I need to read a json file with multiple linkname and url then create a menu link mapping out of it.
Menu
linkname1: This is a link1
linkname2: This is a link2
Using org.apache.model.rest.RestDefinition method if possible, any idea?
I have to put
#Controller
#RequestMapping("/xxxx")
On the main class
I have to put
#GetMapping()
public static RestDefinition
But it only run in eclipse and it compile with no error, but if you run, you will have error. I just decided to rewrite it all in spring-boot without RestDefinition and old java programs.
Related
Project structure:
Here is the repository (no class exceeds 20 lines of code): https://github.com/MoskovchenkoD/spring5-jokes
Here is the problem: Service implementation isn't used, and 'joke' attribute doesn't get printed on the page (just '123'). Controller's #RequestMapping method is simply ignored or bypassed.
How to fix it? I was following a step-by-step video from generating a project at start.spring.io to launching it.
Much appreciated!
Yet another childish error =(
I moved the Application class one level up and now it works fine.
I am building an app that mostly provide REST services, nothing fancy. since my data consumed by the app can have multiple languages I thought about using the bundle files.
I created 3 files, one with the default file name and another two with specific languages. The files created using intellij IDE I am using.
I followed this guide https://www.baeldung.com/java-resourcebundle however on each run I am getting:
MissingResourceException: Can't find bundle for base name tp_app_strings, locale en_US
I tried numerous articles but none of them seems to resolve the issue.
One fun fact is that if I am using the #Value("classpath:tp_app_strings.properties") on a 'Resource' field I am able to get a reference to that file, so it spring is able to find it.
Additional thing that I tried was to create a WEB-INF directory and place the files there (read it in some article) but still no positive affect
The project structure is quite straight forward:
Spring boot version 2.2 running tomcat.
Any suggeestions would be highly appriciated
You can load the .properties file to the application context using #PropertySource annotation instead using #Value to load the .properties file to a org.springframework.core.io.Resource instance.
The usage;
#Configuration
#PropertySource("classpath:tp_app_strings.properties")
public class DefaultProperties {
#Value("${property1.name}") // Access properties in the above file here using SpringEL.
private String prop1;
#Value("${property2.name}")
private String prop2;
}
You wouldn't need java.util.ResourceBundle access properties this way. Use different or same class to load other .properties files as well.
Update 1:
In order to have the functionality of java.util.ResourceBundle, you can't just use org.springframework.core.io.Resource class. This class or non of it sub-classes don't provide functions to access properties by its name java.util.ResourceBundle whatsoever.
However, if you want a functionality like java.util.ResourceBundle, you could implement something custom like this using org.springframework.core.io.Resource;
#Configuration
public class PropertyConfig {
#Value("classpath:tp_app_strings.properties")
private Resource defaultProperties;
#Bean("default-lang")
public java.util.Properties getDefaultProperties() throws IOException {
Properties props = new Properties();
props.load(defaultProperties.getInputStream());
return props;
}
}
Make sure to follow correct naming convention when define the property file as java.util.Properties#load(InputStream) expect that.
Now you can #Autowire and use this java.util.Properties bean wherever you want just like with java.util.ResourceBundle using java.util.Properties#getProperty(String) or its overloaded counterpart.
I think it's problem of you properties file naming convention. use underline "_" for specifying locale of file like
filename_[languageCode]_[regionCode]
[languageCode] and [regionCode] are two letters standard code that [regionCode] section is optional
about code abbrivation standard take a look on this question
in your case change file name to tp_app_strings_en_US.properties
Updated: to describe the question more clearly
I create a web applicaiton with spring boot and thymeleaf, everything works fine if I open the login page, then login, then head for the management module or reports module sequently.
The proleam occurs when I type the url locahost:8080/send/kf/index(needs to authenticate, but I have open access to all in customized filter) in the browser, the page loads without js and css. In debug mode, I saw /send/kf was unexpectly put into the path like the following. I can get the resource if I access localhost:8080/assets/avatars/avatar.png.
The following is the folder structure I put my static resources. How could /send/kf automatically added into the url, please help me solve this problem. Thanks!
you can use spring.resources.static-locations in your application.properties file
spring.resources.static-locations=classpath:/resources/css/
spring.mvc.static-path-pattern=/resources/**
this is taken form documentation
Note:Static resources, like JavaScript or CSS, can easily be served from your Spring Boot application just be dropping them into the right place in the source code. By default Spring Boot serves static content from resources in the classpath at "/static" (or "/public")
Using /assets/ instead of assets/ fixes the issue, as otherwise it's a relative url that's supposed to get added to the end of existing url.
I find a solution for this question. I don't know how /send/kf is put into the url for the static resources, but I think if I put the controller mapping under the root path, this problem should avoid. As I think, the url is correct and resources can load successfully.
#Controller
public class ManualMessageController {
#Autowired
private MsgTemplateRepository msgTemplateRepository;
#RequestMapping("/manualMsg")
public String manualMsg(Model model){
model.addAttribute("msgTemplateList", msgTemplateRepository.findByStatus(1));
return "manualMessage";
}
}
updated:
The right solution is to use absolute path rather than relative path in the project. So change assets/css to /assets/css works.
i have been strugling since 4 days but did not found the solution for how to bind the url in Spring Boot with gradle.
I have a url as, http://loalhost:8080/blog/post.html?pid=2&ptitle=abc
I want this url to be shown as below with html and (?),
http://localhost:8080/blog/post/2/abc
Is there any way to do that. I don't want to use tucky urlrewriter. All my html files are placed in webapp folder.
Thanks in Advance.
if your have a POST method in your #RestController to create a post blog:
#PostMapping("/blog/post/{pid}/{ptitle}")
public void create(#PathVariable("pid") String pid, #PathVariable("ptitle") String ptitle) {
// a repo save call
}
(I supposed that you use last spring boot version)
I have an empty project created using GGTS, my app runs fine, I can see the views and navigate through them fine.
I need con call a REST api and consume the data provided, I read and added the necessary plug in to the BuildConfig file under the dependencies and then under the plugins section, none of them seem to work.
compile ":rest-client-builder:2.0.0"
I've created a controller, I'm not sure where to add the import here, so I've tried:
package myapp
class UserController {
def index() {
import grails.plugins.rest.client.RestBuilder
String url = "https://foo.com/batch/$id"
def resp = new RestBuilder().get(url) { header 'Authorization', 'Basic base64EncodedUsername&Password' }
render resp
}
but I get the error: unable to resolve class....
The API is returning JSON data, what I;ve done so far is just to create a new Grails project, add controller, add view and then the dependency.
I've cleaned an built the project several times but the error remains.
Thanks for your help.
Import goes at the top
After the package line
And before the class line
Also, depending on your version of grails, you might want to move of ggts... Not sure it's supported any more...
I think that the problem is in your build.gradle dependency definition.
Insert the next line to your build.gradle file and I think that will be helpful:
compile "org.grails.plugins:rest-client-builder:2.1.1"
For more information follow the grails plugin documentation.
Please be aware that all the business logic should be placed in the service layer and not in the controller. It is a best practice to keep your controller lean as possible.
Another best practice is to define the following line:
String url = "https://foo.com/batch/$id"
in the beggining of the controller as static final String
static final String url = "https://foo.com/batch/"
and add the $id when needed in the code.
Here is how that should be called inside the method:
String url = "${url}/{$id}"