I have a column that contains either letters or numbers. I want to add a column identifying whether each cell contains a letter or a number. The problem is that there are thousands of records in this particular database.
I tried the following syntax:
= Table.AddColumn(Source, "Column2", each if [Column1] is number then "Number" else "Letters")
My problem is that when I enter this, it returns everything as "Letter" because it looks at the column type instead of the actual value in the cell. This remains the case even when I change the column type from Text to General. Either way, it still produces "Letter" as it automatically assigns text as the data type since the column contains both text and numbers.
Use this expression:
= Table.AddColumn(Source, "Column2", each if List.Contains({"0".."9"}, Text.Start([Column1], 1)) then "Numbers" else "Letters")
Note: It would have been smart to add sample data to your question so I wouldn't have to guess what your data actually looks like!
Add column, custom column with
= try if Value.Is(Number.From([Column1]), type number) then "number" else "not" otherwise "not"
Peter's method works if the choice is AAA/111 but this one tests for A11 and 1BC as well
Related
I have a simple table that has a column with a date in this format:
MM/DD/YYYY.
Unfortunately, there are some folks who are working without leading zeros.
Therefore I would like to add a leading zero into the Month and Day element using Power Query to have a common format.
But how? Does someone have any function to share?
Again, not sure why you want to do this, but
Assuming all of the entries are text that looks like dates, you can use the following M-Code:
Split the string on the delimiter
Change each entry in the list to a number
Add 2000 to the last number
Change the numbers back to text with a "00" format
Recombine with the delimiter
let
Source = Excel.CurrentWorkbook(){[Name="Table29"]}[Content],
//set type = Text
#"Changed Type" = Table.TransformColumnTypes(Source,{{"TextDate", type text}}),
xform = Table.TransformColumns(#"Changed Type",
{"TextDate", each
let
x = Text.Split(_,"/"),
y = List.Transform(x,each Number.From(_)),
z = List.ReplaceRange(y,2,1, {2000+y{2}}),
a= List.Transform(z,each Number.ToText(_,"00")),
b = Text.Combine(a,"/")
in b})
in
xform
I am thinking a better solution might be to set up your data entry method so that all dates are entered as dates rather than text
I have info in a column, that needs to be split into two columns. It can be shown like:
1,000,1111,000 - what we should see is 1,000,111 - 1,000 - or
1,1111,100 - what we should see is 1,111 - 1,100
etc.
I need to separate these columns. I assume the conditions should be "If there are four digits after a comma, separate at this point, into two columns.
It's not immediately obvious how I should fix this. Any thoughts?
EDIT: essentially, the criteria is: If the 4th character after any comma is not another comma, move the 4th character onward onto another column.
This query splits the text string into a list, using its commas as delimiters; then looks at each list entry to find the one that is greater than 3 digits; then inserts a semicolon after the 3rd digit of that entry that is longer than 3 digits; then recombines the list into a text string, with commas; then splits that recombined string into two columns, using the semicolon as the delimiter.
let
Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content],
Custom1 = Table.TransformColumns(Source, {"Column1", each Text.Combine(List.Transform(Text.Split(_,","), each if Text.Length(_) > 3 then Text.Insert(_,3,";") else _),",")}),
#"Split Column by Delimiter" = Table.SplitColumn(Custom1, "Column1", Splitter.SplitTextByDelimiter(";", QuoteStyle.Csv), {"Column1.1", "Column1.2"})
in
#"Split Column by Delimiter"
The table I used to develop/test this is simply this table, which I named Table1:
The query result looks like this:
I would like to filter a specific value as well as blank values.
Example: Filter if the value is "VALUE" or ""
I tried this:
=filter({Summation!E2:K},match(Summation!D2:D,{$B$1,""},false))
And also tried this:
=filter({Summation!E2:K},or(match(Summation!D2:D,{$B$1},false),isblank(Summation!D2:D)))
But non of these work. How do I match for blank values. I want all blank values as well as those with the value B1.
You could use something like =QUERY(B1:K,"Select * where B='' and B='VALUE'",0)
That selects all data in the range B1:K where column B is blank (B='') AND where B is equal to VALUE (B='VALUE').
Replace B with whatever column contains the value you're trying to find.
I have a grid on a form that displays some columns from a dbf table and a textbox.
I want to search the value displayed in the textbox over all columns from a dbf table. Some fields are numeric and other are character
If I want to find a number, should search all record that contain that number in all columns, no matter the column type.
If I want to search a substring should give me all record that contain that substring.
SET FILTER TO ALLTRIM(ThisForm.Text1.Value) $Content or ALLTRIM(val(ThisForm.Text1.Value)) $registrationNumber or ALLTRIM(ThisForm.Text1.Value) $holderNo
Your approach with the "$" wildcard "contains" approach appears to be ok. However, your attempt via allt( val( )) would fail as you cant trim a numeric value, it would have to be pre-converted to a string.
Now, that said, you could shorten your query by just doing a $ against a concatenation of ALL columns something like (assuming your registration number is a numeric field)...
set filter to ALLTRIM(ThisForm.Text1.Value) ;
$ ( Content +"," +str(registrationNumber) +," + holderNo )
if you have dates or date/time fields you could do DTOC( dateField ) or TTOC( dateTimeField). So, by building a single string of all values, you dont have to explicitly repeat the OR condition repeatedly.
You could do something like:
select curGrid
scan
lcRow = transform(field1) + transform(field2) ... + transform(lastfield)
if lcSearchValue $ lcRow
DoWhatever()
endif
endscan
This leverages the fact that transform() will give a string representation of any data type.
Please consider the following XML--
<table class="rel_patent"><tbody>
<tr><td>Name</td><td>Description</td></tr>
<tr><td>A</td><td>Type-A</td></tr>
<tr><td>B</td><td>Type-B</td></tr>
<tr><td>C</td><td>Type-C</td></tr>
<tr><td>AC</td><td>Type-C
Type-A</td></tr>
<tr><td>D</td><td></td></tr>
</tbody></table>
Now I want to select and display all values of "Name" with corresp. values of "Description" element...even when Description element has null values viz element with name=D, and also, when description element has values separated by enter then I want those values (of Description) in separate rows- viz Type-C and Type-A for element with name=AC
This is the type of query I have written--
let $rows_data:= $doc//table[#class="rel_patent"]/tbody/tr[1]/following-sibling::tr
for $data_single_row in $rows_data
return
let $cited_name:= $data_single_row/td[1]
let $original_types_w_return:= $data_single_row/td[4]
let $original_types_list:= tokenize($original_types_w_return, '(\r?\n|\r)$')
for $cited_type_each at $pos2 in $original_types_list
return concat( $cited_name, '^', $original_type_each, '^', $pos2)
However, I am getting the following type of response--
A^Type-A^1
B^Type-B^1
C^Type-C^1
AC^Type-C
Type-A^1
Now, I need to get the following correct in the above code+response---
(1) The data for "AC" should be 2 separate rows with "Type-C" and "Type-A" being in each of the 2 rows along with corresp. value for last field in each row as 1 and 2 (because these are 2 values)
(2) The data for "D" is not being shown at all.
How do I correct the above code to conform with these 2 requirements?
This works:
for $data_single_row in $rows_data
return
let $cited_name:= $data_single_row/td[1]
let $original_types_w_return:= $data_single_row/td[2]
let $original_types_list:= tokenize(concat($original_types_w_return, " "), '(\r?\n|\r)')
for $cited_type_each at $pos2 in $original_types_list
return concat( $cited_name, '^', normalize-space($cited_type_each), '^', $pos2)
(The first change was to replace $original_type_each with $cited_type_each and [4] with [2] which may ).
The first problem can be solved by removing the $ at the end of the tokenize parameter, since in the default mode $ only match the end of the string.
The second one is solved by adding an space $original_types_w_return, so it is not empty and tokenize returns something, and then removing it again with normalize-space (in XQuery 3.0 it could probably be solved by using 'allowing empty' in the for expression)