I have a model class that I store in Redis and I use Jpa Repository with Spring java. Normally(not with redis) jpa repository is saving the new data or updates(conditionally) if the given model is already exist in Db. Here, I want to add new item to redis but if it is not already exists on db otherwise update it just like usual Jpa implementation.
Here is my model:
#Getter
#Setter
#RedisHash("MyRecord")
public class MyRecordRedisModel {
private String id;
#Id
#Indexed
private String recordName;
private Date startDate;
private Date endDate;
}
And my repository class is just a normal spring jpa repo as follows:
#Repository
public interface IFRecordRedisRepository extends JpaRepository<IFRecordRedisModel, String> {
Page<IFRecordRedisModel> findAll(Pageable pageable);
}
Unique key must be the name (I totally do not care about uniquiness of the id). Thus, if the name is already exist in Db than do not add it again. I marked it as Indexed but still it is adding same data (with same recordName).
How can I make it unique?
This would require an additional query, but I think this solution would work for you. You can use query by Example to check if there exists a record with that name, and save conditionally, or do something else if it already exists.
IFRecordRedisModel exampleRecord = new IFRecordRedisModel();
exampleRecord.setRecordName(inputRecord.getRecordName());
if (!repository.exists(Example.of(exampleModel)))
repository.save(inputRecord);
else ..... // do something else
Related
im working in a spring boot project and i have a requirement to save the old object in a specific table before each new save ; this my man entities:
#Entity
#Table(name="demande")
public class Demande {
#Id
private Long id;
// all properties
}
#Entity
#Table(name="demande_log")
public class DemandeLog {
#Id
private Long id;
// all properties
}
what im trying to do is before each demandeRepository.save(demande);
i want to save the old demande object (current row in database) as DemandeLog in my demande_log table.
do you have any idea how using spring data, i know that there is a listener #PrePersist in JPA.. but i want to do it properly.
Regards.
I recommend using Envers. It is easy to set up and gives you a complete change log.
I want to fetch all the records based on the flag value. Flag value can be either 'A' for Active or 'I' for Inactive.
I want to fetch both Active and Inactive records and put them in some kind of List or Map.
These are my repository and entity class:
#Repository
public interface StatusRepository extends JpaRepository<StatusEntity,Long>{
}
public class StatusEntity{
#Id
#Column(name="id_status")
private Long idStatus;
#Column(name="name")
private String name;
#Column(name="status_flg")
private String statusFlg;
}
I am able to fetch all the records using statusRepository.findAll(). I was wondering if there is something like statusRepository.findAllByStatusFlg(String flag) or statusRepository.findByStatusFlg(String flag)?
Is there any way to fetch all the records by specifying where condition on certain columns?
P.S. I am using spring-boot-starter-data-jpa 2.3.2.RELEASE
You should make yourself familiar with the basics of spring data. As you thought, you can define a query method in your StatusRepository that fetches your StatusEntitys according to your needs.
#Repository
public interface StatusRepository extends JpaRepository<StatusEntity,Long>{
List<StatusEntity> findByStatusFlg(String flag);
}
required format image
I want to object data into MongoDB using spring and I have hardcoded it.
please how to write a schema for that and I have taken it as an example only.
I have a different type of categories in it I have taken only clothes.
please tell me how to write one schema for a different type of categories and query too.
please find the attachment for your reference
I would recommend going though Spring Data MongoDB documentation for specifics on mapping java objects to MongoDB documents. Your case would look similar to:
#Document
public class Clothes {
#Id
private ObjectId id;
private Men men;
private Women women;
// getters & setters
}
You would need to define each sub class but this should be the gist of it.
What you can do is create a simple POJO (Plain Old Java Object) and with that you can insert that object into the data base. The the following example:
#Document
public class OAuthModel implements Serializable {
#Id
String username;
#Indexed
String oAuthID;
#Indexed
String type;
// Getter and Setters and Construct.
}
When I insert this object in the DB by calling:
OAuthModel authModel = new OAuthModel(username,firebaseToken.getUid(), OAuthHosts.GOOGLE.getType());
oAuthRepo.insert(authModel);
It will then be seen as this in the Database:
Keep in mind this will work no matter what your object looks like, you can have hashmaps etc. The should be a built in serialization.
Is it possible to publish two different repositories for the same JPA entity with Spring Data Rest?
I gave the two repositories different paths and rel-names, but only one of the two is available as REST endpoint.
The point why I'm having two repositories is, that one of them is an excerpt, showing only the basic fields of an entity.
The terrible part is not only that you can only have 1 spring data rest repository (#RepositoryRestResource) per Entity but also that if you have a regular JPA #Repository (like CrudRepository or PagingAndSorting) it will also interact with the spring data rest one (as the key in the map is the Entity itself).
Lost quite a few hours debugging random load of one or the other. I guess that if this is a hard limitation of spring data rest at least an Exception could be thrown if the key of the map is already there when trying to override the value.
The answer seems to be: There is only one repository possible per entity.
I ended up using the #Subselect to create a second immutable entity and bound that to the second JpaRepsotory and setting it to #RestResource(exported = false), that also encourages a separation of concerns.
Employee Example
#Entity
#Table(name = "employee")
public class Employee {
#Id
Long id
String name
...
}
#RestResource
public interface EmployeeRepository extends PagingAndSortingRepository<Employee, Long> {
}
#Entity
#Immutable
#Subselect(value = 'select id, name, salary from employee')
public class VEmployeeSummary {
#Id
Long id
...
}
#RestResource(exported = false)
public interface VEmployeeRepository extends JpaRepository<VEmployeeSummary, Long> {
}
Context
Two packages in the monolithic application had different requirements. One needed to expose the entities for the UI in a PagingAndSortingRepository including CRUD functions. The other was for an aggregating backend report component without paging but with sorting.
I know I could have filtered the results from the PagingAndSorting Repository after requesting Pageable.unpaged() but I just wanted a Basic JPA repository which returned List for some filters.
So, this does not directly answer the question, but may help solve the underlying issue.
You can only have one repository per entity... however, you can have multiple entities per table; thus, having multiple repositories per table.
In a bit of code I wrote, I had to create two entities... one with an auto-generated id and another with a preset id, but both pointing to the same table:
#Entity
#Table("line_item")
public class LineItemWithAutoId {
#Id
#GeneratedValue(generator = "system-uuid")
#GenericGenerator(name = "system-uuid", strategy = "uuid")
private String id;
...
}
#Entity
#Table("line_item")
public class LineItemWithPredefinedId {
#Id
private String id;
...
}
Then, I had a repository for each:
public interface LineItemWithoutId extends Repository<LineItemWithAutoId,String> {
...
}
public interface LineItemWithId extends Repository<LineItemWithPredefinedId,String> {
...
}
For the posted issue, you could have two entities. One would be the full entity, with getters and setters for everything. The other, would be the entity, where there are setters for everything, but only getters for the fields you want to make public. Does this make sense?
Here is a part of Files.java
#Entity(name="files")
public class Files {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String title;
#ElementCollection
private List<String> filenames= new ArrayList<String>();
//<< getter and setter >>
}
it is correctly created the table 'Files' and 'Files_filenames' on mySql
and I can put data there on Controller with it
Files files = new Files();
files.setTitle(ufile.getTitle());
files.setFilenames(Arrays.asList(ufile.getFilename().split(",")));
so far, everything looks ok
However, when I try to get the data from the database, the filename always returns something like 'persistentbag' not ArrayList.
I would like to know how to get ArrayList from the database
I'm using Spring data JPA using Hibernate as a Jpa vendor.
Thanks in advance
PersistentBag is a List (i.e., it implements List), therefore you can use it as a regular List. There is no need to care about actual implementation of that List in this case.