hasManyThrough query without laravel_through_key - laravel

Question

With a Laravel hasManyThrough relationship how can I prevent extra keys added to the select? Is there a withoutPivot or simiar?
I'm trying to perform a union join and need to the columns to be the same.
SQLSTATE[21000]: Cardinality violation: 1222 The used SELECT statements have a different number of columns
SELECT
count(*) AS aggregate
FROM ((
SELECT
`order_payments`.`id`,
`order_payments`.*,
`orders`.`user_id` AS `laravel_through_key`
FROM
`order_payments`
INNER JOIN `orders` ON `orders`.`id` = `order_payments`.`order_id`
WHERE
`orders`.`user_id` = 1)
UNION (
SELECT
`orders`.`id`
FROM
`orders`
WHERE
`orders`.`user_id` = 1
AND `orders`.`user_id` IS NOT NULL)) AS `temp_table`
I'm unable to use the makeHidden as suggested in another question
$payments = auth()->user()->orderPayments()->select('order_payments.id');
$orders = auth()->user()->orders()->select('orders.id');
$payments->union($orders)->paginate(50);
I guess I could do it without Eloquent manually but just wondering if there was another way?
class User extends Authenticatable implements UserContract {
/**
* Orders for this User
*/
public function orders()
{
return $this->hasMany(Order::class);
}
/**
* Order Payments for this User
*/
public function orderPayments()
{
return $this->hasManyThrough(OrderPayment::class, Order::class);
}
}