Group By inside Rtrim(Xmlagg (Xmlelement (e,element || ',')).extract ( '//text()' ).GetClobVal(), ',') - oracle

I need to group values ​​inside a query using (or not) the command Rtrim(Xmlagg (Xmlelement (e,column || ',')).extract ( '//text()' ).GetClobVal(), ','), but I can't find any literature where explain a way to group the data inside this command. The code is very simple, as you can see below:
SELECT ID,
Rtrim(Xmlagg (Xmlelement (and, CONTRACTS || ',')).extract ( '//text()' ).GetClobVal(), ',') AS CONTRACTS
FROM TABLE_A
GROUP BY ID
The result in CONTRACTS is always repeated when the ID is found, thats ok, it´s working!
ID
CONTRACTS
876
1,1,1,2,3,3
But what I really need is this return:
ID
CONTRACTS
876
1,2,3
It´s not necessary to use the command Rtrim(Xmlagg (Xmlelement (e,column || ',')).extract ( '//text()' ).GetClobVal(), ','), instead, I just use to concatenate element with comma "," in the same column.
If anyone can help me, I would be very grateful!

If your values will fit into a VARCHAR2 data type (rather than a CLOB) then you can use a nested sub-query to get the DISTINCT values for each ID:
SELECT ID,
LISTAGG(contracts, ',') WITHIN GROUP (ORDER BY contracts) AS CONTRACTS
FROM ( SELECT DISTINCT id, contracts FROM TABLE_A)
GROUP BY ID
Or, from Oracle 19c, it is built-in to LISTAGG:
SELECT ID,
LISTAGG(DISTINCT contracts, ',') WITHIN GROUP (ORDER BY contracts) AS CONTRACTS
FROM TABLE_A
GROUP BY ID
If you want a CLOB then you can use the same technique as the first query:
SELECT ID,
Rtrim(
Xmlagg(
Xmlelement(name, CONTRACTS || ',')
ORDER BY contracts
).extract ( '//text()' ).GetClobVal(),
','
) AS CONTRACTS
FROM (SELECT DISTINCT id, contracts FROM TABLE_A)
GROUP BY ID
Which, for the sample data:
CREATE TABLE table_a (id, contracts) AS
SELECT 876, 1 FROM DUAL UNION ALL
SELECT 876, 1 FROM DUAL UNION ALL
SELECT 876, 1 FROM DUAL UNION ALL
SELECT 876, 2 FROM DUAL UNION ALL
SELECT 876, 2 FROM DUAL UNION ALL
SELECT 876, 3 FROM DUAL UNION ALL
SELECT 876, 3 FROM DUAL UNION ALL
SELECT 876, 3 FROM DUAL;
All output:
ID
CONTRACTS
876
1,2,3
db<>fiddle here

It's much easier to do all those operation in XML functions: DBFiddle
SELECT--+ NO_XML_QUERY_REWRITE
id,
xmlquery(
'string-join(distinct-values($R/R/X/text()),",")'
passing
Xmlelement(
R,
Xmlagg(
Xmlelement (X, CONTRACTS)
order by CONTRACTS
)) as R
RETURNING CONTENT
) AS CONTRACTS
FROM TABLE_A
GROUP BY ID;
Full example with test data:
with table_a (id, contracts) AS (
SELECT 876, 1 FROM DUAL UNION ALL
SELECT 876, 1 FROM DUAL UNION ALL
SELECT 876, 1 FROM DUAL UNION ALL
SELECT 876, 2 FROM DUAL UNION ALL
SELECT 876, 2 FROM DUAL UNION ALL
SELECT 876, 3 FROM DUAL UNION ALL
SELECT 876, 3 FROM DUAL UNION ALL
SELECT 876, 3 FROM DUAL
)
SELECT--+ NO_XML_QUERY_REWRITE
id,
xmlquery(
'string-join(distinct-values($R/R/X/text()),",")'
passing
Xmlelement(
R,
Xmlagg(
Xmlelement (X, CONTRACTS)
order by CONTRACTS
)) as R
RETURNING CONTENT
) AS CONTRACTS
FROM TABLE_A
GROUP BY ID;

Related

Duplicated rows numbering

I need to number the rows so that the row number with the same ID is the same. For example:
Oracle database. Any ideas?
Use the DENSE_RANK analytic function:
SELECT DENSE_RANK() OVER (ORDER BY id) AS row_number,
id
FROM your_table
Which, for the sample data:
CREATE TABLE your_table ( id ) AS
SELECT 86325 FROM DUAL UNION ALL
SELECT 86325 FROM DUAL UNION ALL
SELECT 86326 FROM DUAL UNION ALL
SELECT 86326 FROM DUAL UNION ALL
SELECT 86352 FROM DUAL UNION ALL
SELECT 86353 FROM DUAL UNION ALL
SELECT 86354 FROM DUAL UNION ALL
SELECT 86354 FROM DUAL;
Outputs:
ROW_NUMBER
ID
1
86325
1
86325
2
86326
2
86326
3
86352
4
86353
5
86354
5
86354
db<>fiddle here

REGEXP_SUBSTR not able to process only current row

(SELECT LISTAGG(EVENT_DESC, ',') WITHIN GROUP (ORDER BY EVENT_DESC) FROM EVENT_REF WHERE EVENT_ID IN
( SELECT REGEXP_SUBSTR(AFTER_VALUE,'[^,]+', 1, level) FROM DUAL
CONNECT BY REGEXP_SUBSTR(AFTER_VALUE, '[^,]+', 1, level) IS NOT NULL
)
)
A table from which I am fetching AFTER_VALUE has values of integer which is comma seperated like
AFTER_VALUE data
Expected output
1
Event1
1,2
Event1,Event2
1,12,2,5
Event1,Event12,Event2,Event5
15,13
Event15,Event13
these are Ids in EVENT_REF table which have some description. I am trying to basically present
ex. 1,2 as Event1, Event2 and send back from query. There are multiple events so using REPLACE would be very tedious.
When using above query I'm getting error as “ORA-01722: invalid number” whenever there is more than one value in AFTER_VALUE column Ex. if there exists only one id , then the query works but for values like 1,2 or 1,13 etc it throws invalid number error.
PS: The event names are not Event1,Event2 etc , I have just put for reference.
You don't even need regular expressions for this assignment. Standard string function replace() can do the same thing, and faster. You only need an extra 'Event' at the beginning of the string, since that one doesn't "replace" anything.
Like this: (note that you don't need the with clause; I included it only for quick testing)
with
event_ref (after_value) as (
select '1' from dual union all
select '1,2' from dual union all
select '1,12,2,5' from dual union all
select '15,13' from dual
)
select after_value,
'Event' || replace(after_value, ',', ',Event') as desired_output
from event_ref
;
AFTER_VALUE DESIRED_OUTPUT
----------- -----------------------------
1 Event1
1,2 Event1,Event2
1,12,2,5 Event1,Event12,Event2,Event5
15,13 Event15,Event13
Ah,ok, looks, like you have other characters in your comma-separated list, so you can use this query:
with EVENT_REF(EVENT_ID,EVENT_DESC) as (
select 1, 'Desc 1' from dual union all
select 2, 'Desc 2' from dual union all
select 3, 'Desc 3' from dual union all
select 4, 'Desc 4' from dual union all
select 5, 'Desc 5' from dual union all
select 12, 'Desc12' from dual union all
select 13, 'Desc13' from dual union all
select 15, 'Desc15' from dual
)
select
(SELECT LISTAGG(EVENT_DESC, ',')
WITHIN GROUP (ORDER BY EVENT_DESC)
FROM EVENT_REF
WHERE EVENT_ID IN
( SELECT to_number(REGEXP_SUBSTR(AFTER_VALUE,'\d+', 1, level))
FROM DUAL
CONNECT BY level<=REGEXP_COUNT(AFTER_VALUE, '\d+')
)
)
from (
select '1' AFTER_VALUE from dual union all
select '1,2' AFTER_VALUE from dual union all
select '1,12,2,5' AFTER_VALUE from dual union all
select '15,13' AFTER_VALUE from dual
);
PS. And do not forget that to_number has 'default on conversion error' now: https://docs.oracle.com/en/database/oracle/oracle-database/12.2/sqlrf/TO_NUMBER.html
There is no need to split and concatenate substrings, just use regexp_replace:
with EVENT_REF (AFTER_VALUE) as (
select '1' from dual union all
select '1,2' from dual union all
select '1,12,2,5' from dual union all
select '15,13' from dual
)
select regexp_replace(AFTER_VALUE,'(\d+)','Event\1') from EVENT_REF;
REGEXP_REPLACE(AFTER_VALUE,'(\D+)','EVENT\1')
-----------------------------------------------
Event1
Event1,Event2
Event1,Event12,Event2,Event5
Event15,Event13

How to get count by using UNION operator

i'm trying to get total count by using UNION operator but it gives wrong count.
select count(*) as companyRatings from (
select count(*) hrs from (
select distinct hrs from companyA
)
union
select count(*) financehrs from (
select distinct finance_hrs from companyB
)
union
select count(*) hrids from (
select regexp_substr(hr_id,'[^/]+',1,3) hrid from companyZ
)
union
select count(*) cities from (
select regexp_substr(city,'[^/]+',1,3) city from companyY
)
);
individual query's working fine but total count not matching.
individual results here: 12 19 3 6
present total count: 31
Actual total count:40.
so there is any alternate solution without UNION operator?
To add values you'd use +. UNION is to add data sets.
select
(select count(distinct hrs) from companyA)
+
(select count(distinct finance_hrs) from companyB)
+
(select count(regexp_substr(hr_id,'[^/]+',1,3)) from companyZ)
+
(select count(regexp_substr(city,'[^/]+',1,3)) from companyY)
as total
from dual;
But I agree with juergen d; you should not have separate tables per company in the first place.
Edit. Updated query using Sum
select sum(cnt) as companyRatings from
(
select count(*) as cnt from (select distinct hrs from companyA)
union all
select count(*) as cnt from (select distinct finance_hrs from companyB)
union all
select count(*) as cnt from (select regexp_substr(hr_id,'[^/]+',1,3) hrid from companyZ)
union all
select count(*) as cnt from (select regexp_substr(city,'[^/]+',1,3) city from companyY)
)
Previous answer:
Try this
SELECT (
SELECT count(*) hrs
FROM (
SELECT DISTINCT hrs
FROM companyA
)
)
+
(
SELECT count(*) financehrs
FROM (
SELECT DISTINCT finance_hrs
FROM companyB
)
)
+
(
SELECT count(*) hrids
FROM (
SELECT regexp_substr(hr_id, '[^/]+', 1, 3) hrid
FROM companyZ
)
)
+
(
SELECT count(*) cities
FROM (
SELECT regexp_substr(city, '[^/]+', 1, 3) city
FROM companyY
)
)
AS total_count
FROM dual

Select Maximum record

Here is my Table EMP_EARN_DETAILS.
Emp_Ern_No is the primary key.
I need to get the amount for each emp_no for each earn_no where the emp_earn_no is the maximum.
The output should be as follows.
0004321 ERN001 2345 11
0004321 ERN002 345 10
0004321 ERN003 345 9
000507 ER-01 563 4
000732 ERN001 2345 12
000732 ERN002 9 13
000732 ERN003 678 8
Please help me with the query
You can aggregate by the fields you need and, at the same time, order by the EMP_EARN_NO value; this can be a solution, by analytic functions:
WITH TEST(emp_no, earn_no, amount, emp_earn_no) AS
(
SELECT '0004321' , 'ERN001' ,2345 ,11 FROM DUAL UNION ALL
SELECT '0004321' , 'ERN002' ,345 , 10 FROM DUAL UNION ALL
SELECT '0004321' , 'ERN003' ,345 ,9 FROM DUAL UNION ALL
SELECT '000507' , 'ER-01' ,56 ,1 FROM DUAL UNION ALL
SELECT '000507' , 'ER-01' ,563 , 2 FROM DUAL UNION ALL
SELECT '000507' , 'ER-01' ,563 ,3 FROM DUAL UNION ALL
SELECT '000507' , 'ER-01' ,563 ,4 FROM DUAL UNION ALL
SELECT '00732' , 'ERN001' ,123 ,7 FROM DUAL UNION ALL
SELECT '00732' , 'ERN001' ,2345 ,12 FROM DUAL UNION ALL
SELECT '00732' , 'ERN002' ,9 ,13 FROM DUAL UNION ALL
SELECT '00732' , 'ERN003' ,67 ,5 FROM DUAL UNION ALL
SELECT '00732' , 'ERN003' ,456 ,6 FROM DUAL UNION ALL
SELECT '00732' , 'ERN003' ,678 ,8 FROM DUAL
)
SELECT emp_no, earn_no, amount, emp_earn_no
FROM (
SELECT emp_no,
earn_no,
amount,
emp_earn_no, ROW_NUMBER() OVER ( PARTITION BY EMP_NO, EARN_NO ORDER BY emp_earn_no DESC) AS ROW_NUM
FROM TEST
)
WHERE ROW_NUM = 1
Give this a shot,
SELECT EMP_NO, SUM(AMOUNT)
FROM EMP_EARN_DETAILS
GROUP BY EMP_NO
HAVING EMP_EARN_NO = MAX(EMP_EARN_NO)
Try this query:
select emp_no, earn_no,
sum(amount) keep (dense_rank last order by emp_earn_no) as sum_amount
from emp_earn_details
group by emp_no, earn_no
First by following query , your conditions achieved :
select t.emp_no a ,t.earn_no b ,max(t.amount) c
from EMP_EARN_DETAILS t
group by t.emp_no,t.earn_no
order by t.emp_no
Only things that you must specify , in a same record with different EMP_EARN_NO. You have to specify in same record which must be in result.
So if you want maximum EMP_EARN_NO be in result you can use following query as final query (exactly your target in question):
select t.emp_no a ,t.earn_no b ,max(t.amount) c, max(t.emp_earn_no) emp_earn_no
from EMP_EARN_DETAILS t
group by t.emp_no,t.earn_no
order by t.emp_no
If you want minimum or others EMP_EARN_NO be in result you can above query replace max function by your conditions.

Oracle 9.2 pivot distinct value

The pivot function is available from Oracle 11 and i will need similar result using Oracle 9.2.
The main argument is that i need to pivot some values with a distinct result in a table like this:
id col3
1 a
1 b
--
2 a
2 a
2 b
--
3 a
3 b
3 c
My result sould be something like this
id a b c
1 1 1 0
2 1 1 0
3 1 1 1
To create a "manual" pivot i'm using a case/when but I am not able to understand how to get distinct value.
Right now the query is this:
with t as
( select 1 as id, 'a' as col1 from dual union all
select 1 as id, 'b' from dual union all
select 2 as id, 'a' from dual union all
select 2 as id, 'a' from dual union all
select 2 as id, 'b' from dual union all
select 3 as id, 'a' from dual union all
select 3 as id, 'b' from dual union all
select 3 as id, 'c' from dual
)
select t.id,
count(case when t.col1 = 'a' then 1 end) a,
count(case when t.col1 = 'b' then 1 end) b,
count(case when t.col1 = 'c' then 1 end) c
This produce correct value but obviously it just "count" the total a/b/c value and not the distinct.
thanks for the support
If I correctly understand your need, you can try something like the following; it aggregates by id and counts the distinct values of col3:
with t as
( select 1 as id, 'a' as col1 from dual union all
select 1 as id, 'b' from dual union all
select 2 as id, 'a' from dual union all
select 2 as id, 'a' from dual union all
select 2 as id, 'b' from dual union all
select 3 as id, 'a' from dual union all
select 3 as id, 'b' from dual union all
select 3 as id, 'c' from dual
)
select id,
count(distinct decode (col1, 'a', id, null)) a,
count(distinct decode (col1, 'b', id, null)) b,
count(distinct decode (col1, 'c', id, null)) c
from t
group by id
Of course the query depends on the number of different values of col3, but this is the same problem than pivot.

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