Why is a variable declared outside an if block not accessible? [duplicate] - go

Question

This question already has answers here:
Why does golang compiler think the variable is declared but not used?
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Declared but not used
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How to avoid annoying error "declared and not used"
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Closed 8 months ago.
I use a pattern where a variable is declared outside of an if-block and the block determines the value to assign to it. The compiler does not like the following code and reports: "result declared but not used". It looks proper to me... Please explain what I am misunderstanding.
Thank you for your help,
Mike
func blah() {
var result error = nil // "result declared but not used"
if 1 == 1 {
result = fmt.Errorf("ouch")
}
}

Answer 1

Assigning a value into a variable is not using that variable.
This is also an error (here compiler never read the variable so it's not used) .
var result string // "result declared but not used"
result = "sheikh"
"Every declared variable have to be used" means compiler have to read the value of that variable and use it to perform at least one operation (arithmetic Operation or assignment Operation or Unary Operation or Relational Operation)
This is not an error,
var result int
result+=1
This is not an error,
var result int
result=1
if result == 1 {
}
If you want to avoid this error simply do this,
var result int
result=1
_=result