I'm trying to replace any cell that has a date in it with "null" so that I can fill values in PowerQuery. I've used formula's that can can perform the replacement, but the non-date values that I want to remain as text are replaced with "Error". Is there a way to do this?
Something like this might work
#"RemoveDates" = Table.TransformColumns(#"PriorStepNameGoesHere",{{"Date", each try if Number.From(Date.From(_))>0 then null else _ otherwise _, type text}})
x = Table.TransformColumns(Source,{{"Column1", (a)=> try Date.FromText(a) otherwise null , type text}})
Related
I have a simple table that has a column with a date in this format:
MM/DD/YYYY.
Unfortunately, there are some folks who are working without leading zeros.
Therefore I would like to add a leading zero into the Month and Day element using Power Query to have a common format.
But how? Does someone have any function to share?
Again, not sure why you want to do this, but
Assuming all of the entries are text that looks like dates, you can use the following M-Code:
Split the string on the delimiter
Change each entry in the list to a number
Add 2000 to the last number
Change the numbers back to text with a "00" format
Recombine with the delimiter
let
Source = Excel.CurrentWorkbook(){[Name="Table29"]}[Content],
//set type = Text
#"Changed Type" = Table.TransformColumnTypes(Source,{{"TextDate", type text}}),
xform = Table.TransformColumns(#"Changed Type",
{"TextDate", each
let
x = Text.Split(_,"/"),
y = List.Transform(x,each Number.From(_)),
z = List.ReplaceRange(y,2,1, {2000+y{2}}),
a= List.Transform(z,each Number.ToText(_,"00")),
b = Text.Combine(a,"/")
in b})
in
xform
I am thinking a better solution might be to set up your data entry method so that all dates are entered as dates rather than text
Is there any function to replace NULL or empty space with special character in hive? when I execute the below statement it returns a semantic exception stating trim works only on string/nvarchar
CASE
WHEN TRIM(q.address) = '' OR q.address IS NULL THEN '?'
ELSE q.address END as address
Please help.
Use LENGTH() to check the length of the column value. It returns > 0, if there is some value else return 0 for empty or NULL value.
Also frame the column value in CASE WHEN ... END block
The final query may look like:
SELECT CASE WHEN LENGTH(address) > 0 THEN address ELSE '?' END AS address
FROM table_name;
Please refer Replace the empty or NULL value with specific value in HIVE query result
Hope this help you!!!
In order to replace nulls you can use Coalesce
Coalesce( q.address, '?')
But it seems your field adress is not of the proper type to use trim, can you show us the type of that field?
I have a grid on a form that displays some columns from a dbf table and a textbox.
I want to search the value displayed in the textbox over all columns from a dbf table. Some fields are numeric and other are character
If I want to find a number, should search all record that contain that number in all columns, no matter the column type.
If I want to search a substring should give me all record that contain that substring.
SET FILTER TO ALLTRIM(ThisForm.Text1.Value) $Content or ALLTRIM(val(ThisForm.Text1.Value)) $registrationNumber or ALLTRIM(ThisForm.Text1.Value) $holderNo
Your approach with the "$" wildcard "contains" approach appears to be ok. However, your attempt via allt( val( )) would fail as you cant trim a numeric value, it would have to be pre-converted to a string.
Now, that said, you could shorten your query by just doing a $ against a concatenation of ALL columns something like (assuming your registration number is a numeric field)...
set filter to ALLTRIM(ThisForm.Text1.Value) ;
$ ( Content +"," +str(registrationNumber) +," + holderNo )
if you have dates or date/time fields you could do DTOC( dateField ) or TTOC( dateTimeField). So, by building a single string of all values, you dont have to explicitly repeat the OR condition repeatedly.
You could do something like:
select curGrid
scan
lcRow = transform(field1) + transform(field2) ... + transform(lastfield)
if lcSearchValue $ lcRow
DoWhatever()
endif
endscan
This leverages the fact that transform() will give a string representation of any data type.
Excuse me, occasionally I refer with some problem that maybe it's already been fixed. In any case, I would appreciate a clarification on vs.
I have a TariffeEstere table with the fields country, Min, Max, tariff
from which to extract the rate for the country concerned, depending on whether the value is between a minimum and a maximum and I should return a single record from which to extract its tariff:
The query is:
stsql = "Select * from QPagEstContanti Where country = ' Spain '
and min <= ImpAss and max >= ImpAss"
Where ImpAss is a variable of type double.
When I do
rstariffa.open ststql,.....
the recodset contains a record if e.g. ImpAss = 160 (i.e. an integer without decimals), and then the query works, but if it contains 21,77 ImpAss (Italian format) does not work anymore and gives me a syntax error.
To verify the contents of the query string (stsql) in fact I find:
Select * from QPagEstContanti Where country = 'Spain' and min < = 21,77 and max > = 21,77
in practice the bothering and would like a comma decimal, but do not know how do.
I tried to pass even a
format (ImpAss, "####0.00"),
but the value you found in a stsql is 21,77 always.
How can I fix the problem??
It sounds like the underlying language setting in SQL is expecting '.' decimals instead of ',' decimal notation.
To check this out - run the DBCC useroptions command and see what the 'language' value is set to. If the language is set to English or another '.' decimal notation - it explains why your SQL string is failing with values of double.
If that's the problem, the simplest way to fix it is to insert the following line after your stsql = statement:
stsql = REPLACE(stsql, ",", ".")
Another way to fix it would be to change the DEFAULT_LANGUAGE for the login using the ALTER LOGIN command (but this changes the setting permanently)
Another way to fix it would be to add this command to the beginning of your stsql, which should change the language for the duration of the rs.Open:
"SET LANGUAGE Italian;"
Please consider the following XML--
<table class="rel_patent"><tbody>
<tr><td>Name</td><td>Description</td></tr>
<tr><td>A</td><td>Type-A</td></tr>
<tr><td>B</td><td>Type-B</td></tr>
<tr><td>C</td><td>Type-C</td></tr>
<tr><td>AC</td><td>Type-C
Type-A</td></tr>
<tr><td>D</td><td></td></tr>
</tbody></table>
Now I want to select and display all values of "Name" with corresp. values of "Description" element...even when Description element has null values viz element with name=D, and also, when description element has values separated by enter then I want those values (of Description) in separate rows- viz Type-C and Type-A for element with name=AC
This is the type of query I have written--
let $rows_data:= $doc//table[#class="rel_patent"]/tbody/tr[1]/following-sibling::tr
for $data_single_row in $rows_data
return
let $cited_name:= $data_single_row/td[1]
let $original_types_w_return:= $data_single_row/td[4]
let $original_types_list:= tokenize($original_types_w_return, '(\r?\n|\r)$')
for $cited_type_each at $pos2 in $original_types_list
return concat( $cited_name, '^', $original_type_each, '^', $pos2)
However, I am getting the following type of response--
A^Type-A^1
B^Type-B^1
C^Type-C^1
AC^Type-C
Type-A^1
Now, I need to get the following correct in the above code+response---
(1) The data for "AC" should be 2 separate rows with "Type-C" and "Type-A" being in each of the 2 rows along with corresp. value for last field in each row as 1 and 2 (because these are 2 values)
(2) The data for "D" is not being shown at all.
How do I correct the above code to conform with these 2 requirements?
This works:
for $data_single_row in $rows_data
return
let $cited_name:= $data_single_row/td[1]
let $original_types_w_return:= $data_single_row/td[2]
let $original_types_list:= tokenize(concat($original_types_w_return, " "), '(\r?\n|\r)')
for $cited_type_each at $pos2 in $original_types_list
return concat( $cited_name, '^', normalize-space($cited_type_each), '^', $pos2)
(The first change was to replace $original_type_each with $cited_type_each and [4] with [2] which may ).
The first problem can be solved by removing the $ at the end of the tokenize parameter, since in the default mode $ only match the end of the string.
The second one is solved by adding an space $original_types_w_return, so it is not empty and tokenize returns something, and then removing it again with normalize-space (in XQuery 3.0 it could probably be solved by using 'allowing empty' in the for expression)