I try to insert the created field in my_table. The created field has a datetime type. In my_table the field my_created has a date format. So I try to TRUNC the created field. However I'm getting the error ORA-01830: date format picture ends before converting entire input stringwhile inserting the truncated value. It seems, that the time is still there but is reset to 00:00. how can I get only the date without time? It happens only in perl. I'm getting only date in toad.
Very simplified code looks like:
my $SQL="SELECT
TRUNC(CREATED),
FROM
DBA_OBJECTS";
my $sth = $db->prepare($SQL);
$sth->execute();
my $date = $sth->fetchrow();
$SQL = "INSERT INTO MY_TABLE
(MY_CREATED)
VALUES (?)";
my $stmt = $dbh_master->prepare($SQL);
$stmt->execute($date);
EDIT:
I found an ugly workaround and I'm executing it like this:
$stmt->execute(substr($date, 0, 10));
However maybe someone has a nicer solution.
How can I get only the date without time?
In Oracle, a DATE is a binary data type that is composed of 7 bytes representing: century, year-of-century, month, day, hour, minute and second. It ALWAYS has those binary components so if you want an Oracle DATE data type then you cannot get it without a time.
The Oracle DATE data type was released with Oracle version 2 in 1979 and predates the ANSI/ISO standard (of 1986, where a DATE does not have a time component) and Oracle has maintained backwards compatibility with their previous data types rather than adopting the ANSI standard.
If you use the TRUNC(date_value, format_model) function then it will set the binary components of the DATE, up to the specified format model, to the minimum (0 for hours, minutes and seconds, 1 for days and months) but it will NOT give you a data type that does not have a time component.
It happens only in perl. I'm getting only date in toad.
No, you are getting the entire 7 byte binary value in Toad; however, the user interface is only choosing to show you the date component. There should be a setting in the preferences that can set the date format in Toad which will let you see the entire date-time components.
Oracle SQL/Plus and SQL Developer use the NLS_DATE_FORMAT session parameter and Toad may also be able to use that.
If you want to get the value as a DATE then it will always have a time component (even if you set that time component to zeros using TRUNC).
If you want to get the date so that it is formatted in a way without a time component then you need to convert it to another data type and can use TO_CHAR to format it as a string:
SELECT TO_CHAR(CREATED, 'YYYY-MM-DD')
FROM DBA_OBJECTS
But then you will be returning a (formatted) string and not a DATE data type.
Related
I'm trying to store date type data from Oracle FORMS with format mask as like DD-MM-YYYY but every time it store as like DD/MON/YY.
I already alter session with NLS_DATE_FORMAT, but result is as same as before.
Oracle internal date format that is written in the table is something you can't change in any way, but, in the same time, it is irrelevant. If you are dealing with DATE type column then you should know that it containes both the date and the time. How, where and when you will show it or use it is on you. Here is a sample of a few formats derived from that original Oracle DATE format...
WITH
t AS
(
Select SYSDATE "MY_DATE_COLUMN" From Dual
)
Select
MY_DATE_COLUMN "DATE_DEFAULT_FORMAT",
To_Char(MY_DATE_COLUMN, 'mm-dd-yyyy') "DATE_1",
To_Char(MY_DATE_COLUMN, 'yyyy/mm/dd') "DATE_2",
To_Char(MY_DATE_COLUMN, 'dd.mm.yyyy') "DATE_3",
To_Char(MY_DATE_COLUMN, 'dd.mm.yyyy hh24:mi:ss') "DATE_4"
From t
DATE_DEFAULT_FORMAT
DATE_1
DATE_2
DATE_3
DATE_4
22-OCT-22
10-22-2022
2022/10/22
22.10.2022
22.10.2022 10:59:44
You can find a lot more about the theme at https://www.oracletutorial.com/oracle-basics/oracle-date/
Regards...
In Oracle, a DATE is a binary data-type consisting of 7-bytes (representing century, year-of-century, month, day, hour, minute and second). It ALWAYS has those 7 components and it is NEVER stored in any particular human-readable format.
every time it store as like DD/MON/YY.
As already mentioned, no, it does not store a date like that; the database stores dates as 7 bytes.
What you are seeing is that the client application, that you are using to connect to the database, is receiving the 7-byte binary date value and is choosing to convert it to something that is more easily comprehensible to you, the user, and is defaulting to converting the date to a string with the format DD/MON/RR.
What you should be doing is changing how the dates are displayed by the client application by either:
Change the settings in the Toad (View > Toad Options > Data Grids > Data and set the Date Format option) and allow Toad to implicitly format the string; or
Use TO_CHAR to explicitly format the date (TO_CHAR(column_name, 'DD-MM-YYYY')).
I'm trying to store data as like DD-MM-YYYY.
If you want to store a date then STORE it as a date (which has no format) and format it when you DISPLAY it.
If you have a valid business case to store it with a format then you will need to store it as a string, rather than as a date, because you can format strings; however, this is generally considered bad practice and should be avoided.
Sadman, to add to what others have posted I suggest you do not write your applications with reliance on the NLS_DATE_FORMAT parameter but rather you screens and application should specify the expected DATE entry format and the code should use the TO_DATE function to store the data into the database. All application SQL should use the TO_CHAR function to format date output for display.
I have an odd problem about VB6.0 programming when I add a value to database firebird from DtPicker or Calendar. When I add a date where the day is 1 to 12 it can add it into the database, but when I try to add a date where the day is the 13th or above it shows error message
Run-time error '-2147467259'(80004005)':
[ODBC Firebird Driver][Firebird]conversion error from string "13/08/2017"
The type in database is "DATE", but when I turn the type in database into "VARCHAR" everything is fine, but "VARCHAR" cannot do the function Date.
If you pass date value as a string or in context of a concatenated statement, make sure you set the value in 'YYYY-MM-DD' format (ISO_8601).
If you have prepared statements with parameters, then driver itself will handle safely data type conversions automagically. At least it should.
Last option is recommended.
I am at a loss as how to insert the current time in a different format than the default. Can somebody help explain?
Here is how my table was created:
CREATE TABLE ACTIVITY_LOG
(
TIME TIMESTAMP NOT NULL
, ACTIVITY VARCHAR2(200) NOT NULL
);
My insert command works:
insert into activity_log
values (localtimestamp,'blah');
But how do i insert the localtimestamp value into my table in a different format using the various MM DD YY HH MM SS tags? I've tried the following, but it gives me the ORA-1830: date format picture ends before converting entire input string error.
insert into activity_log
values (to_timestamp(localtimestamp,'YYYY/MM/DD'),'blah');
You don't insert a timestamp in a particular format. Timestamps (and dates) are stored in the database using an internal representation, which is betwen 7 and 11 bytes depending on the type and precision. There is more about that in this question, among others.
Your client or application decides how to display the value in a human-readable string form.
When you do:
to_timestamp(localtimestamp,'YYYY/MM/DD')
you are implicitly converting the localtimestamp to a string, using your session's NLS settings, and then converting it back to a timestamp. That may incidentally change the value - losing precision - but won't change how the value is stored internally. In your case the mismatch between the NLS setting and the format you are supplying is leading to an ORA-01830 error.
So your first insert is correct (assuming you really want the session time, not the server time). If you want to see the stored values in a particular format then either change your client session's NLS settings, or preferably format it explicitly when you query it, e.g.:
select to_char(time, 'YYYY-MM-DD HH24:MI:SS.FF3') from activity_log
You don't seem to provide any indication of what your 'localtimestamp' is - is that pseudocode? A variable name? A column you haven't shown the definition for?
What data type is 'localtimestamp'? What data does it contain? Pertinent questions as other answers point out, because if it truly is a time stamp then oracle will be converting it to a string for you, before passing that string to to_timestamp() in your final query. Your initial stab at it should just work if the variable is a timestamp, containing a timestamp
Ultimately "date format picture ends" means "you passed me a string looking like '2017-05-17 12:45:59', but claimed it was only 'yyyy-mm-dd'. What was I expected to do with the rest of it?"
Your current final comment on your question "I was hoping to look in the table and see a useful looking time" - that's your query tool's problem. Have a look in the setting of your query tool and change the date format it displays. As has been noted, dates in oracle are stored as a decimal number days since a certain moment in time. If 0 represents 01 Jan 1970, then 1.75 represents 6pm on the 2 Jan 1970. It is up to the end program the user is using, to format the date into something you like.. you cannot "insert a timestamp with a different format" because time stamps don't have a format any more than a number like 1.75 has a format. It is what your query does with it when it gets it out, that gives it the format:
To_char(timestampcol, 'yyyy mm did')
To-char(tomestampcol, 'mon dd yyyy')
These use oracles built in date formatter, that turns that decimal number of the date into a string in the given format; you will see a string.. or you can just write "select * from table" and run it in TOAD and toad will show you the dates according to the format in settings, or you can write a c# program and get a load of date objects out and call my date.ToString("yyyy-MM-dd") on them to format them. The idea I'm trying to get across is that you don't pick the date format on the way in, you pick it on the way out, if you don't like what you're looking at, you have to change it on the way out, not the way in
1) Why is that this doesn't works
select * from table where trunc(field1)=to_date('25-AUG-15','DD-MON-YY');
select * from table where trunc(field1)=to_date('25/Aug/15','DD/MON/YY');
row is returned in above cases.
So, does this mean that no matter what format the date is there in field1, if it is the valid date and matches with 25th August, it will be returned ( it won't care what format specifier we specify at the right side of the query i.e. DD-MON-YY or DD/MON/YY or anything else) ?
2) but comparsion as string exactly works:
select * from table where to_char(field1)=to_char(to_date
('25/AUG/15','DD/MON/YY'), 'DD/MON/YY');
no row is returned as the comparison is performed exactly.
I have field1 as '25-AUG-15' ( although it can be viewed differently doing alter session NLS_DATE_FORMAT...)
field1 is of DATE type
Any help in understanding this is appreciated specifically with respect to point 1
The DATE data type does not have format -- it's simply a number. So, a DATE 25-Aug-2015 is the same as DATE 25/AUG/15, as well as DATE 2015-08-15, because it's the same DATE.
Strings, on the other hand, are collections of characters, so '25-Aug-2015' is obviously different from '25/AUG/15'.
In the first example you are comparing DATE values. In the second example you are comparing strings.
So you have a field of type DATE with value of The 25th of August 2015,
but it could be visualized in different ways, what in fact is named format.
The DATE has format!
The DATE has implicit format defined by Oracle, in your case it is DD-MON-YY, because you see your field as 25-AUG-15.
You can select your data without TO_DATE conversion, just matching this default format like this:
select * from table where trunc(field1)='25-AUG-15';
In fact, it's not recommended, because if someone will change the default format, Oracle will not be able to understand that you are going to tell him a DATE.
So the to_date conversion in this case:
select * from table where
trunc(field1)=to_date('25/AUG/15','DD/MON/YY');
is used to specify that you wanna tell to Oracle a DATE type with value of 25th of August 2015, using a diffrent format, specified as second parameter. (DD/MM/YY in this case).
I am working (or fixing bugs) on an application which was developed in VS 2005 C#. The application saves data to a SQL server 2005. One of insert SQL statement tries to insert a time-stamp value to a field with GetDate() TSQL function as date time value.
Insert into table1 (field1, ... fieldDt) values ('value1', ... GetDate());
The reason to use GetDate() function is that the SQL server may be at a remove site, and the date time may be in a difference time zone. Therefore, GetDate() will always get a date from the server. As the function can be verified in SQL Management Studio, this is what I get:
SELECT GetDate(), LEN(GetDate());
-- 2010-06-10 14:04:48.293 19
One thing I realize is that the length is not up to the milliseconds, i.e., 19 is actually for '2010-06-10 14:04:48'. Anyway, the issue I have right now is that after the insert, the fieldDt actually has a date time value up to minutes, for example, '2010-06-10 14:04:00'. I am not sure why. I don't have permission to update or change the table with a trigger to update the field.
My question is that how I can use a INSERT T-SQL to add a new row with a date time value ( SQL server's local date time) with a precision up to milliseconds?
Check your table. My guess is that the FieldDT column has a data type of SmallDateTime which stores date and time, but with a precision to the nearest minute. If my guess is correct, you will not be able to store seconds or milliseconds unless you change the data type of the column.
I would guess that you are not storing the GetDate() value in a DateTime field. If you store the value in a datetime field you will get the maximum precision allowed by the DateTime type. Additionally, DateTime is a binary type (a double actually) so 19 means 19 bytes, not 19 characters.
Try to create a simple table with a Datetime field like this
CREATE TABLE [dbo].[DateTable](
[DateField] [datetime] NOT NULL
)
And add a date with
insert into datetable (datefield) values(getdate())
When you execute a select you will get back a value including milliseconds. The following query
select * from datetable
returns
2010-06-11 00:38:46.660
Maybe this would work instead of getdate -
SYSDATETIME()
look here if you can find what you need -
http://msdn.microsoft.com/en-us/library/ms188383.aspx
As you're on SQL 2005, don't forget the getutcdate() function to ensure that, regardless of where your servers are actually located, you have a constant time reference.
Imagine, you have the server in the UK in winter (i.e. GMT+0), and save a record at 10:30am. You then cut over to a SQL server hosted in California (GMT+8) and 8 hours later save another record.
Using getdate(), both saves record the same time "10:30:00". Using getutcdate(), the first save records at "10:30:00", the second save records "18:30:00".
Not really answering the question, but important in your circumstances.
You can use like this in procedure and If there is no procedure use only getdate().
insert into [dbo].[Tbl_User] (UserId,Uvendoremail,UAddress,Ddob,DMobile,
DEmail,DPassword,DAddress,CreatedDate) values (#userid,#vendoremail#address,#dob,#mobile,#email,#dpassword,#daddress,getdate())