i am lost with NET6.
I created this partial view _MenuNav.cshtml :
#model IEnumerable<CateringMilano.Models.Menu>
#foreach (var item in Model)
{
<div>
<a alt="#item.MenuTitle)">#item.MenuName</a>
<b>#item.MenuTitle</b>
</div>
}
and the cod in my controller is :
// GET: /Menus/_MenuNav/
public ActionResult _MenuNav(string menuPosition)
{
// Get my db
var model = _context.Menu.Include(m => m.ChildMenuSub) as IQueryable<Menu>;
model = model.Where(p => p.MenuPosition == menuPosition);
// Send your collection of Mreations to the View
return PartialView(model);
}
and in the last project with net 4 i use to write the following code in the principal view in order to call my partial view :
#Html.Action("_MenuNav", "Menus", new { menuPosition = "Menu" })
but it looks like it does not work anymore this with NET6
Do you know how to rewrite my code in order to get the same result?
you must be mixing view components with partial views. Partial view were always used like this
<div id="partialName">
<partial name="_PartialName" />
</div>
with model
<partial name="_PartialName" model="Model.MyInfo" />
or for async
<div id="partialName">
#await Html.PartialAsync("_PartialName")
</div>
and the most popular way to update parital view is using ajax
And you can check my answer about viewcomponents here
https://stackoverflow.com/a/69698058/11392290
Related
I'm new to AJAX, and I have a very simple example, but has a problem; first call the data is duplicated at the View and in subsequent calls work correctly. What am I doing wrong?
The ~/Views/Shared/_Layout.cshtml file had all scripts necesary:
<script src="~/Scripts/jquery-3.1.0.min.js"></script>
<script src="~/Scripts/jquery.unobtrusive-ajax.js"></script>
First time, the initial view:
Second time, first time button click inserts a number instead of replace number:
Third time, second time button click works fine but in the second line number... an so on:
This is my code:
Model
namespace MQWebSt.Models
{
public class AjaxTest
{
public int Number { get; set; }
}
}
Controller:
using System.Web;
using System.Web.Mvc;
using MQWebSt.Models;
namespace MQWebSt.Controllers
{
public class AjaxTestController : Controller
{
// GET: AjaxTest
public ActionResult Vista()
{
AjaxTest at = new AjaxTest { Number = 1 };
return View(at);
}
[HttpPost]
public ActionResult Vista( AjaxTest model)
{
Random rnd = new Random();
model.Number = rnd.Next(1, 100);
return PartialView("AjaxTestPartial", model);
}
}
}
View Vista.chtml:
#model MQWebSt.Models.AjaxTest
#{
Layout = "~/Views/Shared/_Layout.cshtml";
}
#using (Ajax.BeginForm("Vista", new AjaxOptions { UpdateTargetId = "divEmp", InsertionMode = InsertionMode.Replace }))
{
<button class="btn btn-primary btn-md glyphicon glyphicon-menu-right" name="Contestar" type="submit" value="+1"></button>
<div class="panel panel-footer">
<table id="divEmp">
#Model.Number.ToString()
</table>
</div>
}
AjaxTestPartial.chtml:
#model MQWebSt.Models.AjaxTest
#Model.Number.ToString()
The issue is you're using InsertionMode = InsertionMode.Replace, it's going to replace the data in the UpdateTargetId. You could use InsertionMode.InsertBefore instead and it would build the values out in the parent of #divEmp. However, if you need the values to be placed in #divEmp, you'll need to write a JavaScript handler for the OnSuccess option of your Ajax form, that way you can dictate if you're doing insert vs. pre-pend vs. replace.
The issue is, your HTML markup code in your razor view is not valid. With the code you have, razor will generate the below markup (Check the view source)
<div class="panel panel-footer">
1
<table id="divEmp"></table>
</div>
You can see that 1 is not inside the table. It is outside. So when your ajax form submit happens, it will update the tables content with the new value. that is the reason you are still seeing the initial number.
The solution is to change the table to a div/span
<div id="divEmp"> #Model.Number.ToString() </div>
Or if you absolutely need to have a table for any reason, have the value inside a td and use "divEmp" as the id attribute value of that.
<table >
<tr>
<td id="divEmp">1</td>
</tr>
</table>
I have a main Index view from which I call view called Create, into which I pass type of the widget I want to create as a string.
Index view:
<i class="fa fa-image"></i> Create Image Widget -
<i class="fa fa-file-text"></i> Create Text Widget
Create Action:
public ActionResult Create(string wType)
{
ViewBag.wType = wType;
return View();
}
the type is then passed into view via ViewBag.wType and this is evaluated in the Create View
Create view:
#using (Html.BeginForm())
{
<section class="row">
#{
if (ViewBag.wType == "image")
{
Html.RenderPartial("~/Views/WidgetEditor/_CreateImageWidget.cshtml");
}
else if (ViewBag.wType == "text")
{
Html.RenderPartial("~/Views/WidgetEditor/_CreateTextWidget.cshtml");
}
}
</section>
}
and depending on this, appropriate partial view is loaded.
Partial views have different models so when the form is submitted, I do not know how which model is passed back. The one from _CreateImageWidget or _CreateTextWidget.
If the HttpPost controller look like this
[HttpPost]
public ActionResult Create(DisplayWidgetImageViewModel imageModel, DisplayWidgetTextViewModel textModel)
{
return new ViewResult();
}
I will get populated imageModel if _CreateImageWidget partial is chosen and textMode if _CreateTextWidget partial is chosen.
This is acceptable it the number of widgets types does not change, but this is not the case.
Is there a way to get somehow specific model from a partial view and know/find out which one it is or am I doing this completely wrong way?
You can create multiple forms in single page. You can also use different action methods per partial:
#using (Html.BeginForm("Action", "Controller")) {
Html.RenderPartial("~/Views/WidgetEditor/_CreateImageWidget.cshtml")
}
You all this without having to use Ajax.
I have used this answer to solve my problem: determine-the-model-of-a-partial-view-from-the-controller-within-mvc
there are also several other link with more resources.
I am very new to MVC, let me try to explain my scenario in plain simple English:
I have an strongly typed mvc form/page (Product.cshtml) with a model, say ProductViewModel.
This page has got two search buttons, one to search and bring the items to be added to the Product and other to bring in the location, most probably partial views.
Now, what I want is that these search results work in ajax form without complete post back, and then the results of these searches (items and location) should be posted back using model binding to the form when user clicks on the submit button.
What could be the best way of achieving this functionality?
Immediate responses will be well appreciated.
I thought, its good to share the complete code for clarity:
I have one form(Service1.chtml) that has a partial view to display users(_TestUser a partial view:read only), then another partial view(_PlotServiceRequestData) that should have a field to search the plot and bring back the details lke its owner name and landuser etc.
Then when I click on submit button of the main form, I should be able to read all data(main form) + new data from _PlotServiceRequestData partial view and save all data to database.
I was trying one more option, that is, to use #Ajax.ActionLink on Service1.cshtml to call the _GetPlotDetails method and then store partial view data in TempData, so that it is available to the form when users clicks on "Submit" button of Service1.cshtml, is this a right approach?, if I use ajax.BeginForm inside partial view then the data is posted to the
Service1 controller method which is actually to save the form data and not to update the partialview and in this method even I am not getting model data of the partial view.
Sevice1.cshtml:
#model ViewModels.TestViewModel
#{
ViewBag.Title =
"Service1";
}
#
using (Html.BeginForm())
{
#Html.LabelFor(m => m.Title)
#Html.EditorFor(m => m.Title)
#Html.Partial(
"_TestUser", Model)
<div id="RequestPlotData">
#Html.Partial(
"_PlotServiceRequestData", Model.requestData)
</div>
<button type="submit">Save Form</button>
}
#section Scripts {
}
_PlotServiceRequestData.cshtml:
===============================
#model ViewModels.PlotServicesRequestDataViewModel
<
div id="RequestPlotData">
#
using (Ajax.BeginForm("_GetPlotDetails", "Test", new AjaxOptions { UpdateTargetId = "RequestPlotData", Url = Url.Action("_GetPlotDetails","Test") }))
{
<h1>Request Details</h1>
<div>
#Html.LabelFor(m => m.plotAddress)
#Html.EditorFor(m => m.plotAddress)
<input type="submit" name="submit" value="Ajax Post" />
</div>
<div>
#Html.LabelFor(m => m.LandUser)
#Html.EditorFor(m => m.LandUser)
</div>
<div>
#Html.LabelFor(m => m.OwnerName)
#Html.EditorFor(m => m.OwnerName)
</div>
}
</
div>
CONTROLLER:
==========
using
System;
using
System.Collections.Generic;
using
System.Linq;
using
System.Web;
using
System.Web.Mvc;
namespace
TestNameSpace
{
public class TestController : Controller
{
//
// GET: /Test/
public ActionResult Service1()
{
Injazat.AM.mServices.
LocalDBEntities context = new Injazat.AM.mServices.LocalDBEntities();
TestViewModel model =
new TestViewModel() { user = context.Users.First(), Title = "Land Setting Out",
requestData =
new PlotServicesRequestDataViewModel() { ServiceNumber ="122345", TransactionDate="10/10/2033" } };
return View(model);
}
[
HttpPost()]
public ActionResult Service1(TestViewModel model)
{
PlotServicesRequestDataViewModel s = (PlotServicesRequestDataViewModel)TempData[
"Data"];
TestViewModel vm =
new TestViewModel() { user = model.user, requestData = s, Title = model.Title };
return View(vm);
}
[
HttpGet()]
//public PartialViewResult _GetPlotDetails(string add)
public PartialViewResult _GetPlotDetails(PlotServicesRequestDataViewModel requestData)
{
//PlotServicesRequestDataViewModel requestData = new PlotServicesRequestDataViewModel() { plotAddress = add};
requestData.OwnerName =
"owner";
requestData.LandUser =
"landuser";
TempData[
"Data"] = requestData;
return PartialView("_PlotServiceRequestData", requestData);
}
}
}
You can probably use the jQuery Form plugin for this. This makes the process of posting the data from your form back to the server very easy. The form would post to an action that would return a partial view that you can then push into your UI.
To make this easier, jQuery form actually has a "target" option where it will automatically update with the server response (ie. the partial view returned from your search action).
View
<form id="searchForm" action="#(Url.Action("Search"))" method="POST">
<input name="query" type="text" /> <!-- order use Html.TextBoxFor() here -->
<input type="submit" />
</form>
<div id="result"><!--result here--></div>
Javascript
$('#searchForm').ajaxForm({
target: '#result'
});
Controller
public ActionResult Search(string query)
{
// Do something with query
var model = GetSearchResults(query);
return Partial("SearchResults", model)
}
This should hopefully help you to get on the right track. jQuery Form is a good plugin and is the main thing you should look into for ajaxifying your form posts back to the server. You might also want to look into using jQuery's $.post and $.ajax functions, but these require slightly more work.
I have few tabs in my view and have a partial view.
Partial view contains a web grid. Depending on the selected tab grid has to be loaded with specific data.
Using RenderAction to return partial view. But I am getting overflow exception when I post my view.
This is my code.
<div id="tabs">
<ul>
<li>Sage Pay</li>
<li><a href="#tabs-2" >Pay Pal</a></li>
</ul>
<div id="tabs-1">
#{Html.RenderAction("SagePayPayments", "OrderProcessing");}
</div>
<div id="tabs-2">
#{Html.RenderAction("PayPalPayments", "OrderProcessing");}
</div>
And my controller is
public ActionResult PayPalPayments()
{
var model = new OrderContext().GetNewPayments(PaymentType.PayPal);
return PartialView("_PaymentsToVerify", model);
}
public ActionResult SagePayPayments()
{
var model = new OrderContext().GetNewPayments(PaymentType.SagePay);
return PartialView("_PaymentsToVerify", model);
}
[HttpPost]
public ViewResult VerifyPayments(FormCollection formData)
{
var context = new OrderContext();
var orderIds = formData.GetValues("chkSelected");
if (orderIds != null)
{
IList<long> selectedOrders = orderIds.Select(orderId => Convert.ToInt64(orderId)).ToList();
context.VerifyPayments(selectedOrders);
}
return View("Unverified");
}
Can somebody help me what I am missing.
Thanks
We seemed to have focused on views in this issue, but I doubt it is the problem.
You are convrrting a value to a long, this could throw an overflow exception if it evaluates to a value that exceed long.MaxValue or to less than long.MinValue.
I'd say, put this bit in a try catch block and try to run your code again, then check what is the value you are trying to convert and somve the real issue from there.
i have problem to pass data from view to controller , i have view that is strongly typed with my viewmodel "TimeLineModel", in the first i passed to this view my viewmodel from action on my controller
public ActionResult confirmation(long socialbuzzCompaignId)
{
return View(new TimeLineModel() { socialBuzzCompaignId = socialbuzzCompaignId, BuzzMessages = model });
}
with this i can get info from my action and display it on view , but i have other action POST which i won't get my view model to do some traitement
[HttpPost]
public ActionResult confirmation(TimeLineModel model)
{
}
i can get some propretie of the model but in others no , for example i can get the properti "socialBuzzCompaignId" of model , but other propertie like "IEnumerable BuzzMessages" i can't get it , i dont now why !!
this is the content of my view
#model Maya.Web.Models.TimeLineModel
#{
ViewBag.Title = "confirmation";
}
#using (Html.BeginForm())
{
<h2>confirmation</h2>
<fieldset>
#foreach (var msg in Model.BuzzMessages)
{
<div class="editor-label">
#msg.LongMessage
</div>
<br />
}
<p>
<input type="submit" value="Save" />
</p>
</fieldset>
}
You need to include BuzzMessages properties within a form element. Since it's not editable, you'd probably want to use hiddens. There are two ways to do this. Easiest is instead of doing a foreach loop, do a for loop and insert them by index.
#for (int i =0; i<Model.BuzzMessages.Count(); i++v)
{
<div class="editor-label">
#Model.BuzzMessages[i].LongMessage
#Html.HiddenFor(m => m.BuzzMessages[i].LongMessage);
</div>
<br />
}
but to do this you'd need to use an IList instead of an IEnumerable in your view model to access by index.
Alternatively, you could create an Editor Template named after your BuzzMessages class (whatever its name is).
#model BuzzMessagesClass
#Html.HiddenFor(m => m.LongMessages)
<!-- Include other properties here if any -->
and then in your main page
#Html.EditorFor(m => m.BuzzMessages)
Check out http://coding-in.net/asp-net-mvc-3-how-to-use-editortemplates/ or search stack overflow if the details of editor templates confuse you.
Just like any HTML POST method, you have to get the data back to the Controller somehow. Just simply "showing" the data on the page doesn't rebind it.
You have to put the data in an input (or a control that will post back) to the appropriate model property name.
So, if you have a model property with name FirstName and you want this data to be rebound to the model on POST, you have to supply it back to the model by placing an "input hidden" (or similar control that postbacks) with the ID of FirstName will rebind that property to the model on POST.
Hope that explains it.
#foreach (var msg in Model.BuzzMessages)
{
<div class="editor-label">
#msg.LongMessage
<input type="hidden" name="BuzzMessages.LongMessage" value="#msg.LongMessage" />
</div>
}
It will post array of LongMessages. Get values like this:
[HttpPost]
public ActionResult confirmation(TimeLineModel model, FormCollection collection)
{
var longMessages = collection["BuzzMessages.LongMessage"];
}