Imagine there is a table:
code | value
------------
AAAA | 10
AAAA | 15
BBBB | 5
I would like to count (aggregate) by code and for absent codes counted value to 0:
select code, count(*) count
from table
where code in ('AAAA', 'CCCC')
group by code
The actual result for query above:
code | count
------------
AAAA | 2
But I'd expect result to be:
code | count
------------
AAAA | 2
CCCC | 0
Is it possible to archive expected result? If yes how?
You can do something like this:
SELECT `F`.`code`, IFNULL(`AT`.`count`, 0) as `count` FROM
(
SELECT `code`, count(*) as `count` FROM `table`
WHERE `code` IN ('AAAA', 'CCCC') group by `code`
) as `AT`
RIGHT JOIN
(
SELECT 'AAAA' as `code`
UNION
SELECT 'CCCC' as `code`
) as `F`
ON `F`.`code` = `AT`.`code`
Follow this SQL fiddel.
Related
I have 3 tables to join to get the output in the below format.
My table 1 is like:
--------------------------------------------------------
T1_ID1 | T1_ID2 | NAME
--------------------------------------------------------
123 | T11231 | TestName11
123 | T11232 | TestName12
234 | T1234 | TestName13
345 | T1345 | TestName14
--------------------------------------------------------
My table 2 is like:
--------------------------------------------------------
T2_ID1 | T2_ID2 | NAME
--------------------------------------------------------
T11231 | T21231 | TestName21
T11232 | T21232 | TestName21
T1234 | T2234 | TestName22
--------------------------------------------------------
My table 3 is like:
----------------------------------------------------------
T3_ID1 | TYPE | REF
----------------------------------------------------------
T21231 | 1 | 123456
T21232 | 2 | 1234#test.com
T2234 | 2 | 123#test.com
----------------------------------------------------------
My desired output is:
------------------------------------------------------
T1_ID1 | PHONE | EMAIL
------------------------------------------------------
123 | 123456 | 1234#test.com
234 | | 123#test.com
345 | |
------------------------------------------------------
Requirements:
T1_ID2 of table 1 left joins with T2_ID1 of table 2.
T2_ID2 of table 2 left joins with T3_ID1 of table 3.
TYPE of table 3 specifies 1 if the value is phone and specified 2 if value is email.
My output should contain T1_ID1 of table 1 and its corresponding value of REF in table 3, with the REF in the same row.
That is, in this case, T1_ID1 with value 123 has both phone and email. So, it is displayed in the same row in output.
If phone alone is available for corresponding value of T1_ID1, then phone should be populated in the result with email as null and vice versa.
If neither phone nor email is available, nothing should be populated.
I had tried the below SQLs but in vain. Where am I missing? Please extend your help.
Option 1:
SELECT DISTINCT
t1.t1_id1,
t3.ref
|| (
CASE
WHEN t3.type = 1 THEN
1
ELSE
0
END
) phone,
t3.ref
|| (
CASE
WHEN t3.type = 2 THEN
1
ELSE
0
END
) email
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.t1_id2 = t2.t2_id1
LEFT JOIN table3 t3 ON t2.t2_id2 = t3.t3_id1;
Option 2:
SELECT DISTINCT
t1.t1_id1,
t3.ref,
(
CASE
WHEN t3.type = 1 THEN
1
ELSE
0
END
) phone,
t3.ref,
(
CASE
WHEN t3.type = 2 THEN
1
ELSE
0
END
) email
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.t1_id2 = t2.t2_id1
LEFT JOIN table3 t3 ON t2.t2_id2 = t3.t3_id1;
Option 3:
SELECT DISTINCT
t1.t1_id1,
(
CASE
WHEN t3.type = 1 THEN
1
ELSE
0
END
) phone,
(
CASE
WHEN t3.type = 2 THEN
1
ELSE
0
END
) email
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.t1_id2 = t2.t2_id1
LEFT JOIN table3 t3 ON t2.t2_id2 = t3.t3_id1;
select t1_id1, max(t3.ref )phone, max(t33.ref) email
from table1
left outer join
table2 on t1_id2=t2_id1
left outer join table3 t3 on t3.t3_id1=t2_id2 and t3.type=1
left outer join table3 t33 on t33.t3_id1=t2_id2 and t33.type=2
group by t1_id1
if you have maximum one phone and one email in table3 for each t2_id2 entry in table2.
I have a query in which I am producing results with rows that contain 0 values. I would like to exclude any rows in which columns B or C = 0. To exclude such rows, I have added the T2.A <> 0 and T2.A != 0. When I do this, the 0 values are replaced with NULLs. Thus I also added T2.A IS NOT NULL.
My results still produce the columns that I do not need which show (null) and would like to exclude these.
SELECT
(SELECT
SUM(T2.A) as prem
FROM Table_2 T2, Table_2 T1
WHERE T2.ENT_REF = T1.ENT_REF
AND UPPER(T2.PER) = 'HURR'
AND UPPER(T2.ENT_TYPE) = 'POL'
AND T2.Cov NOT IN ('OUTPROP','COV')
AND T2.A <> 0
AND T2.A IS NOT NULL
) as B,
(SELECT
SUM(T2.A) as prem
FROM Table_2 T2, Table_2 T1
WHERE T2.ENT_REFE = T1.ENT_REF
AND UPPER(T2.PER) IN ('I', 'II', 'II')
AND UPPER(T2.ENT_TYPE) = 'POL'
AND T2.Cov NOT IN ('OUTPROP','COV')
AND T2.A <> 0
AND T2.A IS NOT NULL
) as C
Ideally the result will go from:
+----+--------+--------+
| ID | B | C |
+----+--------+--------+
| 1 | 24 | 123 |
| 2 | 65 | 78 |
| 3 | 43 | 89 |
| 3 | 0 | 0 |
| 4 | 95 | 86 |
| 5 | 43 | 65 |
| 5 | (null) | (null) |
+----+--------+--------+
To something similar to the following:
+----+-----+-----+
| ID | B | C |
+----+-----+-----+
| 1 | 24 | 123 |
| 2 | 65 | 78 |
| 3 | 43 | 89 |
| 4 | 95 | 86 |
| 5 | 43 | 65 |
+----+-----+-----+
I have also attempted distinct values, but I have other columns such as dates which are different per row. Although I need to include dates, they are not as important to me as only getting B and C columns with only values > 0. I have also tried using a GROUP BY ID statement, but I get an error that states 'ORA-00979: not a GROUP BY expression'
You have written all the conditions in the SELECT clause.
You are facing the issue because the WHERE clause decides the number of rows to be fetched and SELECT clause decides values to be returned.
In your case, something like the following is happening:
Simple Example:
-- MANUAL DATA
WITH DATAA AS (
SELECT
1 KEY,
'VALS' VALUE,
1 SEQNUM
FROM
DUAL
UNION ALL
SELECT
2,
'IDEAL OPTION',
2
FROM
DUAL
UNION ALL
SELECT
10,
'EXCLUDE',
3
FROM
DUAL
)
-- QUERY OF YOUR TYPE
SELECT
(
SELECT
KEY
FROM
DATAA I
WHERE
I.KEY = 1
AND O.KEY = I.KEY
) AS KEY, -- DECIDE VALUES TO BE SHOWN
(
SELECT
KEY
FROM
DATAA I
WHERE
I.SEQNUM = 1
AND O.SEQNUM = I.SEQNUM
) AS SEQNUM -- DECIDE VALUES TO BE SHOWN
FROM
DATAA O
WHERE
O.KEY <= 2; -- DECIDES THE NUMBER OF RECORDS
OUTPUT:
If you don't want to change much logic in your query then just use additional WHERE clause outside your final query like:
SELECT <bla bla bla>
FROM <YOUR FINAL QUERY>
WHERE B IS NOT NULL AND C IS NOT NULL
Cheers!!
I guess you were on the right track, trying to group values.
In order to do that, columns (that are supposed to be distinct) will be left alone (such as ID in the following example), while the rest should be aggregated (using min, max or any other you find appropriate).
For example, as you said that there's some date column you don't care about - I mean, which one of them you'll select - then select the first one (i.e. min(date_column)). Similarly, you'd do with the rest. The group by clause should contain all non-aggregated columns (id in this example).
select id,
sum(a) a,
sum(b) b,
min(date_column) date_column
from your_current_query
group by id
If I understand your query right, it would be much easier and more performant, to avoid the lookups in the Select clause. Try to bring it all in one Query:
SELECT * FROM (
SELECT T2.ENT_REF AS ID,
SUM(CASE WHEN UPPER(T2.PER) = 'HURR' THEN T2.A END) AS B,
SUM(CASE WHEN UPPER(T2.PER) IN ('I', 'II', 'II') THEN T2.A END) as C
FROM Table_2 T2
WHERE UPPER(T2.ENT_TYPE) = 'POL'
AND T2.Cov NOT IN ('OUTPROP','COV')
GROUP BY T2.ENT_REF
)
WHERE B IS NOT NULL
OR C IS NOT NULL
There is a column in table 'mytable' named 'Description'.
+----+-------------------------------+
| ID | Description |
+----+-------------------------------+
| 1 | My NAME is Sajid KHAN |
| 2 | My Name is Ahmed Khan |
| 3 | MY friend name is Salman Khan |
+----+-------------------------------+
I need to write an Oracle SQL query/procedure/function to list the distinct words in the column.
The output should be:
+------------------+-------+
| Word | Count |
+------------------+-------+
| MY | 3 |
| NAME | 3 |
| IS | 3 |
| SAJID | 1 |
| KHAN | 3 |
| AHMED | 1 |
| FRIEND | 1 |
| SALMAN | 1 |
+------------------+-------+
Word matching should be case-insensitive.
I am using Oracle 12.1.
Let's suppose we would somehow manage to split every description in words.
So, instead of single row with Id = 1 and Description = 'My NAME is Sajid KHAN' we'd have 5 rows like this
ID | Description
--- | ------------
1 | My
1 | NAME
1 | is
1 | Sajid
1 | KHAN
in this form it'd be trivial, something like
select Description, count(*) from data_in_new_form group by Description
So, let's do this using recursive query.
create table mytable
as
select 1 as ID, 'My NAME is Sajid KHAN' as Description from dual
union all
select 2, 'My Name is Ahmed Khan' from dual
union all
select 3, 'MY friend name is Salman Khan' from dual
union all
select 4, 'test, punctuation! it is' from dual
;
with
rec (id, str, depth, element_value) as
(
-- Anchor member.
select id, upper(Description) as str, 1 as depth, REGEXP_SUBSTR( upper(Description), '(.*?)( |$)', 1, 1, NULL, 1 ) AS element_value
from mytable
UNION ALL
-- Recursive member.
select id, str, depth + 1, REGEXP_SUBSTR( str ,'(.*?)( |$)', 1, depth+1, NULL, 1 ) AS element_value
from rec
where depth < regexp_count(str, ' ')+1
)
, data as (
select * from rec
--order by id, depth
)
select element_value, count(*) from data
group by element_value
order by element_value
;
Please notice this version doesn't do anything about punctuation assuming words are separated with spaces.
UPDATE alternative way using hierarchic query
with rec as
(
SELECT id, LEVEL AS depth,
REGEXP_SUBSTR( upper(description) ,'(.*?)( |$)', 1, LEVEL, NULL, 1 ) AS element_value
FROM mytable
CONNECT BY LEVEL <= regexp_count(description, ' ')+1
and prior id = id
and prior SYS_GUID() is not null
)
, data as (
select * from rec
--order by id, depth
)
select element_value, count(*) from data
group by element_value
order by 2 desc
;
This query will work. The ordering of the words may be different. However, frequent words come at the beginning as you have listed.
SELECT word,
COUNT(*)
FROM
(SELECT TRIM (REGEXP_SUBSTR (Description, '[^ ]+', 1, ROWNUM) ) AS Word
FROM
(SELECT LISTAGG(UPPER(Description),' ') within GROUP(
ORDER BY ROWNUM ) AS Description
FROM mytable
)
CONNECT BY LEVEL <= REGEXP_COUNT ( Description, '[^ ]+')
)
GROUP BY WORD
ORDER BY 2 DESC;
I have a problem with a query, see I have two tables, let say:
table a:
progid | name | type
12 | john | b
12 | anna | c
13 | sara | b
13 | ben | c
14 | alan | b
15 | george| b
table b:
progid | name | type
12 | john | b
12 | anna | c
13 | sara | b
14 | alan | b
15 | george| b
table a gets count
progid | count(*)
12 | 2
13 | 2
14 | 1
15 | 1
table b gets
progid | count(*)
12 | 2
**13 | 1**<-this is what I want to find different count
14 | 1
15 | 1
What I want is to find which progid in table b aren't in table a by count, (because as you can see the prog id is there but they should be there the same times! So ben is gone but the progid 13 is there)
So I want to get progid where count varies in the tables, I tried:
select a.progid from
(select progid ,count(*) total from tablea group by progid) a,
(select progid ,count(*) total from tableb group by progid) b
where
a.progid=b.progid and a.total<>b.total;
I get b.total invalid identifier
if I use a.count(progid)<>b.count(progid)
Error says can't use group functions there, any ideas? I'm desperate!
ok i've checked your answers and here's the original one
select a.beneficiarioid from
(select beneficiarioid,count(*) total from lmml_ejercicio_2012_3 where programaid=61 group by beneficiarioid order by beneficiarioid) a,
(select beneficiarioid,count(*) total from ejercicio_2012_3 where programaid=61 group by beneficiarioid order by beneficiarioid) where
a.beneficiarioid=b.beneficiarioid and a.total<>b.total;
anyway, i'll try your querys and let you know!! thank you very much!!
btw it's Oracle 11g
You should be able to use a subquery to get each count and then join them using a FULL OUTER JOIN:
select coalesce(a.progId, b.progId) progid,
coalesce(a.atotal, 0) atotal,
coalesce(b.btotal, 0) btotal
from
(
select progid, count(*) aTotal
from tablea
group by progId
) a
full outer join
(
select progid, count(*) bTotal
from tableb
group by progId
) b
on a.progid = b.progid
where coalesce(a.atotal, 0) <> coalesce(b.btotal, 0);
See SQL Fiddle with Demo. I used a FULL OUTER JOIN in the event you have rows in one table that do not exist in the other table.
Even though your query works fine on my database, I would prefer set operation:
(select progid ,count(*) total from tablea group by progid)
minus
(select progid ,count(*) total from tableb group by progid)
I'm using Oracle 11g.
I have 2 related tables: stored values (A) and new values to insert (B). Both are related between them with an id of 3 columns (client, group and personcode). Each table has about 20 other columns (let's call them attributes).
I have to match them so I can know which values are new (id in B and not in A) so I insert them in A, which are equals (id in B and in A with the same attributes) and which are not in the new values (id in A but not in B anymore), so I delete them from the stored values (A).
For instance:
A:
client | group | personcode | name | surname
_________________________________________________
1 | 1 | 1 | joe | doe
1 | 1 | 2 | carl | john
1 | 1 | 3 | john | john
B:
client | group | personcode | name | surname
_________________________________________________
1 | 1 | 1 | joe | doe
1 | 1 | 3 | john | john
1 | 1 | 4 | mary | con
In this example, person 4 is new, person 2 should be deleted and 1 and 3 remains the same.
So, I need a query which returns the following results:
client | group | personcode | action
_________________________________________
1 | 1 | 1 | equal
1 | 1 | 2 | remove
1 | 1 | 3 | equal
1 | 1 | 4 | new
What I've made is the following query:
WITH
A AS (
-- select from A table
),
B AS
(
-- select from B table
),
delete AS
(
-- select from A WHERE NOT EXISTS (B.id = A.ID)
),
news AS
(
-- select from B WHERE NOT EXISTS (A.id = B.ID)
),
eq AS
(
-- select A.* from A, B WHERE A.id = B.id AND A.attributes = B.attributes
)
select action.client, action.group, action.personcode, 'remove' from delete action
UNION ALL
select action.client, action.group, action.personcode, 'new' from news action
UNION ALL
select action.client, action.group, action.personcode, 'equal' from eq action
;
The problem is that, although each of those 3 lasts selects runs in less than 10 seconds, when I merge them using UNION or UNION ALL, the complete query lasts about 90 seconds, even if delete or new or equal are empty. It could be more than 3000 rows in A or in B.
Is there any way to get this results in a better, faster way?
You could outer join the tables to produce a log of the differences between them.
select coalesce(a.id,b.id) id,
case when a.id is null
then 'new'
when b.id is null
then 'remove'
when a.col1 = b.col1 and a.col2 = b.col2 ...
then 'same'
else 'different'
end
from a full outer join b on (a.id = b.id)
If the table B has the data that you want, why do you not use that table instead of that in table A? Create a synonym that points to the one with the correct data in it and reference that.
Well, thanks all for your reply.
I've finally made a view to which I pass some parameters to filter the first two queries, using the strategy described in this blog
The complete process lasts 30 secs now, and 0 if there are no rows at A or B (before, it lasts 90 secs always).
This is the solution which less affects my current procedures.