Why does Windows Service not run my django server? - django-rest-framework

Question

I try to create a windows service to run my django project server. I can start the service, however, the server didn't run. So I cannot find the server on the chrome browser. My code is below.
And my based-code from this website https://metallapan.se/post/windows-service-pywin32-pyinstaller/.
Does anyone know what am I missing to create a service to run my Django server? Thanks in advance.
import os
import time
import sys
import win32serviceutil # ServiceFramework and commandline helper
import win32service # Events
import servicemanager # Simple setup and logging
# from django.views.decorators.csrf import ensure_csrf_cookie
class TestServiceForMeasurewarning:
"""Silly little application stub"""
def stop(self):
"""Stop the service"""
self.running = False
def run(self):
"""Main service loop. This is where work is done!"""
self.running = True
while self.running:
def main():
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'django_tutorial.settings')
try:
from django.core.management import execute_from_command_line
except ImportError as exc:
raise ImportError(
"Couldn't import Django. Are you sure it's installed and "
"available on your PYTHONPATH environment variable? Did you "
"forget to activate a virtual environment?"
) from exc
# args = ['manage.py', 'runserver', '0.0.0.0:8002']
args = ['manage.py', 'runserver', '0.0.0.0:8003']
execute_from_command_line(args)
# execute_from_command_line(sys.argv)
if __name__ == '__main__':
main()
class MyServiceFramework(win32serviceutil.ServiceFramework):
_svc_name_ = 'Test Service For Measurementwarning'
_svc_display_name_ = 'MeasurementwarningTestingService'
def SvcStop(self):
"""Stop the service"""
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
self.service_impl.stop()
self.ReportServiceStatus(win32service.SERVICE_STOPPED)
def SvcDoRun(self):
"""Start the service; does not return until stopped"""
self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
self.service_impl = TestServiceForMeasurewarning()
self.ReportServiceStatus(win32service.SERVICE_RUNNING)
# Run the service
self.service_impl.run()
def init():
if len(sys.argv) == 1:
servicemanager.Initialize()
servicemanager.PrepareToHostSingle(MyServiceFramework)
servicemanager.StartServiceCtrlDispatcher()
else:
win32serviceutil.HandleCommandLine(MyServiceFramework)
if __name__ == '__main__':
init()

Answer 1

When the service manager executes SvcDoRun, __name__ will not be '__main__', so just remove that if statement. You can actually remove the main() function and just put the code in the service_impl function directly.