I have a large Comma-Separated File (6GB) and would like to add an index column to it. I'm looking at Unix type solutions for efficiency. I'm using a Mac.
I have this:
V1 V2 V3
0.4625 0.9179 0.8384
0.9324 0.2486 0.1114
0.6691 0.7813 0.6705
0.1935 0.3303 0.4336
Would like to get this:
ID V1 V2 V3
1 0.4625 0.9179 0.8384
2 0.9324 0.2486 0.1114
3 0.6691 0.7813 0.6705
4 0.1935 0.3303 0.4336
This will probably work:
awk -F'\t' -v OFS='\t' '
NR == 1 {print "ID", $0; next}
{print (NR-1), $0}
' input.csv > output.csv
In awk, the NR variable is "the total number of input records seen so far", which in general means "the current line number". So the NR == 1 in the first line is how we match the first record and add the "ID" column header, and for the remaining lines we use NR-1 as the index.
The -F'\t' argument sets the input field separator, and -vOFS='\t' sets the output field separator.
Since no technology is specified in the original post, I'd be happy here to keep it simple.
(all the fancy Vim/bash solutions are fine if you know what you're doing).
Open the CSV file in your favourite spreadsheet programme (I'm using
LibreOffice, but Excel or a native Mac equivalent will do)
insert a column to the left of column A
Enter a 1 into cell A2, the first cell under the headers
Double-click the blob at the bottom right of the cell as shown in the screenshot:
This last step will fill the index column with 1,2,3... etc.
You can then save the resulting spreadsheet as a CSV file again.
I assume you have a commas delimited file.
Using vim, open the file. In normal mode, type
:%s/^/\=line('.').','/
:%s/^/\=line('.')/ adds the line number at the beginning of the line. Since you have a commas delimited file (add a column) you need a comma after your line number. so the .','
see this answer for full explanation about :%s/^/\=line('.')/
Open the CSV file in your favorite spreadsheet program, such as Excel
Insert a column to the left side of first column
Type 1 in the first cell of this column
Type an equation '=A2+1' in the following cell
Double-click the blob at the bottom right of the cell as shown in the screenshot
this is the question based on the previous solved problem.
i have the following type of .csv files(they aren't all sorted!, but the structure of columns is the same):
name1,address1,town1,zip1,email1,web1,,,,category1
name2,address2,town2,zip2,email2,,,,,category2
name3,address3,town3,zip3,email3,,,,,category3_1
name3,address3,town3,zip3,,,,,,category3_2
name3,address3,town3,zip3,,,,,,category3_3
name4,address4,town4,zip4,,,,,,category4_1
name4,address4,town4,zip4,email4,,,,,category4_2
name4,address4,town4,zip4,email4,,,,,category4_3
name4,address4,town4,zip4,,,,,,category4_4
name5,address5,town5,zip5,,,,,,category5_1
name5,address5,town5,zip5,,web5,,,,category5_2
name6,address6,town6,zip6,,,,,,category6
first 4 records in columns are always populated, other columns are not always, except the last one - category
empty space between "," delimiter means that there is no data for the particular line or name
if the nameX doesnt contain addressX but addressY, it is a different record(not the same line) and should not be concatenated
i need the script in sed or awk, maybe the bash(but this solution is little slower on bigger files[hundreds of MB+]), that will take first 4 columns(in this case) compares them and if matched, will merge every category with the ";" delimiter and will keep the structure and the most possible data in other columns of those matched lines of a .csv file:
name1,address1,town1,zip1,email1,web1,,,,category1
name2,address2,town2,zip2,email2,,,,,category2
name3,address3,town3,zip3,email3,,,,,category3_1;category3_2;category3_3
name4,address4,town4,zip4,email4,,,,,category4_1;category4_2;category4_3;category4_4
name5,address5,town5,zip5,,web5,,,,category5_1;category5_2
name6,address6,town6,zip6,,,,,,category6
if that is not possible, solution could be to retain data from the first line of the duped data(the one with categoryX_1). example:
name1,address1,town1,zip1,email1,web1,,,,category1
name2,address2,town2,zip2,email2,,,,,category2
name3,address3,town3,zip3,email3,,,,,category3_1;category3_2;category3_3
name4,address4,town4,zip4,,,,,,category4_1;category4_2;category4_3;category4_4
name5,address5,town5,zip5,,,,,,category5_1;category5_2
name6,address6,town6,zip6,,,,,,category6
does the .csv have to be sorted before using the script?
thank you again!
sed -n 's/.*/²&³/;H
$ { g
:cat
s/\(²\([^,]*,\)\{4\}\)\(\([^,]*,\)\{5\}\)\([^³]*\)³\(.*\)\n\1\(\([^,]*,\)\{5\}\)\([^³]*\)³/\1~\3~ ~\7~\5;\9³\6/
t fields
b clean
:fields
s/~\([^,]*\),\([^~]*~\) ~\1,\([^~]*~\)/\1,~\2 ~\3/
t fields
s/~\([^,]*\),\([^~]*~\) ~\([^,]*,\)\([^~]*~\)/\1\3~\2 ~\4/
t fields
s/~~ ~~//g
b cat
:clean
s/.//;s/[²³]//g
p
}' YourFile
Posix version (so --posixwith GNU sed) and without sorting your file previously
2 recursive loop after loading the full file in buffer, adding marker for easier manipulation and lot of fun with sed group substitution (hopefully just reach the maximum group available).
loop to add category (1 line after the other, needed for next loop on each field) per line and a big sub field temporary structured (2 group of field from the 2 concatened lines. field 5 to 9 are 1 group)
ungroup sub field to original place
finaly, remove marker and first new line
Assuming there is no ²³~ character because used as marker (you can use other marker and adapt the script with your new marker)
Note:
For performance on a hundred MB file, i guess awk will be lot more efficient.
Sorting the data previoulsy may help certainly in performance reducing amount of data to manipulate after each category loop
i found, that this particular problem is faster being processed through db...
SQL - GROUP BY to combine/concat a column
db: mysql through wamp
I have an instrumented log file that have 6 lines of duplicated first column as below.
//SC001#1/1/1#1/1,get,ClientStart,1363178707755
//SC001#1/1/1#1/1,get,TalkToSocketStart,1363178707760
//SC001#1/1/1#1/1,get,DecodeRequest,1363178707765
//SC001#1/1/1#1/1,get-reply,EncodeReponse,1363178707767
//SC001#1/1/1#1/2,get,DecodeRequest,1363178708765
//SC001#1/1/1#1/2,get-reply,EncodeReponse,1363178708767
//SC001#1/1/1#1/2,get,TalkToSocketEnd,1363178708770
//SC001#1/1/1#1/2,get,ClientEnd,1363178708775
//SC001#1/1/1#1/1,get,TalkToSocketEnd,1363178707770
//SC001#1/1/1#1/1,get,ClientEnd,1363178707775
//SC001#1/1/1#1/2,get,ClientStart,1363178708755
//SC001#1/1/1#1/2,get,TalkToSocketStart,1363178708760
Note: , (comma) is the delimiter here
Like wise there are many duplicate first column values (IDs) in the log file (above example having only two values (IDs); //SC001#1/1/1#1/1 and //SC001#1/1/1#1/2) I need to consolidate log records as below format.
ID,ClientStart,TalkToSocketStart,DecodeRequest,EncodeReponse,TalkToSocketEnd,ClientEnd
//SC001#1/1/1#1/1,1363178707755,1363178707760,1363178707765,1363178707767,1363178707770,1363178707775
//SC001#1/1/1#1/2,1363178708755,1363178708760,1363178708765,1363178708767,1363178708770,1363178708775
I suppose to have a bash script for this exercise and appreciate an expert support for this. Hope there may be a sed or awk solution which is more efficient.
Thanks much
One way:
sort -t, -k4n,4 file | awk -F, '{a[$1]=a[$1]?a[$1] FS $NF:$NF;}END{for(i in a){print i","a[i];}}'
sort command sorts the file on the basis of the last(4th) column. awk takes the sorted input and forms an array where the 1st field is the key, and the value is combination of values of the last column.