please help
SELECT CUSTOMER, COUNT(USER_ID) FROM ticket_table GROUP BY CUSTOMER ORDER BY COUNT(USER_ID) DESC LIMIT 10;
for the following query when implemented in the Laravel query builder, what kind of controller is it?
Do you mean like this :
\DB::table('ticket_table')
->selectRaw('customer, count(user_id)')
->groupBy('customer')
->orderBy(\DB::raw('COUNT(user_id)'), 'DESC')
->limit(10);
Related
In Laravel 6.18 I'm trying to figure out how to recreate the following Postgres query.
with data as (
select date_trunc('month', purchase_date) as x_month, date_trunc('year', purchase_date) AS x_year,
sum (retail_value) AS "retail_value_sum"
from coins
where user_email = 'user#email.com' and sold = 0
group by x_month, x_year
order by x_month asc, x_year asc
)
select x_month, x_year, sum (retail_value_sum) over (order by x_month asc, x_year asc rows between unbounded preceding and current row)
from data
I know how to build the main part of the query
$value_of_all_purchases_not_sold = DB::table('coins')
->select(DB::raw('date_trunc(\'month\', purchase_date) AS x_month, date_trunc(\'year\', purchase_date) AS x_year, sum(retail_value) as purchase_price_sum'))
->where('user_email', '=', auth()->user()->email)
->where('sold', '=', 0)
->groupBy('x_month', 'x_year')
->orderBy('x_month', 'asc')
->orderBy('x_year', 'asc')
->get();
but how do you build out the with data as ( and the second select?
I need the data to be cumulative and I'd rather do the calculation in the DB than in PHP.
Laravel doesn't have built-in method(s) for common table expression. You may use a third party package such as this - it has a very good documentation. If you don't want to use an external library, then you need use query builder's select method with bindings such as
$results = DB::select('your-query', ['your', 'bindings']);
return Coin::hydrate($results); // if you want them as collection of Coin instance.
I have two table 1. table_a 2. table_b
And all table have company_id. I want to make relationship among this two table using same company id . Like
select * from table_a left join table_b on table_a.company_id = table_b.company_id;
Please help me out if its really possible. Thank you in advance.
You can use this:
$data = DB::table('table_a')->leftJoin('table_b', 'table_a.company_id', '=', 'table_b.company_id')->get();
Or raw:
$users = DB::table('table_a')
->select(DB::raw('query here'))
->get();
More on:
https://laravel.com/docs/5.7/queries
My Laravel query is not working properly. but MySQL query works fine
Laravel Query :
$data = DB::table(DB::raw('select (sum(case when type="credit" then amount else -amount end)) - (select sum(amount) from total) from report'))
Please refer mysql query in sqlfiidle : http://sqlfiddle.com/#!9/2d0343/9
Rather than try rewrite your MySQL query, let's simplify it and make it more eloquent.
Assuming $data is the overall balance and your model for the report table is called Report then the below should achieve what you are after:
$data = Report::where('type', 'credit')->sum('amount') - Report::where('type', 'debit')->sum('amount');
This will give you the sum of all your credits, minus the sum of all your debits.
I have the following MySQL query which fetches a list of the last 9 authors to write a post and lists them in order of the date of the last post they wrote.
It's working properly but I'd like to re-write it using the Laravel Query Builder. Here is the query at the moment:
$authors = DB::select("
SELECT
`a`.`id`,
`a`.`name`,
`a`.`avatar`,
`a`.`slug` AS `author_slug`,
`p`.`subheading`,
`p`.`title`,
`p`.`slug` AS `post_slug`,
`p`.`summary`,
`p`.`published_at`
FROM
`authors` AS `a`
JOIN
`posts` AS `p`
ON `p`.`id` =
(
SELECT `p2`.`id`
FROM `posts` AS `p2`
WHERE `p2`.`author_id` = `a`.`id`
ORDER BY `p2`.`published_at` DESC
LIMIT 1
)
WHERE
`a`.`online` = 1
ORDER BY
`published_at` DESC
LIMIT 9
");
I understand the basics of using the query builder, but there doesn't appear to be anything in the Laravel docs that allows for me to JOIN a table ON a SELECT.
Can anyone suggest a way that I can write this query using the Laravel Query builder, or perhaps suggest a way that I can rewrite this query to make it easier to structure with the query builder?
Try to do like this
$data = DB::table('authors')
->select(
'a.id',
'a.name',
'a.avatar',
'a.slug AS author_slug',
'p.subheading',
'p.title',
'p.slug AS post_slug',
'p.summary',
p.published_at')
->from('authors AS a')
->join('posts AS p', 'p.id', '=', DB::raw("
(
SELECT p2.id FROM posts AS p2
WHERE p2.author_id = b.id
ORDER BY p2.published_at
DESC LIMIT 1
)"))
->where('a.online', 1)
->limit(9)
->orderBy('p.published_at', 'desc')
->get();
I need to get total count to show in my page.
I can run this & loop through & get the total number
DB::table('table1')
->select((DB::raw('MAX(score)')))
->where('status', 1)
->groupBy('user_id')
->get();
But this query would give me the count in just a single query & I don't need run any extra loop to get the total.
SELECT COUNT( * ) FROM (
SELECT MAX( score ) FROM table1
WHERE status =1
GROUP BY user_id
) AS totalCounter
How am I suppose to run this RAW query in Laravel 4?
Try
DB::statement( 'Your Query' );
or
DB::select( 'Your Query' );
As mentioned by other contributors;-
DB::select('SQL QUERY GOES HERE WITH PARAMETERS ?, ?', array('parameter 1', 'parameter 2'));
The code above should permit raw sql.
However,
DB::table('table1')
->select((DB::raw('MAX(score)')))
->where('status','=', 1)
->groupBy('user_id')
->count();
Should achieve the same effect for the task you seek it for, and is more in tune with laravels philosophy.
DB::select(DB::raw("SQL QUERY CODE HERE"))
Both raw and select are require!
Please see for more info:
Laravel 4: how to run a raw SQL?
Try this
DB::select( DB::raw("SELECT * FROM table_Name WHERE col = :somevariable"), array(
'somevariable' => $someVariable,
));