Is there a function that will determine the minimum number of matches, that is, the minimum number of criteria met for Criteriaquery like in MatchQuery?
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After reading the documentation, I haven't quite wrapped my head around how the rewrite parameter top_terms_boost_N works.
From the documentation:
Assigns each matching document a relevance score equal to the boost
parameter.
This method changes the original query to a bool query. This bool
query contains a should clause and term query for each matching term.
The final bool query only includes term queries for the top N terms.
You can use this method to avoid exceeding the clause limit in the
indices.query.bool.max_clause_count setting.
Example. Say I'm querying with the string A B C D E F G, and I set N to 2, so top_terms_boost_2 is used as the rewrite parameter.
Does that mean Elastic will take two of the terms from the provided string? E.g. C and F.
How does elastic decide what constitutes a "top" term, is it term frequency?
Why is it important that elastic Assigns each matching document a relevance score equal to the boost parameter?
I required search elastic lets consider trigram tokenizer, then ela, las, ast, sti, tic are words should search and minimum score is 60% is given means at least 3-words should match in result like elast.
Aggregations in Elasticsearch are pretty expensive. Before actually computing aggregations, I would like to find out if an aggregation would have non-zero count.
For eg. say based on my query, N documents are returned. Now I want to find out, if on these N documents, I aggregate over a certain field, will that aggregation have any buckets? If for all documents the field has null value or empty string, it should return false or 0. If even single document has field as non-empty string or non-null value, it should return true or a non-zero number. I don't really care about the count.
Is it possible to do in a way which is much faster than computing aggregation?
I'm using neo4j as a graph database and I want to return from a starting node neighbors of that node, and all the related neighbors to a depth varying from 1 to 3. I'm Doing this but it gets stuck:
Note that it is a large graph.
start n = node(*) where n.NID contains "9606.ENS3"
MATCH (n)-[Rel1*1..3]-(m) RETURN m;
Anyone have a clue of how to do traversals on a graph, and getting a result?
Your question shows an old Cypher syntax. The docs says about the START clause:
The START clause should only be used when accessing legacy indexes. In
all other cases, use MATCH instead (see Section 3.3.1, “MATCH”).
I believe this should work:
MATCH(n)-[Rel1*1..3]->(m)
WHERE n.NID contains "9606.ENS3"
RETURN m
I want to perform an undirected traversal to extract all ids connected through a certain type of relationship
When I perform the following query it returns the values fast enough
MATCH path=(s:Node {entry:"a"})-[:RelType*1..10]-(x:Node)
RETURN collect(distinct ID(x))
However doing
MATCH path=(s:Node {entry:"a"})-[:RelType*]-(x:Node)
RETURN collect(distinct ID(x))
takes an huge amount of time. I suspect that by using * it searches every path from s to x, but since I want only the ids these paths can be discarded. What I really want is an BFS or DFS search to find the connect nodes from s.
Both query returns the exact same result since there are no elements with shortest path higher than 5 (only in the test example !).
Did you add an index for create index on :Node(entry) ?
Also depending on the # of rels per node in your path you get rels^10 (or general rels^steps) paths through your graph that are potentially returned.
Can you try first with a smaller upper limit like 3 and work from there?
Also leaving off the direction really hurts as you then get cycles.
What you can also try to do is:
MATCH path=(s:Node {entry:"a"})-[:RelType*]->(x:Node)
RETURN ID(X)
and stream the results and do the uniqueness in the client
Or this if you don't want to do uniqueness in the client
MATCH path=(s:Node {entry:"a"})-[:RelType*]->(x:Node)
RETURN distinct ID(X)