Problem for working with DTO - Laravel, PHP - laravel

Question

For example I have code like this:
$this->users = $data['data'];
$this->month = $data['month'];
$this->year = $data['year'];
But I need to use DTO. For example I used this function in DTO class:
public function getUsers(): string
{
return $this->users;
}
And as I understand I need to add it to the first code. But I don't understand how to use DTO for my the first code. Can you explain me please?
upd
Now I have:
public function __construct($data, $jobWatcherId)
{
$this->jobWatcherId = $jobWatcherId;
$jobsDTO = new JobsDTO($data['data'], $data['month'], $data['year'],
$data['working_days'], $data['holiday_hours'],
$data['advance_payroll_date'], $data['main_payroll_date']);
}
public function handle()
{
$jobWatcher = JobWatcher::find($this->jobWatcherId);
try {
$startedAt = now();
$jobWatcher->update([
'status_id' => JobWatcherStatusEnum::PROCESSING,
'started_at' => $startedAt,
]);
$redmineService = new RedmineAPIService();
foreach ($jobsDTO->getUsers() as $user) {
}
And for line foreach ($jobsDTO->getUsers() as $user) I have Undefined variable '$jobsDTO'

Answer 1

Your question is a bit unclear, but as I understand it, you want to instantiate a DTO with the above data?
You could have a class like:
class UsersDTO
{
public array $users;
public int $month;
public int $year;
public function __construct(array $users, int $month, int $year)
{
$this->users = $users;
$this->month = $month;
$this->year = $year;
}
public function getUsers(): array
{
return $this->users;
}
public function getMonth(): int
{
return $this->month;
}
public function getYear(): int
{
return $this->year;
}
}
and then somewhere else call:
$usersDTO = new UsersDTO($data['data'], $data['month'], $data['year']);
// Do something with $usersDTO->getUsers();