I install the Laravel file manager package in my app. but already I cant use thumbnail images in the blog.
How can I get an image thumbnail of uploaded photos when I use Laravel file manager?
After much searching, I realized that such a function does not exist (at least until the time of writing this message).
I defined a function in the helper that returns the address of the thumbnail from the URL of the original image.
The reader should note that these definitions may differ based on the setting of parameters for another person.
function LMFThums($url)
{
$url2= str_replace(basename($url) , '', $url ) ;
$url2=$url2.'thumbs/'.basename($url);
return $url2 ;
}
Related
Goal: My goal ist to upload images and a) keep the original name and b) know the exact URL path.
I set the Upload preset to:
Overwrite: true
Use filename or externally defined public ID: true
Unique filename: false
Delivery type: upload
Access mode: public
When I upload images using the Dashboard Media Library my images keep the original filename (which is great) but cloudinary adds a unique ID "v1585290075" into the URL.
https:// strong textres.cloudinary.com/xxxxx/image/upload/ => v1585290075 <= /2020-03-27-ee-apps/xxxxxxx.png
This unique ID prevents me from knowing the exact URL.
Question: How can I upload images and avoid getting the unique ID in the URL??
The Unique ID you're referring to is a version component that you can utilize to bust the CDN's cache (see here). It is not mandatory and you can safely remove it and the images will still show.
I'm using storage_path() for storing uploaded images, but when I use it is pointing wrong on my page.
I use it like this {{ $data->thumbnail }} where $data came from the database and thumbnail comes as the string which used storage_path
Let us take a look at the default L4 application structure:
app // contains restricted server-side application data
app/storage // a writeable directory used by L4 and custom functions to store data ( i.e. log files, ... )
public // this directory is accessible for clients
If I were you, I would upload the file to the public directory directly:
Store image here: public_path() . 'img/filename.jpg'
Save the 'img/filename.jpg' in database
Generate the image URL with url('img/filename.jpg') => http://www.your-domain.com/img/filename.jpg
Hope this helps.
The storage_path function returns the path to the storage folder, which is inside the app folder --and outside the public folder-- so it's not directly accessible from the client, that's why your images are not being displayed. You can move them to the public folder path, or you could use a custom controller to handle the image requests, read the image from the storage folder and return the value.
Here is my BrandController.php
https://gist.github.com/a958926883b9e7cc68f7#file-brandcontroller-php-L53
I've gone through all my files of my custom module, and compared them to the one given from the custom module maker, and I couldn't find much differences.
Are you attempting to upload multiple files? If you're using multiple fileupload elements with the same name you'll get an array of items.
So when the following line is called,
//this way the name is saved in DB
$data['filename'] = $_FILES['filename']['name'];
It will have the value
["name"]=>array(2) {
[0]=>string(9)"file0.txt"
[1]=>string(9)"file1.txt"
}
you'll need to update the code to loop through each $_FILES['filename']['name'] and upload and save the files separately.
You may unknowingly uploaded multiple files. If you that is not your intention, you may check your in your HTML and check the name attribute of the tag. It must not be an array (like this).
<input type="file" name="my_files[]" />
If you only see Array() in your database, it means you are indeed uploading a multiple files. You can process them by using loops.
If you are really sure that you are uploading 1 image, you may follow #Palanikumar's suggestion. Use a print_r() and display the $_FILES and paste it here. IF you don't want to use that, You can use
json_encode($the-data-you-are-going-to-insert-to-the-database);
If you don't know where to put the print_r() function, you may put it after line 56 of this file.
https://gist.github.com/desbest/a958926883b9e7cc68f7#file-brandcontroller-php-L53
if(isset($_FILES['filename']['name']) && $_FILES['filename']['name'] != '') {
print_r($_FILES);
die;
If saveAction() is being called inside an ajax function you need to log the ajax response. Assuming you are using jquery..
$ajaxResponse = $.POST({...});
console.log($ajaxResponse.responseText);
Then, you you can view it inside a browser's console. If nothing appears, you may use a non-async request
$ajaxResponse = $.POST({
// your options,
// your another option,
async: FALSE
});
Usually file upload will return in array format. So that each uploaded file will have the information like name, type, size, temporary name, error. You can get the file information using print function (print_r($_FILES)). So if you want to display name of the file you have to use something like this $_FILES['filename']['name']
Use print function and debugging tool then save file information using loops.
For more info please check here.
You aren't setting the enctype of the form so the image will never be sent. updated the code to
$form = new Varien_Data_Form(array( 'enctype' => 'multipart/form-data'));
I would like to call a Ruby script when a user uploads an image to my Drupal content-type. I have a CCK image field that serves as the main image, and ImageCache takes care of resizing and creating thumbnails for me.
I have a Ruby script that does some transformations to the image, however I don't exactly know how to call it (no experience with Ruby really). Basically the script applies some image transforms and then generates a new image.
My question is how to call this script from Drupal...is there some sort of hook regarding the CCK image upload that I would hijack?
ImageField uses the same API as FileField. Therefore, you could add a custom validator for your upload field, which would do some checks on the image (like calling a ruby script).
I described that some time ago on Drupal.org, see: http://drupal.org/node/546146
However, for your convenience, here the code.
First, define a validator for the upload form:
function example_form_alter(&$form, $form_state, $form_id) {
if ($form_id != 'ID_OF_YOUR_FORM')
return;
$form['FIELDNAME'][0]['#upload_validators']['example_FUNCTIONNAME'] = array();
return $form;
}
Second, implement the validator function:
function example_FUNCTIONNAME($field) {
// variable for error messages
$errors = array();
// do some processing on the field
$filepath = $field->filepath;
...
// in case of error, add error message
$errors[] = t('Validation failed, because...');
return $errors;
}
Put this code in a custom module, but make sure that your module is called after FileField and ImageField (adjust weight in system table).
Update: There is another way to hook into it. You can use hook_nodeapi to react on operation "presave". This also allows you to call a script on the content of the uploaded field.
How to populate image field value with drupal_execute.
for ex my content type (test) has two additional fields
1. photo (image filed),
2. phid (text field)
for phid $form_state['values']['field_phid'][0]['value'] ='14'; . how to populate photo which is image field type
If the file is already uploaded to Drupal and has a file ID (fid) then you can just do
$form_state['values']['field_image_filed'][0]['fid'] = 17; //where 17 is the Drupal file ID of the file you want input
If the file isn't already uploaded it's a lot trickier. You'll first need to programmatically create the file. I can't walk you through it off-hand but a good place to look for a template as to how it should be done is the file_service_save() function in the Services module's file_service.inc:
http://drupalcode.org/viewvc/drupal/contributions/modules/services/services/file_service/file_service.inc?revision=1.1.2.7.2.3&view=markup&pathrev=DRUPAL-6--2-2
To be clear: I'm not saying you'll use file_service_save() to accomplish the upload, but that that code shows you what needs to be done. It will show you how to save the file to the server using file_save_data(), record the file to the Drupal "files" table, then call hook_file_insert to notify other modules that a file's been saved.
i found the solution as below . i dont know pros and cons but it works fine for me.
$image = "*******/test.jpg";
$field = content_fields('field_img', 'img_test');
$validators = array_merge(filefield_widget_upload_validators($field), imagefield_widget_upload_validators($field));
$files_path = filefield_widget_file_path($field);
$form_state['values']['field_img'][]= field_file_save_file($image, $validators, $files_path, FILE_EXISTS_REPLACE);