trying to print a loop over x for values of q, but keep getting this syntax error. Can anyone help with this?
Because it's a vector/array, not a single value. You may try the following:
np.set_printoptions(precision=2)
print(f'x = {x} -> q = {q}')
You could also take a look at numpy.array2string function.
Related
I have the following code:
loop (d,
rnd(d)=uniformInt(1,nd)
);
I am going to use the integer numbers rnd(d) as an index of another set s(i). But for example when rnd(d)=34.000 however, it is integer, but s(34.000) has no valid index since, 34.000 is not 34 !! and GAMS shows a error message.
I don't know if #Lutz solution worked out for you. In case it did not, you can try the following:
First, it is not necessary to loop over the set d, just a simple:
rnd(d) = uniformInt(1,nd);
will suffice.
Next line can go like:
loop(d,
s(i)$(i.val = ord(d)) = . . .;
);
If you still have issues, then using #Lutz suggestion just append '*1.000' to 'ord(i)' and/or 'rnd(d)', whichever is giving you issues.
Is i an ordered set? If yes, you could use something like this:
loop(d,
s(i)$(ord(i)=rnd(d)) = ...;
)
So I have some json response content represented as string and I want to get its property names.
What I am doing
let properties = Newtonsoft.Json.Linq.JObject.Parse(responseContent).Properties()
let propertyNames, (jprop: JProperty) = properties.Select(jprop => jprop.Name);
According to this answer I needed to annotate the call to the extension method, however, I still get the error.
A unique overload for method 'Select' could not be determined based on type information prior to this program point. A type annotation may be needed. Candidates: (extension) Collections.Generic.IEnumerable.Select<'TSource,'TResult>(selector: Func<'TSource,'TResult>) : Collections.Generic.IEnumerable<'TResult>, (extension) Collections.Generic.IEnumerable.Select<'TSource,'TResult>(selector: Func<'TSource,int,'TResult>) : Collections.Generic.IEnumerable<'TResult>
Am I doing something wrong?
First, the syntax x => y you're trying to use is C# syntax for lambda expressions, not F# syntax. In F#, the correct syntax for lambda-expressions is fun x -> y.
Second, the syntax let a, b = c means "destructure the pair". For example:
let pair = (42, "foo")
let a, b = pair // Here, a = 42 and b = "foo"
You can provide a type annotation for one of the pair elements:
let a, (b: string) = pair
But this won't have any effect on pair the way you apparently expect it to work.
In order to provide type annotation for the argument of a lambda expression, just annotate the argument, what could be simpler?
fun (x: string) -> y
So, putting all of the above together, this is how your line should look:
let propertyNames = properties.Select(fun (jprop: JProperty) -> jprop.Name)
(also, note the absence of semicolon at the end. F# doesn't require semicolons)
If you have this level of difficulty with basic syntax, I suggest you read up on F# and work your way through a few examples before trying to implement something complex.
I am trying to write a code that calculate the size of a list.
Here is what I've done:
let rec l = function
| [] -> 0
| t::q -> 1 + l q
print_int(l ([1;2;3;4]))
The problem is that it's saying me :
It is applied to too many arguments; maybe you forgot a `;'.
When I put the double semicolon ;; at the end of the definition of l it works well, yet I've read that ;; is not useful at all if you are not coding in the REPL, so here I don't see why it's giving me this error.
The following
print_int(l [1;2;3;4])
is a toplevel expression. Such expression needs to be preceded by ;;:
;; print_int(l [1;2;3;4])
Another option is to make this toplevel expression a binding with
let () = print_int(l [1;2;3;4])
When parsing the code the parser advances until it hits l q. At this point there could be more arguments that should get applied to the function l. So the parser keeps going and the next thing it finds is the value print_int. Another argument to l. Which gives you your error.
The parser has no way of knowing that you had finished the code for the function l. In the top level the special token ;; is used to tell the parser that the input is finished and it should evaluate the code now. After that it starts paring the remaining input again.
Now why doesn't compiled code also have the ';;' token?
Simply because its not needed. In compiled code the line print_int(l [1;2;3;4]) is not valid input. That would be a statement you want to execute and functional languages have no such thing. Instead print_int(l [1;2;3;4]) is an expression that returns a value, () in this case, and you have to tell the compiler what to do with that value. A let () = tells the compiler to match it against (). And the let ... also tells the compiler that the previous let rec l ... has finished. So no special ;; token is needed.
Or think of it this way: In the top level there is an implicit let _ = if your input doesn't start with let. That way you can just type in some expression and see what it evaluates to without having to type let _ = every time. The ';;' token still means "evaluate now" though and is still needed.
I'm trying to get a value returned through the variable A such as loves, however I'm getting a result like _382 instead.
Here's the query: ?- checksyn(likes,Result).
I would want Result to return loves, not _628. Is it not binding? I'm not sure.
Here's the code...
synonym(loves,[likes,adores]).
synonym(challenge,[problem]).
checksyn(X,A):-
synonym(_,[X|_])
; synonym(_,[_|X]),
synonym(A,[X|_]),
synonym(A,[_|X]).
Thanks in advance for any help :)
I am trying to run a granger causality test on two currency pairs but I seem to get this error message in Shell whenever I try and test it. Can anyone please advise?
I am very new to programming and need this to run an analysis for my project. In shell, I am putting -
import ats15
ats15.grangertest('EURUSD', 'EURGBP', 8)
What is going wrong? I have copied the script below.
Thanks in advance.
Heading ##def grangertest(Y,X,maxlag):
"""
Performs a Granger causality test on variables (vectors) Y and X.
The null hypothese is: Does X cause Y ?
Returned value: pvalue, F, df1, df2
"""
# Create linear model involving Y lags only.
n = len(Y)
if n != len(X):
raise ValueError, "grangertest: incompatible Y,X vectors"
M = [ [0] * maxlag for i in range(n-maxlag)]
for i in range(maxlag, n):
for j in range(1, maxlag+1):
M[i-maxlag][j-1] = Y[i-j]
fit = ols(M, Y[maxlag:])
RSSr = fit.RSS
# Create linear model including X lags.
for i in range(maxlag, n):
xlagged = [X[i-j] for j in range(1, maxlag+1)]
M[i-maxlag].extend(xlagged)
fit = ols(M, Y[maxlag:])
RSSu = fit.RSS
df1 = maxlag
df2 = n - 2 * maxlag - 1
F = ((RSSr - RSSu)/df1)/(RSSu/df2)
pvalue = 1.0 - stats.f.cdf(F,df1,df2)
return pvalue, F, df1, df2, RSSr, RSSu
You didn't post the full traceback, but this error message:
TypeError: unsupported operand type(s) for -: 'str' and 'int'
means what it says. There's an operand - -- the subtraction operator -- and it doesn't know how to handle subtracting an integer from a string. Why would strings be involved? Well, you're calling the function with:
ats15.grangertest('EURUSD', 'EURGBP', 8)
and so you're giving grangertest two strings and an integer. But it seems like grangertest expects
def grangertest(Y,X,maxlag):
two sequences (lists, arrays, whatever) of numbers to use as Y and X, not strings. If EURUSD and EURGBP are names you've given to lists beforehand, then you don't need the quotes:
ats15.grangertest(EURUSD, EURGBP, 8)
but if not, then you should pass grangertest the lists under whatever name you've called them.
The input to the grangertest function must be two lists of numbers. grangertest doesn't know anything about currencies, so passing it currency strings won't work.
You have to fetch the exchange rate data somehow so that you can pass it to grangertest. If EURUSD and EURGBP are variables, then you don't put quotes around them when you pass them to a function (e.g. ats15.grangertest(EURUSD, EURGBP, 8)).