Automatic select only member in the object list - bash

Question

Is there a way to automatically address/select the only member in a object?
In my case the 3rd level member jobf can vary. But on that level it will always only have one member.
### get aeObject ###
try {
$response = Invoke-RestMethod -Method GET -Uri "$client_id/objects/$($i -replace "#","%23")" -Headers $header
}
catch {
Write-Error -Message "$($_.Exception.Message)"
$Error[0] | Format-List -Force
}
### modify JSON and import it ###
$JSON = $response | ConvertTo-Json -Depth 100 | ConvertFrom-Json
$JSON.data
if ($JSON.data.jobf.general_attributes.time_zone) {
$JSON.data.jobf.general_attributes.time_zone = "$TZ"
}
else {
$JSON.data.jobf.general_attributes | Add-Member -Name "time_zone" -MemberType NoteProperty -Value "$TZ"
}
enter image description here

Answer 1

You can use Get-Member to iterate the members at the third level, then filter out the noise and select the name of the first (and only one) member.
# Get the third level single item (eg: jobf, jobx, etc)
$Job = ($JSON.data | Get-Member -MemberType NoteProperty | Select-Object -First 1).Name
# Instead of "jobf", we use the value stored in $Job
if ($JSON.data.$Job.general_attributes.time_zone) {
$JSON.data.$Job.general_attributes.time_zone = "$TZ"
}
else {
$JSON.data.$Job.general_attributes | Add-Member -Name "time_zone" -MemberType NoteProperty -Value "$TZ"
}
References
Get-Member - Gets the properties and methods of objects.