Hello awesome community i am using git bash to run this command: cp -r thisfolder thatfolder to copy the contents of a folder in another one
now i want to make a script out of this to create a scheduler to run that script and my script looks like this
#!/bin/bash
set -euo pipefail
IFS=$'\n\t
cp -r thisfolder thatfolder && echo done > debug.txt
#the debug.txt is just to know if the script copied stuff
its a .bat script and all folders and script are on the same directory but for some reason it doesnt copy the files as git bash does
any thoughts??
Related
I have an script which creates a folder named "data". Then it downloads a file using wget and these files (.zip format) are moved from the current directory to the folder "data". After that what I want is to unzip these files. I'm using unzip filename.zip and it works when I use it on the cmd, however I don't know why it's not working in the script.
Here is the script:
#!/bin/bash
mkdir data
wget http://187.191.75.115/gobmx/salud/datos_abiertos/datos_abiertos_covid19.zip && mv datos_abiertos_covid19.zip data && unzip datos_abiertos_covid19.zip
wget http://187.191.75.115/gobmx/salud/datos_abiertos/diccionario_datos_covid19.zip && mv diccionario_datos_covid19.zip data && unzip diccionario_datos_covid19.zip
datos_abiertos_covid19.zip and diccionario_datos_covid19.zip are the files I want to unzip once they are in my folder "data". I would really appreciate if someone can help me. Thanks in advance!
It fails because unzip foo.zip assumes foo.zip is in the current directory, but you just moved it to a subdirectory data. Interactively, you probably cd data first and that's why it works.
To make it work in your script, just have your script cd data as well:
#!/bin/bash
mkdir data
cd data || exit 1
wget http://187.191.75.115/gobmx/salud/datos_abiertos/datos_abiertos_covid19.zip && unzip datos_abiertos_covid19.zip
That way, the file is downloaded directly to the data directory so no mv is necessary, and the unzip command works as expected.
My approach:
#!/bin/bash
set -e # Exit if any command fails
mkdir data
pushd ./data >/dev/null
for i in 'datos_abiertos_covid19.zip' 'diccionario_datos_covid19.zip'; do
# Don't unzip (or exit) if 'wget' fails, don't exit if 'unzip' fails
wget "http://187.191.75.115/gobmx/salud/datos_abiertos/$i" -O "./$i" || continue
unzip "./$i" || true
done
popd >/dev/null
The file names don't need to be quoted in this case, but I did so anyway, to emphasise you can/should do so if necessary
You could of course use variables for the file list, URL, download dir, etc. if you wanted to build a more general script for downloading zip files
I know it's marked bash, but worth mentioning: pushd and popd are not defined in POSIX, you can change those to cd ./data and cd .. for more portability. Obviously wget is not POSIX either, but very common (see this thread for interesting info on that topic)
Description
I want to copy all files ending on .jpg from my local machine to the remote machine with scp.
For this i have a small "script". It looks like this:
#!/bin/bash
xfce4-terminal -e "scp -r -v /path/to/local/folder/*.jpg <user>#<IP>:/var/path/to/remote/folder/" --hold
Problem
When i open a terminal and enter scp -r -v /path/to/local/folder/*.jpg <user>#<IP>:/var/path/to/remote/directory/ it works.
So SSH is working correct.
When i start the script it doesnt.
The script works, when i copy the whole local folder. It then looks like this (simply the *.jpg is removed):
#!/bin/bash
xfce4-terminal -e "scp -r -v /path/to/local/folder/ <user>#<IP>:/var/path/to/remote/folder/" --hold
But then i have the local folder inside the remote folder, where i only want to have the files.
I dont know, if it is important but currently i use a computer with Linux Mint 19.3, xfce terminal and zshell.
Question
So how do i run a script correctly that copys files from a local folder to remote folder?
It's the shell who expands the wildcard, but when you run -e in xfce4-terminal, it runs the command without letting the shell parse it. You can run a shell to run the command, though:
xfce4-terminal -e "bash -c 'scp -r -v /path/to/local/folder/*.jpg user#ip:/var/path/to/remote'" --hold
Are you sure you need the -r? Directories are usually not named .jpg.
I'm trying to make this bash script but get this: Error reading *.docx. The file doesn’t exist
Here's the script:
#!/bin/bash
textutil -convert txt *.docx
cat *.txt | wc -w
I'm currently running it from the folder but I'd like to make it a global script I can just call from any current folder.
If you want to make it available on your whole system you need to move it to a bin location like so
chmod a+rx yourscript.sh && sudo mv yourscript.sh /usr/local/bin/yourscript
then you can use it like a normal script in any folder
I have a file named syscheck.sh in /system/0211/ and I want to rename it to checkone.sh.
How can I do it?
To do a rename in a bash script, you simply need to use the mv (move) command.
mv /system/0211/syscheck.sh /system/0211/checkone.sh
You can put this command inside a shell script myrenamescript.sh file like so:
#!/bin/bash
mv /system/0211/syscheck.sh /system/0211/checkone.sh
Now set the script as executable
chmod a+x myrenamescript.sh
Now you can run it:
./myrenamescript.sh
This question already has answers here:
Why can't I change directories using "cd" in a script?
(33 answers)
Closed 7 years ago.
What I'm trying to do
I've created a shell script that I've added to my $PATH that will download and get everything setup for a new Laravel project. I would like the script to end by changing my terminal directory into the new project folder.
From what I understand right now currently it's only changing the directory of the sub shell where the script is actually running. I can't seem to figure out how to do this. Any help is appreciated. Thank you!
#! /usr/bin/env bash
echo -e '\033[1;30m=========================================='
## check for a directory
if test -z "$1"; then
echo -e ' \033[0;31m✖ Please provide a directory name'
exit
fi
## check if directory already exist
if [ ! -d $1 ]; then
mkdir $1
else
echo -e ' \033[0;31m✖ The '"$1"' directory already exists'
exit
fi
# move to directory
cd $1
## Download Laravel
echo -e ' \033[0;32m+ \033[0mDownloading Laravel...'
curl -s -L https://github.com/laravel/laravel/zipball/master > laravel.zip
## Unzip, move, and clean up Laravel
echo -e ' \033[0;32m+ \033[0mUnzipping and cleaning up files...'
unzip -q laravel.zip
rm laravel.zip
cd *-laravel-*
mv * ..
cd ..
rm -R *-laravel-*
## Make the /storage directory writable
echo -e ' \033[0;32m+ \033[0mMaking /storage directory writable...'
chmod -R o+w storage
## Download and install the Generators
echo -e ' \033[0;32m+ \033[0mInstalling Generators...'
curl -s -L https://raw.github.com/JeffreyWay/Laravel-Generator/master/generate.php > application/tasks/generate.php
## Update the application key
echo -e ' \033[0;32m+ \033[0mUpdating Application Key...'
MD5=`date +”%N” | md5`
sed -ie 's/YourSecretKeyGoesHere!/'"$MD5"'/' application/config/application.php
rm application/config/application.phpe
## Create .gitignore and initial git if -git is passed
if [ "$2" == "-git" ]; then
echo -e ' \033[0;32m+ \033[0mInitiating git...'
touch .gitignore
curl -s -L https://raw.github.com/gist/4223565/be9f8e85f74a92c95e615ad1649c8d773e908036/.gitignore > .gitignore
# Create a local git repo
git init --quiet
git add * .gitignore
git commit -m 'Initial commit.' --quiet
fi
echo -e '\033[1;30m=========================================='
echo -e ' \033[0;32m✔ Laravel Setup Complete\033[0m'
## Change parent shell directory to new directory
## Currently it's only changing in the sub shell
filepath=`pwd`
cd "$filepath"
You can technically source your script to run it in your parent shell instead of spawning a subshell to run it. This way whatever changes you make to your current shell (including changing directories) persist.
source /path/to/my/script/script
or
. /path/to/my/script/script
But sourcing has its own dangers, use carefully.
(Peripherally related: how to use scripts to change directories)
Use a shell function to front-end your script
setup () {
# first, call your big script.
# (It could be open-coded here but that might be a bit ugly.)
# then finally...
cd someplace
}
Put the shell function in a shell startup file.
Child processes (including shells) cannot change current directory of parent process. Typical solution is using eval in the parent shell. In shell script echo commands you want to run by parent shell:
echo "cd $filepath"
In parent shell, you can kick the shell script with eval:
eval `sh foo.sh`
Note that all standard output will be executed as shell commands. Messages should output to standard error:
echo "Some messages" >&2
command ... >&2
This can't be done. Use exec to open a new shell in the appropriate directory, replacing the script interpreter.
exec bash
I suppose one possibility would be to make sure that the only output of your script is the path name you want to end up in, and then do:
cd `/path/to/my/script`
There's no way your script can directly affect the environment (including it's current directory) of its parent shell, but this would request that the parent shell itself change directories based on the output of the script...