I am pretty new to PowerBI and cannot figure out a way to compare two values in two columns. All I need is a columns that says True or False. This would be pretty easy in Excel but I am sure there is a way in PowerBI as well?
My data looks like this:
Number
Type
Size
PO1
5
10
PO1
6
12
PO2
5
09
PO2
6
10
PO3
5
10
PO3
6
10
Which I organise to look like this in a matrix (not exactly this formatting but I don't know how to show this, but it's a matrix):
Number
Type 5
Size
Type 6
Size
PO1
5
10
6
12
PO2
5
09
6
10
PO3
5
10
6
10
And I want to know:
Number
Type 5
Size
Type 6
Size
Same size
PO1
5
10
6
12
False
PO2
5
09
6
10
False
PO3
5
10
6
10
True
You could solve this with a calculated table like:
Comparison =
SUMMARIZE(
'Table',
'Table'[Number],
"Same size", MIN('Table'[Size]) = MAX('Table'[Size])
)
which will look like this in a table visual:
What I did was Transform the data as follows:
Number as index column
Min size as 'input'
Max size as 'output'
New column comparing input and output
Save and Run
Week Sales
1 100
2 250
3 350
4 145
5 987
6 26
7 32
8 156
I wanted to calculate the sales only for the last 3 weeks so the total will be 156+32+26.
If new weeks are added it should automatically calculate only the data from the last 3 rows.
Tried this formula but it is returning an incorrect sum
sum(sales) over (lastperiod(3(week))
https://i.stack.imgur.com/6Y7h7.jpg
If you want only the last 3 weeks sum in calculated column you can use a simple if calculation.
If([week]>(Max([week]) - 3),Sum([sales]),0)
If you need 3 weeks calculation throughout table use below one.
sum([sales]) OVER (LastPeriods(3,[week]))
I'm trying to plot some data from a four columns file. The first one is the numbre of data the second one is the year the third one are months and the final one are values of temperature. The thing is that I woul like that my x axis takes a date from the second and the third columns.
The text file look like this:
1 1990 2 265.78945923
2 1990 3 260.53842163
3 1990 4 265.00366211
4 1990 5 277.61206055
5 1990 6 284.72595215
6 1990 7 291.54879761
7 1990 8 293.61392212
8 1990 9 288.47149658
9 1990 10 284.55172729
12 1991 1 285.98762388
13 1991 2 283.47484293
I'm using a code like this:
set xdata time
set timefmt '%Y %m'
plot 'datafile' u 2:4
But it doesn't work. I woul like to have on my x axis the year and the months.
All help appreciated! Thanks
I have an array of numbers ([1,2,3,4,5,6,7,8,9,10]). These numbers represent players. I would like these players to each "play" each other exactly once.
I need to create "Rounds" for these games. These rounds will include a even number of matches, and each player can only play in a round, at most, once. If there's an odd number of matches, than a final round with irregular number of matches is okay.
The end result being an array of "Round" arrays. These round arrays will contain the matches between players. The end result being something like below, but complete:
[[[1,2],[3,4],[5,6],[7,8],[9,10]],[[1,3],[2,4],[5,7],[6,8],[9,1],[10,2]]]
I've found Array#combination for getting the matches created, but I can't seem to get the rounds to build properly.
That is called a round robin tournament. Wikipedia gives the following algorithm
Round 1. (1 plays 14, 2 plays 13, ... )
1 2 3 4 5 6 7
14 13 12 11 10 9 8
then fix one competitor (number one in this example) and rotate the others clockwise one position:
Round 2. (1 plays 13, 14 plays 12, ... )
1 14 2 3 4 5 6
13 12 11 10 9 8 7
And keep rotating:
Round 3. (1 plays 12, 13 plays 11, ... )
1 13 14 2 3 4 5
12 11 10 9 8 7 6
An odd number of players is handled by one player per round having no game (often implemented by adding a dummy player).
I'm trying to solve this problem and I'm new to backtracking algorithms,
The problem is about making a pyramid like this so that a number sitting on two numbers is the sum of them. Every number in the pyramid has to be different and less than 100. Like this:
88
39 49
15 24 25
4 11 13 12
1 3 8 5 7
Any pointers on how to do this using backtracking?
Not necessarily backtracking but the property you are asking for is interestingly very similar to the Pascal Triangle property.
The Pascal Triangle (http://en.wikipedia.org/wiki/Pascal's_triangle), which is used for efficient computation of binomial coefficient among other things, is a pyramid where a number is equal to the sum of the two numbers above it with the top being 1.
As you can see you are asking the opposite property where a number is the sum of the numbers below it.
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1
1 8 28 56 70 56 28 8 1
For instance in the Pascal Triangle above, if you wanted the top of your pyramid to be 56, your pyramid will be a reconstruction bottom up of the Pascal Triangle starting from 56 and that will give something like:
56
21 35
6 15 20
1 5 10 10
Again that's not a backtracking solution and this might not give you a good enough solution for every single N though I thought this was an interesting approximation that was worth noting.