OpenAPI add server at Server Start - spring

Question

I try to modify server list (or default server) on Swagger UI.
1/ On Spring (Not Spring Boot) configuration class I add this :
#Bean
public OpenAPI customOpenAPI() {
log.info("<<<customOpenAPI>>>");
Server server = new Server();
server.setUrl("http://localhost:8091/eatery_spring_rs/rs/");
return new OpenAPI()
.servers(List.of(server));
}
2/ But I never obtain result on Swagger UI, no server is added :
3/ Maven dependencies are :
<!--SWAGGER-->
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-boot-starter</artifactId>
<version>3.0.0</version>
</dependency>
<!-- https://mvnrepository.com/artifact/org.springdoc/springdoc-openapi-ui -->
<dependency>
<groupId>org.springdoc</groupId>
<artifactId>springdoc-openapi-ui</artifactId>
<version>1.6.7</version>
</dependency>
<!-- END -->
5/ Question :
Is it possible to change context path, or add server URL, by program ?

Answer 1

6/ I can affine the description of problem
The context path of application is not complete
It is a Spring 5.3 application, start with web.xml in App Server.
like Tomcat, ...
This is the web.xml definition :
`
<servlet>
<servlet-name>springServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:servlet-service.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springServlet</servlet-name>
<url-pattern>/rs/*</url-pattern>
</servlet-mapping>`
This mean that the real context path is : [app.context]/rs but in the case of :
#Bean public Docket api(ServletContext servletContext) {
servletContext is equal to [app.context] NOT to [app.context]/rs
It's help ?