I need to use two nested lists.
The first is a numeric list and the second is an alphabetical one.
When the second is over and I go to the first list, the numbers are counted from the beginning.
I tried to create a new list createList() but it didn't work
else if (object == ui->textEdit_left && event->type() == QEvent::KeyPress)
{
QTextCursor cursor = ui->textEdit_left->textCursor();
QTextListFormat::Style currentStyle = cursor.currentList()->format().style();
QTextBlockFormat format = cursor.blockFormat();
QKeyEvent *keyEvent = static_cast<QKeyEvent *>(event);
QTextListFormat::Style newStyle = createNewStyle(currentStyle, keyEvent->key());
if (keyEvent->key() == Qt::Key_Return || keyEvent->key() == Qt::Key_Enter)
{
format.setIndent(format.indent() - 1);
cursor.setBlockFormat(format);
cursor.createList(newStyle);
return true;
}
else if (keyEvent->key() == Qt::Key_Tab)
{
format.setIndent(format.indent() + 1);
cursor.setBlockFormat(format);
cursor.createList(newStyle);
return true;
}
else
{
return false;
}
}
return false;
Hi I'm new to MQL5 and I wanted to add a trailing stop loss to my expert advisor but some reason it does not add. Here is the code:
if(PositionSelect(_Symbol) && UseTrailingStop == true)
{
double TrailingStop = (atr[1] * 3) + close[1];
Trail.TrailingStop(_Symbol,TrailingStop,0,0);
}
Please note that close[1] is for the close price of the previous bar and atr[1] is for the value of the average true range. What am i doing wrong?????
There you go: hope this is helpful.
//--- trailing position
for(i=0;i<PositionsTotal();i++)
{
if(Symbol()==PositionGetSymbol(i))
{
if(PositionGetInteger(POSITION_TYPE)==POSITION_TYPE_BUY)
{
sl=MathMax(PositionGetDouble(POSITION_PRICE_OPEN)+Spread*_Point,Bid-SL*_Point);
if(sl>PositionGetDouble(POSITION_SL) && (Bid-StopLevel*_Point-Spread*_Point)>PositionGetDouble(POSITION_PRICE_OPEN))
{
request.action = TRADE_ACTION_SLTP;
request.symbol = _Symbol;
request.sl = NormalizeDouble(sl,_Digits);
request.tp = PositionGetDouble(POSITION_TP);
OrderSend(request,result);
if(result.retcode==10009 || result.retcode==10008) // request executed
Print("Moving Stop Loss of Buy position #",request.order);
else
{
Print(ResultRetcodeDescription(result.retcode));
return;
}
return;
}
}
if(PositionGetInteger(POSITION_TYPE)==POSITION_TYPE_SELL)
{
sl=MathMin(PositionGetDouble(POSITION_PRICE_OPEN)-Spread*_Point,Ask+SL*_Point);
if(sl<PositionGetDouble(POSITION_SL) && (PositionGetDouble(POSITION_PRICE_OPEN)-StopLevel*_Point-Spread*_Point)>Ask)
{
request.action = TRADE_ACTION_SLTP;
request.symbol = _Symbol;
request.sl = NormalizeDouble(sl,_Digits);
request.tp = PositionGetDouble(POSITION_TP);
OrderSend(request,result);
if(result.retcode==10009 || result.retcode==10008) // request executed
Print("Moving Stop Loss of Sell position #",request.order);
else
{
Print(ResultRetcodeDescription(result.retcode));
return;
}
return;
}
}
}
}
Learning Golang and was wondering if there is a shorter way to write this
if tiletype == 0 || tiletype == 2 {
levelmap[passage1block] = "wall"
} else {
levelmap[passage1block] = "floor"
}
Was thinking this would be the way though it does not work
if tiletype ==0,2 {
levelmap[passage1block] = "wall"
} else {
levelmap[passage1block] = "floor"
}
You can write a switch-case statement:
switch tiletype {
case 0,2: levelmap[passage1block]="wall"
default: levelmap[passage1block]="floor"
}
Suppose we've a grid with sortable columns.
If a user clicks on a column, it gets sorted by 'asc', then if a user clicks the column header again, it gets sorted by 'desc', now I want similar functionality when a user clicks the column third time, the sorting is removed, i.e. returned to previous style, the css is changed back to normal/non-italic etc?
Today I was trying to achieve same thing. I've skimmed through SlickGrid code but didn't find any 'Reset' function. So, I've tweaked the slick.grid.js v2.2 a little bit.
Basically you just need to add a new array - 'latestSortColumns' which will store sort columns state (deep copy of internal SlickGrid sortColumns array).
var latestSortColumns = [];
Optionally add new setting to opt-in for sort reset.
var defaults = {
(...),
autoResetColumnSort: false
};
Change setupColumnSort to reset sort after third click on column's header.
function setupColumnSort() {
$headers.click(function (e) {
// temporary workaround for a bug in jQuery 1.7.1 (http://bugs.jquery.com/ticket/11328)
e.metaKey = e.metaKey || e.ctrlKey;
if ($(e.target).hasClass("slick-resizable-handle")) {
return;
}
var $col = $(e.target).closest(".slick-header-column");
if (!$col.length) {
return;
}
var column = $col.data("column");
if (column.sortable) {
if (!getEditorLock().commitCurrentEdit()) {
return;
}
var sortOpts = null;
var i = 0;
for (; i < sortColumns.length; i++) {
if (sortColumns[i].columnId == column.id) {
sortOpts = sortColumns[i];
sortOpts.sortAsc = !sortOpts.sortAsc;
break;
}
}
**if ((e.metaKey || (options.autoResetColumnSort && latestSortColumns[i] != null && latestSortColumns[i].sortAsc === !column.defaultSortAsc)) && options.multiColumnSort) {**
if (sortOpts) {
sortColumns.splice(i, 1);
**latestSortColumns.splice(i, 1);**
}
}
else {
if ((!e.shiftKey && !e.metaKey) || !options.multiColumnSort) {
sortColumns = [];
}
if (!sortOpts) {
sortOpts = { columnId: column.id, sortAsc: column.defaultSortAsc };
sortColumns.push(sortOpts);
} else if (sortColumns.length == 0) {
sortColumns.push(sortOpts);
}
}
setSortColumns(sortColumns);
if (!options.multiColumnSort) {
trigger(self.onSort, {
multiColumnSort: false,
sortCol: column,
sortAsc: sortOpts.sortAsc}, e);
} else {
trigger(self.onSort, {
multiColumnSort: true,
sortCols: $.map(sortColumns, function(col) {
return {sortCol: columns[getColumnIndex(col.columnId)], sortAsc: col.sortAsc };
})}, e);
}
}
});
}
Store new state after every sort change in latestSortColumns:
function setSortColumns(cols) {
sortColumns = cols;
var headerColumnEls = $headers.children();
headerColumnEls
.removeClass("slick-header-column-sorted")
.find(".slick-sort-indicator")
.removeClass("slick-sort-indicator-asc slick-sort-indicator-desc");
$.each(sortColumns, function(i, col) {
if (col.sortAsc == null) {
col.sortAsc = true;
}
var columnIndex = getColumnIndex(col.columnId);
if (columnIndex != null) {
headerColumnEls.eq(columnIndex)
.addClass("slick-header-column-sorted")
.find(".slick-sort-indicator")
.addClass(col.sortAsc ? "slick-sort-indicator-asc" : "slick-sort-indicator-desc");
}
});
**for (var i = 0; i < sortColumns.length; i++)
latestSortColumns[i] = { columnId: sortColumns[i].columnId, sortAsc: sortColumns[i].sortAsc };**
}
That's all, should work now.
This is a function I call to reset all columns back to their original order.
It requires one of columns to be set up as not sortable.
In the example below I use the first column of the table, columns[0], which has the field id "locus".
function removeSorting() {
columns[0].sortable = true;
$('.slick-header-columns').children().eq(0).trigger('click');
columns[0].sortable = false;
// clear other sort columns
grid.setSortColumns( new Array() );
}
Then in the typical dataView.sort() function you make an exception for this column:
grid.onSort.subscribe(function(e,args) {
var cols = args.sortCols;
dataView.sort(function (dataRow1, dataRow2) {
for( var i = 0; i < cols.length; i++ ) {
var field = cols[i].sortCol.field;
// reset sorting to original indexing
if( field === 'locus' ) {
return (dataRow1.id > dataRow2.id) ? 1 : -1;
}
var value1 = dataRow1[field];
var value2 = dataRow2[field];
if( value1 == value2 ) continue;
var sign = cols[i].sortAsc ? 1 : -1;
return (value1 > value2) ? sign : -sign;
}
return 0;
});
});
Will the table always be sorted in some order on some column?
If not then you'll have to store a lot of state the first time a column is clicked just in case you want to restore it after a third click.
Consider a MxN bitmap where the cells are 0 or 1. '1' means filled and '0' means empty.
Find the number of 'holes' in the bitmap, where a hole is a contiguous region of empty cells.
For example, this has two holes:
11111
10101
10101
11111
... and this has only one:
11111
10001
10101
11111
What is the fastest way, when M and N are both between 1 and 8?
Clarification: diagonals are not considered contiguous, only side-adjacency matters.
Note: I am looking for something that takes advantage of the data format. I know how to transform this into a graph and [BD]FS it but that seems overkill.
You need to do connected component labeling on your image. You can use the Two-pass algorithm described in the Wikipedia article I linked above. Given the small size of your problem, the One-pass algorithm may suffice.
You could also use BFS/DFS but I'd recommend the above algorithms.
This seems like a nice use of the disjoint-set data structure.
Convert the bitmap to a 2d array
loop through each element
if the current element is a 0, merge it with the set of one its 'previous' empty neighbors (already visited)
if it has no empty neighbors, add it to its own set
then just count the number of sets
There may be advantages gained by using table lookups and bitwise operations.
For example whole line of 8 pixels may be looked up in 256 element table, so number of holes in a field 1xN is got by single lookup. Then there may be some lookup table of 256xK elements, where K is number of hole configurations in previous line, contatining number of complete holes and next hole configuration. That's just an idea.
I wrote an article describe the answer on Medium https://medium.com/#ahmed.wael888/bitmap-holes-count-using-typescript-javascript-387b51dd754a
but here is the code, the logic isn't complicated and you can understand it without reading the article.
export class CountBitMapHoles {
bitMapArr: number[][];
holesArr: Hole[] = [];
maxRows: number;
maxCols: number;
constructor(bitMapArr: string[] | number[][]) {
if (typeof bitMapArr[0] == 'string') {
this.bitMapArr = (bitMapArr as string[]).map(
(word: string): number[] => word.split('').map((bit: string): number => +bit))
} else {
this.bitMapArr = bitMapArr as number[][]
}
this.maxRows = this.bitMapArr.length;
this.maxCols = this.bitMapArr[0].length;
}
moveToDirection(direction: Direction, currentPosition: number[]) {
switch (direction) {
case Direction.up:
return [currentPosition[0] - 1, currentPosition[1]]
case Direction.down:
return [currentPosition[0] + 1, currentPosition[1]]
case Direction.right:
return [currentPosition[0], currentPosition[1] + 1]
case Direction.left:
return [currentPosition[0], currentPosition[1] - 1]
}
}
reverseDirection(direction: Direction) {
switch (direction) {
case Direction.up:
return Direction.down;
case Direction.down:
return Direction.up
case Direction.right:
return Direction.left
case Direction.left:
return Direction.right
}
}
findNeighbor(parentDir: Direction, currentPosition: number[]) {
let directions: Direction[] = []
if (parentDir === Direction.root) {
directions = this.returnAvailableDirections(currentPosition);
} else {
this.holesArr[this.holesArr.length - 1].positions.push(currentPosition)
directions = this.returnAvailableDirections(currentPosition).filter((direction) => direction != parentDir);
}
directions.forEach((direction) => {
const childPosition = this.moveToDirection(direction, currentPosition)
if (this.bitMapArr[childPosition[0]][childPosition[1]] === 0 && !this.checkIfCurrentPositionExist(childPosition)) {
this.findNeighbor(this.reverseDirection(direction), childPosition)
}
});
return
}
returnAvailableDirections(currentPosition: number[]): Direction[] {
if (currentPosition[0] == 0 && currentPosition[1] == 0) {
return [Direction.right, Direction.down]
} else if (currentPosition[0] == 0 && currentPosition[1] == this.maxCols - 1) {
return [Direction.down, Direction.left]
} else if (currentPosition[0] == this.maxRows - 1 && currentPosition[1] == this.maxCols - 1) {
return [Direction.left, Direction.up]
} else if (currentPosition[0] == this.maxRows - 1 && currentPosition[1] == 0) {
return [Direction.up, Direction.right]
} else if (currentPosition[1] == this.maxCols - 1) {
return [Direction.down, Direction.left, Direction.up]
} else if (currentPosition[0] == this.maxRows - 1) {
return [Direction.left, Direction.up, Direction.right]
} else if (currentPosition[1] == 0) {
return [Direction.up, Direction.right, Direction.down]
} else if (currentPosition[0] == 0) {
return [Direction.right, Direction.down, Direction.left]
} else {
return [Direction.right, Direction.down, Direction.left, Direction.up]
}
}
checkIfCurrentPositionExist(currentPosition: number[]): boolean {
let found = false;
return this.holesArr.some((hole) => {
const foundPosition = hole.positions.find(
(position) => (position[0] == currentPosition[0] && position[1] == currentPosition[1]));
if (foundPosition) {
found = true;
}
return found;
})
}
exec() {
this.bitMapArr.forEach((row, rowIndex) => {
row.forEach((bit, colIndex) => {
if (bit === 0) {
const currentPosition = [rowIndex, colIndex];
if (!this.checkIfCurrentPositionExist(currentPosition)) {
this.holesArr.push({
holeNumber: this.holesArr.length + 1,
positions: [currentPosition]
});
this.findNeighbor(Direction.root, currentPosition);
}
}
});
});
console.log(this.holesArr.length)
this.holesArr.forEach(hole => {
console.log(hole.positions)
});
return this.holesArr.length
}
}
enum Direction {
up = 'up',
down = 'down',
right = 'right',
left = 'left',
root = 'root'
}
interface Hole {
holeNumber: number;
positions: number[][]
}
main.ts file
import {CountBitMapHoles} from './bitmap-holes'
const line = ['1010111', '1001011', '0001101', '1111001', '0101011']
function main() {
const countBitMapHoles = new CountBitMapHoles(line)
countBitMapHoles.exec()
}
main()
function BitmapHoles(strArr) {
let returnArry = [];
let indexOfZ = [];
let subarr;
for(let i=0 ; i < strArr.length; i++){
subarr = strArr[i].split("");
let index = [];
for(let y=0 ; y < subarr.length; y++){
if(subarr[y] == 0)
index.push(y);
if(y == subarr.length-1)
indexOfZ.push(index);
}
}
for(let i=0 ; i < indexOfZ.length; i++){
for(let j=0; j<indexOfZ[i].length ; j++){
if(indexOfZ[i+1] && (indexOfZ[i][j]==indexOfZ[i+1][j] || indexOfZ[i+1].indexOf(indexOfZ[i][j])))
returnArry.indexOf(strArr[i]) < 0 ? returnArry.push(strArr[i]): false;
if(Math.abs(indexOfZ[i][j]-indexOfZ[i][j+1])==1)
returnArry.indexOf(strArr[i]) < 0 ? returnArry.push(strArr[i]): false;
}
}
return returnArry.length;
}
// keep this function call here
console.log(BitmapHoles(readline()));
function findHoles(map) {
let hole = 0;
const isHole = (i, j) => map[i] && map[i][j] === 0;
for (let i = 0; i < map.length; i++) {
for (let j = 0; j < map[i].length; j++) {
if (isHole(i, j)) {
markHole(i, j);
hole++;
}
}
}
function markHole(i, j) {
if (isHole(i, j)) {
map[i][j] = 2;
markHole(i, j - 1);
markHole(i, j + 1);
markHole(i + 1, j);
markHole(i - 1, j);
}
}
return hole;
}