What wildcard should I use to block all elements of this type with any number? Whether it's 50, 500 or 9999999 and etc. Here are the elements:
example.com###ad-row-1
example.com###ad-row-2
example.com###ad-row-3
Related
I have a string:
'my_array1: ["1445","374","1449","378"], my_array2: ["1445","374", "1449","378"]'
I need to match all sets of digits from my_array2: [...] and count how many of them there.
I need to do something like this with regex and ruby MatchData
string = 'my_array1: ["1445","374", "1449","378"], my_array2: ["1445","374", "1449","378"]'
matches = string.match(/my_array2\:\s[\[,]\"(\d+)\"/)
count_matches = matches.size
Expected result should be 4.
What is the correct way of doing it?
If you are guaranteed that the content of my_array2 is always numeric you could simply use split twice. First you splitby my_array2: [" and then split by ,. This should give you the amount of items you are after.
If you are not guaranteed that, you could still split by my_array2 and instead of splitting again, you use a pattern such as "\d+" (or "\d+(\.\d+)? if you have floating point values) and count.
An example of the expression is available here.
Let's say we have this:
something
Now is there a way to return the #href like: "www.something/page/2". Basically to return the #href value, but with the substring-after(.,"page/") incremented by 1. I've been trying something like
//a/#href[number(substring-after(.,"page/"))+1]
but it doesn't work, and I don't think I can use
//a/#href/number(substring-after(.,"page/"))+1
It's not precisely a paging think, so that I can use the pagination, I just picked that for an example. The point is just to find a way to increment a value in xpath 1.0. Any help?
What you can do is
concat(
translate(//a/#href, '0123456789', ''),
translate(//a/#href, translate(//a/#href, '0123456789', ''), '') + 1
)
So that concatenates the 'href' attribute with all digits being removed with the the sum of 1 and the 'href' with anything but digits being removed.
That might suffice is all digits in your URLs occur at the end of your URL. But generally XPath 1.0 is good at selecting nodes in your input but bad at constructing new values based on parts of node values.
There is a simpler way to achieve this, just take the substring after the page, add 1, and then munge it all back together:
This XPath is based on the current node being the #href attribute:
concat(substring-before(.,'page/'),
'page/',
substring-after(.,'page/')+1
)
Your order of operations is a little, well, out of order. Use something like this:
substring-after(//a/#href, 'page/') + 1
Note that it is not necessary to explicitly convert the string value to a number. From the spec:
The numeric operators convert their operands to numbers as if by
calling the number function.
Putting it all together:
concat(
substring-before(//a/#href, 'page/'),
'page/',
substring-after(//a/#href, 'page/') + 1)
Result:
www.something/page/2
I tried the following regex in Ruby:
"the foodogand the catlada are mouseing".scan(/\b(?=\w{6,12}\b)\w{0,9}(cat|dog|mouse)\w*/)
but instead of it returning
["foodogand", "catlada", "mouseing"]
I'm getting
[["dog"],["cat]] # the results are also in arrays
What's wrong here?
the results are also in arrays, I could flatten this but is there a way to avoid it?
Use ?: for the last group:
"the foodogand the catlada are mouseing".scan(/\b(?=\w{6,12}\b)\w{0,9}(?:cat|dog|mouse)\w*/)
#=> ["foodogand", "catlada", "mouseing"]
From the docs:
If the pattern contains groups, each individual result is itself an array containing one entry per group.
The ?: makes the group non-capturing, avoiding a nested array.
I would just clean that up a bit by moving the second \b to the end and replacing \w{0,9} with \w* (the lookahead takes care of the length)
"the foodogand the catlada are mouseing".scan /\b(?=\w{6,12})\w*(?:cat|dog|mouse)\w*\b/
#=> ["foodogand", "catlada", "mouseing"]
Dim str as String
str = "30 40 50 60"
I want to count the number of substrings.
Expected Output: 4
(because there are 4 total values: 30, 40, 50, 60)
How can I accomplish this in VB6?
You could try this:
arrStr = Split(str, " ")
strCnt = UBound(arrStr) + 1
msgBox strCnt
Of course, if you've got Option Explicit set (which you should..) then declare the variables above first..
Your request doesn't make any sense. A string is a sequence of text. The fact that that sequence of text contains numbers separated by spaces is quite irrelevant. Your string looks like this:
30 40 50 60
There are not 4 separate values, there is only one value, shown above—a single string.
You could also view the string as containing 11 individual characters, so it could be argued that the "count" of the string would be 11, but this doesn't get you any further towards your goal.
In order to get the result that you expect, you need to split the string into multiple strings at each space, producing 4 separate strings, each containing a 2-digit numeric value.
Of course, the real question is why you're storing this value in a string in the first place. If they're numeric values, you should store them in an array (for example, an array of Integers). Then you can easily obtain the number of elements in the array using the LBound() and UBound() functions.
I agree with everything Cody stated.
If you really wanted to you could loop through the string character by character and count the number of times you find your delimiter. In your example, it is space delimited, so you would simply count the number of spaces and add 1, but as Cody stated, those are not separate values..
Are you trying to parse text here or what? Regardless, I think what you really need to do is store your data into an array. Make your life easier, not more difficult.
I'm trying to select an anchor element by first containing the text "To Be Coded", then extracting a number from a string using substring, then using the greater than comparison operator (>0). This is what I have thus far:
/a[number(substring(text(),???,string-length()-1))>0]
An example of the HTML is:
<a class="" href="javascript:submitRequest('getRec','30', '63', 'Z')">
To Be Coded (23)
</a>
My issue right now is I don't know how to find the first occurrence of the open parenthesis. I'm also not sure how to combine what I have with the contains(text(),"To Be Coded") function.
So my criteria for the selection is:
Must be an anchor element
Must include the text "To Be Coded"
Must contain a number greater than 0 in the parentheses
Edit: I suppose I could just "hard code" the starting position for the substring, but I'm not sure what that would be - will XPath count the white space before the text in the element? How would it handle/count the characters?
Here try this :
a[contains(., 'To Be Coded') and number(substring-before(substring-after(., '('), ')')) > 0]