declare
i number;
sum number;
begin
i:=1;
sum:=0;
for i in 1..100 loop
if MOD(i,2) != 0 then
sum:= sum + i;
dbms_output.put_line(i);
end if;
end loop;
dbms_output.Put_line(sum);
end;
sum is a reserved word, reserved for built-in function. Rename variable to v_sum (for example).
SQL> set serveroutput on
SQL>
SQL> DECLARE
2 v_sum NUMBER;
3 BEGIN
4 v_sum := 0;
5 FOR i IN 1 .. 100 LOOP
6 IF MOD (i, 2) != 0 THEN
7 v_sum := v_sum + i;
8 -- DBMS_OUTPUT.put_line (i);
9 END IF;
10 END LOOP;
11 DBMS_OUTPUT.Put_line (v_sum);
12 END;
13 /
2500
PL/SQL procedure successfully completed.
SQL>
Related
n number := &n;
c number;
i number;
function isprime(x in number)
RETURN number
IS
begin
count number:=0;
for i in 2..x/2 loop
if mod(x,i)=0 then
count := count+1;
end if;
end loop;
return count;
end;
begin
c:=isprime(n);
if c=0 then
dbms_output.put_line(n||'is a prime number');
else
dbms_output.put_line(n||'is not prime');
end if;
end;
/
ORA-06550: line 11, column 7:
PLS-00103: Encountered the symbol "NUMBER" when expecting one of the following:
:= . ( # % ;
The symbol "." was substituted for "NUMBER" to continue.
Don't use column names that match Oracle's built-in functions (count is one of them). Declare variables in declaration section, not just anywhere.
SQL> DECLARE
2 n NUMBER := &par_n;
3 c NUMBER;
4 i NUMBER;
5
6 FUNCTION isprime (x IN NUMBER)
7 RETURN NUMBER
8 IS
9 l_count NUMBER := 0;
10 BEGIN
11 FOR i IN 2 .. x / 2
12 LOOP
13 IF MOD (x, i) = 0
14 THEN
15 l_count := l_count + 1;
16 END IF;
17 END LOOP;
18
19 RETURN l_count;
20 END;
21 BEGIN
22 c := isprime (n);
23
24 IF c = 0
25 THEN
26 DBMS_OUTPUT.put_line (n || ' is a prime number');
27 ELSE
28 DBMS_OUTPUT.put_line (n || ' is not prime');
29 END IF;
30 END;
31 /
Enter value for par_n: 6
6 is not prime
PL/SQL procedure successfully completed.
SQL> /
Enter value for par_n: 7
7 is a prime number
PL/SQL procedure successfully completed.
SQL>
I am getting output as a = 1. I have taken a for loop from 1 to 500 and while loops inside the outer for loop.
declare
n number;
s number:=0;
r number;
len number;
m number;
begin
for a in 1..500 loop
m:=a;
n:=a;
len:=length(to_char(n));
while(n>0) loop
r:=mod(n,10);
s:=s+power(r,len);
n:=trunc(n/10);
end loop;
if m=s then
dbms_output.put_line('a='||to_char(a)');
end if;
end loop;
end;
How about this?
substr splits i to 3 separate digits
nvl is here to avoid adding null value if those digits don't exist (yet)
power function calculates i's cube
display i if it is equal to r (as "result")
SQL> declare
2 r number;
3 begin
4 for i in 1 .. 500 loop
5 r := power(to_number(substr(to_char(i), 1, 1)), 3) +
6 nvl(power(to_number(substr(to_char(i), 2, 1)), 3), 0) +
7 nvl(power(to_number(substr(to_char(i), 3, 1)), 3), 0);
8
9 if r = i then
10 dbms_output.put_line(i);
11 end if;
12 end loop;
13 end;
14 /
1
153
370
371
407
PL/SQL procedure successfully completed.
SQL>
You never reset s and you do not need the final IF statement (unless you are only interested in the Armstrong numbers which equal the original number):
declare
n number;
s number:=0;
r number;
len number;
m number;
begin
for a in 1..500 loop
m:=a;
n:=a;
s:=0; -- Reset s for each loop
len:=length(to_char(n));
while(n>0) loop
r:=mod(n,10);
s:=s+power(r,len);
n:=trunc(n/10);
end loop;
dbms_output.put_line(a || '=' || s); -- Output values for every loop.
end loop;
end;
/
db<>fiddle here
I was trying to use the variable 'ind' to get the ROWNUM on my select, but everytime I try to use the variable there I get a error like:
ORA-01008: not all variables bound
or these two:
ORA-01403: no data found
ORA-06512: at line 10
DECLARE
texto VARCHAR2(255);
ind NUMBER := 0;
BEGIN
LOOP
ind := ind + 1;
IF ind > 3 THEN
EXIT;
END IF;
SELECT TEXTO_LOG
INTO texto
from table WHERE REGEXP_LIKE(TEXTO_LOG, 'Alteração') AND ROWNUM >= :ind AND ROWNUM <= :ind ;
dbms_output.put_line(substr(trim(texto), 1, instr(texto, ' ')));
dbms_output.put_line(substr(texto, 0, 100));
END LOOP;
END;
/
I searched and found someone telling that not all variables bound is a bug, I'm not sure if it's.
I tried the ROWNUM with different opperators. Any suggestions?
Usage of rownum is the problem here apart from other issues already answered. a predicate like rownum>=2 and rownum <=2 (and so on...till exit point) yield no result and thus no_data_found error
But as workaround put the rownum inside from clause and restrict it outside should work,
DECLARE
texto VARCHAR2(255);
ind NUMBER := 0;
BEGIN
LOOP
ind := ind + 1;
IF ind > 3
THEN
EXIT;
END IF;
SELECT texto_log
INTO texto
FROM (SELECT texto_log
,rownum myrownum
FROM TABLE
WHERE regexp_like(texto_log
,'Alteração'))
WHERE myrownum >= ind
AND myrownum <= ind;
dbms_output.put_line(substr(TRIM(texto)
,1
,instr(texto
,' ')));
dbms_output.put_line(substr(texto
,0
,100));
END LOOP;
END;
/
The error is that you are referring to :ind as if it were a bind variable, when it is not. It is in fact a variable declared in your DECLARE section.
You might try this
** Update **
As your query looks like it is faling, the reason perhaps is in the query itself. Run this and get the output and running separately
set serveroutput on size unlimited
DECLARE
texto VARCHAR2(255);
ind NUMBER := 0;
BEGIN
for r in 1..4
LOOP
ind := r + 1;
dbms_output.put_line ( q'[SELECT TEXTO_LOG
INTO texto
from table WHERE REGEXP_LIKE(TEXTO_LOG, 'Alteração') AND ROWNUM <= ind ;
dbms_output.put_line(substr(trim(texto), 1, instr(texto, ' ')));
dbms_output.put_line(substr(texto, 0, 100));]');
exit when ind > 3;
END LOOP;
END;
/
Although you can build it like this which is easier
DECLARE
texto VARCHAR2(255);
ind NUMBER := 0;
BEGIN
for r in 1..4
LOOP
ind := r + 1;
dbms_output.put_line(ind);
SELECT TEXTO_LOG
INTO texto
from table WHERE REGEXP_LIKE(TEXTO_LOG, 'Alteração') AND ROWNUM >= ind AND ROWNUM <= ind ;
dbms_output.put_line(substr(trim(texto), 1, instr(texto, ' ')));
dbms_output.put_line(substr(texto, 0, 100));
exit when ind > 3;
END LOOP;
END;
/
EXample
SQL> DECLARE
texto VARCHAR2(255);
ind NUMBER := 0;
BEGIN
for r in 1..4
LOOP
ind := r + 1;
dbms_output.put_line(ind);
exit when ind > 3;
END LOOP;
END;
/ 2 3 4 5 6 7 8 9 10 11 12
2
3
4
PL/SQL procedure successfully completed.
SQL>
With implicit cursor
DECLARE
-- texto VARCHAR2(255);
ind NUMBER := 0;
BEGIN
FOR i IN (SELECT TEXTO_LOG FROM table WHERE REGEXP_LIKE(TEXTO_LOG, 'Alteração'))
LOOP
ind:=ind+1;
EXIT WHEN ind >3;
DBMS_OUTPUT.PUT_LINE(SUBSTR(TRIM(i.TEXTO_LOG), 1, INSTR(i.TEXTO_LOG, ' ')));
DBMS_OUTPUT.PUT_LINE(SUBSTR(i.TEXTO_LOG, 0, 100));
END LOOP;
END;
I'm trying to run the following loop:
DECLARE
v_banknumber varchar2(9) := '123456789';
v_counter number := 9;
v_result number;
begin
for i in v_banknumber
loop
v_result := v_counter * TO_NUMBER(i) + v_result;
v_counter := v_counter - 1;
end loop;
end;
I'm getting a error at line 2:
Error report -
ORA-06550: line 6, column 10:
PLS-00456: item 'V_BANKNUMBER' is not a cursor
ORA-06550: line 6, column 1:
PL/SQL: Statement ignored
06550. 00000 - "line %s, column %s:\n%s"
*Cause: Usually a PL/SQL compilation error.
*Action:
If I read this well, it seems like it should work. Anyone here that can explain me why it's not working?
The first digit must be multiplied by 9, the second with 8, the third with 7, and so on and save the sum of it in a result variable.
At a guess, what you want to do is
DECLARE
v_banknumber varchar2(9) := '123456789';
v_counter number := 9;
v_result number := 0;
begin
for i in 1..LENGTH(v_banknumber)
loop
v_result := v_counter * TO_NUMBER(SUBSTR(v_banknumber, i, 1)) + v_result;
v_counter := v_counter - 1;
end loop;
end;
This gives a result of 165.
Best of luck.
EDIT
Or you could really use a cursor:
DECLARE
v_banknumber varchar2(9) := '123456789';
v_counter number := 9;
v_result number := 0;
begin
for aRow in (SELECT LEVEL AS I FROM DUAL CONNECT BY LEVEL <= LENGTH(v_banknumber))
loop
v_result := v_counter * TO_NUMBER(SUBSTR(v_banknumber, aRow.I, 1)) + v_result;
v_counter := v_counter - 1;
end loop;
end;
Produces 165 as the result.
EDIT #2
Or, because there's no kill like overkill, you could just do it all in SQL:
WITH cteBank_number AS (SELECT '123456789' AS BANK_NUMBER FROM DUAL),
cteI AS (SELECT LEVEL AS I
FROM DUAL d
CROSS JOIN cteBank_number b
CONNECT BY LEVEL <= LENGTH(b.BANK_NUMBER)),
cteNums AS (SELECT TO_NUMBER(SUBSTR(b.BANK_NUMBER, LENGTH(b.BANK_NUMBER)-i.I+1, 1)) AS DIGIT,
i.I AS I,
TO_NUMBER(SUBSTR(b.BANK_NUMBER, LENGTH(b.BANK_NUMBER)-i.I+1, 1)) * i.I AS NUM
FROM cteBank_number b
CROSS JOIN cteI i)
SELECT SUM(NUM)
FROM cteNums n;
Still produces 165 as the result.
Your v_banknumber variable is a string not a cursor. You need to loop over each character in that string, and treat that character as a digit.
You could do this as:
set serveroutput on
declare
v_banknumber varchar2(9) := '123456789';
v_result number := 0;
begin
for v_counter in reverse 1..length(v_banknumber)
loop
v_result := v_result
+ (v_counter * to_number(substr(v_banknumber, -v_counter, 1)));
end loop;
dbms_output.put_line('The result is: ' || v_result);
end;
/
The result is: 165
PL/SQL procedure successfully completed.
With extra debugs to try to show what is happening on each iteration:
declare
v_banknumber varchar2(9) := '123456789';
v_result number := 0;
begin
dbms_output.put_line('length(v_banknumber) is: ' || length(v_banknumber));
for v_counter in reverse 1..length(v_banknumber)
loop
dbms_output.put_line('v_counter is: ' || v_counter);
dbms_output.put_line(' Digit is substr(v_banknumber, v_counter, 1): '
|| substr(v_banknumber, -v_counter, 1));
dbms_output.put_line(' Calculation for digit is: '
|| v_counter * to_number(substr(v_banknumber, -v_counter, 1)));
v_result := v_result
+ (v_counter * to_number(substr(v_banknumber, -v_counter, 1)));
dbms_output.put_line(' Running total: ' || v_result);
end loop;
dbms_output.put_line('The result is: ' || v_result);
end;
/
length(v_banknumber) is: 9
v_counter is: 9
Digit is substr(v_banknumber, v_counter, 1): 1
Calculation for digit is: 9
Running total: 9
v_counter is: 8
Digit is substr(v_banknumber, v_counter, 1): 2
Calculation for digit is: 16
Running total: 25
v_counter is: 7
Digit is substr(v_banknumber, v_counter, 1): 3
Calculation for digit is: 21
Running total: 46
v_counter is: 6
Digit is substr(v_banknumber, v_counter, 1): 4
Calculation for digit is: 24
Running total: 70
v_counter is: 5
Digit is substr(v_banknumber, v_counter, 1): 5
Calculation for digit is: 25
Running total: 95
v_counter is: 4
Digit is substr(v_banknumber, v_counter, 1): 6
Calculation for digit is: 24
Running total: 119
v_counter is: 3
Digit is substr(v_banknumber, v_counter, 1): 7
Calculation for digit is: 21
Running total: 140
v_counter is: 2
Digit is substr(v_banknumber, v_counter, 1): 8
Calculation for digit is: 16
Running total: 156
v_counter is: 1
Digit is substr(v_banknumber, v_counter, 1): 9
Calculation for digit is: 9
Running total: 165
The result is: 165
Did you mean to do it as an array?
DECLARE
type array_t is varray(9) of number;
a_banknumber array_t := array_t (1,2,3,4,5,6,7,8,9);
v_counter number := a_banknumber.count;
v_result number := 0;
begin
for i in 1..a_banknumber.count
loop
v_result := v_counter * a_banknumber(i) + v_result;
v_counter := v_counter - 1;
end loop;
dbms_output.put_line('Result: ' || v_result);
end;
DECLARE
n NUMBER;<br>i NUMBER;
pr NUMBER;
BEGIN
FOR n IN 2 .. 1000 LOOP
pr := 1;
FOR i IN 2 .. n / 2 LOOP
IF MOD(n, i) = 0 THEN
pr := 0;
END IF;
END LOOP;
IF (N = 997) THEN
DBMS_OUTPUT.PUT(n);
pr:=2;
ELSE
IF pr = 1 THEN
DBMS_OUTPUT.PUT(n||'&');
END IF;
END if;
END LOOP;
dbms_output.new_line;
END;
output should be as in one line----> 2&3&5&7&11&13&17&19&23&29&31&37&41&43&47&53&59&61&67&71&73&79&83&89&97&101&103&107&109&113&127&131&137&139&149&151&157&163&167&173&179&181&191&193&197&199&211&223&227&229&233&239&241&251&257&263&269&271&277&281&283&293&307&311&313&317&331&337&347&349&353&359&367&373&379&383&389&397&401&409&419&421&431&433&439&443&449&457&461&463&467&479&487&491&499&503&509&521&523&541&547&557&563&569&571&577&587&593&599&601&607&613&617&619&631&641&643&647&653&659&661&673&677&683&691&701&709&719&727&733&739&743&751&757&761&769&773&787&797&809&811&821&823&827&829&839&853&857&859&863&877&881&883&887&907&911&919&929&937&941&947&953&967&971&977&983&991&997
but not working in hackerrank compiler question is "Print Prime Numbers"
There's no problem in your code to produce the desired string except <br>i NUMBER;
Just comment out that piece in the declaration section as below :
DECLARE
n NUMBER; -- <br>i NUMBER;
pr NUMBER;
Here's a Demo for it.