indicator("sigbars")
study("Significant Bar gku", shorttitle="Significant Bar", overlay=false)
length=input(14, "length")
ThreshStrong = input(2, "Strong Significant Bar")
ThreshWeak = input(1.4, "Weak Significant Bar")
TrueRange = at.tr
ATR = atr(length)
strongSB = tr > ATR*ThreshStrong
weakSB = tr > ATR*ThreshWeak
cold1=white
cold2=#b2ebf2
color = strongSB ? cold1 : weakSB ? cold2 : na
band1 = hline(ThreshStrong, "Upper Band", color=#C0C0C0)
band0 = hline(ThreshWeak, "Lower Band", color=#C0C0C0)
fill(band1, band0, color=#9915FF, transp=90, title="Background")
plot(tr, "true range", blue)
plot(ATR, "ATR", black)
plot(tr/ATR,"TR/ATR", red, style = histogram)
//plot(ma,"ma(TR/ATR)", green)
barcolor(color)
plot(close)
I copied this code from a fellow coder but it doesn't seem to work for me; my experience is very limited so im not having any luck getting it to work and hoping someone can point me in the right direction -
i keep getting the following error 9:18:39 AM — Compilation error. Line 9: Syntax error at input 'TrueRange'
here is the code for you
//#version=5
indicator("Significant Bar gku", shorttitle="Significant Bar", overlay=false)
length=input(14, "length")
ThreshStrong = input(2, "Strong Significant Bar")
ThreshWeak = input(1.4, "Weak Significant Bar")
TrueRange = ta.tr
ATR = ta.atr(length)
strongSB = ta.tr > ATR*ThreshStrong
weakSB = ta.tr > ATR*ThreshWeak
cold1=color.white
cold2=#b2ebf2
color = strongSB ? cold1 : weakSB ? cold2 : na
band1 = hline(ThreshStrong, "Upper Band", color=#C0C0C0)
band0 = hline(ThreshWeak, "Lower Band", color=#C0C0C0)
fill(band1, band0, color=#9915FF, transp=90, title="Background")
plot(ta.tr, "true range", color.blue)
plot(ATR, "ATR", color.black)
plot(ta.tr/ATR,"TR/ATR", color.red, style = plot.style_histogram)
//plot(ma,"ma(TR/ATR)", green)
barcolor(color)
plot(close)
Related
Hi I'm new to latex I use here the Algorithmic package to write my pseudo code the problem I faced is that 'some text' is displayed correctly under the second loop but the 'return' statement which needs to be outside the first for loop isn't showing correctly also it does not mark the end of each loop (the vertical tic is missing), the execution result is shown in the image:
\documentclass{article}
\usepackage[utf8,linesnumbered,ruled,vlined]{algorithm2e}
\usepackage {algpseudocode}
\usepackage{algorithmicx}
\usepackage{algcompatible}
\begin{document}
\begin{algorithm}
\ContinuedFloat
\caption{My algorithm}
\textbf{Input:} solution,bound, data\_matrix, vehicle\_capacity, demand\_data,k\_max,operations\_data, move\_type,tenure, max\_number\_of\_moves,max\_iter,non\_improvement\_maxiter,itermax,epsilon\\
\textbf{Output:} $best$ $solution$ \\[0.1in]
routes = extract routes from \textbf{solution}\\
oldfitness = fitness(\textbf{solution})\\
ls\_move\_type = inversion\\
best\_solution = routes\\[0.1in]
\For{0 \leq i \leq itermax}{
new\_routes = [ ]\\
desc = 'normal route'\\
\For{route \textbf{in} routes}{
n=length(route)\\
comb = int($\frac{n!}{(n-2)!}$)\\
\If{n \geq 4}{
tabu\_list\_tenure = $\frac{comb}{5}$\\
ls\_maxiteration = 50 \\
ls\_move\_type = 'inversion'\\
}
\If{3 \leq n \leq 4}{
tabu\_list_tenure = $\frac{comb}{4}$ \\
ls\_maxiteration = 25\\
ls\_move\_type = 'relocation'\\
}
\Else{
append \textbf{route} to \textbf{new\_routes}\\
desc = 'short route'\\
}\\[0.1in]
}
some action
}
return
\end{algorithm}
\end{document}
There is no point in wondering about the output as long as you get errors in your .log file. After an error, latex only recovers enough to syntax check the rest of the document, not necessarily producing sensible output.
Some of the most critical problems:
never ignore error messages!
utf8 isn't a valid option for the algorithm2e package
\ContinuedFloat is not defined by default. If you want to use it, you need a package which defines it. Maybe you want to use the caption package?
never ever use math mode to fake italic text as in $best$ $solution$. This completely messes up the kerning
some of your _ are not escaped
you mustn't use math commands like 0 \leq i \leq outside of math mode
use something like \Return to properly format it
using \\ for line breaks is already quite questionable, but using them two times in a row is simply an error.
because one can't say it often enough: never ignore error messages!
\documentclass{article}
\usepackage[
%utf8,
linesnumbered,ruled,vlined]{algorithm2e}
\usepackage {algpseudocode}
\usepackage{algorithmicx}
\usepackage{algcompatible}
\begin{document}
\begin{algorithm}
%\ContinuedFloat
\caption{My algorithm}
\textbf{Input:} solution,bound, data\_matrix, vehicle\_capacity, demand\_data,k\_max,operations\_data, move\_type,tenure, max\_number\_of\_moves,max\_iter,non\_improvement\_maxiter,itermax,epsilon
\textbf{Output:} \emph{best solution}
\medskip
routes = extract routes from \textbf{solution}
oldfitness = fitness(\textbf{solution})
ls\_move\_type = inversion
best\_solution = routes
\medskip
\For{$0 \leq i \leq$ itermax}{
new\_routes = [ ]
desc = 'normal route'
\For{route \textbf{in} routes}{
n=length(route)
comb = int($\frac{n!}{(n-2)!}$)
\If{$n \geq 4$}{
tabu\_list\_tenure = $\frac{comb}{5}$
ls\_maxiteration = 50
ls\_move\_type = 'inversion'
}
\If{$3 \leq n \leq 4$}{
tabu\_list\_tenure = $\frac{comb}{4}$
ls\_maxiteration = 25
ls\_move\_type = 'relocation'
}
\Else{
append \textbf{route} to \textbf{new\_routes}
desc = 'short route'
}
\medskip
}
some action
}
\Return
\end{algorithm}
\end{document}
From a file i import lines. In this line an (escaped) string is part of the line:
DP,0,"021",257
DP,1,"022",257
DP,2,"023",513
DP,3,"024",513
DP,4,"025",1025
DP,5,"026",1025
DP,6,"081",257
DP,7,"082",257
DP,8,"083",513
DP,9,"084",513
DP,10,"085",1025
DP,11,"086",1025
DP,12,"087",1025
DP,13,"091",257
DP,14,"092",513
DP,15,"093",1025
IS,0,"FIX",0
IS,1,"KARIN02",0
IS,2,"KARUIT02",0
IS,3,"KARIN02HOV",0
IS,4,"KARUIT02HOV",0
IS,5,"KARIN08",0
IS,6,"KARUIT08",0
IS,7,"KARIN08HOV",0
IS,8,"KARUIT08HOV",0
IS,9,"KARIN09",0
IS,10,"KARUIT09",0
IS,11,"KARIN09HOV",0
IS,12,"KARUIT09HOV",0
IS,13,"KARIN10",0
IS,14,"KARUIT10",0
IS,15,"KARIN10HOV",0
I get the following Objects (if DP) :
index - parts1 (int)
name - parts2 (string)
ref - parts3 (int)
I tried using REGEX to replace the excape-sequence from the lines but to no effect
#name_to_ID = {}
kruising = 2007
File.open(cfgFile).each{|line|
parts = line.split(",")
if parts[0]=="DP"
index = parts[1].to_i
hex = index.to_s(16).upcase.rjust(2, '0')
cname = parts[2].to_s
tname = cname.gsub('\\"','')
p "cname= #{cname} (#{cname.length})"
p "tname= #{tname} (#{tname.length})"
p cname == tname
#name_to_ID[tname] = kruising.to_s + "-" + hex.to_s
end
}
teststring = "021"
p #name_to_ID[teststring]
> "021" (5)
> "021" (5)
> true
> nil
The problem came to light when calling from another string reference (length3)
hash[key] isnt equal as string "021" ( length 5) is not string 021 ( length 3)
any method that actually replaces the chars i need?
EDIT: I used
cname.each_char{|c|
p c
}
> "\""
> "0"
> "2"
> "1"
> "\""
EDIT: requested outcome update:
# Current output:
#name_to_ID["021"] = 2007-00 "021".length = 5
#name_to_ID["022"] = 2007-01 "022".length = 5
#name_to_ID["081"] = 2007-06 "081".length = 5
#name_to_ID["082"] = 2007-07 "082".length = 5
#name_to_ID["091"] = 2007-0D "091".length = 5
#name_to_ID["101"] = 2007-10 "101".length = 5
# -------------
# Expected output:
#name_to_ID["021"] = 2007-00 "021".length = 3
#name_to_ID["022"] = 2007-01 "022".length = 3
#name_to_ID["081"] = 2007-06 "081".length = 3
#name_to_ID["082"] = 2007-07 "082".length = 3
#name_to_ID["091"] = 2007-0D "091".length = 3
#name_to_ID["101"] = 2007-10 "101".length = 3
Your problem is you don't know the correct character in your string. It might not be the same character when printing it.
Try parts[2].to_s.bytes to check exactly what is the character code of that unexpected character. For example:
> "asd".bytes
=> [205, 184, 97, 115, 100]
Alternatively, you can delete the first and the last characters, if you are sure that every part of the string has the same format:
cname = parts[2].to_s[1..-2]
Or you can remove all special characters in the string if you know that the string will not contain any special character
cname = parts[2].to_s.gsub(/[^0-9A-Za-z]/, '')
I am programming a little game based on the Fate RPG. When the dice are rolled, I want to replace a string with another string using .replace. I can get it to work in an isolated environment, but when I try to call the function from inside my program; it is as if Shoes is completely unaware of it.
Here is a simple example of how the function works that is executing correctly:
Shoes.app {
#push = button "Push me"
#note = para "Nothing pushed so far"
#push.click { #note.replace "Aha! Click!" }
}
And here is the relevant code from my game:
$results = para "Roll results go here.", :align => "center",
:margin_bottom => 20, :margin_top => 8
#roll_button.click {
current_roll = Die.new
current_roll.roll
current_roll.display_dice
current_roll.tally
current_roll.calc_total_roll(1) #param = skill level
$shift = current_roll.calc_total_shift(2) #param = opposition
$results.replace "Actual results"
}
The $results block is in a different position in the code than the #roll_button.click block, but I have tries moving the click block to many different places in the code, and it didn't make a difference, so I don't think its relevant. Thanks.
*edit: Removed unnecessary '=' after $results.replace
I finally got it to work. The problem was the .display_dice function running just before .replace. The offending code is here:
if $result1 == 1
$die1.path = "dice_plus-1.png"
elsif $result1 == 0
$die1.path = "dice_nil-1.png"
elsif $result1 == -1
$die1.path = "dice_minus-1.png"
else
exit(1)
end
I intended the exit(1) to let me know if my dice were receiving values they shouldn't, but it somehow prevented the next line of code from running, even though the flow of the program avoided those lines. The fixed code is here:
if $result1 == 1
$die1.path = "dice_plus-1.png"
elsif $result1 == 0
$die1.path = "dice_nil-1.png"
else $result1 == -1
$die1.path = "dice_minus-1.png"
end
You're not calling a replace method, you're calling a replace= method which probably doesn't exist. Try it without the equals sign.
I'm working on a class project and I'm trying to take it beyond the requirements a little here (I'm doing my own homework, just need help improving it!) so I want to update the GUI based on certain selections the user makes instead of just having all irrelevent options available all the time (requirements are to just present the options).
I'm still new to Python and even more new to Tkinter so my only attempt has been the following:
#Step Type
ttk.Label(mainframe, text = "Step Type").grid(column = 1, row = 16)
type_entry = OptionMenu(mainframe, StepType, "Kill", "Explore" , "Conversation")
type_entry.grid(column = 2, row = 16, sticky = (E))
#Step Goal
if StepType.get() == "Kill":
ttk.Label(mainframe, text = "Required Kills").grid(column = 1, row = 17)
goal_entry = ttk.Entry(mainframe, width = 20, textvariable = StepGoal)
goal_entry.grid(column = 2, row = 17, sticky = (E))
elif StepType.get() == "Explore":
ttk.Label(mainframe, text = "Location ID").grid(column = 1, row = 17)
goal_entry = ttk.Entry(mainframe, width = 20, textvariable = StepGoal)
goal_entry.grid(column = 2, row = 17, sticky = (E))
elif StepType.get() == "Conversation":
ttk.Label(mainframe, text = "NPC ID").grid(column = 1, row = 17)
goal_entry = ttk.Entry(mainframe, width = 20, textvariable = StepGoal)
goal_entry.grid(column = 2, row = 17, sticky = (E))
Obviously what I want to do here is when the user selects one of the options from the menu, to display the corresponding entry box and label instead of having all 3 all the time.
Also looking for the same situation for CheckButton
Full working example: tested od 2.7.5 and 3.3.2
It use command= in OptionMenu to call function when user changed option.
import tkinter as ttk
#----------------------------------------------------------------------
def on_option_change(event):
selected = step_type.get()
if selected == "Kill":
goal_label['text'] = "Required Kills"
elif selected == "Explore":
goal_label['text'] = "Location ID"
elif selected == "Conversation":
goal_label['text'] = "NPC ID"
# show label and entry
#goal_label.grid(column=1, row=17)
#goal_entry.grid(column=2, row=17, sticky='E')
#----------------------------------------------------------------------
mainframe = ttk.Tk()
# Step Type
step_type = ttk.StringVar() # there is the rule: variable name lowercase with _
ttk.Label(mainframe, text="Step Type").grid(column=1, row=16)
type_entry = ttk.OptionMenu(mainframe, step_type, "Kill", "Explore" , "Conversation", command=on_option_change)
type_entry.grid(column=2, row=16, sticky='E')
step_type.set("Kill")
# Step Goal
step_goal = ttk.StringVar()
goal_label = ttk.Label(mainframe, text="Required Kills")
goal_label.grid(column=1, row=17)
goal_entry = ttk.Entry(mainframe, width=20, textvariable=step_goal)
goal_entry.grid(column=2, row=17, sticky='E')
# hide label and entry
#goal_label.grid_forget()
#goal_entry.grid_forget()
# --- star the engine ---
mainframe.mainloop()
BTW: you can use grid() and grid_forget() to show and hide elements.
EDIT: example with Radiobutton using trace on StringVar
import tkinter as ttk
#----------------------------------------------------------------------
def on_variable_change(a,b,c): # `trace` send 3 argument to `on_variable_change`
#print(a, b, c)
selected = step_type.get()
if selected == "Kill":
goal_label['text'] = "Required Kills"
elif selected == "Explore":
goal_label['text'] = "Location ID"
elif selected == "Conversation":
goal_label['text'] = "NPC ID"
#----------------------------------------------------------------------
mainframe = ttk.Tk()
# Step Type
step_type = ttk.StringVar() # there is the rule: variable name lowercase with _
ttk.Label(mainframe, text="Step Type").grid(column=1, row=16)
ttk.Radiobutton(mainframe, text="Kill", value="Kill", variable=step_type).grid(column=2, row=16, sticky='E')
ttk.Radiobutton(mainframe, text="Explore", value="Explore", variable=step_type).grid(column=3, row=16, sticky='E')
ttk.Radiobutton(mainframe, text="Conversation", value="Conversation", variable=step_type).grid(column=4, row=16, sticky='E')
step_type.set("Kill")
# use `trace` after `set` because `on_variable_change` use `goal_label` which is not created yet.
step_type.trace("w", on_variable_change)
# Step Goal
step_goal = ttk.StringVar()
goal_label = ttk.Label(mainframe, text="Required Kills")
goal_label.grid(column=1, row=17)
goal_entry = ttk.Entry(mainframe, width=20, textvariable=step_goal)
goal_entry.grid(column=2, row=17, sticky='E')
# --- star the engine ---
mainframe.mainloop()
I= 0.299*C1(:,:,1)+0.587*C1(:,:,2)+0.114*C1(:,:,3);
NumberOfGrayLevels=32;
I' =C ln (I+1);
new=uint8(mat2gray(I')*(NumberOfGrayLevels-1));
[m,n]= size(new);
rgb = zeros(m,n,3);
rgb(:,:,1) = new;
rgb(:,:,2) = rgb(:,:,1);
rgb(:,:,3) = rgb(:,:,1);
new = rgb/255;
imshow(new,[]);
no6=figure;
image(new);
this is the code for image generation. error is at I' = . it is showing that + is error.
I assume this is matlab. You're missing operators in the line with an error:
change the third line to:
I=(C*ln(I+1))';