Loop Excel columns - ruby
The solution below solves my problem when there is a vertical column that validates the record in the cell with the field on the application screen.
But if the spreadsheet is horizontal, I cannot read the records and validate them on the application screen.
Spreadsheet.client_encoding = 'UTF-8'
book = Spreadsheet.open('c:/temp/gab.xls', "r")
sheet = book.worksheet 4
xls_offset = 1
row_offset = 2
sheet.each_with_index(xls_offset) do |row, idx|
expected_tooltip = row[1]
break if row[1].nil?
expect(page).to have_css("tr.tvRow:nth-child(#{row_offset+idx}) .tvCell:nth-child(6) img[tooltip='#{expected_tooltip}']")
end
OK: I get the values from the status column [invisible....etc]
fields
status
Leitura
Invisível
Hidrometro
Invisíve
Diametro
Invisível
Lacre
Obrigatório
NOK
code
situation
tab
leitura
hidrometro
diametro
lacre
8
ok
B
Invisivel
Invisivel
Habilitado
Invisivel
9
ok
C
Invisivel
Invisivel
Habilitado
Invisivel
10
ok
C
Invisivel
Invisivel
Habilitado
Invisivel
How to adjust the code above to do this reading horizontally to read the records [Invisivel, Invisivel,Habilitado,Invisivel] in line 3 from the Leitura column?
You can try getting a specific row and then iterating over cells in this row skipping the first N cells:
row = sheet.row(2) # get the third row
row.each_with_index do |cell, index|
next if index < 3 # skip first three cells
# do something with the data specified in cell variable
end
Related
Loop in excel column with Ruby horizontally. No one will help me?
Friends, the solution below solves my problem when there is a vertical column that validates the record in the cell with the field on the application screen. But if the spreadsheet is horizontally, I am not able to read the records and validate on the application screen.
here OK I get the values from the status column [invisible....etc]
fields
status
Leitura
Invisível
Hidrometro
Invisíve
Diametro
Invisível
Lacre
Obrigatório
Spreadsheet.client_encoding = 'UTF-8'
book = Spreadsheet.open('c:/temp/gab.xls', "r")
sheet = book.worksheet 4
xls_offset = 1
row_offset = 2
sheet.each_with_index(xls_offset) do |row, idx|
expected_tooltip = row[1]
break if row[1].nil?
expect(page).to have_css("tr.tvRow:nth-child(#{row_offset+idx}) .tvCell:nth-child(6) img[tooltip='#{expected_tooltip}']")
end
end
How to adjust the code above to do this reading horizontally to read the records [Invisivel, Invisivel,Habilitado,Invisivel] in line 3 from the Leitura column?
Here NOK
code
situation
tab
leitura
hidrometro
diametro
lacre
8
ok
B
Invisivel
Invisivel
Habilitado
Invisivel
9
ok
C
Invisivel
Invisivel
Habilitado
Invisivel
10
ok
C
Invisivel
Invisivel
Habilitado
Invisivel
enter image description here
Remove nTh record from array using loop [closed]
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I'm writing a program that reads a .csv file, and then loops through it removing every 10th record it encounters before outputting it.
I've been stuck on what I believe is a syntax issue for a while now and just can't seem to nail it. Anyone mind having a look?
lines = []
i = 0
elements = []
element2 = []
output = []
file = File.open("./properties.csv", "r")
while (line = file.gets)
i += 1
# use split to break array up using commas
arr = line.split(',')
elements.push({ id: arr[0], streetAddress: arr[1], town: arr[2], valuationDate: arr[3], value: arr[4] })
end
file.close
# filter out blanks and nill rows
x = elements.select { |elements| elements[:id].to_i >= 0.1}
# Loop to remove every 10th record
e = 0
d = 1
loop do x.length
if e == (10 * d)
d ++
e ++
else
x = elements.select[e]
e ++
end
puts x
puts "#{x.length} house in list, #{d} records skipped."
CSV FILE
ID,Street address,Town,Valuation date,Value
1,1 Northburn RD,WANAKA,1/1/2015,280000
2,1 Mount Ida PL,WANAKA,1/1/2015,280000
3,1 Mount Linton AVE,WANAKA,1/1/2015,780000
4,1 Kamahi ST,WANAKA,1/1/2015,155000
5,1 Kapuka LANE,WANAKA,1/1/2015,149000
6,1 Mohua MEWS,WANAKA,1/1/2015,560000
7,1 Kakapo CT,WANAKA,1/1/2015,430000
8,1 Mt Gold PL,WANAKA,1/1/2015,1260000
9,1 Penrith Park DR,WANAKA,1/1/2015,1250000
10,1 ATHERTON PL,WANAKA,1/1/2015,650000
11,1 WAIMANA PL,WANAKA,1/1/2015,780000
12,1 ROTO PL,WANAKA,1/1/2015,1470000
13,1 Toms WAY,WANAKA,1/1/2015,2230000
14,1 MULBERRY LANE,WANAKA,1/1/2015,415000
15,1 Range View PL,WANAKA,1/1/2015,300000
16,1 Clearview ST,WANAKA,1/1/2015,1230000
17,1 Clutha PL,WANAKA,1/1/2015,700000
18,1 Centre CRES,WANAKA,1/1/2015,295000
19,1 Valley CRES,WANAKA,1/1/2015,790000
20,1 Edgewood PL,WANAKA,1/1/2015,365000
21,1 HUNTER CRES,WANAKA,1/1/2015,335000
22,1 KOWHAI DR,WANAKA,1/1/2015,480000
23,1 RIMU LANE,WANAKA,1/1/2015,465000
24,1 CHERRY CT,WANAKA,1/1/2015,495000
25,1 COLLINS ST,WANAKA,1/1/2015,520000
26,1 AUBREY RD,WANAKA,1/1/2015,985000
27,1 EELY POINT RD,WANAKA,1/1/2015,560000
28,1 LINDSAY PL,WANAKA,1/1/2015,385000
29,1 WINDERS ST,WANAKA,1/1/2015,760000
30,1 Manuka CRES,WANAKA,1/1/2015,510000
31,1 WILEY RD,WANAKA,1/1/2015,420000
32,1 Baker GR,WANAKA,1/1/2015,820000
33,1 Briar Bank DR,WANAKA,1/1/2015,1260000
34,1 LAKESIDE RD,WANAKA,1/1/2015,440000
35,1 PLANTATION RD,WANAKA,1/1/2015,345000
36,1 Allenby PL,WANAKA,1/1/2015,640000
37,1 ROB ROY LANE,WANAKA,1/1/2015,380000
38,1 Ansted PL,WANAKA,1/1/2015,590000
39,1 Fastness CRES,WANAKA,1/1/2015,640000
40,1 APOLLO PL,WANAKA,1/1/2015,385000
41,1 AEOLUS PL,WANAKA,1/1/2015,370000
42,1 Peak View RDGE,WANAKA,1/1/2015,1750000
43,1 Moncrieff PL,WANAKA,1/1/2015,530000
44,1 Islington PL,WANAKA,1/1/2015,190000
45,1 Hidden Hills DR,WANAKA,1/1/2015,1280000
46,1 Weatherall CL,WANAKA,1/1/2015,425000
47,1 Terranova PL,WANAKA,1/1/2015,900000
48,1 Cliff Wilson ST,WANAKA,1/1/2015,1200000
49,1 TOTARA TCE,WANAKA,1/1/2015,460000
50,1 Koru WAY,WANAKA,1/1/2015,570000
51,1 Bovett PL,Wanaka,1/1/2015,495000
52,1 Pearce PL,Wanaka,1/1/2015,675000
53,1 Ironside DR,WANAKA,1/1/2015,570000
54,1 Bob Lee PL,WANAKA,1/1/2015,610000
55,1 Hogan LANE,WANAKA,1/1/2015,395000
56,1 ARDMORE ST,WANAKA,1/1/2015,1190000
57,1 Bullock Creek LANE,WANAKA,1/1/2015,11125000
58,1 DUNMORE ST,WANAKA,1/1/2015,1300000
59,1 Primary LANE,WANAKA,1/1/2015,430000
60,1 SYCAMORE PL,WANAKA,1/1/2015,720000
61,1 FAULKS TCE,WANAKA,1/1/2015,780000
62,1 Alpha CL,WANAKA,1/1/2015,500000
63,1 Coromandel ST,WANAKA,1/1/2015,530000
64,1 Niger ST,WANAKA,1/1/2015,475000
65,1 Maggies Way,WANAKA,1/1/2015,375000
66,1 Hollyhock LANE,QUEENSTOWN,1/1/2015,1080000
67,1 ELDERBERRY CRES,WANAKA,1/1/2015,1340000
68,1 Foxglove HTS,WANAKA,1/1/2015,2520000
69,1 MEADOWSTONE DR,WANAKA,1/1/2015,650000
70,1 OAKWOOD PL,WANAKA,1/1/2015,580000
71,1 MEADOWBROOK PL,WANAKA,1/1/2015,645000
72,1 Jessies CRES,WANAKA,1/1/2015,320000
73,1 Lansdown ST,WANAKA,1/1/2015,700000
74,1 Stonebrook DR,WANAKA,1/1/2015,640000
75,1 Hyland ST,WANAKA,1/1/2015,500000
76,1 TAPLEY PADDOCK,WANAKA,1/1/2015,720000
77,1 Homestead CL,WANAKA,1/1/2015,1750000
78,1 NORMAN TCE,WANAKA,1/1/2015,620000
79,1 Sunrise Bay DR,WANAKA,1/1/2015,3000000
80,1 LARCH PL,WANAKA,1/1/2015,570000
81,1 MILL END,WANAKA,1/1/2015,600000
82,1 Bills WAY,WANAKA,1/1/2015,750000
83,1 Heuchan LANE,WANAKA,1/1/2015,610000
84,1 SARGOOD DR,WANAKA,1/1/2015,455000
85,1 Frederick ST,WANAKA,1/1/2015,455000
86,1 Connell TCE,WANAKA,1/1/2015,600000
87,1 Soho ST,QUEENSTOWN,1/1/2015,320000
88,1 Hikuwai DR,ALBERT TOWN,1/1/2015,280000
89,1 Harrier LANE,WANAKA,1/1/2015,1000000
90,1 Ewing PL,WANAKA,1/1/2015,780000
91,1 Sherwin AVE,ALBERT TOWN,1/1/2015,440000
92,1 Hardie PL,WANAKA,1/1/2015,830000
93,1 Finch ST,ALBERT TOWN,1/1/2015,540000
94,1 Poppy LANE,ALBERT TOWN,1/1/2015,395000
95,1 Warbler LANE,ALBERT TOWN,1/1/2015,410000
96,1 Balneaves LANE,WANAKA,1/1/2015,250000
97,1 Mill Green,Arrowtown,1/1/2015,800000
require 'csv'
elements = {}
CSV.foreach("properties.csv", :headers => true, :header_converters => :symbol) do |row|
elements[row.fields[0]] = Hash[row.headers[1..-1].zip(row.fields[1..-1])]
end
d = 0
e = 0
elements.delete_if do |key, value|
e += 1
if e == 10
e = 0
d += 1
end
e == 0
end
puts "#{elements.length} house in list, #{d} records skipped."
At the end of this, elements will have every 10th row removed, and d contains the number of rows removed.
Ruby - How to subtract numbers of two files and save the result in one of them on a specified position?
I have 2 txt files with different strings and numbers in them splitted with ;
Now I need to subtract the
((number on position 2 in file1) - (number on position 25 in file2)) = result
Now I want to replace the (number on position 2 in file1) with the result.
I tried my code below but it only appends the number in the end of the file and its not the result of the calculation which got appended.
def calc
f1 = File.open("./file1.txt", File::RDWR)
f2 = File.open("./file2.txt", File::RDWR)
f1.flock(File::LOCK_EX)
f2.flock(File::LOCK_EX)
f1.each.zip(f2.each).each do |line, line2|
bg = line.split(";").compact.collect(&:strip)
bd = line2.split(";").compact.collect(&:strip)
n = bd[2].to_i - bg[25].to_i
f2.print bd[2] << n
#puts "#{n}" Only for testing
end
f1.flock(File::LOCK_UN)
f2.flock(File::LOCK_UN)
f1.close && f2.close
end
Use something like this:
lines1 = File.readlines('file1.txt').map(&:to_i)
lines2 = File.readlines('file2.txt').map(&:to_i)
result = lines1.zip(lines2).map do |value1, value2| value1 - value2 }
File.write('file1.txt', result.join(?\n))
This code load all files in memory, then calculate result and write it to first file.
FYI: If you want to use your code just save result to other file (i.e. result.txt) and at the end copy it to original file.
String search with in the excel column values row wise
I have an Excel sheet which has 200 columns. Now number of rows are 3500. So i have to search a string if it presents within any column for each row. Now to make the process fatser,I am looking for any alternate instead of Looping technique. Is there any such?
IntRow6 = 2
DataCount = 0
Do While objSheet6.Cells(IntRow6,1).Value <> ""
For DataCount = 0 to UBound(VMHArray)
IntClmn3 = 1
Do While 1 = 1
If objSheet6.Cells(IntRow6,IntClmn3).Value = VMHArray(DataCount) Then
objSheet6.Cells(IntRow6,IntClmn3+2).Value=objSheet6.Cells(IntRow6,IntClmn3+5).Value
Exit Do
End If
IntClmn3 = IntClmn3 + 1
Loop
Next
IntRow6 = IntRow6 + 1
Loop
The above is taking to much time, thus i am looking for an equivalent VBScript code which can run more faster search.
EDIT:
ParentColmnCount=ParentColmnCount-1
IntRow6=2
DataCount=0
Do While objSheet6.Cells(IntRow6,1).Value <> ""
For DataCount=0 to UBound(VMHArray)
If objSheet6.Range(objSheet6.Cells(IntRow6,1),objSheet6.Cells(IntRow6,ParentColmnCount)).Find(VMHArray(DataCount)) <> Nothing Then
MsgBox("Hi")
End If
Next
IntRow6=IntRow6+1
Loop
I'm getting any error saying that, "Object variable not set" error at the Range line of the above code.
UPDATE
I have updated my code as per your suggestion,and modified the declaration of variables as below:
Option Explicit
Dim objExcel1,objWorkbook
Dim strPathExcel1
Dim objSheet6,objSheet3
Dim IntRow6,IntRow3
Dim IntClmn3
Dim DataCount,ParentColmnCount
Dim Falg
Dim TaskCounter
Dim r As Range
Dim s As Variant
But I am getting the error again: Expected end of statement" in the line "Dim r As Range"
Check out Range.Find (which returns a Range object). It's faster than a loop.
Example:
Sub Test()
Dim r As Range
Dim matched As Range
'Get the second row
Set r = Sheet1.Range("2:2")
Set matched = r.Find("myString")
'Do stuff with matched
End Sub
UDPATE:
Assuming you are using CreateObject("Excel.Application"), then the Range object will be present (as CreateObject will return an instance of Excel which contains Range objects and functionality).
For further proof, you're already looping through the worksheet using Range objects (Cells is a Range object).
UPDATE:
Here's a more advanced example. Assume the following data in on Sheet1:
fred ethel ricky bobby 1 2 3 4
lucy myrtle fonzy rickie 1 2 3 4
joanie chachie donna patty 1 2 3 4
selma homer lisa bart 1 2 3 4
You can loop through the ranges like so:
Sub test()
Dim r As Range
Dim names(3) As String
Dim s As Variant
names(0) = "ethel"
names(1) = "fonzy"
names(2) = "patty"
names(3) = "selma"
For Each s In names
For Each r In Sheet1.Cells.CurrentRegion.Find(s)
r.Offset(0, 4).Value = r.Offset(0, 4).Value + 1000
Next r
Next s
End Sub
After the routine is done, the data is now:
fred ethel ricky bobby 1 1002 3 4
lucy myrtle fonzy rickie 1 2 1003 4
joanie chachie donna patty 1 2 3 1004
selma homer lisa bart 1001 2 3 4
UPDATE:
I just saw your comment on your question (and edited your question to include the updated code).
You're getting "Object variable not set" on that line because you cannot use <> comparisons with objects. Change the line to read:
If Not objSheet6.Range(objSheet6.Cells(IntRow6,1),objSheet6.Cells(IntRow6,ParentColmnCount)).Find(VMHArray(DataCount)) Is Nothing Then
ruby multiple loop sets but with limited rows per set
Alrightie, so I'm building an CSV file this time with ruby. The outer loop will run up to length of num_of_loops, but it runs for an entire set rather than up to the specified row. I want to change the first column of a CSV file to a new name for each row.
If I do this:
class_days = %w[Wednesday Thursday Friday]
num_of_loops = (num_of_loops / class_days.size).ceil
num_of_loops.times {
["Wednesday","Thursday","Friday"].each do |x|
data[0] = x
data[4] = classname()
# Write all to file
#
csv << data
end
}
Then the loop will run only 3 times for a 5 row request.
I'd like it to run the full 5 rows such that instead of stopping at Wed/Thurs/Fri it goes to Wed/Thurs/Fri/Wed/Thurs instead.
class_days = %w[Wednesday Thursday Friday] num_of_loops.times do |i| data[0] = class_days[i % class_days.size] data[4] = classname csv << data end The interesting part is here: class_days[i % class_days.size] We need an index into class_days that is between 0 and class_days.size - 1. We can get that with the % (modulo) operator. That operator yields the remainder after dividing i by class_days.size. This table shows how it works: i i % 3 0 0 1 1 2 2 3 0 4 1 5 2 ... The other key part is that the times method yields indices starting with 0.