Regular expression is not working if json response value contain special character . how to extract the 'sid' value from below mention json as ""sid"?\s*:?\s*"(\w+)"" is not working as json response contain special character on sid.
0{"sid":"RhANkc9V7-psbnzmJAAGS","upgrades":["websocket"],"pingTimeout":20000,"pingInterval":25000}
Your \w+ meta character matches "word" characters (alphanumeric and underscores, can be also written as [a-zA-Z0-9_] character class)
Dash symbol - won't be captured so you either need to use wildcard characters instead of "word" something like:
sid"?\s*:?\s*"(.*)"
Demo:
Another possible option is removing this starting 0 using JSR223 Post-Processor and the following Groovy code:
prev.setResponseData(prev.getResponseDataAsString().substring(1),'UTF-8')
once done you will be able to use JSON Extractor or JSON JMESPath Extractor
Your matching group currently scoped to capture ONLY one or more word characters, In order to capture special characters along with word characters you have to tweak your regular expression like below,
sid":"(.+?)"
In above regular expression, . matches any character (except for line terminators) whereas \w captures only word characters i.e. a-z, A-Z, 0-9, _
You can also use Boundary Extractor if you don't want to mess with the complexity of Regular Expression.
Left Boundary: sid":"
Right Boundary: ",
Related
I have an XSL template that takes 2 parameters (text and separator) and calls tokenize($text, $separator).
The problem is, the separator is supposed to be a regex. I have no idea what I get passed as separator string.
In Java I would call Pattern.quote(separator) to get a pattern that matches the exact string, no matter what weird characters it might contain, but I could not find anything like that in XPath.
I could iterate through the string and escape any character that I recognize as a special character with regard to regex.
I could build an iteration with substring-before and do the tokenize that way.
I was wondering if there is an easier, more straightforward way?
You could escape your separator tokens using the XPath replace function to find any character that requires escaping, and precede each occurrence with a \. Then you could pass such an escaped token to the XPath tokenize function.
Alternatively you could just implement your own tokenize stylesheet function, and use the substring-before and substring-after functions to extract substrings, and recursion to process the full string.
I need to capture below values
(1589913628397qzhQpW, 1589913628397qzhQr5, 1589883028581e8w3u6,
1589915918676qzhQkS, 1589915918676qzhQkS)
through regular expression post processor in jmeter. please let me know the regular expression for the same.
<div class="tspacer" onclick="treeClickDocument(
'1589913628397qzhQpW','1589913628397qzhQr5',
'1589883028581e8w3u6','1589915918676qzhQkS',
'1589915918676qzhQkS',false,
'Perf3575','10050')">
If the output looks like exactly as in your question the relevant regular expression would be:
<div class="tspacer" onclick="treeClickDocument\(\n\s+'(\w+)','(\w+)',\n\s+'(\w+)','(\w+)',\n\s+'(\w+)'
Demo:
Explanation of potentially not obvious stuff:
\ - escape symbol for meta-characters
\n - matches new line
\s+ - matches arbitrary amount of white spaces
\w+ - matches a "word" - sequence of alphanumeric characters
More information:
Using RegEx (Regular Expression Extractor) with JMeter
JMeter - Regular Expressions
Perl 5 Regex Cheat sheet
I have this character , or see screenshot below. Its the "replacement character" in Ruby.
I'm using an external API that does parsing, and unfortunately returns this character instead of - for un-ordered list points.
I would like to split by this character in what is returned, but I've been unsuccessful with below.
text.split(//)
How can I split by this character?
These will match any non ASCII character:
[^\x00-\x7F] or [^[:ascii:]].
As noted by #engineersmnky this may not be the most ideal solution if the data you are parsing could contain more unrecognized characters.
Use this regex if you want to split only the character:
[\uF0B7]
i was using standard preg_match for making url excluding
http://domainlllll.com/
and it was working without any issue
preg_match("/^[0-9a-z_\/.\|\-]+$/",$url)
but now i want to support multiple languages so i used this and it is also working without any problem
preg_match("/\S+/",$url)
my url is
link/kn/some-word-গরম-এবং-সেক্সি-ইমেজ/611766
but i want to exclude some special characters which is hackers favorite like single quotes and other. i dont want to exclude all special character as few are part of few languages and it will break those languages in link
Any guide will be great
Look, the /^[0-9a-z_\/.\|\-]+$/ regex requires the whole string to match the patterns, 1+ chars from the defined ranges (digits, lowercase ASCII letters) and sets. The /\S+/ regex does not require a full string match since there are no anchors, ^ (start of string) and $ (end of string), and matches 1 or more non-whitespace chars anywhere inside a string.
If you plan to match strings that only contain non-whitespace symbols and NOT quotes, use
preg_match('~^[^\s\'"]+$~', $url)
The ^[^\s\'"]+$ matches
^ - start of string
[^\s\'"]+ - 1 or more chars other than whitespace (\s), ' and "
$ - end of string (better use \z instead if you need to validate a string).
I want to fetch all the strings between _(" ") from my file.
How may i fetch that?
Assuming there are no quotation marks nested within the string you're looking for, you want to load the file into a string
str=File.read("/path/to/file")
Then scan the string using a regular expression. The following regular expression should do the trick. It looks for the characters _(" (the open parentheses here is escaped, because parentheses have a special meaning in regular expressions). The next parentheses starts a capturing group (so that the text of the string will be stored in the special variable $1. Then it finds a string of consecutive characters until the first quotation mark. Then it ends the capturing group (with an unescaped close parentheses) looks for a ") to finish the expression.
/_\("([^"]*)"\)/
To use it
str.scan( /_\("([^"]*)"\)/ ) do
puts $1
end