In which class in the source code of spring-boot or spring is the application.yml or application.properties file processed? - spring

In which class in the source code of spring-boot or spring is the application.yml file or application.properties processed?

For spring boot (version 2.x) the application properties are loaded from the environment into the context via a PropertySourceLoader.
In for example the spring-boot-2.6.3.jar we can find the following file:
META-INF/spring.factories
# PropertySource Loaders
org.springframework.boot.env.PropertySourceLoader=\
org.springframework.boot.env.PropertiesPropertySourceLoader,\
org.springframework.boot.env.YamlPropertySourceLoader
Where PropertiesPropertySourceLoader loads .properties and .xml files, and YamlPropertySourceLoader loads .yml and .yaml.
These are loaded with the SpringFactoriesLoader, which we can see in action in org.springframework.boot.context.config.ConfigFileApplicationListener (deprecated) or org.springframework.boot.context.config.StandardConfigDataLocationResolver (via ConfigDataEnvironmentPostProcessor -> ConfigDataEnvironment -> ConfigDataLocationResolvers) :
this.propertySourceLoaders = SpringFactoriesLoader.loadFactories(PropertySourceLoader.class,
getClass().getClassLoader());
You can read in the ConfigFileApplicationListener JavaDoc that the properties are indeed loaded with this class:
EnvironmentPostProcessor that configures the context environment by loading properties from well known file locations. By default properties will be loaded from 'application.properties' and/or 'application.yml' files in the following locations:
file:./config/
file:./config/*/
file:./
classpath:config/
classpath:
...
If you're interested in context loading from the environment in spring(boot), I suggest you setup your project with maven, download the sources jars, and have a look around in the mentioned factories file. You will find more relevant code in the org.springframework.boot.env and org.springframework.boot.context (config and properties) packages.

You can find your application.yml or application.properties at the src/main/resources. You can have as many as possible configurations for your spring boot application for every case. Lets assume that you have 3 local-profiles like demo, production and server, so you made 3 configuration and assumingyou set for active profile the demo at the application.yml . I hope you get the idea. Its the first thing that actually is running before the springboot is up.
Please look the officials docs !

Related

Spring Boot application to have separated multiple property files

Coming from Play Framework, a handy feature that has helped to organize the application configurations was to use includes (Link) to spilt the various configurations into multiple .conf files as below.
application.conf Content
include "play-http.conf"
include "play-modules.conf"
include "play-i18n.conf"
include "authentication.conf"
include "hbase.conf"
include "custom-caches.conf"
include "custom-filters.conf"
#Any other root level application configurations
Is there an equivalent to this in Spring Boot .properties files?
From Spring 2.4, we can create multiple properties file for each profiles as below.
application-main1.properties
application-sub1.properties
application-sub2.properties
And then in default application.properties file we can group all sub profiles and activate the main profile
spring.profiles.group.main1=sub1,sub2
spring.profiles.active=main1
I am not sure if we can group sub profiles under default profile. You can try out
spring.profiles.group.default=sub1,sub2
This way you don't need to have another file for main profile.
I use yaml configuration files myself but I think that the configuration is mostly similar. You should take a look at the PropertySourcesPlaceholderConfigurer.
I have defined a PropertySourcesPlaceholderConfigurer bean to use a configuration override file located outside of the jar. Anything that is in the override file will be used instead of the default configuration. Anything that is not in the override file is still retrieved from the default configuration file. I think you can create a similar bean to achieve what you are looking for.
Here's my code:
#Bean
static PropertySourcesPlaceholderConfigurer propertySourcesPlaceholderConfigurer() {
var properties = new PropertySourcesPlaceholderConfigurer();
properties.setLocation(new FileSystemResource("./application.yaml"));
properties.setIgnoreResourceNotFound(true);
return properties;
}
For my use case, I only needed to define one properties location, but it is also possible to specify multiple locations:
...
properties.setLocations(Resource... locations);
...
My requirement was simply achieved using the spring.config.import (Link).
I created multiple property files such as hbase.properties, custom-caches.properties etc. And then in my application.properties imported those additional property files as below.
spring.config.import=hbase.properties,custom-caches.properties
#Any other properties in the application.properties file
Thanks

Different YAML configuration file for junit test using an Externalized configuration in Spring Boot

I am following a tutorial on using external configuration files for Spring Boot. I got everything to work exactly as intended but I'm having issues overriding the default YAML config for my tests.
Could someone please point me in the right direction or advice if using '#PropertySource' is the best way to load config files into the project (There is a bunch of properties and I would like to keep the application.yaml as clean as possible)
Project Structure:
src: - main/resources/foo.yml <-- always loads this one
- test/resources/foo.yml <-- never loads
What I tried:
#PropertySource(value = "classpath:foo.yml")
Doesn't load test/resoruces/foo.yml to the classpath
ActiveProfiles()
How I usually change config properties but in this case, it's not a profile so it doesn't work.
Details:
Spring boot: 2.2.7.RELEASE
Try this:
#TestPropertySource(properties = { "spring.config.location=classpath:foo.yml" })

Externalizing configuration for Hibernate Search

I am running hibernate search with spring boot. I have written a working configuration for my application. How ever, i want to externalize my configuration and use ./config/hibernate.properties instead of src/main/resources/hibernate.properties. After copying my properties file to the desired location, i am getting and exception:
nested exception is java.io.FileNotFoundException: class path resource [hibernate.properties] cannot be opened because it does not exist
Anyone with any idea on how i should tell spring to read my configuration file?
Move your configuration to an src/main/resources/application.properties file and prepend spring.jpa.properties. everywhere, so hibernate.dialect will become spring.jpa.properties.hibernate.dialect, for example.
Then you can use Spring features to move your configuration wherever you want. To move it to ./config/application.properties I suppose you will have to add #PropertySource("./config/application.properties") to one of your #Configuration classes, or something similar.
I'm sure you can also keep the hibernate configuration in a separate file (separate from the rest of your application configuration).
See https://docs.spring.io/spring-boot/docs/current/reference/html/boot-features-external-config.html for more details about externalizing configuration in Spring Boot.
For some reason, it seems hibernate-search will prevent application from starting as long as a hibernate.properties configuration file does not exist. After trying for a while without success, i found a work around for my problem.
First, i created an empty hibernate.properties file and place it under src/main/resources.
Secondly, i moved all hibernate-search configurations to application.properties as follows:
spring.jpa.properties.hibernate.search.default.indexmanager = elasticsearch
spring.jpa.properties.hibernate.search.default.elasticsearch.host = http://my-server.com
spring.jpa.properties.hibernate.search.default.elasticsearch.index_schema_management_strategy = CREATE
spring.jpa.properties.hibernate.search.default.elasticsearch.required_index_status = yellow
This way, the application will start and spring will get all configuration from the externalized configuration as documented here.

Create Externalized Configuration in spring-boot along with profiles

I have a spring-boot application with annotations instead of context.xml.
In my src/main/resources folder I have: application-dev.properties and application-test.properties.
which work perfectly for different profiles (while running with VM option like -Dspring.profiles.active=dev)
Now I need to externalize this properties with file in /opt/software/Tomcat8/conf/app.properties
Some props override each other, some don't.
in Tomcat config context.xml I say:
<Environment name="app.properties"
value="file:///opt/software/Tomcat8/conf/app.properties"
type="java.lang.String" override="false"/>
How to use it via JNDI in my application configuring app with no XML but annotations in Spring-bot application class?
I need it to have priority to inner jar properties according to
Link to Spring-boot.doc
One solution I found was to have the vm argument -Dloader.path with the external path when executing the application. Please keep in mind if you're using a fat jar you may need to create the package in Zip model, otherwise it will not work.

Spring Boot profile specific properties

I'm using Sprint Boot, and would like to have multiple profile specific property files. The docs state:
In addition to application.properties files, profile specific
properties can also be defined using the naming convention
application-{profile}.properties.
http://docs.spring.io/spring-boot/docs/current-SNAPSHOT/reference/htmlsingle/#boot-features-external-config-profile-specific-properties
However I have multiple properties files (e.g. db.properties). I'm loading currently load this non-profile specific file as:
#Configuration
#PropertySource( {"classpath:db.properties"} )
class DataSourceConfig {
#Value("db.server") String server;
...
}
How can I combine these two things together, so it loads db-dev.properties like Spring Boot does for application.properties
It sounds like it should be easy, but I can't work out how to do it?!
Java -jar my-spring-boot.jar --spring.profiles.active=test you can set profile.active=your environment via commandline
I just saw that you use #PropertySource. The docs say:
Profile specific variants of both application.properties (or application.yml) and files referenced via #ConfigurationProperties are considered as files are loaded.

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