FlxSpriteGroup is not visible (haxeflixel) - macos

I'm trying to create some sort of "item displayer" in a game to showcase items or act as an icon in the inventory (it will include informations like item tier, item name, exc).
To achieve this, i wanted to create a ItemDisplay class extending FlxSpriteGroup, and put inside it the frame, background and info for the item as Sprites, so that i would be able to work with all as if they were a single Sprite.
So i did just that, but the group isn't showing up when the ItemDisplay object is created and supposedly added to the FlxState.
After some troubleshooting, i discovered that the object exists, but isOnScreen() returns false, and i don't know why.
Here's the code i'm using to create the ItemDisplay object:
var itd:ItemDisplay = new ItemDisplay(FlxG.width / 2, FlxG.height / 2, test_sword);
add(itd);
...and here's the ItemDisplay class in all it's glory:
class ItemDisplay extends FlxSpriteGroup
{
override public function new(posX:Float, posY:Float, itemToShow:Item)
{
super();
x = posX;
y = posY;
// create sprites
var bckgr:FlxSprite = new FlxSprite(x, y);
var itPng:FlxSprite = new FlxSprite(x, y);
var itFrm:FlxSprite = new FlxSprite(x, y);
// load sprites graphics (problem's not here, i checked)
bckgr.loadGraphic("assets/images/ui/item_framing/ifbg_" + itemToShow.tier + "Tier.png");
itPng.loadGraphic(itemToShow.pngPath);
itFrm.loadGraphic("assets/images/ui/item_framing/item_frame.png");
// add all sprites to group
this.add(bckgr);
this.add(itPng);
this.add(itFrm);
}
}
(i'm running the code on macos, not HTML5)
If you have any idea why the ItemDisplay is not showing up, please explain it to me, as i'm not that good of a programmer, and i might have missed something.
Thank you ^-^

Nvm, as i thought, it was my stupid error: when creating the sprites in lines 10-12, i set their positions to X and Y, to make them the same as the group positions.
I just found out that the sprites consider the group's x and y as (0, 0), and start calculating their position from there.
So, by setting the sprites' x/y the same as the group's, i was essentially doubling the values, and putting the sprites outside of the screen
lmao sorry for bad english

Related

i can't use (point_distance) to kill any enemy nearset my hero GMK

I have a problem with a code in the Game Maker program
I make a little game that has a path that the enemies walk on and put heroes on his side and when the enemy approaches him he turns to him and he shoots him
I am using this code
var ex, ey;
ex = instance_nearest(x, y, enemy).x;
ey = instance_nearest(x, y, enemy).y;
if point_distance(x, y, ex, ey) < 150
{
image_angle = point_direction(x, y, enemy.x, enemy.y);
}
The code works well, but the problem is that my heroes only go to the first enemy when they come close to them and do not go to the rest even when the first enemy is out of range
What is the solution, please
Photo for illustration
Heroes ignore the nearby enemy and only head for the first enemy to appear in the game
You are checking the correct enemy but not pointing at the correct enemy. Store the found instance ID instead, and use it for all:
var e;
e = instance_nearest(x, y, enemy);
if (e != noone) { // wouldn't want to crash when you run out of enemies
if (point_distance(x, y, e.x, e.y) < 150) {
image_angle = point_direction(x, y, e.x, e.y);
}
}
I think the answer gave by YellowAfterlife solved the problem. But not sure if the reason of the problem was clear, then I want to complement by explain that the problem happened because the code in "point_direction" is referencing the object instead of the instance.
The object is the template that the created instance is based of, if you want to manipulate or get information you should reference the instance. If you only have one instance of that object, it will work referencing the object directly, but after more were created, it will return the index of only one of them (maybe the first created).
About instances: every object that you drag to the room will became an instance of that object or when you create an instance from the code, like calling "instance_create_layer(x, y, "instance_layer", obj_Bullet)", this function will return the reference/index of the new instance created.
When the function "instance_nearest" is called it receives the player instance position (x and y) and the object of the instances that you want to check if it's near to the player, for example, the enemy object. The function will check all instances that was created from the informed object and will returns the index/reference of the instance nearest to the player. In the original code when calling the point_direction, was used the object enemy instead of the instance returned by instance_nearest function.
The object will always return the same index of some instance, causing the problem reported, that the player instance always point to the same enemy instance (coincidentally, the first instance created)
You can use the object if want to manipulate all instances at once, like this: "with(o_player) y++;". This code will make all instances of that object move down together.
You could use something like collision_circle_list(...).
This function will get you a list of all objects that collide within that circle and you can iterate through them to find which is closest, furthest, etc.
Resource:
https://docs2.yoyogames.com/source/_build/3_scripting/4_gml_reference/movement%20and%20collisions/collisions/collision_circle_list.html

ScalaFx children hierarchy and casting / instance reference

I'm wandering if this is the optimal way of doing it with ScalaFx: A GUI is composed of bunch of nodes, to which I suck content from a SQL-DB. Main Pane is a FlowPane populated with few hundred elements. Each element is composed of four level hierarchy (see numbers describing the levels):
1 2 3 4
VBox -+-> VBox ---> StackPane -+-> ImageView
+-> Label +-> Rectangle
As far as I have experienced the I can access the nodes and their attributes in different levels. Ie. I can give user feedback by changing the Rectangle color below the ImageView Node as the compound element is chosen by mouse click or by ContextMenu.
I could access the Rectangle attributes directly, but it is easy to make mistakes as the list references children.get(0) are directly dependent from order of the children as the nodes are positioned in parent.
val lvone = vbnode.children // VBox (main)
val lvtwo = lvone.get(0) // VBox
val lvthree = lvtwo.asInstanceOf[javafx.scene.layout.VBox].children.get(0) // StackPane
val lvfour = lvthree.asInstanceOf[javafx.scene.layout.StackPane].children.get(0) // Rectangle
if (lvfour.isInstanceOf[javafx.scene.shape.Rectangle]) lvfour.asInstanceOf[javafx.scene.shape.Rectangle].style = "-fx-fill: #a001fc;"
println("FOUR IS:"+lvfour.getClass)
Here's sample to demonstrate the "safer" access to the elements in node hierarchy (node hierarchy creation is in rather annoying structure of code, so it is not included):
val levelone = vbnode.children
println("LV1 Node userData:"+vbnode.userData) // my database reference for the main / container element
println("LV1 Parent children class:"+levelone.get(0).getClass) // class javafx.scene.layout.VBox
for (leveltwo <- levelone) {
println("LV2 Children Class:"+leveltwo.getClass)
println("LV2 Children Class Simple Name:"+leveltwo.getClass.getSimpleName) // VBox
if (leveltwo.getClass.getSimpleName == "VBox") {
leveltwo.style = "-fx-border-width: 4px;" +
"-fx-border-color: blue yellow blue yellow;"
for (levelthree <- leveltwo.asInstanceOf[javafx.scene.layout.VBox].children) {
println("LV3 children:"+levelthree.getClass.getName)
if (levelthree.getClass.getSimpleName == "StackPane") {
for (levelfour <- levelthree.asInstanceOf[javafx.scene.layout.StackPane].children) {
println("LV4 children:"+levelfour.getClass.getName)
if (levelfour.getClass.getSimpleName == "Rectangle") {
if (levelfour.isInstanceOf[javafx.scene.shape.Rectangle]) println("Rectangle instance confirmed")
println("LV4 Found a Rectangle")
println("original -fx-fill / CSS:"+ levelfour.asInstanceOf[javafx.scene.shape.Rectangle].style)
levelfour.asInstanceOf[javafx.scene.shape.Rectangle].style = "-fx-fill: #a001fc;"
} // end if
} // end for levelfour
} // end if
} // end for levelthree
} // end if
} // end for leveltwo
Questions:
Is there smarter way to do the type casting of node types, since only javafx API based references are acceptable (BTW I'm using ScalaIDE)? Options I am using are:
1- simple / shortcut way: evaluation by using leveltwo.getClass.getSimpleName == "VBox" , which is the shortcut from API jungle. But is it efficient and safe?
2- cluttering way by using probably the by the book style:
if (levelfour.isInstanceOf[javafx.scene.shape.Rectangle])
Other question: Now in reference to the fully qualified reference based on javafx ie. javafx.scene.shape.Rectangle, I would like to use scala reference instead, but I get an error which enforces me to adopt the javafx based reference. Not a big deal as I can use javafx reference, but I wander if there is scalafx based option?
Happy to get constructive feedback.
If I understand you correctly, you seem to be wanting to navigate the nodes of a sub-scene (that belongs to a higher-level UI element construct) in order to change the appearance of some of the nodes within it. Do I have that right?
You raise a number of different issues, all within the one question, so I'll do my best to address them all. As a result, this is going to be a long answer, so please bear with me. BTW, In future, it would help if you ask one question for each issue. ;-)
Firstly, I'm going to take your problem at face value: that you need to browse through a scene in order to identify a Rectangle instance and change its style. (I note that your safe version also changes the style of the second VBox, but I'm going to ignore that for the sake of simplicity.) This is a reasonable course of action if you have little to no control over the structure of each element's UI. (If you directly control this structure, there are far better mechanisms, which I'll come to later.)
At this point, it might be worth expanding on the relationship between ScalaFX and JavaFX. The former is little more than a set of wrappers for the latter, to give the library a Scala flavor. In general, it works like this: the ScalaFX version of a UI class takes a corresponding JavaFX class instance as an argument; it then applies Scala-like operations to it. To simplify things, there are implicit conversions between the ScalaFX and JavaFX instances, so that it (mostly) appears to work by magic. However, to enable this latter feature, you must add the following import to each of your source files that reference ScalaFX:
import sclafx.Includes._
For example, if JavaFX has a javafx.Thing (it doesn't), with setSize and getSize accessor methods, then the ScalaFX version would look like this:
package scalafx
import javafx.{Thing => JThing} // Rename to avoid confusion with ScalaFX Thing.
// ScalaFX wrapper for a Thing.
class Thing(val delegate: JThing) {
// Axilliary default constructor. Let's assume a JThing also has a default
// constructor.
//
// Creates a JavaFX Thing when we don't have one available.
def this() = this(new JThing)
// Scala-style size getter method.
def size: Int = delegate.getSize
// Scala-style size setter method. Allows, say, "size = 5" in your code.
def size_=(newSize: Int): Unit = delegate.setSize(newSize)
// Etc.
}
// Companion with implicit conversions. (The real implementation is slightly
// different.)
object Thing {
// Convert a JavaFX Thing instance to a ScalaFX Thing instance.
implicit def jfxThing2sfx(jThing: JThing): Thing = new Thing(jThing)
// Convert a ScalaFX Thing instance to a JavaFX Thing instance.
implicit def sfxThing2jfx(thing: Thing): JThing = thing.delegate
}
So, quite a lot of work for very little gain, in all honesty (although ScalaFX does simplify property binding and application initialization). Still, I hope you can follow me here. However, this allows you to write code like the following:
import javafx.scene.shape.{Rectangle => JRectangle} // Avoid ambiguity
import scalafx.Includes._
import scalafx.scene.shape.Rectangle
// ...
val jfxRect: JRectangle = new JRectangle()
val sfxRect: Rectangle = jfxRect // Implicit conversion to ScalaFX rect.
val jfxRect2: JRectangle = sfxRect // Implicit conversion to JavaFX rect.
// ...
Next, we come to type checking and casting. In Scala, it's more idiomatic to use pattern matching instead of isInstanceOf[A] and asInstanceOf[A] (both of which are frowned upon).
For example, say you have a Node and you want to see if it is actually a Rectangle (since the latter is a sub-class of the former). In the style of your example, you might write something like the following:
def changeStyleIfRectangle(n: Node): Unit = {
if(n.isInstanceOf[Rectangle]) {
val r = n.asInstanceOf[Rectangle]
r.style = "-fx-fill: #a001fc;"
}
else println("DEBUG: It wasn't a rectangle.")
}
The more idiomatic Scala version of the same code would look like this:
def changeStyleIfRectangle(n: Node): Unit = n match {
case r: Rectangle => r.style = "-fx-fill: #a001fc;"
case _ => println("DEBUG: It wasn't a rectangle.")
}
This may seem a little finicky, but it tends to result in simpler, cleaner code, as I hope you'll see. In particular, note that case r: Rectangle only matches if that is the real type of n, and it then casts n to r as a Rectangle.
BTW, I would expect that comparing types is more efficient than getting the name of the class, via getClass.getSimpleName and comparing to a string, and there's less chance of error. (For example, if you mistype the class name of the string you're comparing to, e.g. "Vbox", instead of "VBox", then this will not result in a compiler error, and the match will always fail.)
As you point out, your direct approach to identifying the Rectangle is limited by the fact that it requires a very specific scene structure. If you change how each element is represented, then you must change your code accordingly, or you'll get a bunch of exceptions.
So let's move on to your safe approach. Clearly, it's going to be a lot slower and less efficient than the direct approach, but it still relies upon the structure of the scene, even if it's less sensitive to the order in which the children are added at each level of hierarchy. If we change the hierarchy, it will likely stop working.
Here's an alternative approach that uses the class hierarchy of the library to assist us. In a JavaFX scene, everything is a Node. Furthermore, nodes that have children (such as VBox and StackPane) are subclasses of Pane as well. We'll use a recursive function to browse the elements below a specified starting Node instance: every Rectangle it encounters will have its style changed.
(BTW, in this particular case, there are some issues with implicit conversions, which makes a pure ScalaFX solution a little cumbersome, so I'm going to match directly on the JavaFX versions of the classes instead, renamed to avoid any ambiguity with the equivalent ScalaFX types. The implicit conversions will work fine when calling this function.)
import javafx.scene.{Node => JNode}
import javafx.scene.layout.{Pane => JPane}
import javafx.scene.shape.{Rectangle => JRectangle}
import scala.collection.JavaConverters._
import scalafx.Includes._
// ...
// Change the style of any rectangles at or below starting node.
def setRectStyle(node: JNode): Unit = node match {
// If this node is a Rectangle, then change its style.
case r: JRectangle => r.style = "-fx-fill: #a001fc;"
// If the node is a sub-class of Pane (such as a VBox or a StackPane), then it
// will have children, so apply the function recursively to each child node.
//
// The observable list of children is first converted to a Scala list to simplify
// matters. This requires the JavaConverters import above.
case p: JPane => p.children.asScala.foreach(setRectStyle)
// Otherwise, just ignore this particular node.
case _ =>
}
// ...
A quick few observations on this function:
You can now use any hierarchy of UI nodes that you like, however, if you have more than one Rectangle node, it will change the style of all of them. If this doesn't work for you, you could add code to check other attributes of each Rectangle to determine which one to modify.
The asScala method is used to convert the children of the Pane node to a Scala sequence, so we can then use the foreach higher-order function to recursively pass each child in turn to the setRectStyle method. asScala is made available by the import scala.collection.JavaConverters._ statement.
Because the function is recursive, but the recursive call is not in the tail position (the last statement of the function), it is not tail-recursive. What this means is if you pass a huge scene to the function, you might get a StackOverflowException. You should be fine with any reasonable size of scene. (However, as an exercise, you might want to write a tail-recursive version so that the function is stack safe.)
This code is going to get slower and less efficient the bigger the scene becomes. Possibly not your top concern in UI code, but a bad smell all the same.
So, as we've seen, having to browse through a scene is challenging, inefficient and potentially error prone. Is there a better way? You bet!
The following will only work if you have control over the definition of the scene for your data elements. If you don't, you're stuck with solutions based upon the above.
The simplest solution is to retain a reference to the Rectangle whose style you want to change as part of a class, then access it directly as needed. For example:
import scalafx.Includes._
import scalafx.scene.control.Label
import scalafx.scene.layout.{StackPane, VBox}
import scalafx.scene.shape.Rectangle
final class Element {
// Key rectangle whose style is updated when the element is selected.
private val rect = new Rectangle {
width = 600
height = 400
}
// Scene representing an element.
val scene = new VBox {
children = List(
new VBox {
children = List(
new StackPane {
children = List(
// Ignore ImageView for now: not too important.
rect // Note: This is the rectangle defined above.
)
}
)
},
new Label {
text = "Some label"
}
)
}
// Call when element selected.
def setRectSelected(): Unit = rect.style = "-fx-fill: #a001fc;"
// Call when element deselected (which I assume you'll require).
def setRectDeselected(): Unit = rect.style = "-fx-fill: #000000;"
}
Clearly, you could pass a data reference as an argument to the class and use that to populate the scene as you like. Whenever you need to change the style, calling one of the two latter functions achieves what you need with surgical precision, no matter what the scene structure looks like.
But there's more!
One of the truly great features about ScalaFX/JavaFX is that it has observable properties that can be used to make the scene manage itself. You will find that most fields on a UI node are of some type "Property". What this allows you to do is to bind a property to the field, such that when you change the property, you change the scene accordingly. When combined with event handlers, the scene takes care of everything all by itself.
Here, I've reworked the latter class. Now, it has a handler that detects when the scene is selected and deselected and reacts by changing the property that defines the style of the Rectangle.
import scalafx.Includes._
import scalafx.beans.property.StringProperty
import scalafx.scene.control.Label
import scalafx.scene.input.MouseButton
import scalafx.scene.layout.{StackPane, VBox}
import scalafx.scene.shape.Rectangle
final class Element {
// Create a StringProperty that holds the current style for the Rectangle.
// Here we initialize it to be unselected.
private val unselected = "-fx-fill: #000000;"
private val selected = "-fx-fill: #a001fc;"
private val styleProp = new StringProperty(unselected)
// A flag indicating whether this element is selected or not.
// (I'm using a var, but this is heavily frowned upon. A better mechanism might be
// required in practice.)
private var isSelected = false
// Scene representing an element.
val scene = new VBox {
children = List(
new VBox {
children = List(
new StackPane {
children = List(
// Ignore ImageView for now: not too important.
// Key rectangle whose style is bound to the above property.
new Rectangle {
width = 600
height = 400
style <== styleProp // <== means "bind to"
}
)
}
)
},
new Label {
text = "Some label"
}
)
// Add an event handler. Whenever the VBox (or any of its children) are
// selected/unselected, we just change the style property accordingly.
//
// "mev" is a "mouse event".
onMouseClicked = {mev =>
// If this is the primary button, then change the selection status.
if(mev.button == MouseButton.Primary) {
isSelected = !isSelected // Toggle selection setting
styleProp.value = if(isSelected) selected
else unselected
}
}
}
}
Let me know how you get on...

Storyboard-Animating a Grid from CodeBehind

I need a MenuBar on the left side of my screen that can slide in and out. As this app is crossplattform it should be on the left side and not like the usual ApplicationBar on the Bottom or NavigationBar on Top.
What I have so far is:
private bool isTapped = false;
private void TEST_TAP(object sender, TappedRoutedEventArgs e)
{
System.Diagnostics.Debug.WriteLine("TAP");
Storyboard s = new Storyboard();
DoubleAnimation doubleAni = new DoubleAnimation();
doubleAni.To = -30;
if (isTapped) doubleAni.To = 0;
doubleAni.Duration = new Duration(TimeSpan.FromMilliseconds(500));
Storyboard.SetTarget(doubleAni, LOGO);
Storyboard.SetTargetProperty(doubleAni, "(UIElement.RenderTransform).(TranslateTransform.XProperty)");
s.Children.Add(doubleAni);
s.Begin();
}
The bar I want to move is a Grid or should be something similar. But this even fails to move a single Image. I googled a bit and replaced "(UIElement.RenderTransform).(TranslateTransform.XProperty)" with "(Canvas.Left)". This doesn't crash but also doesn't move anything else.
Any ideas or solutions?
EDIT:
Well I played around a lot and now I know (and tested it) that "(Canvas.Left)" only works inside of a Canvas. Yay.
My App looks like this: Scrollview (horizontal) and inside is a Grid with columns to display different stuff. The left-most Column contains another Grid that I want to move out of the screen and back in again. But how do I move a grid with Storyboard-animation?
If anybody thinks of a different way to do this, I'm totally happy if it works in any way.
EDIT2:
It seems to be THE way to use Storyboard.SetTargetProperty(doubleAni, "(UIElement.RenderTransform).(CompositeTransform.TranslateX)"); but it keeps crashing =/
Before using this transform you need to add it:
Storyboard s = new Storyboard();
DoubleAnimation doubleAni = new DoubleAnimation();
doubleAni.To = to;
doubleAni.From = from;
doubleAni.Duration = new Duration(TimeSpan.FromMilliseconds(250));
// THIS LINE IS NEW
NaviBar.RenderTransform = new CompositeTransform();
Storyboard.SetTarget(doubleAni, NaviBar);
Storyboard.SetTargetProperty(doubleAni, "(UIElement.RenderTransform).(CompositeTransform.TranslateX)");
s.Children.Add(doubleAni);
s.Begin();
This does the trick. It's still not the functionality that I wanted but the hardest part - the animation - works now.

Flixel Game Over Screen

I am new to game development but familiar with programming languages. I have started using Flixel and have a working Breakout game with score and lives.
I am just stuck on how I can create a new screen/game over screen if a player runs out of lives. I would like the process to be like following:
Check IF lives are equal to 0
Pause the game and display a new screen (probably transparent) that says 'Game Over'
When a user clicks or hits ENTER restart the level
Here is the function I currently have to update the lives:
private function loseLive(_ball:FlxObject, _bottomWall:FlxObject):void
{
// check for game over
if (lives_count == 0)
{
}
else
{
FlxG:lives_count -= 1;
lives.text = 'Lives: ' + lives_count.toString()
}
}
Here is my main game.as:
package
{
import org.flixel.*;
public class Game extends FlxGame
{
private const resolution:FlxPoint = new FlxPoint(640, 480);
private const zoom:uint = 2;
private const fps:uint = 60;
public function Game()
{
super(resolution.x / zoom, resolution.y / zoom, PlayState, zoom);
FlxG.flashFramerate = fps;
}
}
}
There are multiple ways to go about doing this...
You could use different FlxStates, like I described in the answer to your other post: Creating user UI using Flixel, although you'll have to get smart with passing the score or whatever around, or use a Registry-type setup
If you want it to actually work like you described above, with a transparent-overlay screen, you can try something like this (keep in mind, the exact details may differ for your project, I'm just trying to give you an idea):
First, make sure you have good logic for starting a level, lets say it's a function called StartLevel.
You'll want to define a flag - just a Boolean - that tracks whether or not the game is still going on or not: private var _isGameOver:Boolean; At the very end of StartLevel(), set this to false.
In your create() function for your PlayState, build a new FlxGroup which has all the things you want on your Game Over screen - some text, an image, and something that says "Press ENTER to Restart" (or whatever). Then set it to visible = false. The code for that might look something like:
grpGameOver = new FlxGroup();
grpGameOver.add(new FlxSprite(10,10).makeGraphic(FlxG.Width-20,FlxG.Height-20,0x66000000)); // just a semi-transparent black box to cover your game screen.
grpGameOver.add(new FlxText(...)); // whatever you want to add to the group...
grpGameOver.visible = false;
add(grpGameOver); // add the group to your State.
Depending on how your game is setup, you may also want to set the objects in your group's scrollFactor to 0 - if your game screen scrolls at all:
grpGameOver.setAll("scrollFactor", new FlxPoint(0,0));
In your update() function, you'll need to split it into 2 parts: one for when the game is over, and one for if the game is still going on:
if (_isGameOver)
{
if (FlxG.keys.justReleased("ENTER"))
{
grpGameOver.visible = false;
StartLevel();
}
}
else
{
... the rest of your game logic that you already have ...
}
super.update();
Keep in mind, if you have things that respond to user input anywhere else - like a player object or something, you might need to change their update() functions to check for that flag as well.
Then, the last thing you need to do is in your loseLive() logic:
if (lives_count == 0)
{
_isGameOver = true;
grpGameOver.visible = true;
}
else
...
That should do it!
I would highly recommend spending some time with different tutorials and sample projects to kind of get a better feel for Flixel in general. Photon Storm has some great material to play with (even though he's jumped over to HTML5 games)
I also want to note that if you get comfortable with the way Flixel handles updates, you can get really smart with your state's update() function and have it only call update on the grpGameOver objects, instead of having to change all your other objects updates individually. Pretty advanced stuff, but can be worth it to learn it.

problem in displaying BitmapFields in HorizontalFieldManager in a row in Blackberry Storm

I had created a HorizontalFieldManager & added BitmapFields in that.
In Blackberry Storm, Display.getWidth() is 480. In that I want to use first 450 to add some BitmapFields at LHS of screen which I m creating at runtime & add 2 BitmapFields at start at RHS of Screen.
2 BimapFields which I want to show at start r added in Constructor & other BitmapFields which I m creating at run time r added afterwords like..
class MyCanvas extends MainScreen
{
MyCanvas()
{
hfm_BitmapField = new HorizontalFieldManager(){
protected void sublayout(int maxWidth, int maxHeight) {
super.sublayout(maxWidth, maxHeight);
setExtent(Display.getWidth()-30, 60);
}
};
startBitmap = Bitmap.getBitmapResource("start.png");
startBitmapField = new BitmapField(startBitmap, BitmapField.ACTION_INVOKE | BitmapField.FIELD_HCENTER | BitmapField.FIELD_RIGHT);
hfm_BitmapField.add(startBitmapField);
endBitmap = Bitmap.getBitmapResource("end.png");
endBitmapField = new BitmapField(endBitmap, BitmapField.ACTION_INVOKE | BitmapField.FIELD_HCENTER | BitmapField.FIELD_RIGHT);
hfm_BitmapField.add(endBitmapField);
drawBitmap();
}
public void drawBitmap()
{
bitmap[i] = new Bitmap(50, 50);
Graphics g = new Graphics(bitmap[i]);
g.drawLine(5,5,25,25);
bitmapField[i] = new BitmapField(bitmap[i]);
synchronized(UiApplication.getEventLock()) { hfm.add(bitmapField[i]); }
}
I want startBitmapField & endBitmapField at RHS & bitmapField[i] which I m creating at runtime at LHS of HorizontalFieldManagers.
I m thinking to add 2 HorizontalFieldManagers. 1 for bitmapField[i] & 1 for startBitmapField & endBitmapField. But how to add 2 HorizontalFieldManagers or any other FieldManagers in a row?
Any solution? How to do it?
You can put the 2 horizontal field managers inside another HorizontalFieldManager.
Rather than use the alignment flags try adding to your sublayout method.
For each child of your Manager (hfm) you need to call setPositionChild. So if you want it right aligned and vertically centred you would do something like:
setPositionChild(deleteButton, hfm.getPreferredWidth() - deleteButton.getPreferredWidth(), (hfm.getPreferredHeight() / 2) - (deleteButton.getPreferredHeight() / 2));
This would set the top left hand corner of the delete button to be at the correct position such that it is right aligned and vertically centred within the hfm.
There is going to be a problem if you see the application in touch. You must have each of your customized field in a separate field manager to avoid using touch event. If you use layoutChild instead of super.sublayout(width,height), this will disable the navigation in the screen, so avoid using it. Use navigationMovement to customize your navigation of your fields. More: If you do not use super.sublayout function, it might not layout some of your fields, hence it is recommended that you use it.
More: use Storm emulator for all your touch based application, and 4.5 Pearl emulator JDEs for all the other releases, for the compatibility issues.

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