I am trying to remove the url parameters based on some conditions ,i can able to remove some of the parameters , i want to replace the some new value for the url, can you please give me some idea how to do this one
$request->query->remove('key');
$request->query->add(['admin'=>"true"]);
$request->request->remove('key');
$request->request->add(['admin'=>"true"]);
You almost done in a correct way, simply change the order of the queries then it will be working fine.
$request->query->remove('key');
$request->request->remove('key');
Related
I come from here:
Laravel pagination trouble with offset
Investigating into my code, I found that when a random alike parameter is given through a route, it will do an like query or I don't know, but it will still work as it will get the first part of the parameter:
The route I'm trying to "ensure" goes like this:
Route::get('/videos/cats/{race_id}/{cat_id}, [App\Http\Controllers\MeowController::class, 'getCatVideo']);
Can someone help me to get that exact parameter as integer, or prevent a route from working if the parameter is not exactly the given one?
Thank you in advance.
Parameters are required by default.
To validate parameter:
Route::get('/videos/cats/{race_id}/{cat_id}, [App\Http\Controllers\MeowController::class, 'getCatVideo'])
->where('race_id', '\d+')
->where('cat_id', '\d+');
Useful link: https://laravel.com/docs/8.x/routing#parameters-regular-expression-constraints
I've got a paginated list of cars, on a Spring Boot server, with the parameters sort, range, desc, page, etc to filter and sort by and am generating the URL in Thymeleaf that looks like:
example.com/cars?page=5&sort=mileage
I am wanting to be able to add more parameters to a URL with a few of these already but I'm quite new to this and don't really know how to get the current URL with all the parameters to add more params without losing the previous ones look like
example.com/cars?page=5&sort=mileage&desc=true
I've found an answer to do something like this on Spring but would ideally want to do it on the Thymeleaf template, is this possible?
Get full current url thymeleaf with all parameters
I found that you can get hold of specific parameters in Thymeleaf using ${param.sort} to get hold of the param sort, could something similar to this get hold of all the params currently?
Thanks
If someone is still looking for a thymeleaf template only solution, you could use ${#request.getRequestURI()} with ${#request.getQueryString()} and add your additional parameters via concatenation:
<a th:href="#{${url}}" th:with="url=${#request.getRequestURI()+'?'+#request.getQueryString()+'&foo=bar'}">Link</a>
If you need to escape query parameters, you can use #uris.escapeQueryParam():
<a th:href="#{${url}}" th:with="url=${#request.getRequestURI()+'?'+#request.getQueryString()+'&foo='+#uris.escapeQueryParam('b a r')}">Link</a>
Some further details:
You have to use th:with, otherwise the parser will throw TemplateProcessingException: Access to request parameters is forbidden in this context. in newer thymeleaf versions.
It also works when the current query is empty, the url generator will create a valid url, in my example including one ? and no & in the query part.
I got a big search module in my Codeigniter project. Well simply I am passing variable to a view like
<a href=<?php echo site_url('controller/view/1'); ?>>View List</a>
And fetching its data in controller like
$id=$this->uri->segment(3);
For pagination
http://wwww.site.com/controller/view/<filter id>/<page from>
This is working perfectly in the case of simple query.
Now I got some more filter quires like
Country
State
City
Customer type
etc etc
then the url should be
http://wwww.site.com/controller/view/1/id2/id3/i4/id5
Is this the correct way to do the process ? If not please give a little advice...
I am new to codeigniter
The problem you are facing i have recently found a solution for this.
When you are first sending parameters through url use POST instead.
When you get the parameters you can pass them to session in a variable
type. Next time when you paginate get the type value from session and
put it in your query to get the desired result.
If you have more than 1 parameters you can put them in sessions and
unset them on certain conditions so that they are not called in every query.
I think the best approach here is to create another method in the controller something like filtered_view that accepts a filter_id and a page number, and that methode will fetch the data from the database with the provided filter and you'll use your pagination class as usual.
Hope this help.
I am using CodeIgniter, and I am new to it.
I came to know that I can pass parameters to another page like http://example.com/users/list/param1/param2/param3/.... and so on.
Now on the destination php script, I can get it as $this->uri->segment(2) , but I must know that which location it is in the uri. Say I am getting param2 , I must know that it is uri segment 4. This is a great pain for me. I previously worked with ZEND , where we send parameters like
http://examples.com/controller/action/key/value/key/value , Now in this case I can always dynamic number of parameters and I don't need to know their location in the uri, but I just need to know the key.
Qestion : Is there a way where I can pass parameters using GET in key-value pairs in codeigniter, like the one ZEND do?
Take a look at the function $this->uri->uri_to_assoc(n) in the URI class. It will take in your url segments as an associative array. You could then check whether the keys are present in it or not.
Example and full explanation in the user guide.
I'm having a little trouble with a CodeIgniter route when there is a query (stuff after the ?) in the URI. I know it is good practice to replace queries with routes in CI, but I'm importing in a premade messageboard that already does everything with queries. This is my route:
$route['messageboard/:any'] = "messageboard/index";
Any in this case refers to a script name. So if it's messageboard/admin.php, I have it load a view that loads my premade messageboard's script "admin.php". It's working just fine if I do messageboard/admin.php. It does fine if I do messageboard/admin.php?. If I put a parameter into the query, however, the route won't correctly send the user to the messageboard controller, and instead sends them to a 404. Does anyone have any ideas on how to make this work? I would be eternally grateful. Thanks!
Okay guys, I solved it. I needed to change three things. The first was mtvee's suggestion, which lets it read query strings. The second one you're going to want to change the $config['permitted_uri_chars'] in the config file to include an equals sign, since it starts off disabled and all query strings will be of the for ?a=34 or something like that. The third is you need to go to $config['uri_protocol'] and change it from AUTO to PATH_INFO. Once I did those, it worked.
I'm sure the syntax is:
$route['messageboard/(:any)'] = "messageboard/index"; //<-- notice brackets
and not
$route['messageboard/:any'] = "messageboard/index";
I believe CI doesn't do GET out of the box. Check out Enabling Query Strings here http://ellislab.com/codeigniter/user-guide/general/urls.html