09 Dec 2012 00:01:36 +0800
refer to:
https://ruby-doc.org/stdlib-3.1.1/libdoc/date/rdoc/Date.html
in Ruby 1.8, the ParseDate module will convert this and many other date/time formats. However, it does not deal gracefully with the colon between the year and the hour. Assuming that colon is a typo and is actually a space, then:
#!/usr/bin/ruby1.8
require 'parsedate'
s = "30/Nov/2009 16:29:30 +0100"
p Time.mktime(*ParseDate.parsedate(s)) # => Mon Nov 30 16:29:30 -0700 2009
You can parse a date time string with a given timezone as well:
zone = "Pacific Time (US & Canada)"
ActiveSupport::TimeZone[zone].parse("2020-05-24 18:45:00")
=> Sun, 24 May 2020 18:45:00 PDT -07:00