I am trying to print an EAN barcode vertically on a label with below ZPL code:
^FO895,273^BY3^BUB,200,Y,N
^FO895,261^FD9827755779090^FS
I'm expecting the output as 9827755779090. However, it prints out as 277557790900.
It cuts off the first 2 digit(98) and adds (0) on the final digit. Can I know how do I fix my code?
^BE is the EAN command. It will calculate the check digit for you.
^BE; EAN-13 Bar Code. Description: The ^BE command is similar to the
UPC-A bar code. It is widely used throughout Europe and Japan in the
retail marketplace. The EAN-13 bar code has 12 data characters, one
more data character than the UPC-A code. An EAN-13 symbol contains the
same number of bars as the UPC-A, but encodes a 13th digit into a
parity pattern of the left-hand six digits. This 13th digit, in
combination with the 12th digit, represents a country code. • ^BE
supports fixed print ratios. • Field data (^FD) is limited to exactly
12 characters. ZPL II automatically truncates or pads on the left with
zeros to achieve the required number of characters.
Here is the fixed code (with changed ^FO).
^XA
^FO95,273^BY3^BEB,200,Y,N
^FD9827755779090^FS
^XZ
You are feeding the barcode more data than the specification is set for.
Plus, you are not creating an EAN code, but a UPC(12).
Specification :
UPC (technically refers to UPC-A) consists of 12 digits
Specification of ZPL II on UPC-A (code ^BU) section 5.34 specifically states:
^FD : exactly 11 characters. ZPL II auto-truncates or pads ON THE LEFT with 0 to achieve required number of characters.
(I added italics)
So you get
^FO895,261^FD9827755779090^FS
----------- << these 11 digits
It just so happens that the UPC checksum of 27755779090 is 0
This is why you would get same result for ^FO895,261^FD999999988889827755779090^FS
To get exactly what you want, use
^FO895,261^FD98277557790^FS
.. this will get a checksum of 4
Related
I need to generate a GS1-128 barcode using ZPL. It needs to include a check digit. I do not seem to get the check digit.
Here is my code:
^BCN,088,Y,Y,Y,D^FD(00)00123456000057763^FS
The first "Y" is saying to print the human readable along with the
barcode. The third "Y" is supposed to tell it to include a check digit.
I'm not seeing the check digit in the human readable, my scanner is not
displaying a check digit, so I'm assuming it is also not in the barcode?
Here is from the spec:
SSCC Barcode Structure (20 digits)
Application Identifier = (00)
Positions of SSCC barcode:
1 = Extension Digit (0-9 assigned by Vendor)
2 = 0 if mfg id # assigned by GS1 US;
1-9 if mfg id # assigned by another GS1 MO
3 thru 8 = 6-digit mfg id #
9 thru 17 = 9-digit serial id # -must be unique for one year
18 = Modulo 10 check character
TLDR;
^BCN,088,Y,Y,,D
^FD(00)001234560000577630^FS
The third Y does include a Checkdigit, but not the one you want (ZPL Manual, p73):
Mod 103 check digit is always there. It cannot be turned on or off. Mod 10 and 103 appear together with [the third Y] turned on.
When you use D, it will automatically add a checkdigit(ZPL Manual, p80):
The printer automatically
determines if a check digit is required, calculate it, and print it.
But more importantly, it expects you to send 18 digits :
Parentheses and spaces can be in the field data. '00' application identifier, followed
by 17 characters, followed by bogus check digit place holder.
It'll strip out the 18th digit and replace it in both the barcode and the human readable part.
https://www.zebra.com/content/dam/zebra/manuals/printers/common/programming/zpl-zbi2-pm-en.pdf
I'd like to generate a GS1-128 barcode like this
(01)5410413901026(17)170612(10)LOT100
in ZPL code
^BY5,3,160^FT372,1506^BCB,,N,N,N
^FD>;>8015410413901026>817170612>810>6LOT100^FS
My problem is the 01 code is normally exactly 14 digits, here my EAN is only 13 digits. So my barcode is misformed.
I have already tried to put >8 at the begin of every new AI without result.
EAN is always 13 digits. Add a leading zero to convert to a 14-digit GTIN. (A digit other than 0 at the start identifies a wholesale container of the item.)
Ref: https://stackoverflow.com/a/56673316/323917
Parentheses and spaces can be in the field data. '00' application identifier, followed by 17 characters, followed by bogus check digit place holder.
Ref: https://www.zebra.com/content/dam/zebra/manuals/printers/common/programming/zpl-zbi2-pm-en.pdf
I have verified the barcode from https://zxing.org/w/decode and https://online-barcode-reader.inliteresearch.com/
I am printing a code 128 barcode in ZPL, which must be 78mm. The following numeric barcode works as expected:
^XA^FO141,330^BY3,3,^BCR,243,Y,N,N,A^FD12001752107481808006410360011596^FS^XZ
But changing one number to 'X' near the end of the barcode, means the barcode is now printed as 91mm:
^XA^FO141,330^BY3,3,^BCR,243,Y,N,N,A^FD1200175210748180800641036001X596^FS^XZ
Changing the barcode module with from 3 to 2 with ^BY2 makes the barcode 60mm which is not acceptable.
Any suggestions?
Code 128 has different Subtypes. One of them can encode two numbers in one barcode-character. Your Zebra optimizes your barcode because you use the
^BCo,h,f,g,e,m
Command with Parameter m = mode set to
A = Automatic Mode
This analyzes the data sent and automatically
determines the best packing method. The full
ASCII character set can be used in the ^FD
statement — the printer determines when to shift
subsets. A string of four or more numeric digits
causes an automatic shift to Subset C.
Switching modes and printing alphanumeric makes your barcode longer.
I am trying to come to terms with how a barcode is decoded and generated by a scanner.
A note from the client says the following generated bar code consists of extra characters:
Generated Code: |2389299920014}
Extra Characters: Apparently the first two and last three characters are not part of the bar code.
Question
Are the extra characters attached by the bar code reader (therefore dependent on the scanner) or are they an intrinsic part of the barcode?
Here is a sample image of a barcode:
http://imageshack.us/a/img824/1862/dm6x.jpg
Thanks
[SOLVED] My apologies. This was just another one of those cases of 'shooting your mouth off' without doing proper research.
Solution The code is EAN13. The prefix and suffix are probably scanner dependent. The 13 digits in between are as follows (first digit from the left) Check Sum (Next 9 digits) Company Id + Item Id (Last 3 Digits ) GS1 prefix
It's hard to answer without understanding what format you are trying to encode, what the intended contents are, and what the purported contents are.
Some formats add extra information as part of the encoding process, but it does not become part of the content. When correctly encoded and decoded, the output should match the input exactly.
Barcodes encode what they encode and there is no data that is somehow part of the barcode but not somehow encoded in it.
EAN-13 has no scanner-dependent considerations, no. The encoding and decoding of a given number is the same everywhere. EAN-13 encodes 13 digits, so I am not sure what the 13 digits "in between" mean.
You mention GS1, which is something else. A family of barcodes in fact. You'd have to say what specifically you are using. The GS1 encodings are likewise not ambiguous or scanner-dependent. You know what you want to encode, you encode it exactly, it's read exactly.
I am trying to print a Code 128 barcode on a label using the following the piece of ZPL with a Zebra ZP 450 printer:
^BY3^BCN,112,N^FO090,660^FD>;>89102100^FS
I'm expecting the barcode to scan as "9102100". However, when I scan the printed barcode, it reads as "910210" -- cutting off the final digit.
If I change the last digit, it is still cut off. But if I add more digits onto the end, e.g. "9102100357", the barcode correctly reads as "9102100357".
Why am I "losing" a digit in this particular case?
The >; inside of your ^FD block is telling the code 128 barcode to go into a subset (subset C in this case) which forces the data in the barcode to be numeric pairs (00 - 99). Any data that is not supplied in numeric pairs is ignored. If you put a letter in there, it will ignore that pair. In your case 9102100 has an odd number of numbers, so it ignores the last one. If for example, you add another 0, it will put all the letters in the barcode.
The ;> which puts the barcode in Subset C is not the default. Subset B or :> is the default which will allow any character to be encoded in the barcode. So you can replace the ;> with :>, or just remove the ;> entirely, and it will print out properly.
Check out the ^BC documentation in the ZPL programming manual for more information about Code 128 subsets and data validation
See pg 92 of the ZPL Programming Guide.
This issue may have been fixed in the firmware update, see below:
Example: This is an example with the mode parameter set to D*:
^XA
^PON
^LH0,0
^BY2,2.5,145
^FO218,343
^BCB,,Y,N,N,D
^FD(91)0005886>8(10)0000410549>8(99)05^FS
^XZ
D* — When trying to print the last Application Identifier with an odd number of characters, a problem
existed when printing EAN128 bar codes using Mode D. The problem was fixed in firmware version
V60.13.0.6."