I have got a question. How should I proceed and make this code print out and execute curl examples that I have on my external file?
How I want it to work is to match the pattern, get text between the patterns (without the pattern) and then execute it.
Is there way to do this?
Thanks for the help.
read -p "Enter a word: " instance
testfile=test.txt
case $instance in
loresipsum)
sed -n '/^loremipsum1/,${p;/^loremipsum2/q}' $testfile \
| while read -r line; do
makingcurlCall=$(eval "$line")
echo "makingcurlCall"
done < $testfile ;;
foobar)
sed -n '/^foobar1/,${p;/^foobar2/q}' $testfile \
| while read -r line; do
makingcurlCall=$(eval "$line")
echo "makingcurlCall"
done < $testfile ;;
*)
printf 'No match for "%s"\n' ":instance"
esac
Text file looks like this
loremipsum1
curl example1
curl example2
curl example3
loremipsum2
foobar1
curl foo
curl bar
curl foo
foobar2
You cannot have the while loop read from both the output of sed and directly from the file. Your current code is ignoring the output from sed and reading directly from the file. Perhaps refactor it like:
#!/bin/sh
instance=${1-loresipsum}
testfile=test.txt
case $instance in
loresipsum) sed -n '/^loremipsum1/,/^loremipsum2/p' "$testfile";;
foobar) sed -n '/^foobar1/,/^foobar2/p' "$testfile";;
*) echo "Error: no match" >&2;;
esac \
| sed -e 1d -e '$d' -e '/^\s*$/d' | while read -r line; do
# makingcurlCall=$(eval "$line")
echo "makingcurlCall: $line"
done
Related
so the file contains data like
# entertainment
youtube.com
twitch.tv
# research
google.com
wikipedia.com
...
and I would like to pass that file as an argument in a script that would open all lines if they doesn't start with an #. Any clues on how to ?
so far what i have:
for Line in $Lines
do
case "# " in $Line start firefox $Line;; esac
done
some code that could be useful (?):
while read line; do chmod 755 "$line"; done < file.txt
grep -e '^[^#]' inputfile.txt | xargs -d '\n' firefox --new-tab
grep -e '^[^#]': Will print all lines that don't start with a sharp (comments)
xargs -d '\n' firefox --new-tab: Will pass each line that is not blank, as argument to Firefox.
Removes both the lines that start with # and empty lines.
#!/bin/bash
#
while read -r line
do
if [[ $(echo "$line" | grep -Ev "^#|^$") ]]
then
firefox --new-tab "$url" &
fi
done <file.txt
Skip the empty lines and the lines that starts with a #
#!/usr/bin/env bash
while IFS= read -r url; do
[[ "$url" == \#* || -z "$url" ]] && continue
firefox --new-tab "$url" &
done < file.txt
awk 'NF && $1!="#"{print "firefox --new-tab", $0, "&"}' file.txt | bash
I am reading a file with lines like:
folder=abc
name=xyz
For some lines line I would like set a variable e.g name=xyz corresponding to the line I have read.
Cutting it down, with name=xyz and folder=abc, I have tried:
while read -r line; do
$line
echo $name
done < /etc/testfile.conf
This gives an error message ./test: line 4: folder=abc: command not found etc.
I have tried "$line" and $($line) and it is the same. Is it possible to do what I whant?
I have succeeded by doing:
while read -r line; do
if [[ "$line" == 'folder'* ]]; then
folder="$(echo "$line" | cut -d'=' -f 2)"
fi
if [[ "$line" == 'name'* ]]; then
name="$(echo "$line" | cut -d'=' -f 2)"
fi
done < /etc/testfile.conf
but this seems messy
for your sample, declare is the safest option:
while read -r line; do
declare "$line"
done
$ echo "$folder"
abc
$ echo "$name"
xyz
Direct approach, use eval.
Different approach, try with source or .:
$ echo "$line"
folder=abc
$ . <(echo "$line")
$ echo "$folder"
abc
But probably the good answer will be to tackle the problem in a different way.
You can clean up your approach a bit without resorting to eval.
while IFS="=" read -r name value; do
case $name in
folder) folder=$value ;;
name) name=$value ;;
esac
done < /etc/testfile.conf
why not only source de file ?
$ . infile ; echo "$name"
xyz
i try to remove some string of my result before to send them on my array . i tried different stuff but i didn't found it :(
actually in my $LOGFILE i've something like that :
STATUS TO_CHAR(TO_TIMESTAM
--------------- -------------------
AVAILABLE 2017.10.18 18:00:30
AVAILABLE 2017.10.24 18:00:26
And i try to have only the date 2017.10.18 18:00:30
function read_file {
while read line;do
arr[$i]="$line"
i=$((i+1))
# $line | sed s/"-"//g | sed s/"STATUS"//g | sed s/'TO_CHAR(TO_TIMESTAM'//g | sed s/"AVAILABLE"//g | sed '/^ *$/d'
done< $LOGFILE
printf '%s\n' "${arr[#]}"
}
Would grep be acceptable?
grep -o '[0-9].*' $LOGFILE
Output:
2017.10.18 18:00:30
2017.10.24 18:00:26
Use mapfile to capture the output in an array.
$ mapfile -t arr < <(grep -o '[0-9].*' $LOGFILE)
$ echo ${arr[0]}
2017.10.18 18:00:30
$ echo ${arr[1]}
2017.10.24 18:00:26
Many thanks to this post.
This is my code
title=""
line=""
fname=$1
numoflines=$(wc -l < $fname)
for ((i=2 ; i<=$numoflines ; i++))
do
...
done
In the for loop i want to print the first word of every line into $title
and the rest of the line without the first word into $line
(using bash)
tnx
I am assuming that by print to a variable you mean add the contents of each line to the variable. To do this, you can use the bash built-in function read:
while read -r t l; do title+="$t"; line+="$l"; done < "$fname"
This will add the first word of every line to $title and the rest of the line to $line.
You can do some like this:
echo "$fname"
This is my line.
My cat is green.
title=$(awk '{print $1}' <<< "$fname")
line=$(awk '{$1="";sub(/^ /,"")}1' <<< "$fname")
echo "$title"
This
My
echo "$line"
is my line.
cat is green.
Alternative approach using the cut command:
file="./myfile.txt"
title=$(cut -f1 -d ' ' "$file")
line=$(cut -f2- -d ' ' "$file")
#check print
pr -tm <(echo -e "TITLES\n$title") <(echo -e "LINES\n$line")
for the next myfile.txt
My cat is green.
Green cats are strange.
prints
TITLES LINES
My cat is green.
Green cats are strange.
do
Tempo="$( sed -n "${i} {s/^[[:blank:]]*\([^[:blank:]]*\)[[:blank:]]*\(.*\)/title='\1';line='\2'/p;q;}" ${fname} )"
eval "${Tempo}"
done
# or
do
sed -n "${i} {p;q;}" | read Line Title
# but this does not keep content available on each OS/shell
done
I have in a bash script:
for i in `seq 1 10`
do
read AA BB CC <<< $(cat file1 | grep DATA)
echo ${i}
echo ${CC}
SORT=${CC}${i}
echo ${SORT}
done
so "i" is a integer, and CC is a string like "TODAY"
I would like to get then in SORT, "TODAY1", etc
But I get "1ODAY", "2ODAY" and so
Where is the error?
Thanks
You should try
SORT="${CC}${i}"
Make sure your file does not contain "\r" that would end just in the end of $CC.
This could well explain why you get "1ODAY".
Try including
|tr '\r' ''
after the cat command
try
for i in {1..10}
do
while read -r line
do
case "$line" in
*DATA* )
set -- $line
CC=$3
SORT=${CC}${i}
echo ${SORT}
esac
done <"file1"
done
Otherwise, show an example of file1 and your desired output
ghostdog is right: with the -r option, read avoids succumbing to potential horrors, like CRLFs. Using arrays makes the -r option more pleasant:
for i in `seq 1 10`
do
read -ra line <<< $(cat file1 | grep DATA)
CC="${line[3]}"
echo ${i}
echo ${CC}
SORT=${CC}${i}
echo ${SORT}
done