When I type in the command, give a space before hitting the enter button, it works fine, but it doesn't work if there is no space
I have tried several ways to fix this, but have been unable to
import (
"bufio"
"fmt"
"os"
"strings"
)
func main() {
var notes []string
for {
fmt.Print("Enter a command and data: ")
reader := bufio.NewReader(os.Stdin)
line, _ := reader.ReadString('\n')
var joinedNote string
var note []string
splittedString := strings.Split(line, " ")
if splittedString[0] == "create" && len(splittedString) > 1 {
i := 1
for ; i < len(splittedString); i++ {
note = append(note, splittedString[i])
}
joinedNote = strings.Join(note, "")
notes = append(notes, joinedNote)
fmt.Println("[OK] The note was successfully created")
}
if splittedString[0] == "list" || string(line) == "list" {
for i, noteList := range notes {
newNote := strings.TrimSpace(noteList)
fmt.Printf("[Info] %d: %s!\n", i, newNote)
}
}
if splittedString[0] == "clear" || line == "clear" {
notes = nil
fmt.Println("[OK] All notes were successfully deleted")
}
if splittedString[0] == "exit" || line == "exit" {
fmt.Println("[Info] Bye!")
os.Exit(0)
}
}
}
The reason for this is that you are including the \n in line you capture from the user and without the space after it, the \n gets tagged onto the word you are looking for ( create\n does not equal create ). Easiest way to fix this is to manually remove the trailing \n with line = line[:len(line)-1].
Here is a little more a deep dive. First the ReadString method says it included the delimiter, in this case \n, you give it:
ReadString reads until the first occurrence of delim in the input, returning a string containing the data up to and including the delimiter. So we know line will always have the \n at the end of it unless you manually remove it.
Your code worked when the word was followed by a space because your strings.Split(line," ") turned the input create \n into {"create","\n"}.
Related
Label values in Kubernetes need to be valid.
See IsValidLabelValue()
For example the input I receive from a rest-API of a provider, which I want to write to a label: Dedicated Server 1U.
Is there a way to generate a valid label via Go from an arbitrary string?
you can have a function to do this, for example:
func generateLabel(input string) string {
input = strings.Replace(input, " ", "-", -1)
return "api-label=" + input
}
the function replaces the spaces in the received string to "-"
you can change the key to any string you like.
you can also add a regex check to make sure that the generated value complies with the label constraints. (this depends if any special characters are being received from the API)
To accept the string even when there are unwanted characters, check the below:
package main
import (
"regexp"
"strings"
"fmt"
)
func generateLabel(input string) string {
input = strings.Replace(input, " ", "-", -1)
re := regexp.MustCompile("[^a-zA-Z0-9-]")
input = re.ReplaceAllString(input, "")
re = regexp.MustCompile("^[^a-zA-Z0-9]([-a-zA-Z0-9]*[a-zA-Z0-9])?$")
input = re.ReplaceAllString(input, "")
return "api-label=" + input
}
func main() {
label := generateLabel("Dedicated Server 1U")
fmt.Println(label) // Output: "api-label=Dedicated-Server-1U"
label1 := generateLabel("Dedicated&test")
fmt.Println(label1) // Output: "api-label=Dedicatedtest"
label2 := generateLabel("Dedicated,test##&(*!great")
fmt.Println(label2) // Output: "api-label=Dedicatedtestgreat"
}
I can use the below code to search if the text str contains any or both of the keys, i.e.if it contains "MS" or "dynamics" or both of them
package main
import (
"fmt"
"regexp"
)
func main() {
keys := []string{"MS", "dynamics"}
keysReg := fmt.Sprintf("(%s %s)|%s|%s", keys[0], keys[1], keys[0], keys[1]) // => "(MS dynamics)|MS|dynamics"
fmt.Println(keysReg)
str := "What is MS dynamics, is it a product from MS?"
re := regexp.MustCompile(`(?i)` + keysReg)
matches := re.FindAllString(str, -1)
fmt.Println("We found", len(matches), "matches, that are:", matches)
}
I want the user to enter his phrase, so I trim unwanted words and characters, then doing the search as per above.
Let's say the user input was: This,is,a,delimited,string and I need to build the keys variable dynamically to be (delimited string)|delimited|string so that I can search for my variable str for all the matches, so I wrote the below:
s := "This,is,a,delimited,string"
t := regexp.MustCompile(`(?i),|\.|this|is|a`) // backticks are used here to contain the expression, (?i) for case insensetive
v := t.Split(s, -1)
fmt.Println(len(v))
fmt.Println(v)
But I got the output as:
8
[ delimited string]
What is the wrong part in my cleaning of the input text, I'm expecting the output to be:
2
[delimited string]
Here is my playground
To quote the famous quip from Jamie Zawinski,
Some people, when confronted with a problem, think "I know, I'll use regular expressions." Now they have two problems.
Two things:
Instead of trying to weed out garbage from the string ("cleaning" it), extract complete words from it instead.
Unicode is a compilcated matter; so even after you have succeeded with extracting words, you have to make sure your words are properly "escaped" to not contain any characters which might be interpreted as RE syntax before building a regexp of them.
package main
import (
"errors"
"fmt"
"regexp"
"strings"
)
func build(words ...string) (*regexp.Regexp, error) {
var sb strings.Builder
switch len(words) {
case 0:
return nil, errors.New("empty input")
case 1:
return regexp.Compile(regexp.QuoteMeta(words[0]))
}
quoted := make([]string, len(words))
for i, w := range words {
quoted[i] = regexp.QuoteMeta(w)
}
sb.WriteByte('(')
for i, w := range quoted {
if i > 0 {
sb.WriteByte('\x20')
}
sb.WriteString(w)
}
sb.WriteString(`)|`)
for i, w := range quoted {
if i > 0 {
sb.WriteByte('|')
}
sb.WriteString(w)
}
return regexp.Compile(sb.String())
}
var words = regexp.MustCompile(`\pL+`)
func main() {
allWords := words.FindAllString("\tThis\v\x20\x20,\t\tis\t\t,?a!,¿delimited?,string‽", -1)
re, err := build(allWords...)
if err != nil {
panic(err)
}
fmt.Println(re)
}
Further reading:
https://pkg.go.dev/regexp/syntax
https://pkg.go.dev/regexp#QuoteMeta
https://pkg.go.dev/unicode#pkg-variables and https://pkg.go.dev/unicode#Categories
How can I extract only email addresses from a long string in Golang? For example:
"a bunch of irrelevant text fjewiwofjfjvnvkdlslsosiejwoqlwpwpwo
mail=jim.halpert#gmail.com,ou=f,c=US
mail=apple.pie#gmail.com,ou=f,c=US
mail=hello.world#gmail.com,ou=f,c=US
mail=alex.alex#gmail.com,ou=f,c=US
mail=bob.jim#gmail.com,ou=people,ou=f,c=US
mail=arnold.schwarzenegger#gmail.com,ou=f,c=US"
This would return a list of all the emails:
[jim.halpert#gmail.com, apple.pie#gmail.com, etc...]
Each email address would begin with "mail=" and end with a comma ",".
For this you need to breakdown the long go string into parts that you need. You can do filtration and searching using Regular Expressions to match the email pattern you see above.
Here's a piece of code using Regular Expressions to first obtain the section with "mail=" then further format the email removing the trailing ,
import (
"fmt"
"regexp"
"strings"
)
func main() {
var re = regexp.MustCompile(`(?m)mail=[A-Za-z.#0-9]+\,`)
var str = `a bunch of irrelevant text fjewiwofjfjvnvkdlslsosiejwoqlwpwpwo
mail=jim.halpert#gmail.com,ou=f,c=US
mail=apple.pie#gmail.com,ou=f,c=US
mail=hello.world#gmail.com,ou=f,c=US
mail=alex.alex#gmail.com,ou=f,c=US
mail=bob.jim#gmail.com,ou=people,ou=f,c=US
mail=arnold.schwarzenegger#gmail.com,ou=f,c=US`
for i, match := range re.FindAllString(str, -1) {
fmt.Println(match, "found at index", i)
email := strings.Split(match, "=")[1]
email = strings.ReplaceAll(email, ",", "")
fmt.Print(email)
}
}
while i agree with the comment from user datenwolf here is another version which does not involve regular expressions.
It also handle more complex emails format including comma within the local parts. Something uneasy to implement using regexp.
see https://stackoverflow.com/a/2049510/11892070
import (
"bufio"
"fmt"
"strings"
)
var str = `a bunch of irrelevant text fjewiwofjfjvnvkdlslsosiejwoqlwpwpwo
mail=jim.halpert#gmail.com,ou=f,c=US
mail=apple.pie#gmail.com,ou=f,c=US
mail=hello.world#gmail.com,ou=f,c=US
mail=alex.alex#gmail.com,ou=f,c=US
mail=bob.jim#gmail.com,ou=people,ou=f,c=US
mail=arnold.schwarzenegger#gmail.com,ou=f,c=US
mail=(comented)arnold.schwarzenegger#gmail.com,ou=f,c=US
mail="(with comma inside)arnold,schwarzenegger#gmail.com",ou=f,c=US
mail=nocommaatall#gmail.com`
func main() {
var emails []string
sc := bufio.NewScanner(strings.NewReader(str))
for sc.Scan() {
t := sc.Text()
if !strings.HasPrefix(t, "mail=") {
continue
}
t = t[5:]
// Lookup for the next comma after the #.
at := strings.Index(t, "#")
comma := strings.Index(t[at:], ",")
if comma < 0 {
email := strings.TrimSpace(t)
emails = append(emails, email)
continue
}
comma += at
email := strings.TrimSpace(t[:comma])
emails = append(emails, email)
}
for _, e := range emails {
fmt.Println(e)
}
}
You can use this package to do that :
https://github.com/hamidteimouri/htutils/blob/main/htregex/htregex.go
// Emails finds all email strings
func Emails(text string) []string {
return match(text, EmailsRegex)
}
you can use an original package from golang is regexp.Compile or regexp.MustCompile
r, _ := regexp.Compile(regexEmail)
newVariable := `a bunch of irrelevant text fjewiwofjfjvnvkdlslsosiejwoqlwpwpwo
mail=jim.halpert#gmail.com,ou=f,c=US
mail=apple.pie#gmail.com,ou=f,c=US
mail=hello.world#gmail.com,ou=f,c=US
mail=alex.alex#gmail.com,ou=f,c=US
mail=bob.jim#gmail.com,ou=people,ou=f,c=US
mail=arnold.schwarzenegger#gmail.com,ou=f,c=US`
fmt.Printf("%#v\n", r.FindStringSubmatch(newVariable))
fmt.Printf("%#v\n", r.SubexpNames())
I am trying to add a bunch of values in a map data type and after that trying to print it out. But it is performing strangely. When I am directly calling the map with the key it is giving me the correct output but not giving me any output when I am storing the key in a variable and then calling it. I am not been able to figure it out what is happening and why am I getting this kind of output. Can Somebody help me with the same.
package main
import (
"bufio"
"fmt"
"os"
)
func main(){
type Authentication struct {
password string
}
var authentication = map[string]Authentication{}
var user1 Authentication
user1.password = "abc"
authentication["def"] = user1
reader := bufio.NewReader(os.Stdin)
usid := readString(reader)
fmt.Println(authentication)
fmt.Println(authentication[usid])
fmt.Println(authentication["def"])
}
// Reading input functions
func readString(reader *bufio.Reader) string {
s, _ := reader.ReadString('\n')
for i := 0; i < len(s); i++ {
if s[i] == '\n' {
return s[:i]
}
}
return s
}
Input:
def
Output:
map[def:{abc}]
{abc}
You're trying to do the same thing twice in readString. But all you have to do is to cut it by one byte.
func readString(reader *bufio.Reader) string {
s, _ := reader.ReadString('\n')
return s[:len(s)-1]
}
The program in the question does not work when \r\n is used as the line terminator in stdin. The program removes the trailing \n from the line, but not the \r.
Fix by using bufio.Scanner instead of bufio.Reader to read lines from the input. The bufio.Scanner type removes line terminators.
func main() {
type Authentication struct {
password string
}
var authentication = map[string]Authentication{}
var user1 Authentication
user1.password = "abc"
authentication["def"] = user1
scanner := bufio.NewScanner(os.Stdin)
if !scanner.Scan() {
log.Fatal(scanner.Err())
}
usid := scanner.Text()
fmt.Println(authentication)
fmt.Println(authentication[usid])
fmt.Println(authentication["def"])
}
There can always be a better way of reading string, but I see your code works too. I ran it in my local and it gives the expected output:
From your description, I presume you are using go playground or any such platform. If that is so, the thing is, go playground doesn't take standard input, and your code has reader on os.Stdin. When I copy your code to playground and add the following line to check,
fmt.Printf("Length of usid: %d\nusid: %q\n", len(usid), usid)
I see the following output:
Length of usid: 0
usid: ""
Conclusion: There is no issue with variables, map or code, but just the stdin.
I'm writing a small pragram to number the paragraph:
put paragraph number in front of each paragraph in the form of [1]..., [2]....
Article title should be excluded.
Here is my program:
package main
import (
"fmt"
"io/ioutil"
)
var s_end = [3]string{".", "!", "?"}
func main() {
b, err := ioutil.ReadFile("i_have_a_dream.txt")
if err != nil {
panic(err)
}
p_num, s_num := 1, 1
for _, char := range b {
fmt.Printf("[%s]", p_num)
p_num += 1
if char == byte("\n") {
fmt.Printf("\n[%s]", p_num)
p_num += 1
} else {
fmt.Printf(char)
}
}
}
http://play.golang.org/p/f4S3vQbglY
I got this error:
prog.go:21: cannot convert "\n" to type byte
prog.go:21: cannot convert "\n" (type string) to type byte
prog.go:21: invalid operation: char == "\n" (mismatched types byte and string)
prog.go:25: cannot use char (type byte) as type string in argument to fmt.Printf
[process exited with non-zero status]
How to convert string to byte?
What is the general practice to process text? Read in, parse it by byte, or by line?
Update
I solved the problem by converting the buffer byte to string, replacing strings by regular expression. (Thanks to #Tomasz Kłak for the regexp help)
I put the code here for reference.
package main
import (
"fmt"
"io/ioutil"
"regexp"
)
func main() {
b, err := ioutil.ReadFile("i_have_a_dream.txt")
if err != nil {
panic(err)
}
s := string(b)
r := regexp.MustCompile("(\r\n)+")
counter := 1
repl := func(match string) string {
p_num := counter
counter++
return fmt.Sprintf("%s [%d] ", match, p_num)
}
fmt.Println(r.ReplaceAllStringFunc(s, repl))
}
Using "\n" causes it to be treated as an array, use '\n' to treat it as a single char.
A string cannot be converted into a byte in a meaningful way. Use one of the following approaches:
If you have a string literal like "a", consider using a rune literal like 'a' which can be converted into a byte.
If you want to take a byte out of a string, use an index expression like myString[42].
If you want to interpret the content of a string as a (decimal) number, use strconv.Atoi() or strconv.ParseInt().
Please notice that it is customary in Go to write programs that can deal with Unicode characters. Explaining how to do this would be too much for this answer, but there are tutorials out there which explain what kind of things to pay attention to.