Multiple subscriptions causing source stream to fire twice - rxjs

Question

I want to use RxJS to listen to clicks, perform a transaction, and keep track of the transaction status:
function performTransaction() {
const status = {
'0': 'pending',
'1': 'success'
}
return interval(1000).pipe(take(2), map((i) => status[`${i}`]))
}
const click$ = new Subject<void>()
const claimTxnState$ = click$.pipe(switchMap(() => {
console.log('performing transaction') // -> runs once which is expected
return performTransaction()
}))
claimTxnState$.subscribe((v) => {
console.log('claimTxnState', v);
})
export default function App() {
return (
<div className="App">
<button onClick={() => click$.next()}>click me</button>
</div>
);
}
This causes performing transaction to be output once, as is expected.
But I want to pipe claimTxnState$ to more places:
const claimIsPending$ = claimTxnState$.pipe(map((claim) => claim === 'pending'))
claimIsPending$.subscribe((v) => {
console.log('claimIsPending', v);
})
This now causes performing transaction to be output twice, which I understand because these are cold observables that get recreated on each subscription. But I don't want this. I only want my performTransaction to get called once. How can I achieve this?
Complete example.

Answer 1

I found the answer as I was typing the question. I need to use the share operator to convert the observable from cold to hot. This has the effect of sharing claimTxnState$ between all subscribers (i.e. .pipes(...)):
const claimTxnState$ = click$.pipe(
switchMap(() => {
console.log('performing transaction')
return performTransaction()
}),
share() // <- this is the interesting line
)
Sandbox.
More detail.