I wrote a kernel, without using -ffreestanding option, and while looking some kernels source codes, I see they compiled its kernels with -ffreestanding option. So, I tried to see what happens if I compile with the -ffreestanding option? And I see there was no difference between compiling with the -ffreestanding, and without the -ffreestanding option:
$ xxd kernel > kernel.xxd
$ xxd kernel_freestanding > kernel_freestanding.xxd
$ diff kernel kernel_freestanding
Why use an option, and see the files are same with, and without using that option?
And the diff's command output was empty, and the files are same.
Edit
That's how I compile, and it has no effect:
$(CPP_OBJS): %.o: %.cpp
$(CC) -m32 -nostdlib -nostdinc -fno-builtin -c $< -o $# -Iinclude -Iinclude/lib/k -Iinclude/lib/kc
Related
I am trying to understand makefile.
I took atmega168 bootloader's makefile and simplified it to this:
CC = avr-gcc
override CFLAGS = -g -Wall -Os -mmcu=atmega328p -DF_CPU=16000000L '-DMAX_TIME_COUNT=F_CPU>>4' '-DNUM_LED_FLASHES=1' -DBAUD_RATE=57600
atmega328: ATmegaBOOT_168_atmega328.hex
%.elf: ATmegaBOOT_168.o
avr-gcc -g -Wall -Os -mmcu=atmega328p -DF_CPU=16000000L '-DMAX_TIME_COUNT=F_CPU>>4' '-DNUM_LED_FLASHES=1' -DBAUD_RATE=57600 -Wl,--section-start=.text=0x7800 -o $# $<
clean:
rm -rf *.o *.elf *.lst *.map *.sym *.lss *.eep *.srec *.bin *.hex
%.hex: %.elf
avr-objcopy -j .text -j .data -O ihex $< $#
When I ran $ make atmega328 I get:
avr-gcc -g -Wall -Os -mmcu=atmega328p -DF_CPU=16000000L '-DMAX_TIME_COUNT=F_CPU>>4' '-DNUM_LED_FLASHES=1' -DBAUD_RATE=57600 -c -o ATmegaBOOT_168.o ATmegaBOOT_168.c
avr-gcc -g -Wall -Os -mmcu=atmega328p -DF_CPU=16000000L '-DMAX_TIME_COUNT=F_CPU>>4' '-DNUM_LED_FLASHES=1' -DBAUD_RATE=57600 -Wl,--section-start=.text=0x7800 -o ATmegaBOOT_168_atmega328.elf ATmegaBOOT_168.o
avr-objcopy -j .text -j .data -O ihex ATmegaBOOT_168_atmega328.elf ATmegaBOOT_168_atmega328.hex
rm ATmegaBOOT_168_atmega328.elf ATmegaBOOT_168.o
Why cannot I remove CC or CFLAGS?
I understand some basics of makefile. I read a lot on the internet, plus went through gnu manual, but I cannot understand the very first output with ATmegaBOOT_168.c. What/How has generated first command?
Was there used some second makefile? If yes, how to find its location?
UPDATE:
If I rename ATmegaBOOT_168.c to ATmegaBOOT_1681.c. Running $ make atmega328 gives:
make: *** No rule to make target 'ATmegaBOOT_168_atmega328.hex', needed by 'atmega328'. Stop.
but the rule is present.
CC and CFLAGS are variables used in the built in implicit rules of GNU make. When you run make, it reads your makefile a bit like:
No target given, so we'll make the first: atmega328. This requires a .hex file.
The .hex file can be generated from a .elf file per the last rule.
.elf files can be generated by the %.elf rule (which here looks like you've broken the pattern, as there's no % in the dependencies).
There's no rule for .o in this file, so the default recipe $(CC) $(CPPFLAGS) $(CFLAGS) -c is used. Since a .c file is found, this rule is applicable and generates the first command. The rule could have been written (as shown in suffix rules):
.c.o:
$(CC) -c $(CFLAGS) $(CPPFLAGS) -o $# $<
Backtrack up this list, now that the source has been found, and run the commands.
If the implicit rule variables are left unset, you will typically get programs built for your host system using cc.
I want to automate the compilation of a toy library using CUDA and C++. Then I write a Makefile as follows
CC=g++
NVCC=nvcc
CXXFLAGS= -fopenmp -O3 -Wextra -std=c++11
CUDAFLAGS= -std=c++11 -c -arch=sm_20
LIBS= -lopenblas -lpthread -lcudart -lcublas
LIBDIRS=-L/usr/local/cuda-7.5/lib64
INCDIRS=-I/usr/local/cuda-7.5/include
matrix_cuda.o: marix_cuda.cu
$(NVCC) $(CUDAFLAGS) matrix_cuda.cu
all: matrix_cuda.o
$(CC) -o test matrix_blas.cpp alg.cpp test.cpp matrix_cuda.o $(LIBDIRS) $(INCDIRS) $(LIBS) $(CXXFLAGS)
clean:
rm -rf test *.o
Typing make I get
make: *** No rule to make target `marix_cuda.cu', needed by `matrix_cuda.o'. Stop.
I never wrote a Makefile before. Where did I go wrong?
I think you have a typo in the CUDA file name
matrix_cuda.o: marix_cuda.cu
$(NVCC) $(CUDAFLAGS) matrix_cuda.cu
IMHO it should be
matrix_cuda.o: matrix_cuda.cu
$(NVCC) $(CUDAFLAGS) matrix_cuda.cu
This may take a couple of iterations.
1) First try this:
nvcc -std=c++11 -c -arch=sm_20 matrix_cuda.cu
If that works (and produces matrix_cuda.o, I presume), remove matrix_cuda.o and
2) try this makefile:
matrix_cuda.o: matrix_cuda.cu
nvcc -std=c++11 -c -arch=sm_20 matrix_cuda.cu
If that works,
3) try this:
g++ -o test matrix_blas.cpp alg.cpp test.cpp matrix_cuda.o -L/usr/local/cuda-7.5/lib64 -I/usr/local/cuda-7.5/include -lopenblas -lpthread -lcudart -lcublas -fopenmp -O3 -Wextra -std=c++11
If that works, remove test and
4) try this makefile:
test: matrix_cuda.o
g++ -o test matrix_blas.cpp alg.cpp test.cpp matrix_cuda.o -L/usr/local/cuda-7.5/lib64 -I/usr/local/cuda-7.5/include -lopenblas -lpthread -lcudart -lcublas -fopenmp -O3 -Wextra -std=c++11
matrix_cuda.o: matrix_cuda.cu
nvcc -std=c++11 -c -arch=sm_20 matrix_cuda.cu
If that works, remove test and matrix_cuda.o and
5) try that makefile again.
If that works, there are further refinements we can make.
Also your first make rule corresponds to compiling the object file matrix_cuda.o. The all make rule should come first since the first rule in the make file is the one that gets updated first when invoking the command make. GNU Make has great documentation explaining how to make simple to complex makefiles. You can check it out here:
https://www.gnu.org/software/make/manual/make.html.
Also another issue you are going to run into is that in your make recipe for the all rule, you are supposed to be linking together only object files to create the final executable. However you are trying to include matrix_blas.cpp alg.cpp test.cpp in this linking step. Instead of .cpp versions of these files they need to be .o versions (the compiled objects). Make can generate these object files for you. You just need to have a make rule and recipe for each one. For example:
matrix_blas.o: matrix_blas.cpp
$(CC) $(CXXFLAGS) -c matrix_blas.cpp -o matrix_blas.o
I want to add some commentary on this Makefile for future reference and better automation :
1. NVCC=nvcc environment variable is superfluous. There is only one compiler for NVIDIA GPUs and you would nonetheless have to change a lot of flags to compile for other architectures like AMD.
-arch=native is better suited if you want to deploy your code on multiple machines with GPUs having different architectures
-dc is the flag for separate compilation. The architecture must be specified before -dc see (with a generic Makefile): https://developer.nvidia.com/blog/separate-compilation-linking-cuda-device-code/
You should add automatic rule to avoid these typos errors :
%.o: %.cu
nvcc -dc $(CUDAFLAGS) $< -o $#
The Makefile will look for all dependencies ending by .o. If it needs to build one, it looks if it has the corresponding .cu file. I would actually remove the -dc from flags and be explicit here that I want to build object files.
$# is the name of the rule target. $< is the first prerequisite. Only one file at a time can be passed to nvcc with the -dc flag, so here $< is better than $^.
You may add the name of the executable in a variable so that you delete the same executable that you generated (and facilitate name change).
I added a .PHONY rule. This only removes the confusion that happens whenever someone writes a file named clean in the directory.
The Makefile can not differenciate between the file and the make clean rule.
CC=g++
CXXFLAGS= -fopenmp -O3 -Wextra -std=c++11
CUDAFLAGS= -std=c++11 -arch=sm_20
LIBS= -lopenblas -lpthread -lcudart -lcublas
LIBDIRS=-L/usr/local/cuda-7.5/lib64
INCDIRS=-I/usr/local/cuda-7.5/include
PROGRAM= test
%.o: %.cu
nvcc -dc $(CUDAFLAGS) $< -o $#
all: matrix_cuda.o
$(CC) -o $(PROGRAM) matrix_blas.cpp alg.cpp test.cpp matrix_cuda.o $(LIBDIRS) $(INCDIRS) $(LIBS) $(CXXFLAGS)
.PHONY: clean
clean:
rm -rf $(PROGRAM) *.o
I'm using CentOS 6.5. When I do a make, I typically see the full gcc/g++ commands that the Makefile is executing, like
...
gcc -std=gnu99 -DHAVE_CONFIG_H -I. -I/opt/emacs/emacs-24.3/lib -I../src -I/opt/emacs/emacs-24.3/src -g3 -O2 -MT pthread_sigmask.o -MD -MP -MF .deps/pthread_sigmask.Tpo -c -o pthread_sigmask.o pthread_sigmask.c
...
But in some systems, I only see:
$ make
Building test1.o...
Building test2.o...
...
Is it possible to change the "Building ..." messages back to the full gcc/g++ command output?
The output that you see when you run make with a given makefile
depends on how the makefile is written. You will see the
output that the author of the makefile wants you to see.
If a command in a recipe in the makefile is prefixed with #,
then make will not echo the command. So if my makefile is, e.g.
foobar: foobar.o
gcc -o $# $<
foobar.o: foobar.c
gcc -c -o $# $<
then the output of make will be:
gcc -c -o foobar.o foobar.c
gcc -o foobar foobar.o
But if I change the makefile to:
foobar: foobar.o
#echo "Linking foobar"
#gcc -o $# $<
foobar.o: foobar.c
#echo "Compiling foobar"
#gcc -c -o $# $<
then the output becomes:
Compiling foobar
Linking foobar
So to see the output that you would prefer to see you will have to edit the
makefile, removing the #-prefixes from the commands you expect to see
and deleting entirely the commands that print the "Building..." messages.
At least, this is what you would need to do if the makefiles that bother
you in this way build the target using recipes that directly invoke gcc/g++. It
is possible that they build their targets using recipes that invoke some intermediate
tool that doesn't echo the compiler commands and instead emits the "Building..."
messages. Without seeing the makefile(s) I can't say.
when Makefile execute some tasks, il will print many information in console, can we choose to hide them? when I have many .o to generate, these information will be too many to see and they are just meaningless if we don't read them.
The following code
$(obj)environment.o: $(src)environment.c
$(CC) $(AFLAGS) -Wa, --no-warn \
-DENV_CRC=$(shell $(obj)../tools/envcrc) \
-c -o $# $(src)environment.c
will print heavy information like
arm-linux-gcc -g -Os -fno-strict-aliasing -fno-common -ffixed-r8 -msoft-float
-D__KERNEL__ -DTEXT_BASE=0x01000000
-I/home/mingzhao/Documents/bootloader/u-boot-1.2.0/include
-fno-builtin -ffreestanding -nostdinc -isystem
/home/mingzhao/Documents/bootloader/arm/4.3.2/bin/../lib/
gcc/arm-none-linux-gnueabi/4.3.2/include -pipe -DCONFIG_ARM
-D__ARM__ -march=armv4 -mabi=apcs-gnu -Wall -Wstrict-prototypes
-c -o environment.o environment.c
The "right" way to handle this (IMO) is to add this to your makefile:
$(VERBOSE).SILENT:
Then in your rules where you don't ever want the command printed (for example, an echo statement as in Beta's answer below) you prefix it with #. For all other commands, you don't prefix it with #.
What this does is enable "silent" mode by default (because the variable VERBOSE is not set and so this resolves to the .SILENT pseudo-target).
Then if you want to see everything, you add a VERBOSE=1 (actually you can set it to any non-empty value, so VERBOSE=true if you prefer). When you do that it turns off "silent" mode because the above line expands to 1.SILENT: (or true.SILENT: or whatever) which is meaningless to make.
You can use the option make --silent which will suppress output for all targets. If you want to suppress output for some commands, you can prefix them by #
I like something like this:
$(obj)environment.o: $(src)environment.c
#echo building $#
#$(CC) $(AFLAGS) -Wa, --no-warn \
-DENV_CRC=$(shell $(obj)../tools/envcrc) \
-c -o $# $(src)environment.c
The #echo ... gives a minimal status message, the '#' in front of the $(CC) suppresses standard output (but still allows error messages).
You can use this syntax : #$(CC) $(AFLAGS) -Wa, --no-warn \...
I am pretty new to Makefiles and i am trying to build an executable from 3 files, file1.c, file2.c, and file1.h into an executable called exFile. Here's what I got:
all: exFile
exFile: file1.o file2.o
gcc -Wall -g -m32 repeat.o show.o -o repeat
file1.o: file1.c file1.h
gcc -Wall -g -m32 -S file1.c -o file1.o
file2.o: file2.c
gcc -Wall -g -m32 -S file2.c -o file2.o
I've searched the web for makefiles in this format, but i came up empty handed so i was wondering if someone can help. When it tries to compile i get:
usr/bin/ld:file1.o:1: file format not recognized; treating as linker script
I've compiled programs using assembly files but I'm not to sure what to do with c files or the file1.h file. file1.c includes file1.h so i have to link them (I think?). Any suggestions or links to a reference would be appreciated
You have two problems with your gcc command-line. First, you're specifying the -S flag, which causes gcc to emit assembly code, rather than object code. Second, you're missing the -c flag, which tells gcc to compile the file to an object file, but not link it. If you just remove -S and change nothing else, you'll end up with an executable program named file1.o and another named file2.o, rather than two object files.
Besides those errors, you could simplify your makefile by the use of pattern rules. I suggest you try the following instead:
all: exFile
exFile: file1.o file2.o
gcc -Wall -g -m32 $^ -o $#
%.o: %.c
gcc -Wall -g -m32 -c $< -o $#
file1.o: file1.h
Or, as EmployedRussian points out, you can go with something even more minimal that leverages more of the built-in features of GNU make:
CC=gcc
CFLAGS=-Wall -g -m32
all: exFile
exFile: file1.o file2.o
$(LINK.c) $^ -o $#
file1.o: file1.h
The -S switch to gcc tells it to output assembler so this:
gcc -Wall -g -m32 -S file1.c -o file1.o
Is putting assembler into file1.o but you want, presumably, to compile file1.c into object code:
gcc -Wall -g -m32 file1.c -o file1.o
When the linker gets your file1.o it is confused because file1.o is assembler when the linker is expecting object code, hence your error.
So get rid of the -S switches for file1.o and file2.o.