On the website i have a custom form with specifics arguments to do a research of products.
I would like the transform the original prestasop search to test if the specifics arguments are sent and if it's the case change the sql request.
What is the best way to do this ?
I tried to override SearchController and did a class
override/controllers/front/listing/SearchController.php
but can't modify the function getProductSearchQuery
Thanks
If you want to do it "the Prestashop way" I'll suggest to build a module and use hookProductSearchProvider to route your arguments to a custom search.
Have a look at this devdoc article.
Related
I have two dynamic url with simillar structure. For example, lets say, Product page and category page.
I have set both pages in
Route::get('/{product}', [UsersController:: class, 'productDetail']);
Route::get('/{category}', [UsersController:: class, 'categoryProducts']);
But when I click on url which suppose to go in category page, it redirect to product page only because of same structure. How I can differentiate both URLs for Laravel without altering their url structure?
I don't think this can be done without modifying the URL pattern at least a little bit.
If you do something like /50?type=category then in the show method you can use the query parameter to determine which table to look at. But you'll have to use the same show method and I don't recommend doing it this way.
I hope someone else will be able to shine some more light on the matter.
this is the best practice for your case to make yourapi Resful
Route::get('/product/{product-id}', [UsersController:: class, 'productDetail']);
Route::get('/product/categories, [UsersController:: class, 'categoryProducts']);
learn more about Restful api here https://restfulapi.net/resource-naming/
This should be done by calling index, update diff() function. You can try by using the below:
Route::get('/category/{slug}', 'site\categorycontroller#show')->name('category.show');
Route::get('/product/{slug}', 'site\productcontroller#show')->name('product.show');
Currently url display like this
news/?tid=telecom
I need to alias
news/telecom
using clean URL its works in all pages but in view exposed filters not worked
Have you tried views contextual filters to solve your problem?
You can also solve it using contextual filter. You can use taxonomy term names with this filter by adjusting Specify validation criteria settings. please see this answer Drupal 7 views contextual filters taxonomy name
Currently, it's my belief that the only generic way to solve this issue is either manipulating the URLs at the httpd layer, or using hook_url_inbound_alter and hook_url_outbound_alter. You can read a bit more about the mentioned hooks at this question.
However, if I were to give this another shoot myself, I would attempt a Views specific solution instead, as this problem is common enough that it could be justified to have a module for this.
In hook_views_pre_build, one could take data from a url like "members/valuea/valueb", push these values into $_GET['q'], let views build it's query seeing the get arguments "in the url", then possibly remove them again in hook_views_post_build.
I hope this will help you.
I know that we can design the layout in *.xml then in the action just invoke loadLayout, and renderLayout to render the blocks/views.
But, I have a question is:
- How can I load the layout at runtime?
If we have an action which does not really design its layout and will be decided how to render at runtime.
You can please consider the answer from the question for more clear.
Writing a new answer because it seems that you actually DO still want to render, you just want to render a different route's layout XML updates. I believe the _forward() method from Mage_Core_Controller_Varien_Action will allow you to do what you are describing with the least amount of pain.
You should add your action controller directory ahead of the catalog directory, create a ProductController with a viewAction, and check customer is not logged in - in this check you would call $this->_forward('customer','account','login');.
This approach though is going to require more effort in order to be usable, as I imagine that you want the user to be sent to the product page upon login. Have you seen Vinai Kopp's Login Only Catalog module? It should do this for you.
loadLayout() and renderLayout() just execute block output method toHtml() (usually) and take the resulting strings and apply them to the response object via appendBody(). In an action controller you can just call $this->getResponse()->setBody('response string'). How you build the string is up to you.
You can also use Mage_Core_Block_Flush to immediately send output to the browser without using the response object.
Now before you burn me at the stake hear me out!
I want some keywords of a product description field to link to other products (kinda like mediawiki links), however at some point I need to make these associations and link the keywords up, so I'll need to do a search on each curly-braced word I find in the description and produce a formatted version of the description to cut down on processing these keyword links every time the description is displayed.
For ease/consistency I am creating all product links with a custom helper, and all I need to do is pass the product row in and the helper products a link for me with any options I specify. The only this is, is that I need to now do this in beforeSave() so I can populate description_formatted.
At the minute, beforeSave() checks for the original description row, then calls a private method in the model which matches each keyword, queries the db for a matching row... that is as far as I've got.
Just like any other MVC, Cake makes big restrictions how to couple your classes. This is needed to keep script kiddies to shoot themselves in the foot. However, there is a niche workaround for cake if you really need to get along: http://book.cakephp.org/view/933/The-App-Class
How I would do this? With the helper I would replace all curly braces words into links and when the user hovers the linked word I would call an Ajax which will get the word description or the link or whatever you need to do. This way you request the description only when it's needed.
If you still insist to use the helper - it's just a class in PHP, so you can include it in your Model, create an object of the class and use it's functions.
The third option is to create your own class and use it both in Model and the Helper.
I've created a custom content type with CCK.
If I need to add some custom code for validating fields of this content type's record form, where do I add the code and which functions are best for this task?
The easiest way would probably be hook_form_alter() and the #validation attribute on the form. You would of cause have to implement this in your own module.
The form api is what you use to validate, you'll be crafting your own validation function. I'm going to assume you are using D6
There's a less painful way:
http://drupal.org/project/validation_api
This module lets you make php code or regex for any given field.
Hope this helps.
To create your own module to implement form validation I suggest this method:
create a new module for content type field validation in drupal