I am trying to upload a file in Django using Ajax. I have tried different approaches but I've get same results. The file cannot be read in the view.
Here is my codes:
#JS
$("#upload-file").click(function() {
var data = new FormData($('#fileForm').get(0));
var csrftoken = getCookie('csrftoken');
$.ajax({
type: "POST",
headers: {'X-CSRFToken': csrftoken},
url: "/countwords/",
data: data,
cache: false,
processData: false,
contentType: false,
success: function(json) {
var ss = json.len;
alert(ss);},
error: function() {
alert('error');}
});
});
finally here is my view codes:
if request.method == 'POST':
print request.FILES.keys()
print request.FILES
print request.POST.keys()
But I get following output when the code is run:
[]
MultiValueDict: {}
[]
I am new to codeigniter and Ajax, so please be patient with me.
I am attempting a school assignment in which we have to upload a file to our server. I tried to follow the instructions but I receive the error "You did not select a file to upload." Can someone help me please?
Here is my javascript
function uploadFile(){
data = {};
data['file']= document.getElementById('fileToUpload').files[0];
$.ajax({
url:'/admin/conference/presentation/changes/file',
data: data,
type: 'POST',
contentType: false,
processData: false,
success: function(data){
console.log(data);
}
});}
And here is the code from CI
$config['upload_path'] = FCPATH.'./';
$config['allowed_tyeps'] = '*';
$this->load->library('upload', $config);
if(!$this->upload->do_upload()){
$upload_error = $this->upload->display_errors();
echo $upload_error;
}
What did I do wrong?
CodeIgniter probably needs data in multipart form data which would require a FormData object.
function uploadFile(){
var data = new FormData;
data.append('file', document.getElementById('fileToUpload').files[0]);
$.ajax({
url:'/admin/conference/presentation/changes/file',
data: data,
type: 'POST',
contentType: false,
processData: false,
success: function(data){
console.log(data);
}
});}
Also, specify the name of the file to upload in code igniter
$this->upload->do_upload('file')
Lately I've been trying to solve an issue with no luck, basically I'm trying to submit a form to the server using AJAX, the form has files, so I'm using the FormData javascript object in JQuery 1.12. The data arrives to the server but in I way I don't know how to format it.
This is my AJAX function:
function saveMenu(id){
var formElement = document.getElementById("menu-form");
var formData = new FormData(formElement);
formData.append('_method', 'PUT');
$( "#form-wrapper" ).toggleClass( "be-loading-active" );
$.ajax({
type: 'PUT',
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
},
url: "{{url('myUrl')}}",
data: formData,
enctype: 'multipart/form-data',
processData: false,
success: function(response) {
toastr.success('Yai! Saved successfully!')
},
error: function(response) {
toastr.error('Oh oh! Something went really wrong!')
},
complete: function() {
$( "#form-wrapper" ).toggleClass( "be-loading-active" )
}
});
}
and when I perform a dd($request->all()); in my controller I get something like this:
array:1 [
"------WebKitFormBoundaryRCIAg1VylATQGx46\r\nContent-Disposition:_form-data;_name" => """
"_token"\r\n
\r\n
jtv4bnn8WQnP3eqmKZV3xWka2YOpnNc1pgrIfk0D\r\n
------WebKitFormBoundaryRCIAg1VylATQGx46\r\n
Content-Disposition: form-data; name="blocks[43][title]"\r\n
\r\n
...
Things I've tried:
Set the HTTP verb to POST. Same result.
Set the AJAX contentType: false, contentType: application/json. Empty response.
Remove enctype: 'multipart/form-data'. Same response.
Any help is appreciated.
This fixed it for me
data: form_data,
contentType: false,
processData: false,
processData: false prevents jQuery from parsing the data and throwing an Illegal Invocation error. JQuery does this when it encounters a file in the form and can not convert it to string (serialize it).
contentType: false prevents ajax sending the content type header. The content type header make Laravel handel the FormData Object as some serialized string.
setting both to false made it work for me.
I hope this helps.
$('#my-form').submit(function(e) {
e.preventDefault();
var api_token = $('meta[name="api-token"]').attr('content');
form_data = new FormData(this);
$.ajax({
type: 'POST',
url: '/api/v1/item/add',
headers: {
Authorization: 'Bearer ' + api_token
},
data: form_data,
contentType: false,
processData: false,
success: function(result,status,xhr) {
console.log(result);
},
error: function(xhr, status, error) {
console.log(xhr.responseText);
}
});
});
also remember to use $request->all(); $request->input() excludes the files
I've been trying to debug that for 2 hours and i found out that method PUT is not working with formData properly.
Try changing
type : "PUT"
into
method : "POST"
Then change your method on your backend from put to post and you'll see the difference.
I used below codes to test it
$("#menu-form").submit(function (){
var fd = new FormData();
fd.append('section', 'general');
fd.append('action', 'previewImg');
fd.append('new_image', $('.new_image')[0].files[0]);
$.ajax({
method : 'POST',
headers: {
'X-CSRF-TOKEN': '{{ csrf_token()}}'
},
url: "{{url('upload-now')}}",
data : fd,
contentType: false,
processData: false,
success: function(response) {
console.log(response);
},
});
return false;
});
And in my controller
public function test(Request $request){
dd($request->all());
}
Ill try to research more about this issue.
Laravel 7,
if use method PUT in ajax, you can follow
1. change method method: 'PUT' to method: 'POST'
2. add formdata.append with _method PUT like this example :
$('#updateBtn').click(function(e){
e.preventDefault();
var frm = $('#tambahForm');
frm.trigger("reset");
$('.edit_errorNama_kategori').hide();
$('.edit_errorGambar').hide();
var url = "/pengurus/category/"+$('#edit_id').val();
var formdata = new FormData($("#editForm")[0]);
formdata.append('_method', 'PUT'); //*** here
$.ajax({
method :'POST', //*** here
url : url,
data : formdata,
dataType : 'json',
processData: false,
contentType: false,
success:function(data){
if (data.errors) {
if (data.errors.nama_kategori) {
$('.edit_errorNama_kategori').show();
$('.edit_errorNama_kategori').text(data.errors.nama_kategori);
}
if (data.errors.gambar){
$('.edit_errorGambar').show();
$('.edit_errorGambar').text(data.errors.gambar);
}
}else {
frm.trigger('reset');
$('#editModal').modal('hide');
swal('Success!','Data Updated Successfully','success');
table.ajax.reload(null,false);
}
},
error: function (jqXHR, textStatus, errorThrown) {
alert('Please Reload to read Ajax');
console.log("ERROR : ", e);
}
});
});
its works for me
Finally I gave up trying to make it work and tried a more vanilla approach, I still don't know the reason why the request is formated like that, but the XMLHttpRequest() function works perfectly and the migration is not a big deal.
The equivalent of the function I posted about would be:
function saveMenu(action){
var formElement = document.getElementById("menu-form");
var formData = new FormData(formElement);
formData.append('_token', $('meta[name="csrf-token"]').attr('content'));
var request = new XMLHttpRequest();
request.open("POST", "{{url('myUrl')}}");
request.send(formData);
request.onload = function(oEvent) {
if (request.status == 200) {
toastr.success('Yai! Saved successfully!');
} else {
toastr.error('Oh oh! Something went really wrong!');
}
$( "#form-wrapper" ).toggleClass( "be-loading-active" );
};
}
Bit late, but;
This will solve your problem;
var formData = new FormData(document.getElementById('form'));
console.log(...formData);
var object = {};
formData.forEach(function (value, key) {
object[key] = value;
});
Then you can send this object to the server. This is much more readable and works great.
OR
You can simply send this directly;
JSON.stringify(Object.fromEntries(formData));
This is the newer approach.
And don't give up :-)
when i get multiple objects, it works fine but if i only get 1, it returns an error
views.py
def get_incident_personnel(request):
args = {}
store = Store.objects.get(store_id=request.POST['store'])
data = serializers.serialize('json', store)
return HttpResponse(data, mimetype='application/json')
and here is my ajax.js
$('#id_store').change(function() {
var store = $('#id_store').val();
$.ajax({
url: '/incidents/get_incident_personnel/',
type: 'POST',
dataType: 'json',
data: {
'store': store,
'csrfmiddlewaretoken': $('input[name=csrfmiddlewaretoken]').val()
},
success: function(data) {
console.log(data);
}
});
});
You can't use serializers.serialize on a model instance, only on a QuerySet. Use filter even though you know you're only going to get one object.
store = Store.objects.filter(...)
I have the below that uploads an image using JQuery's AJAX function
var id = <?php echo $id; ?>;
var img_data = new FormData($("form")[0]);
$.ajax({
url: 'add.php',
data: img_data,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});
I'd like to include a string with the FormData sent. I tried the following, but no luck
data: img_data {id: id},
What's the correct syntax here?
Use append
var img_data = new FormData($("form")[0]);
img_data.append('id', id);
You could create a JSON data object and pass that as application/json and process the data within add.php:
var data = {
id : <?php echo !empty($id) ? $id : "''",
img_data : new FormData($("form")[0])
};
$.ajax({
url: 'add.php',
data: data,
contentType: "application/json",
type: 'POST',
success: function(data){
alert(data);
}
});
Although unconventional, you could also append the data as a query string to the URL with the POST. You'd also need to edit add.php to get this parameter.
$.ajax({
url: 'add.php?id=' + id,
data: img_data,
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});