This question is for CakePHP 4.3:
In my action, I am accessing the session. For a normal GET request, everything works fine. If I call the same action through an AJAX request, I do not have access to the session. Why is that?
For example, even this does not work:
public function select3() {
debug($this->request->getSession()->read());
}
For a GET request, the session is printed. For an AJAX call, an empty array is printed.
Is the AppController NOT called for an AJAX request?
Any help is appreciated!
First, thanks to "ndm" for your offered help.
I solved it after seeing that something was mixed up with the URLS.
The URL has "server-4.2" in it, and "server" is a link to it.
Both "server-4.2" and "server" seemed to have confused the Authentication controller.
Glad it works now.
Related
I don't know why I get this
I tested the route with
Route::delete("/attachments/{url}","TrixAttachmentController#destroyAttachment");
localhost:3000/api/v1/attachments?url=hDXtilCleTWc6WyiMeWpp9O0xIx3cRyJuEwVPxzL.jpeg
public function destroyAttachment($url){
dd($url);
}
still i get it
localhost:3000/api/v1/attachments?url=hDXtilCleTWc6WyiMeWpp9O0xIx3cRyJuEwVPxzL.jpeg
here ?url it shows it now using get request
call this route via delete method
can you show form
When using the Route::delete, the request is expecting a POST request with a method of DELETE.
If you are hitting the route in the browser using a GET request, this is the sort of error that will be thrown.
If you are calling the route in a browser you need to change that.
Make sure you are calling it on a form using DELETE verb.
Important: this comes from ajax call.
Everything works perfectly except:
use Illuminate\Routing\Redirector;
public function my_call() {
return redirect()->route('page-1');
}
Throws 500 error.
return view('page-1') works without problems.
Maybe anybody sees what I am doing wrong?
Thank you.
Do you have an actual route with the name that you are using, you cannot redirect to a view as these are returned by routes
Apperantly you cannot do this on server side if you do AJAX call:/
Here an explanation: https://laracasts.com/discuss/channels/vue/redirect-after-ajax-post-request
It's for vue but I believe it applies universally for ajax.
This is my first Laravel project I'm on, and it has been a ton of fun so far.
I'm setting up an OAuth2 server. I have copied the code posted here in to my routes file.
Via this block of code...
Route::post('oauth/access_token', function()
{
return AuthorizationServer::performAccessTokenFlow();
});
I have tried doing http://local.server.com/oauth/access_token and a "MethodNotAllowedHttpException" error.
If there is any other information I could provide that would help you help me, please tell me!
Cheers
If you are typing http://local.server.com/oauth/access_token into the browser URL bar, then you are sending the request:
GET oauth/access_token
However, your route handles a POST request, and since there is no GET route defined, Laravel is responding with MethodNotAllowedHttpException
In order to properly test your route, you will need to send a POST request.
I am trying to redirect to a new page using CakePHP redirect method but for some reason the redirect is not working. The code I am using to redirect is
public function update_sticky_postition_in_db()
{
$this->autoRender = false;
... // Save info to database
$this->redirect(array('action' => 'tool'));
}
Where tool is the name of the view I am tring to redirect to. To try and speed the process of finding the problem I have checked few things and think I have found the cause of the problem. Basically I am trying to redirect to the view that is currently active which I think is part of the reason why it is not redirecting. I have read that it might have something to do with caching of the page but I am not sure how to solve that issue.
Also when using firebug I can see the redirect is sending a GET request but after that nothing is happening. Do I have to do something with the GET request or should Cake handle that for me. Also I have checked the URL of the GET and it is correct.
It is located within the controller with the correct name as I can view the original tool page.
Also the update_sticky_postition_in_db() method does not have a view (hence why the auto render is set to false), its intended purpose is to update a row in the database from an ajax call.
From your post it seems you're firing the update_sticky_postition_in_db() using ajax call, so that the redirection will not work.
You can do redirection using JavaScript within ajax success method.
In order to do that, you may send some json_encode() message from you above method and checking that status within ajax success method you can do a redirect using window.location.
I want to take use of the ajax login feature of the spring security plugin.
I am completely stuck getting a JSON success response from the loginController into my GWT client.
As I understood from the documentation I need to post my params to the url /j_spring_security_check and spring security is redirecting me to the right action.
If I look into my LoginController I see nothing of the actual login logic and its a bit magic for me where all the login/db stuff is done. Further spring security always redirects to action auth instead of using AjaxAuth even if I add the header "X-Requested-With" to post. If I do my post to the url /login/ajaxAuth I am getting a 401 which is OK because its written down in the controller(even if i dont know why we need to return a 401 here). Maybe I am doing something completely wrong :-)
My basic questions are:
Where can I find the login logic?
What parameter do I have to provide?
Which URL do I have to use?
What do I have to do if I dont want to use the username but instead and email field?
Thanks for all your help!
Looks like you're correctly implemented it, maybe there some small bug, like a typo.
Btw:
It's implemented at filter, that process your request before actual controllers. At your case it will be UsernamePasswordAuthenticationFilter (or RequestHolderAuthenticationFilter). Controller is used there only to render an additional data. As for ajax auth, it uses /login/ajaxSuccess, that renders a JSON response
By default it uses j_username & j_password. And you can use ajax=true parameter, instead of X-Request-With header
/j_spring_security_check by default
You can implement your own GrailsUserDetailsService (or extend GormUserDetailsService), and setup it as a spring bean, with name userDetailsService, at resources.xml
You can also turn on logging for Spring Security by:
log4j {
debug 'org.codehaus.groovy.grails.plugins.springsecurity',
'org.springframework.security'
}
maybe it will be helpful
I am using Grails 2.1.1 and ran into this same issue. Tried all the above things but still couldnt get my AJAX login to call the ajaxSuccess method.
However when it failed it was calling authFail?ajax=true.
After digging in more, here is what I did:
Added grails.plugins.springsecurity.successHandler.targetUrlParameter = 'ajaxUrl' in my Config.groovy
Added <input type="hidden" name="ajaxUrl" value="/login/ajaxSuccess" /> in my AJAX login form
Not sure why it fixed, but it seemed to work for me.
Just posting this solution for users who get stuck and come to this ticket for solution.