Split lines in GeoPandas - geopandas

Question

I can find how to split 1 line using geopandas/shapely
def split_line_by_point(line, point, tolerance: float=1.0e-12):
return split(snap(line, point, tolerance), point)
However I can't figure out how to apply this over an entire geometry column while maintaining other values.
Applying the above function to df.geometry loses a bunch of information
How do split a below linestring so that it 'explodes' maintaining 'type' and 'properties' cols?
{"Feature":'Hi',"ID":1,Linestring([1,1],[2,2],[3,3])},
{"Feature":'bye',"ID":2,Linestring([10,10],[20,20],[30,30])}
To
{"Feature":'Hi',"ID":1,Linestring([1,1],[2,2])},
{"Feature":'Hi',"ID":1,Linestring([2,2],[3,3])},
{"Feature":'bye',"ID":2,Linestring([10,10],[20,20])}
{"Feature":'bye',"ID":2,Linestring([20,20],[30,30])}
Lines need to be smaller where length > x

Answer 1

This works for me:
import geopandas
from shapely import geometry
from shapely.ops import split, snap
gdf = geopandas.GeoDataFrame([
{"Feature":'Hi',"ID":1,"geometry": geometry.LineString(([1,1],[2,2],[3,3]))},
{"Feature":'bye',"ID":2, "geometry": geometry.LineString(([10,10],[20,20],[30,30]))}
])
def split_line_by_point(line, point, tolerance: float=1.0e-12):
return split(snap(line, point, tolerance), point)
result = (
gdf
.assign(geometry=gdf.apply(
lambda x: split_line_by_point(
x.geometry,
geometry.Point(x.geometry.coords[1])
), axis=1
))
.explode()
.reset_index(drop=True)
)
Output:
Feature ID geometry
0 Hi 1 LINESTRING (1.00000 1.00000, 2.00000 2.00000)
1 Hi 1 LINESTRING (2.00000 2.00000, 3.00000 3.00000)
2 bye 2 LINESTRING (10.00000 10.00000, 20.00000 20.00000)
3 bye 2 LINESTRING (20.00000 20.00000, 30.00000 30.00000)