QueryDSL Null Pointer exception left join unrelated tables - spring-boot

I have got two tables which are unrelated . Below are the entity classes .
UsersStaging
#Entity
#Table(name = "users_staging")
#Data
public class Usersstaging implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO, generator = "native")
#GenericGenerator(name = "native", strategy = "native")
#Column(name = "id", updatable = false, nullable = false)
private Integer id;
#Column(name = "employee_id", length = 10)
private String employeeId;
#Column(name="user_name")
private String userName;
#Column(name = "email")
private String email;
Roles table
#Entity
#Table(name = "user_roles")
#Data
#TypeDefs({ #TypeDef(name = "json", typeClass = JsonType.class) })
public class UserRoles implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Column(name = "employeeId", length = 10)
private String employeeId;
#Column(name = "username")
private String username;
#Type(type = "json")
#Column(name = "roles", columnDefinition = "json")
private List<String> roles;
}
I am trying to write the below query by using left join on username column. Query works fine as long as there are predicates(exp) for UsersStaging table . But if I add a predicate for userRoles table (roleExp) , the query fails .
JPAQuery<UsersStaging> query = new JPAQuery<>(entityManager);
QUsersStaging usersStagingPath = QUsersStaging.usersStaging;
QUserRoles userRolesPath = QUserRoles.userRoles;
BooleanExpression exp = usersStagingPath.legalFirstName
.containsIgnoreCase(criteria.getValue());
BooleanExpression roleExp = userRolesPath.roles.any().eq("SUPERADMIN");
return query
.select(Projections.constructor(UsersStagingDTO.class, usersStagingPath.employeeId,
usersStagingPath.userName, usersStagingPath.email, usersStagingPath.isActive,
usersStagingPath.legalFirstName, usersStagingPath.legalLastName, usersStagingPath.legalFullName,
userRolesPath.roles))
.from(usersStagingPath).leftJoin(userRolesPath).on(usersStagingPath.userName.eq(userRolesPath.username))
.where(exp.and(roleExp)).limit(10).fetch();
}
Getting the below exception
java.lang.NullPointerException: null
at org.hibernate.hql.internal.ast.HqlSqlWalker.createFromJoinElement(HqlSqlWalker.java:432) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.joinElement(HqlSqlBaseWalker.java:4007) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3793) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3671) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:746) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:602) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.collectionFunctionOrSubselect(HqlSqlBaseWalker.java:5020) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.comparisonExpr(HqlSqlBaseWalker.java:4713) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2180) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2108) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.whereClause(HqlSqlBaseWalker.java:841) ~[hibernate-core-5.6.10.Final.jar:5.6.10.Final]

I was able to resolve it . The issue was that roles field is a json type column and JSON_CONTAINS function is not supported by Hibernate yet .
To fix it , I implemented the MetadataBuilderContributor interface .
public class SQLFunctionContributor implements MetadataBuilderContributor {
#Override
public void contribute(MetadataBuilder metadataBuilder) {
metadataBuilder.applySqlFunction("json_contains_key",
new SQLFunctionTemplate(BooleanType.INSTANCE, "JSON_CONTAINS(?1, JSON_QUOTE(?2))"));
}
}
Add the below line in application.properties so that Hibernate can register the contrib SQL function .
spring.jpa.properties.hibernate.metadata_builder_contributor=com.xxx.xxx.utils.SQLFunctionContributor
I modified my query in below way and no issues.
BooleanExpression roleExp = Expressions.booleanTemplate("json_contains_key({0}, {1})", userRolesPath.roles,
Expressions.constant(criteria.getValue())).isTrue();

Related

Sending file and JSON in a many-to-many relationship

I have a model called EPI that has a many to many relationship with Model Images, I am not able to do the #PostMapping for this object.
see my code
EPI Entity:
#Entity
#Data
#NoArgsConstructor
#AllArgsConstructor
#Builder
#Table(name = "EPI")
public class EPI implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "Id_EPI")
private UUID id;
#Column(name = "Nome", nullable = false, length = 100)
private String nome;
#Column(name = "Marca", nullable = false, length = 100)
private String marca;
#Column(name = "CA", nullable = false, length = 100)
private String ca;
#Column(name = "Descricao", nullable = false)
private String descricao;
#Column(name = "Foto")
#ManyToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
#JoinTable(name = "epi_images",
joinColumns = {
#JoinColumn(name = "epi_id")
},
inverseJoinColumns = {
#JoinColumn(name = "image_id")
})
private Set<ImageModel> foto;
#Column(name = "Quantidade", nullable = false)
private Integer quantidade;
}
Image Entity:
#Entity
#Data
#NoArgsConstructor
#AllArgsConstructor
#Builder
#Table(name = "image_model")
public class ImageModel implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private UUID id;
private String name;
#Column(name = "type")
private String type;
#Column(name = "image_data", unique = false, nullable = false, length = 100000)
private byte[] imageData;
}
Controller EPI:
#PostMapping("/addNewEPI")
public ResponseEntity<Object> salvarFEPI(#RequestPart("image")MultipartFile file,
#RequestPart("epiModel") EPI epi) throws IOException {
try {
ImageModel foto = productImageService.uploadImage(file);
epi.setFoto((Set<ImageModel>) foto);
return ResponseEntity.status(HttpStatus.CREATED).body(epiService.save(epi));
} catch (Exception e){
System.out.println(e.getMessage());
return null;
}
Service Image:
public ImageModel uploadImage(MultipartFile file) throws IOException {
ImageModel image = new ImageModel();
image.setName(file.getOriginalFilename());
image.setType(file.getContentType());
image.setImageData(ImageUtility.compressImage(file.getBytes()));
return image;
}
As I am passing the parameters in Postman:
enter image description here
Return from Spring Boot:
enter image description here
If anyone can help me I would be very grateful!
I tried passing the parameters in different ways. I just want it to populate my tables passing the parameters of the EPI entity and the Image file.
enter image description here

Spring-Data-Jpa OneToMany query duplicate ids in the info log?

I don't understand why the ids are duplicated (id_msg, id_pers_acct), that's what's in my Springboot log :
select personneco0_.id_pers_acct as id_pers_1_2_0_,
…
from test.person_account personacc0_ where personacc0_.id_pers_acct=?
select messages0_.id_pers_acct as id_pers_5_1_0_,
messages0_.id_msg as id_msg1_1_0_,
messages0_.id_msg as id_msg1_1_1_,
messages0_.content as content2_1_1_,
messages0_.date as date3_1_1_,
messages0_.id_pers_acct_person_account as id_pers_4_1_1_,
messages0_.id_pers_acct as id_pers_5_1_1_
from test.message messages0_ where messages0_.id_pers_acct=?
In my entity PersonAccount i have this code :
#OneToMany(mappedBy = "sender", fetch = FetchType.LAZY)
public Set<Message> messages = new HashSet <Message>();
In my entity Message i have this code :
#Entity
#Table(name = "MESSAGE", catalog = "TEST")
public class Message implements Serializable{
/**
*
*/
private static final long serialVersionUID = -602563072975023074L;
#Id
#GeneratedValue
#Column(name = "ID_MSG")
Long idMsg;
#Column(name = "CONTENT")
String content;
#Column(name = "DATE")
Date date;
#Column(name = "ID_PERS_ACCT", nullable = false)
Long sender;
#Column(name = "ID_PERS_ACCT_PERSON_ACCOUNT", nullable = false)
Long receiver;
In my RestController, i call this :
#RequestMapping(value = "/users/{id}", method = RequestMethod.GET)
public PersonAccount getUser(#PathVariable Long id) {
return userRepository.getOne(id);
}

QuerySyntaxException in Spring Data JPA custom query

I have a Entity:
#Entity
#Table(name = "story", schema = "")
#Data
public class Story implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "sID", unique = true, nullable = false)
private Long sID;
#Column(name = "vnName", nullable = false)
private String vnName;
#Temporal(TemporalType.TIMESTAMP)
#DateTimeFormat(pattern = "dd-MM-yyyy HH:mm:ss")
#Column(name = "sUpdate", length = 19)
private Date sUpdate;
}
And:
#Entity
#Table(name = "chapter", schema = "")
#Data
public class Chapter implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "chID", unique = true, nullable = false)
private Long chID;
#Column(name = "chName", nullable = false)
private String chName;
#JoinColumn(name = "sID", referencedColumnName = "sID")
#ManyToOne(fetch = FetchType.LAZY)
private Story story;
}
I had created custom pojo to get the latest update story with the latest chapter:
#Data
public class NewStory{
private Story story;
private Chapter chapter;
}
but when I get list :
#Repository
public interface StoryRepository extends CrudRepository<Story, Long> {
#Query(value="SELECT NEW com.apt.truyenmvc.entity.NewStory(s as newstory, c as newchapter)"
+ " FROM story s LEFT JOIN (SELECT * FROM Chapter c INNER JOIN "
+ " (SELECT MAX(c.chID) AS chapterID FROM Story s LEFT JOIN Chapter c ON s.sID = c.sID GROUP BY s.sID) d"
+ " ON c.chID = d.chapterID) c ON s.sID = c.sID order by s.sUpdate desc")
public List<NewStory> getTopView();
}
Error:
Warning error: org.hibernate.hql.internal.ast.QuerySyntaxException: story is not mapped.
Who could help me fix it? Or could it be done in a different way?
The error is pretty self explainatory. And its just a typo in your query. You are using story. And obviously thats not mapped as an Entity.
Fix it to Story

UUID Mapping in hibernate

I have mapped a table to my table and trying to add some values in it. but I am getting errors as below
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'create, delete, read, role_id, update, id) values
(_binary'ØN_WlAs—\niÊnÙ' at line 1
my entities are
RoleSettings.java
#Entity #Table(name = "role_settings")
#Getter #Setter #Data
public class RoleSettings implements Serializable {
private static final long serialVersionUID = 8862104773442047690L;
#Id
#GeneratedValue(generator = "uuid2")
#GenericGenerator(name = "uuid2", strategy = "org.hibernate.id.UUIDGenerator")
private UUID id;
#ManyToOne
#JoinColumn(name = "role_id", referencedColumnName = "id", foreignKey = #ForeignKey(name = "role_settings_iam_role_FK"))
private RoleMaster roleId;
}
RoleMaster.java
#Entity #Table(name = "role")
#Getter #Setter #Data
public class RoleMaster implements Serializable {
private static final long serialVersionUID = 1792968151371176640L;
#Id
#GeneratedValue(generator = "uuid2")
#GenericGenerator(name = "uuid2", strategy = "org.hibernate.id.UUIDGenerator")
private UUID id;
#Column(name = "name", nullable = false, length = 255)
private String name;
}
RoleSettingsRepository.java
public interface RoleSettingsRepository extends JpaRepository<RoleSettings, UUID>{}
RoleSettingsService.java
#Service
Class RoleSettingsService {
#Autowired
private RoleSettingsRepository roleSettingsRepository;
public BaseDTO create(RoleSettings roleSettings) {
BaseDTO response = new BaseDTO();
RoleSettings newRoleSettings = new RoleSettings();
try {
newRoleSettings.setRoleId(roleSettings.getRoleId());
newRoleSettings.setAppAccessId(roleSettings.getAppAccessId());
newRoleSettings.setCreate(roleSettings.getCreate());
newRoleSettings.setUpdate(roleSettings.getUpdate());
newRoleSettings.setRead(roleSettings.getRead());
newRoleSettings.setDelete(roleSettings.getDelete());
roleSettingsRepository.save(newRoleSettings);
response.setStatusCode(200);
} catch (Exception e) {
}
return response;
}
}
RoleSettingsController.java
#RestController
#RequestMapping("/v1/rolesettings")
public class RoleSettingsController {
#Autowired
private RoleSettingsService roleSettingsService;
#PostMapping("/post")
public BaseDTO create(#RequestBody RoleSettings roleSettings) {
BaseDTO response = roleSettingsService.create(roleSettings);
return response;
}
}
my json object
{ "roleId" :{"id": "b2e64c82-ab75-41d3-bb10-e9150f314807"} }
and my roleId is stored in database as type binary(16).
Check in your database data type of the id column. It has to be BINARY(16). And annotate your entity field as:
#Id
#GeneratedValue(generator = "uuid2")
#GenericGenerator(name = "uuid2", strategy = "org.hibernate.id.UUIDGenerator")
#Column(columnDefinition = "BINARY(16)")
private UUID id;
Note that you nned to add a column definition in this case.

Spring JPA: How to insert data to join many tables with #ManytoMany relationship

I'm starting to learn Spring Java Framework . I created some Enity to join 2 Model like my Database. And now I want to insert to Join Table by JpaRepository. What i have to do?
This is my Code (Please fix help me me if something is not right)
Model Users_RoomId to define Composite Primary Key
#Embeddable
public class Users_RoomId implements Serializable {
private static final long serialVersionUID = 1L;
#Column(name = "ID_room", nullable = false)
private String idRoom;
#Column(name = "user_id", nullable = false)
private int idUser;
}
Model Users_Room to join 2 Model Users and Room
#Entity
#Table(name ="bookroom")
public class Users_Room {
#EmbeddedId
private Users_RoomId usersroomId;
#ManyToOne
#MapsId("idRoom")
private Room room;
#ManyToOne
#MapsId("idUser")
private Users users;
#Column(name = "Bookday")
private String bookday;
Model Users and Room I used annotation #OneToMany
Model Users
#Entity
#Table(name = "users")
public class Users implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "user_id", nullable = false)
private int id;
#Column(name = "name", nullable = false)
private String name;
#Column(name = "email")
private String email;
#Column(name = "pass")
private String pass;
#Column(name = "role")
private int role;
#OneToMany(mappedBy = "users")
private List<Users_Room> user;
Model Room
#Entity
#Table(name ="room")
public class Room implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "ID_room", nullable = false)
private String id;
#Column(name = "name_room", nullable = false)
private String name;
#Column(name = "Description")
private String describe;
#ManyToOne
#JoinColumn(name = "ID_status")
private Status status;
#Column(name = "room_image")
private String image;
public Room() {
super();
}
#ManyToOne
#JoinColumn(name = "ID_kind")
private KindRoom kind;
#OneToMany(mappedBy = "room")
private List<Users_Room> rooms;
This is my database
So I don't know how to insert a new bookroom with iduser,idroom and bookday with JPA repository.. It'necessary to write Query in JPARepository or We just need to use method save() to insert data
Thanks everyone
I had same problem and solved with following code. I used method save() to insert data. Following code is 'createRoom' method in 'RoomService.java'.
RoomService.java
private final RoomRepository roomRepository;
private final UserRoomRepository userRoomRepository;
private final UserRepository userRepository;
public RoomService(RoomRepository roomRepository, UserRoomRepository userRoomRepository, UserRepository userRepository) {
this.roomRepository = roomRepository;
this.userRoomRepository = userRoomRepository;
this.userRepository = userRepository;
}
#Transactional
public RoomDto createRoom(Long userId, Long chattingUserId) {
Room room = roomRepository.save(new Room());
room.addUserRoom(userRepository.findById(userId).orElseThrow(()->new NoSuchElementException("No User")));
room.addUserRoom(userRepository.findById(chattingUserId).orElseThrow(()->new NoSuchElementException("No User")));
userRoomRepository.save(new UserRoom(userRepository.findById(userId).orElseThrow(()->new NoSuchElementException("No User")),room));
userRoomRepository.save(new UserRoom(userRepository.findById(chattingUserId).orElseThrow(()->new NoSuchElementException("No User")),room));
RoomDto roomDto = RoomDto.of(room);
return roomDto;
}

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