I want to find all files with certain name (Myfile.txt) that do not contain certain string (my-wished-string) and then do a sed in order to do a replace in the found files. I tried with:
find . -type f -name "Myfile.txt" -exec grep -H -E -L "my-wished-string" {} + | sed 's/similar-to-my-wished-string/my-wished-string/'
But this only displays me all files with wished name that miss the "my-wished-string", but does not execute the replacement. Do I miss here something?
With a for loop and invoking a shell.
find . -type f -name "Myfile.txt" -exec sh -c '
for f; do
grep -H -E -L "my-wished-string" "$f" &&
sed -i "s/similar-to-my-wished-string/my-wished-string/" "$f"
done' sh {} +
You might want to add a -q to grep and -n to sed to silence the printing/output to stdout
You can do this by constructing two stacks; the first containing the files to search, and the second containing negative hits, which will then be iterated over to perform the replacement.
find . -type f -name "Myfile.txt" > stack1
while read -r line;
do
[ -z $(sed -n '/my-wished-string/p' "${line}") ] && echo "${line}" >> stack2
done < stack1
while read -r line;
do
sed -i "s/similar-to-my-wished-string/my-wished-string/" "${line}"
done < stack2
With some versions of sed, you can use -i to edit the file. But don't pipe the list of names to sed, just execute sed in the find:
find . -type f -name Myfile.txt -not -exec grep -q "my-wished-string" {} \; -exec sed -i 's/similar-to-my-wished-string/my-wished-string/g' {} \;
Note that any file which contains similar-to-my-wished-string also contains the string my-wished-string as a substring, so with these exact strings the command is a no-op, but I suppose your actual strings are different than these.
I have a directory $dir that contains .txt.xy files and subdirectories with .txt.xy files. I try to iterate over each file and pass the whole path as well as the path without $dir as argument to a program like this:
dir="/path/to/"
suffix=".xy"
find "$dir" -name "*.txt.xy" -print0 | xargs -0 -I {} sh -c 'program "$1" |
subprogram filename="$2"' _ {} "$(echo {} | sed -e "s#^${dir}##" -e "s#${suffix}\$##")"
$1 shold be the full path (e.g. /path/to/subdir/file.txt.xy)
$2 should be the full path without $dir and $suffix (e.g. subdir/file.txt)
$1 is the propper full path but $2 is also the full path as if the pipe in $(...) is never executed. What am I missing here?
Your attempt seems rather roundabout. It sounds like you are looking for
find /path/to -name "*.txt.xy" -exec sh -c '
for f; do
g=${f##*/}
program "$f" | subprogram filename="${g%.xy}"
done' _ {} +
If you really need your parameters to be in variables, maybe pass in the suffix as $0 which isn't used for anything useful here anyway. It's a bit obscure, but helps avoid the mess you had with double quotes.
find /path/to -name "*.txt.xy" -exec sh -c '
for f; do
g=${f##*/}
program "$f" | subprogram filename="${g%"$0"}"
done' ".xy" {} +
The above simply trims g to the basename which I guess on closer reading you don't want. So pass /path/to in $0 instead, and hardcode .xy inside:
find /path/to -name "*.txt.xy" -exec sh -c '
for f; do
g=${f#"$0"/}
program "$f" | subprogram filename="${g%.xy}"
done' "/path/to" {} +
or if you really need both to be command-line parameters,
dir="/path/to"
suffix=".xy"
find "$dir" -name "*.txt$suffix" -exec sh -c '
suffix=$1
shift
for f; do
g=${f#"$0"/}
program "$f" | subprogram filename="${g%"$suffix"}"
done' "$dir" "$suffix" {} +
One reason for the failure, is that the command substitution with xargs under double quotes is expanded by the shell even before the former is executed. One way to avoid that would be to do the whole substitution inside the sub-shell created by sh -c as
find "$dir" -name "*.txt.xy" -print0 |
xargs -0 -I {} sh -c '
f="{}"
g="$(echo "$f" | sed -e 's|"'^"${dir}"'"||' -e 's|"'\\"${suffix}"$'"||' )"
program "$f" | subprogram filename="$g"
'
How do I properly escape the path to come out of find to a new command argument?
#!/bin/bash
for f in $(find . -type f -name '*.flac')
do
if flac -cd "$f" | lame -bh 320 - "${f%.*}".mp3; then
rm -f "$f"
echo "removed $f"
fi
done
returns
lame: excess arg Island of the Gods - 3.mp3
Using a Bash for loop is not ideal for the results of find or ls. There are other ways to do it.
You may want to use -print0 and xargs to avoid word splitting issues.
$ find [path] -type f -name *.flac -print0 | xargs -0 [command line {xargs puts in fn}]
Or use -exec primary in find:
$ find [path] -type f -name *.flac -exec [process {find puts in fn}] \;
Alternative, you can use a while loop:
find [path] -type f -name *.flac | while IFS= read -r fn; do # fn not quoted here...
echo "$fn" # QUOTE fn here!
# body of your loop
done
I wrote this command:
find -exec test -e "{}/meta" ";" -exec du -h -t 500M {} ";"
It checks if file meta is in location and if it's whole location bigger than 500MB. Now I want to read first line of this meta file. I tried with this
find -exec test -e "{}/meta" ";" -exec test du -h -t 500M {} ";" -exec sed '1q;d' {}/meta ";"
or this
find -exec test -e "{}/meta" ";" -exec du -h -t 500M {} ";" -exec head -n 1 {}/meta ";"
But it ignores du and read line from every meta file.
How it should looks like?
After a try with find . -type d -size +500M, it appears that the -size option applied to directory does not check its total file size.
Searching for the desired file and checking its directory size should be the better approach:
find . -type f -name 'meta' -execdir bash -c 's=$(du -sh .); [[ "${s%M*}" -gt "500" ]] && sed "1q" meta' \;
I would actually use a while loop in bash for this, like that:
find -type d | \
while IFS= read -r dir; do
if (($(du -ms -- "$dir" | cut -f1) >= 500)); then
[[ -e "$dir/meta" ]] && head -n1 "$dir/meta"
fi
done
I am also not relying on the -t flag of du because it only affects the output, not the status code of `du, so I just use a simple arithmetic comparison in bash instead.
Another approach would be to use -execdir:
find -name meta -type f -execdir bash -c 's=($(du -s .)) ; (( s > 2000 ))' \; -exec head -n1 {} \;
I am trying to use find -exec with multiple commands without any success. Does anybody know if commands such as the following are possible?
find *.txt -exec echo "$(tail -1 '{}'),$(ls '{}')" \;
Basically, I am trying to print the last line of each txt file in the current directory and print at the end of the line, a comma followed by the filename.
find accepts multiple -exec portions to the command. For example:
find . -name "*.txt" -exec echo {} \; -exec grep banana {} \;
Note that in this case the second command will only run if the first one returns successfully, as mentioned by #Caleb. If you want both commands to run regardless of their success or failure, you could use this construct:
find . -name "*.txt" \( -exec echo {} \; -o -exec true \; \) -exec grep banana {} \;
find . -type d -exec sh -c "echo -n {}; echo -n ' x '; echo {}" \;
One of the following:
find *.txt -exec awk 'END {print $0 "," FILENAME}' {} \;
find *.txt -exec sh -c 'echo "$(tail -n 1 "$1"),$1"' _ {} \;
find *.txt -exec sh -c 'echo "$(sed -n "\$p" "$1"),$1"' _ {} \;
Another way is like this:
multiple_cmd() {
tail -n1 $1;
ls $1
};
export -f multiple_cmd;
find *.txt -exec bash -c 'multiple_cmd "$0"' {} \;
in one line
multiple_cmd() { tail -1 $1; ls $1 }; export -f multiple_cmd; find *.txt -exec bash -c 'multiple_cmd "$0"' {} \;
"multiple_cmd()" - is a function
"export -f multiple_cmd" - will export it so any other subshell can see it
"find *.txt -exec bash -c 'multiple_cmd "$0"' {} \;" - find that will execute the function on your example
In this way multiple_cmd can be as long and as complex, as you need.
Hope this helps.
There's an easier way:
find ... | while read -r file; do
echo "look at my $file, my $file is amazing";
done
Alternatively:
while read -r file; do
echo "look at my $file, my $file is amazing";
done <<< "$(find ...)"
Extending #Tinker's answer,
In my case, I needed to make a command | command | command inside the -exec to print both the filename and the found text in files containing a certain text.
I was able to do it with:
find . -name config -type f \( -exec grep "bitbucket" {} \; -a -exec echo {} \; \)
the result is:
url = git#bitbucket.org:a/a.git
./a/.git/config
url = git#bitbucket.org:b/b.git
./b/.git/config
url = git#bitbucket.org:c/c.git
./c/.git/config
I don't know if you can do this with find, but an alternate solution would be to create a shell script and to run this with find.
lastline.sh:
echo $(tail -1 $1),$1
Make the script executable
chmod +x lastline.sh
Use find:
find . -name "*.txt" -exec ./lastline.sh {} \;
Thanks to Camilo Martin, I was able to answer a related question:
What I wanted to do was
find ... -exec zcat {} | wc -l \;
which didn't work. However,
find ... | while read -r file; do echo "$file: `zcat $file | wc -l`"; done
does work, so thank you!
1st answer of Denis is the answer to resolve the trouble. But in fact it is no more a find with several commands in only one exec like the title suggest. To answer the one exec with several commands thing we will have to look for something else to resolv. Here is a example:
Keep last 10000 lines of .log files which has been modified in the last 7 days using 1 exec command using severals {} references
1) see what the command will do on which files:
find / -name "*.log" -a -type f -a -mtime -7 -exec sh -c "echo tail -10000 {} \> fictmp; echo cat fictmp \> {} " \;
2) Do it: (note no more "\>" but only ">" this is wanted)
find / -name "*.log" -a -type f -a -mtime -7 -exec sh -c "tail -10000 {} > fictmp; cat fictmp > {} ; rm fictmp" \;
I usually embed the find in a small for loop one liner, where the find is executed in a subcommand with $().
Your command would look like this then:
for f in $(find *.txt); do echo "$(tail -1 $f), $(ls $f)"; done
The good thing is that instead of {} you just use $f and instead of the -exec … you write all your commands between do and ; done.
Not sure what you actually want to do, but maybe something like this?
for f in $(find *.txt); do echo $f; tail -1 $f; ls -l $f; echo; done
should use xargs :)
find *.txt -type f -exec tail -1 {} \; | xargs -ICONSTANT echo $(pwd),CONSTANT
another one (working on osx)
find *.txt -type f -exec echo ,$(PWD) {} + -exec tail -1 {} + | tr ' ' '/'
A find+xargs answer.
The example below finds all .html files and creates a copy with the .BAK extension appended (e.g. 1.html > 1.html.BAK).
Single command with multiple placeholders
find . -iname "*.html" -print0 | xargs -0 -I {} cp -- "{}" "{}.BAK"
Multiple commands with multiple placeholders
find . -iname "*.html" -print0 | xargs -0 -I {} echo "cp -- {} {}.BAK ; echo {} >> /tmp/log.txt" | sh
# if you need to do anything bash-specific then pipe to bash instead of sh
This command will also work with files that start with a hyphen or contain spaces such as -my file.html thanks to parameter quoting and the -- after cp which signals to cp the end of parameters and the beginning of the actual file names.
-print0 pipes the results with null-byte terminators.
for xargs the -I {} parameter defines {} as the placeholder; you can use whichever placeholder you like; -0 indicates that input items are null-separated.
I found this solution (maybe it is already said in a comment, but I could not find any answer with this)
you can execute MULTIPLE COMMANDS in a row using "bash -c"
find . <SOMETHING> -exec bash -c "EXECUTE 1 && EXECUTE 2 ; EXECUTE 3" \;
in your case
find . -name "*.txt" -exec bash -c "tail -1 '{}' && ls '{}'" \;
i tested it with a test file:
[gek#tuffoserver tmp]$ ls *.txt
casualfile.txt
[gek#tuffoserver tmp]$ find . -name "*.txt" -exec bash -c "tail -1 '{}' && ls '{}'" \;
testonline1=some TEXT
./casualfile.txt
Here is my bash script that you can use to find multiple files and then process them all using a command.
Example of usage. This command applies a file linux command to each found file:
./finder.sh file fb2 txt
Finder script:
# Find files and process them using an external command.
# Usage:
# ./finder.sh ./processing_script.sh txt fb2 fb2.zip doc docx
counter=0
find_results=()
for ext in "${#:2}"
do
# #see https://stackoverflow.com/a/54561526/10452175
readarray -d '' ext_results < <(find . -type f -name "*.${ext}" -print0)
for file in "${ext_results[#]}"
do
counter=$((counter+1))
find_results+=("${file}")
echo ${counter}") ${file}"
done
done
countOfResults=$((counter))
echo -e "Found ${countOfResults} files.\n"
echo "Processing..."
counter=0
for file in "${find_results[#]}"
do
counter=$((counter+1))
echo -n ${counter}"/${countOfResults}) "
eval "$1 '${file}'"
done
echo "All files have been processed."