Not able to call SOAP API in WebServiceGatewaySupport by Spring WebServiceTemplate - Need help to fix this issue - spring

Question

I am trying to call SOAP API in Java Spring Boot using WebServiceGatewaySupport by Spring WebServiceTemplate
Config java class
public WebServiceTemplate createWebServiceTemplate(Jaxb2Marshaller marshaller, ClientInterceptor clientInterceptor) {
WebServiceTemplate webServiceTemplate = new WebServiceTemplate();
//SOAP URL
webServiceTemplate.setDefaultUri("http://host/Services.asmx");
//Auth ---It seems issue is here only????? need to check
webServiceTemplate.setMessageSender(new Authentication());
webServiceTemplate.setMarshaller(marshaller);
webServiceTemplate.setUnmarshaller(marshaller);
webServiceTemplate.afterPropertiesSet();
webServiceTemplate.setCheckConnectionForFault(true);
webServiceTemplate.setInterceptors((ClientInterceptor[]) Arrays.asList(createLoggingInterceptor()).toArray());
return webServiceTemplate;
}
SOAP Client Call
public class TicketClient extends WebServiceGatewaySupport {
public String getTicket(Ticket req) {
System.out.println("test inside webservice support1");
response = (AcquireTicketResponse) getWebServiceTemplate().marshalSendAndReceive(req);
Authentication Class
public class Authentication extends HttpUrlConnectionMessageSender {
#Override protected void prepareConnection(HttpURLConnection connection) {
String userpassword = username+":"+password+":"+domain;
String encoded =
Base64.getEncoder().withoutPadding().encodeToString(userpassword.getBytes(StandardCharsets.UTF_8));
connection.setRequestProperty("Authorization", "Basic "+encoded); connection.setRequestProperty("Content-Type", "application/xml"); super.prepareConnection(connection);
}
Not using Authetication class and add the above into
ClientInterceptor
public class SoapLoggingInterceptor implements ClientInterceptor {
#Override
public boolean handleRequest(MessageContext messageContext) throws WebServiceClientException {
String username="test";
String password="test";
String domain = "#test";
String userpassword = username+":"+password+domain;
String encoded = Base64.getEncoder().withoutPadding().encodeToString(userpassword.getBytes(StandardCharsets.UTF_8));
messageContext.setProperty("Authorization", "Basic "+encoded);
messageContext.setProperty("Content-type", "XML");
Case -1 --->When I passed (user, pwd, domain and content-type) through messagesender, content type is taking but throwed "BAD REQUEST ERROR 400"....When i comment contenttype property, then it throwed "INTERNAL SERVER ERROR 500".
Case-2...when I passed (user, pwd, domain and content-type) through ClientInterceptor , always it throwed "INTERNAL SERVER ERROR 500"......It seems Authentication properties for the service are not going to API call.............................Please suggest some options
Both the cases, Authentication is not passing to service, if i comment,Authentication code (userid/pwd/domain) in both cases also...no efforts in output
After setting the user ID/pwd
#Override
public boolean handleRequest(MessageContext messageContext) throws WebServiceClientException {
String username="test";
String password="test";
String domain = "#test";
String userpassword = username+":"+password+domain;
byte[] userpassword = (username+":"+password).getBytes(StandardCharsets.UTF_8);
String encoded = Base64.getEncoder().encodeToString(userpassword);
ByteArrayTransportOutputStream os = new
ByteArrayTransportOutputStream();
try {
TransportContext context = TransportContextHolder.getTransportContext();
WebServiceConnection conn = context.getConnection();
((HeadersAwareSenderWebServiceConnection) conn).addRequestHeader("Authorization", "Basic " + encoded);
} catch (IOException e) {
throw new WebServiceIOException(e.getMessage(), e);
}

Answer 1

First of all don't set the content type Spring WebServices will do that for you, messing around with that will only make things worse.
You should get the WebServiceConnection and cast that to a HeadersAwareSenderWebServiceConnection to add a header.
public class BasicAuthenticationInterceptor implements ClientInterceptor {
#Override
public boolean handleRequest(MessageContext messageContext) throws WebServiceClientException {
String username="test#test";
String password="test";
byte[] userpassword = (username+":"+password).getBytes(UTF_8);
String encoded = Base64.getEncoder().encodeToString(userpassword);
WebServiceConnection conn = TransportContext.getConnection();
((HeadersAwareSenderWebServiceConnection) conn).addHeader("Authorization", "Basic " + encoded);
}
}
You also need to configure it. Assuming it is a bean don't call afterPropertiesSet (and ofcourse you are now using the ClientInterceptor remove the new Authentication() for your customized message sender.
The List<ClientInterceptor> will automatically create a list with all the interceptors so you can easily inject them.
#Bean
public WebServiceTemplate createWebServiceTemplate(Jaxb2Marshaller marshaller, List<ClientInterceptor> clientInterceptors) {
WebServiceTemplate webServiceTemplate = new WebServiceTemplate(marshaller);
//SOAP URL
webServiceTemplate.setDefaultUri("http://host/Services.asmx");
webServiceTemplate.setCheckConnectionForFault(true);
webServiceTemplate.setInterceptors(clientInterceptors);
return webServiceTemplate;
}
If this doesn't work there is something else you are doing wrong and you will need to get in touch with the server developers and get more information on the error.
Update:
Apparently you also need to provide a SOAP Action in your request, which you currently don't. For this you can specify the SoapActionCallback in the marshalSendAndReceive method. Which action to specify you can find in the WSDL you are using.
SoapActionCallback soapAction = new SoapActionCallback("SoapActionToUse");
response = (AcquireTicketResponse) getWebServiceTemplate().marshalSendAndReceive(req, soapAction);