Upload directory as whole instead of contents in s3 - bash

Question

I have folder path /images/2020/05/ which contains subdirectories:
ls /images/2020/05/
1 2 3 4 ... 30
I want to feed the bash script to s3 sync folders, e.g.
./sync.sh 11 12 13 14 29 30 such that those directories are uploaded to s3 bucket called imgbucket2021/myimages/
#!/bin/bash
workdir="/images/2020/05"
for subdir in $#; do
/usr/bin/docker run --rm -it -v /root/.aws:/root/.aws -v ${workdir}:/root/ amazon/aws-cli s3 sync /root/${subdir} -- s3://imgbucket2021/myimages/
done
With above script execution, the image files inside the directory are uploaded to bucket path instead of whole folder(e.g. 11 12 13 14 29 30 and contents inside).
Is there some way (without using --exclude, --include) so I can upload a whole directory and content?
Such that listing bucket(imgbucket2021/myimages/) content would have contents like 11 12 13 14 29 30.
edit:
Some commands only perform operations on the contents of a local
directory or S3 prefix/bucket. Adding or omitting a forward slash or
back slash to the end of any path argument, depending on its type,
does not affect the results of the operation
https://docs.aws.amazon.com/cli/latest/reference/s3/
it looks like i will have to use include, exclude flags