I have a query which has sub query with 2 joins inside a Left join and I was trying to convert it to Laravel
LEFT JOIN (
orders xo
JOIN factories xs
ON ( xs.factory_id = xo.factory_id )
JOIN setup sp
ON ( sp.factory_id = xs.legacy_factory_id)
)
ON ( xo.production_id = po.production_id )
I tried something like this
->leftJoin('orders AS xo', function ($query) use ($input) {
$query->join('factories AS xs','xs.factory_id','=','xo.factory_id')
->join('setup AS sp','sp.factory_id','=','xs.legacy_factory_id');
},function($join) {
$join->on('xo.production_id','=','po.production_id');
Would like some help with this convertion
You can use Subquery Joins like so
$SubQuery= DB::table('orders AS xo')
->join('factories AS xs','xs.factory_id','=','xo.factory_id')
->join('setup AS sp','sp.factory_id','=','xs.legacy_factory_id');
// then use the subQuery like below:
// here a is the alias to the subquery
DB::table('your_table as po')
->leftjoinSub($SubQuery, 'a', function ($join) { $join->on('a.production_id', '=', 'po.production_id'); })
There was a problem that you don't wanna do Eloquent: Relationships?
look the below link:
https://laravel.com/docs/9.x/eloquent-relationships#main-content
Additionally, You will need a patch for this problem hasOne or hasMany.
Related
I have a complicated query that I would like to translate either in Eloquent ORM or with the Query Builder for a Laravel site, but I can't do it, can someone help me?
Here is my SQL query
SELECT opp_id, risk_study.rst_id, risk_study.rst_status
FROM opportunity
LEFT JOIN risk_study ON risk_study.rst_id =
(SELECT risk_study_quote_vehicle.rst_id
FROM risk_study_quote_vehicle
INNER JOIN quote_vehicle ON quote_vehicle.quv_id = risk_study_quote_vehicle.quv_id
INNER JOIN quote ON quote.quo_id = quote_vehicle.quo_id
WHERE quote.opp_id = opportunity.opp_id
ORDER BY risk_study_quote_vehicle.rst_id DESC
LIMIT 0,1)
WHERE 1 = 1
AND opportunity.per_id_process = '5'
AND opportunity.opp_locked = '1'
Here is my solution.
But this query does not retrieve values from the risk_study table.
$opportunities = Opportunity::select('opp_id', 'risk_study.rst_id', 'risk_study.rst_status')
->leftJoin('risk_study', function ($join) {
$join->on('risk_study.rst_id', '=', DB::raw('"SELECT risk_study_quote_vehicle.rst_id FROM risk_study_quote_vehicle INNER JOIN quote_vehicle ON quote_vehicle.quv_id = risk_study_quote_vehicle.quv_id INNER JOIN quote ON quote.quo_id = quote_vehicle.quo_id WHERE quote.opp_id = opportunity.opp_id ORDER BY risk_study_quote_vehicle.rst_id DESC LIMIT 0,1"'));
})
->where([
['per_id_process', 5],
['opp_locked', 1],
])
->get();
Finally, I wrote the query and it works ! Thanks !
$opportunities = Opportunity::query()
->select(
'opp_id',
'risk_study.rst_id',
'risk_study.rst_status'
)
->from('opportunity')
->leftJoin('risk_study', function ($join) {
$join->where('risk_study.rst_id', function ($sub) {
$sub->select('risk_study_quote_vehicle.rst_id')
->from('risk_study_quote_vehicle')
->join('quote_vehicle', 'quote_vehicle.quv_id', 'risk_study_quote_vehicle.quv_id')
->join('quote', 'quote.quo_id', 'quote_vehicle.quo_id')
->whereColumn('quote.opp_id', 'opportunity.opp_id')
->orderByDesc('risk_study_quote_vehicle.rst_id')
->limit(1);
});
})
->where('opportunity.per_id_process', '5')
->where('opportunity.opp_locked', '1')
->get();
You should be able to use a Closure as the second parameter of where() inside your join Closure.
I don't think Laravel's query builder supports the LIMIT 0,1 statement.
I don't know why you need WHERE 1 = 1, but you should be able to use whereRaw for that.
When you're done, the result looks very alike a formatted SQL query.
$opportunities = Opportunity::query()
->select(
'opp_id',
'risk_study.rst_id',
'risk_study.rst_status'
)
->from('opportunity')
->leftJoin('risk_study', function ($join) {
$join->where('risk_study_quote_vehicle.rst_id', function ($sub) {
$sub->select('risk_study_quote_vehicle.rst_id')
->from('risk_study_quote_vehicle')
->join('quote_vehicle', 'quote_vehicle.quv.id', 'risk_study_quote_vehicle.quv_id')
->join('quote', 'quote.quo_id', 'quote_vehicle.quo_id')
->where('quote_opp_id', 'opportunity.opp_id')
->orderByDesc('risk_study_quote_vehicle.rst_id')
->limit(1);
});
})
->whereRaw('1 = 1')
->where('opportunity.per_id_process', '5')
->where('opportunity.opp_locked', '1')
->get();
Hi I want to know how can i do this query in Laravel 8 , I tried adding the join clause but not work as expected, i need join clause? Or maybe there is another form to do it. I search others examples but i don´t see anythat help me. The query is the next:
DB::table('escandallo_p as esc')
->select("esc.material", "esc.referencia", "esc.ancho", "esc.proveedor", "esc.punto",
"esc.precio", "esc.consumo", "esc.veces", "esc.001", "esc.002", "esc.003", "esc.004",
"esc.005", "esc.006", "esc.007", "esc.008", "esc.009", "esc.010", "esc.011", "esc.um", "esc.merma", "esc.importe", "esc.tipo", "esc.xtalla", "esc.fase",
DB::raw("(select anulado from prototipos_p as p where p.prototipo = '".$scandal[0]->prototipo."' and p.tipo = 'c' and p.referencia = esc.referencia )"),
// ignore
//original query "(select anulado from prototipos_p as p where p.prototipo = ",$request->prototipo," and p.tipo = 'c' and p.referencia = esc.referencia ) as 'anulado'",
// "(select clase from prototipos_p as p where p.prototipo = ",$request->prototipo," and p.tipo = 'c' and p.referencia = esc.referencia ) as 'clase'")
//Converted query ->select('pro.anulado')->where('pro.prototipo', $request->prototipo)
// ->where("p.prototipo", "=", $request->prototipo)
->where("esc.id_escandallo", "=", $request->id_escandallo)
->where("esc.id_version", "=", $request->version)
->orderBy("id","asc")
->get();
!!!! I need to pass the esc.referencia to the sub select query
The second select is the conversion of the select inside "" ( i know this is wrong is only for explain it).
Thank you in advance for any suggestion.
Best regards
EDIT: I can solve my problem with DB::raw, but if anyone know others methos are welcome!
You need to pass callback to the join query to add the extra query to the laravel's join method,
Example from Laravel Doc:
DB::table('users')
->join('contacts', function ($join) {
$join->on('users.id', '=', 'contacts.user_id')
->where('contacts.user_id', '>', 5);
})
->get();
It is explained in Laravel's doc, Advanced Join Clauses
There is Subquery support too Subquery Joins,
Eg:
$latestPosts = DB::table('posts')
->select('user_id', DB::raw('MAX(created_at) as last_post_created_at'))
->where('is_published', true)
->groupBy('user_id');
$users = DB::table('users')
->joinSub($latestPosts, 'latest_posts', function ($join) {
$join->on('users.id', '=', 'latest_posts.user_id');
})
->get();
These two might help you to achieve what you are trying
After test joins, joinSub, whereIn and other forms of doing this, I solved my problem using the DB::raw():
DB::table('escandallo_p as esc')
->select('parameters',....,
DB::raw("(SELECT column //(ONLY ONE)
FROM table
WHERE column = '".$parameter."' ...) AS nombre"),
)
->where('column', "=", $parameter)
->orderBy("id","asc")
->get();
I'm trying to build a query joining multiple tables and I'm having trouble writing a join using an IN operator. Here's an example:
LEFT JOIN sProductDetailWarehouse pdw ON (pdw.ID_sProductDetail = pd.ID AND pdw.ID_sWarehouse IN (52,118))
The two values are set and don't need to be parameters....but this doesn't work since there is no IN operator:
->leftJoin('sProductDetailWarehouse as pdw', function($join)
{
$join->on('pdw.ID_sProductDetail', '=', 'pd.ID');
$join->on('pdw.ID_sWarehouse','IN',DB::raw("(52,118)"));
})
How can I do that join? I'm sure there's a way to do it, I just can't find it...
When you need to join to data you need to use a 'where' method instead of 'on'
e.g.
->leftJoin('sProductDetailWarehouse as pdw', function($join)
{
$join->on('pdw.ID_sProductDetail', '=', 'pd.ID');
$join->whereIn('pdw.ID_sWarehouse',[52,118]);
})
My query is as below
SELECT * FROM `user_register`
INNER JOIN `locationdetail` on `locationdetail`.`userid` = `user_register`.`id`
INNER JOIN `lifestyle` on `lifestyle`.`userid` = `user_register`.`id`
WHERE `lifestyle`.`drink` in (2) and
( `locationdetail`.`state_id` in (4121) or `locationdetail`.`country_id` in (38))
In this query how to make bracket inner query in laravel model
Sorry there got distracted
$drinks = [1];
$state_ids = [1,2]
$country_ids = [1,2,3]
$someModel
->join() // enter your joins here
->whereIn('lifestyle.drink', $drinks)
->where(function( $q1 ) use ($state_ids, $country_ids) {
// insert the whereOr queries here against the $q1 using the data in `use` params
})
->get();
To check your query there is a toSql() function you can use in laravel too.
I wan to wirte a join query to connect same table, and without ON, but when i write it in laravel without on it is showing error
$key = DB::table('api_keys as ak')
->join('api_keys as bk','')
->where('ak.api_key', $api_key)->where('ak.user_id',0)
->pluck('api_key');
want to build the below query,
SELECT * FROM `api_keys` as ak
JOIN `api_keys` as bk
WHERE ak.`api_key`=$akey
and ak.`user_id`=$auser
and bk.`user_id`=$bsuer
and bk.`api_key`=$bkey
You must provide an ON clause for the join. More about where ON clauses are required can be found in this answer.
You can view the generated query using toSql() on a QueryBuilder object:
echo $key = DB::table('api_keys as ak')
->join('api_keys as bk','')
->where('ak.api_key', $api_key)->where('ak.user_id',0)
->toSql();
Which in your case returns:
select * from `api_keys` as `ak` inner join `api_keys` as `bk`
on `` `` where `ak`.`api_key` = ? and `ak`.`user_id` = ?
In your case it isn't totally clear what you are trying to achieve, but you might consider joining on api_key or the primary key of the api_keys table, if that is different:
$key = DB::table('api_keys as ak')
->join('api_keys as bk','ak.api_key', '=', bk.api_key)
->where('ak.api_key', $api_key)->where('ak.user_id',0)
->pluck('api_key');
DB::table('registerusers as a')
->join('registerusers as b', 'a.id', 'b.refer_id')
->where('a.username', 'b.username')
->where('b.id', 'a.refer_id')
->value('b.id');
without using on clause in laravel query builder you can use following
$key = DB::table(DB::raw('api_keys as ak, api_keys as bk'))
->where('ak.api_key', '=', $api_key)
->where('ak.user_id','=',0)
->where('ak.PK','=','bk.PK')
->pluck('ak.api_key')
where PK references to your table's primary key.
result will in your case.
select * from api_keys as ak, api_keys as bk where ak.api_key= 'api_key_value' and ak.user_id = 0 and ak.PK = bk.PK
I solved this by creating my own class and starting out with a base query which I modify to apply the join (using Laravel's joinSub function) as follows:
public function __construct()
{
$this->query = DB::table('question_responses as BASE');
}
public function applyFilter($questionId, $questionValue) {
$filterTableStr = 'filter_table_'.$questionId;
$filterIdStr = 'filter_id_'.$questionId;
$filterQuery = DB::table('question_responses AS '.$filterTableStr)
->select('survey_response_id AS '.$filterIdStr)
->where($filterTableStr.'.question_short_name', $questionId)
->where($filterTableStr.'.value', $questionValue);
$resultTableStr = 'result_table_'.$questionId;
$this->query = $this->query
->joinSub($filterQuery, $resultTableStr, function($join) use ($resultTableStr, $filterIdStr) {
$join->on('BASE.survey_response_id', '=', $resultTableStr.'.'.$filterIdStr);
});
}
After applying my required filters I can just call $this->query->get() as normal to obtain the result.
The important part was to make sure that each resulting table and join fields has unique names.
With this method I can apply unlimited filters to my base query.