How to read a specific data from a yaml file inside a shell script - bash

Question

I have a yaml file say "test.yaml". The below is the content of yaml file.
...
test:
config:
abc: name1
xyz: name2
...
Now I want to read the value of abc and xyz alone from the yaml inside a shell script and store it in two variables inside shell script. test.yaml file contains additional data apart from the above one which I don't need to bother about that inside this shell script.
Eg: test.sh
var1=name1 //test[config[abc]]
var2=name2 //test[config[xyz]]
How do I read specific data (as key-value) from yaml inside a shell script. It would be really helpful if someone helps me out on this. Thanks in advance!!!

Answer 1

Here's an example with yq. All of the following assumes that the values do not contain newlines.
Given
$ cat test.yaml
---
test:
config:
abc: name1
xyz: name2
then
yq e '.test.config | to_entries | map(.value) | .[]' test.yaml
outputs
name1
name2
You can read them into variables like
{ read -r var1; read -r var2; } < <(yq e '.test.config | to_entries | map(.value) | .[]' test.yaml)
declare -p var1 var2
declare -- var1="name1"
declare -- var2="name2"
I would read them into an associative array with the yaml key though:
declare -A conf
while IFS="=" read -r key value; do conf["$key"]=$value; done < <(
yq e '.test.config | to_entries | map([.key, .value] | join("=")) | .[]' test.yaml
)
declare -p conf
declare -A conf=([abc]="name1" [xyz]="name2" )
Then you can write
echo "test config for abc is ${conf[abc]}"
# or
for var in "${!conf[#]}"; do printf "key %s, value %s\n" "$var" "${conf[$var]}"; done
I'm using "the Go implementation"
$ yq --version
yq (https://github.com/mikefarah/yq/) version 4.16.1