I am trying to get images from a online book website.This is what I have done so far
var listAll= document
.querySelectorAll("div.prd-wrapper div.product-img")
.map((e) => e.getElementsByTagName("a")[0])
.toList();
listAll.forEach((element) {
print(element.innerHtml);
});
}
This code give this output
<img class="lazyload" data-src="https://i.dr.com.tr/cache/154x170-0/originals/0001742911001-1.jpg" alt="Minik Elif'in Tuvalet
<img class="lazyload" data-src="https://i.dr.com.tr/cache/154x170-0/originals/0001847750001-1.jpg" alt="Unutma Mutlu Bir Hayat Çok Az
I am required to get image links.I tried this.But Doesnt work
var img=listAll.forEach((element) {
print(element.getElementsByTagName("data-src").length);
});
Concerning this line:
element.getElementsByTagName("data-src")
data-src is an attribute, not a tag, which is probably why getElementsByTagName does not return a useful result.
You would want use something like getAttributeByName (or whatever your method your lib provides).
Related
Please I need your help. So am trying to display an image in my view, it quite working on the index blade but not working on the show with the same code.
Here is my code
<img src="{{asset('/blog_images/'.$post->photo )}}" style="width:300px; height:150px" alt="NO IMAGE">
I've even gone ahead to try other helpers like public_path, url.
Please note that i inspected on the browser and it returned the full part to the image yet didn't display.
I'm thinking it might have to do with a certain settings somewhere.
Cheers!
What is in your Controller show method?)
It must be somthing like this:
public function show($id)
{
$post = Post::find($id);
return view('post.show', compact('post'));
}
Is there a way to check in a blade view if an image is really there or not?
I need to show results from a search box.
The results are many boxes with infos and a picture for each box.
The point is in my DB I store links to images that are on remote servers and also name of images that are stored locally.
So what I am doing is check if the file exists locally and if so use it and if not look on the remote server (if the picture data is not NULL it's either there or in a remote server).
I was trying to check if file exists using curl and it works but for big collections it takes too much time to finally spit the data to the view (every link has to be checked).
So what I want to do, if possible, is check directly in the blade view if the picture is not broken (404) and if so replace with an "image-not-found.png" I store locally. How can I do that?
I usually handle this with JavaScript using the img tag's onerror event. Typically I add a few more bells and whistles to the solution but this is it in a nutshell.
Plan JavaScript
function loadNextImage(id,uri){
document.getElementById(id).src = uri;
}
Plain HTML
<img src="http://local/image.jpg"
onerror="loadNextImage('image1', 'http://remote/imae.jpg'));"
id='image1' />
VueJS and Webpack
<template>
<img :src="local_url" #error="imgOnError()" ref="image"/>
</template>
<script>
export default{
name: 'Thumbnail',
props: {
local_url: String,
remote_url: String
},
methods: {
imgOnError: function (e) {
this.$refs.image.src = this.remote_url
}
}
}
</script>
You can use the func "file_get_contents" inside a try-catch block. I know i not the best way, but i could work for you.
Tray this (no the best way):
<?php
try{
$img = 'myproject.dev/image.jpg';
$test_img = file_get_contents($img);
echo "<img src='{$img}'>";
}catch(Exception $e){
echo "<img src='img/no-img.jpg'>";
}
?>
Is there a way to check if the file exists in Twig for an image uploaded in a newly created post?
The way I have my post setup is if an image is not uploaded the Twig template will show an empty box with the proportions of where the image should be, but it's a blank box that's awkward to look at.
Question, is if there is a specific command to use with an if statement to check if a file exists if so, display the image code if not do not display the image code.
Image code: (this is the code I want to hide if no image exists to get rid of the empty box)
<div class="entry-thumbnail">
<img width="230" height="172" src="{{ asset(['images/', post.image]|join) }}" class="" alt=""/>
</div>
you could write a twig extension and use some code like this:
use Symfony\Component\Filesystem\Filesystem;
use Symfony\Component\Filesystem\Exception\IOException;
use Symfony\Component\Finder\Finder;
$this->fs=new Filesystem();
if (!$this->fs->exists($directory)) {
$this->logger->info("there is no ".$directory." ...");
} else {
$this->logger->info("Directory ".$directory." already exists.");
}
but i would rather use javascripz like
in your img tag :
<img ... onError="this.src='imagefound.gif';" />
update:
The image Tag has an onError-Handler that triggers when the image in the src attribute is not found. So instead of using this simple inline syntax you could do the same like :
pseudo jquery code:
$(document).on('error','img',function(){
$(this).attr("src","../path/to/placeholerImage.png");
});
I'm trying to set up a basic web page, and it has a small music player on it (niftyPlayer). The people I'm doing this for want the player in the footer, and to continue playing through a song when the user navigates to a different part of the site.
Is there anyway I can do this without using frames? There are some tutorials around on changing part of a page using ajax and innerHTML, but I'm having trouble wrapping my head aroung getting everything BUT the music player to reload.
Thank you in advance,
--Adam
Wrap the content in a div, and wrap the player in a separate div. Load the content into the content div.
You'd have something like this:
<div id='content'>
</div>
<div id='player'>
</div>
If you're using a framework, this is easy: $('#content').html(newContent).
EDIT:
This syntax works with jQuery and ender.js. I prefer ender, but to each his own. I think MooTools is similar, but it's been a while since I used it.
Code for the ajax:
$.ajax({
'method': 'get',
'url': '/newContentUrl',
'success': function (data) {
// do something with the data here
}
});
You might need to declare what type of data you're expecting. I usually send json and then create the DOM elements in the browser.
EDIT:
You didn't mention your webserver/server-side scripting language, so I can't give any code examples for the server-side stuff. It's pretty simple most of time. You just need to decide on a format (again, I highly recommend JSON, as it's native to JS).
I suppose what you could do is have to div's.. one for your footer with the player in it and one with everything else; lets call it the 'container', both of course within your body. Then upon navigating in the site, just have the click reload the page's content within the container with a ajax call:
$('a').click(function(){
var page = $(this).attr('page');
// Using the href attribute will make the page reload, so just make a custom one named 'page'
$('#container').load(page);
});
HTML
<a page="page.php">Test</a>
The problem you then face though, is that you wouldnt really be reloading a page, so the URL also doesnt get update; but you can also fix this with some javascript, and use hashtags to load specific content in the container.
Use jQuery like this:
<script>
$("#generate").click(function(){
$("#content").load("script.php");
});
</script>
<div id="content">Content</div>
<input type="submit" id="generate" value="Generate!">
<div id="player">...player code...</div>
What you're looking for is called the 'single page interface' pattern. It's pretty common among sites like Facebook, where things like chat are required to be persistent across various pages. To be honest, it's kind of hard to program something like this yourself - so I would recommend standing on top of an existing framework that does some of the leg work for you. I've had success using backbone.js with this pattern:
http://andyet.net/blog/2010/oct/29/building-a-single-page-app-with-backbonejs-undersc/
You can reload desired DIVs via jQuery.ajax() and JSON:
For example:
index.php
<script type="text/javascript" src="jquery-1.4.2.js"></script>
<script type="text/javascript" src="ajax.js"></script>
<a href='one.php' class='ajax'>Page 1</a>
<a href='two.php' class='ajax'>Page 2</a>
<div id='player'>Player Code</div>
<div id='workspace'>workspace</div>
one.php
<?php
$arr = array ( "workspace" => "This is Page 1" );
echo json_encode($arr);
?>
two.php
<?php
$arr = array( 'workspace' => "This is Page 2" );
echo json_encode($arr);
?>
ajax.js
jQuery(document).ready(function(){
jQuery('.ajax').click(function(event) {
event.preventDefault();
// load the href attribute of the link that was clicked
jQuery.getJSON(this.href, function(snippets) {
for(var id in snippets) {
// updated to deal with any type of HTML
jQuery('#' + id).html(snippets[id]);
}
});
});
});
Given the following Html.ActionLink:
#Html.ActionLink(Model.dsResults.Tables[0].Rows[i]["title"].ToString(), "ItemLinkClick",
new { itemListID = #Model.dsResults.Tables[0].Rows[i]["ItemListID"], itemPosNum = i+1 }, ...
Data from the model contains HTML in the title field. However, I am unable to display the HTML encoded values. ie. underlined text shows up with the <u>....</u> around it.
I've tried Html.Raw in the text part of the ActionLink, but no go.
Any suggestions?
If you still want to use a helper to create an action link with raw HTML for the link text then I don't believe you can use Html.ActionLink. However, the answer to this stackoverflow question describes creating a helper which does this.
I would write the link HTML manually though and use the Url.Action helper which creates the URL which Html.ActionLink would have created:
<a href="#Url.Action("ItemLinkClick", new { itemListID = #Model.dsResults.Tables[0].Rows[i]["ItemListID"], itemPosNum = i+1 })">
#Html.Raw(Model.dsResults.Tables[0].Rows[i]["title"].ToString())
</a>
MVCHtmlString.Create should do the trick.
Using the actionlink below you do not need to pass html in the model. Let the css class or inline style determine how the href is decorated.
#Html.ActionLink(Model.dsResults.Tables[0].Rows[i]["title"], "ItemLinkClick", "Controller", new { #class = "underline", style="text-decoration: underline" }, null)
those are the cases that you should take the other path
#{
string title = Model.dsResults.Tables[0].Rows[i]["title"].ToString(),
aHref = String.Format("/ItemLinkClick/itemListID={0}&itemPosNum={1}...",
Model.dsResults.Tables[0].Rows[i]["ItemListID"],
i+1);
}
#Html.Raw(title)
Remember that Razor helpers, help you, but you can still do things in the HTML way.
You could also use this:
<a class='btn btn-link'
href='/Mycontroler/MyAction/" + item.ID + "'
data-ajax='true'
data-ajax-method='Get'
data-ajax-mode='InsertionMode.Replace'
data-ajax-update='#Mymodal'>My Comments</a>