I want to automate my vscode react start process - windows

To better explain it, this is how my normal work day starts:
I usually work on 3 different websites at the same time, so I open a local repository on VS code, run npm start, and it opens in the browser, I repeat this process for the 3 local repositories, and it's kinda tedious having to do this manually every day, so is there any way to automate this process on windows?

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Why can't I access terminal on vscode dev neither on edge nor chrome?

I can not run any program.
As per the instruction I went to vscode dev.
Open up my repository to run a test program.
However, unfortunately, I can not run any of my programs.
I have checked the doctrine which said that only chrome and edge are supported.
But I can not run my program on the terminal window because it tells the code can only run on environments such as codespaces, and local vs code.
What do I miss so that the problem is occurring?
As VSCode(.dev) issue 166506 illustrates, you cannot access terminal from your browser probably because that menu entry was hidden/removed on purpose.
With VSCode 1.75 (Jan. 2023), it will be restored with an explanation.
I'm guessing we intentionally suppressed it because terminals can't run in the web, but participants were simply confused that it wasn't there without connecting its absence to the fact that vscode.dev was a browser application.
Additionally, RemoteHub contributes a welcome view for the terminal which is one of the primary ways we explain that users must continue working elsewhere to run or debug code, and the fact that the terminal is completely suppressed means one less opportunity for users to organically learn the limitations of vscode.dev through our welcome views.
The message is the one you saw:
Terminal are not available in the web editor.
To use the terminal, you will need to continue in an environment that can run code, like a codespace or local VS Code.
You can develop remotely, but you need to execute locally.

How to Check the Number of Times an Application has been opened on a Mac?

I have a script that imitates the war games logon and I was hoping to track the number of times an application has been open, so that way the script doesn't run every time I open a new terminal. Rather I would like it to run when I reboot the machine and open iTerm for the first time since reboot. Is there a way to track the number of times an application has been open since reboot? That way I can write a condition for an if statement.
If you want it to only execute once on boot, you could check for the existence (or not) of a specific file, and just touch it after it's opened for the first time, and delete it on shutdown or on startup before the full desktop/terminal window/environment loads in.

Persistent Virtual Machine Process

I'm using Google Cloud Platform and have a virtual machine. I'm also messing around with webscrapers.
I'm currently trying to do a simple scrape of reddit using a ruby script. That part works pretty well. It essentially continues down and down (to the end of reddit!) scrape the articles, though this, obviously takes some time.
Right now, in order to scrape (I'm running ruby scrape.rb > reddit.txt) I have to keep the google virtual machine ssh browser window open on my computer or the process will exit (which makes enough sense). However, what I'd like to do is have the process persist even if I close the window.
Is there a way to somehow have this process continue to run? Then I can periodically log in and check reddit.txt which will continue to grow even I'm not ssh'ed in.
Thanks!
This seems to be the answer.
The command nohup is exactly what I was looking for!

Automatically force quit frozen applications in OSX maybe using a ruby script?

I built an application using openframeworks that is live 24/7 on a kiosk. Every now and then (every few weeks) it will randomly go unresponsive and I still can't get to the bottom of it because it's so random and infrequent it is hard to debug.
I wrote a ruby script that looks for the application running and if it doesn't exist it will start it up. This works in all cases where the application name doesn't show up in activity monitor. Meaning if the app crashes and completely force quits itself or something. It works just fine.
However, if the app just freezes and goes unresponsive (red highlight in activity monitor) the app doesn't quit out completely unless I force quit manually. Is there some kind of script I can write to look for all "unresponsive apps/processes" every few seconds and force quits them automatically? That way my app launcher script will be able to detect that the app isn't running and boot it up again.
I suggest you look at Monit because it's solid, well tested, well documented, and easy to learn.
If you still want to write your own monitoring script, Monit is a good example to follow.
The most reliable way to detect an unresponsive app is to have a "vital sign" which is a generic term for a signal that an app emit to prove it's healthy. Some people call this a "pulse" or "heartbeat" or "brainwave". Your external script watches the vital sign. If your external script sees the vital sign flatline, then the script takes action to cure the app or restart it.
An alternate way is to have a "ping" which is a generic term for your external script sending a signal to the app or the system, then listening for a reply. You can use tools such as the Unix ps command for processes, or AppleScript Activity Monitor. As far as I know, these do a pretty good job of catching common cases, but have trouble catching apps that are soaking up resources, such as being caught in endless loops.

Windows Task Scheduler will run app only once

So my situation is that I am running an app on the Windows Task Scheduler. This app is run once a day at 1pm. the app does some queries and transfers data to an FTP site. All that is working great except on the weekends when i am not here the app is run and the GUI is still displayed for me to review. This seems to make it stop running on the scheduler until I shut down the app. So on Saturday it will run and the app will remain displayed for me to review when I get back on Monday. but on Sunday when the scheduler attempts to run it again it will fail because the app has not been closed down.
First let me confirm that this is how the Task Scheduler is supposed to work. Second, what are my alternatives for scheduling to run every day and keep the GUI displayed so that I can review. The app can run multiple times as each session does not interfere with the other sessions. So if I'm gone for a week on vacation I would expect that when i get back that 7 instances of the app have been run and are waiting for my review.
Thanks
AGP
Your best bet is to eliminate the UI and log messages to the Event Log or a log file. The UI could be spawned from the CLI as a separate process if you prefer, but it should be done so in as its own non-child process.
Alternatively, you could run a batch file instead of the process directly. In the batch file, invoke "START path_to_exe" instead of the EXE. That will cause the batch file to "finish" instantly, and the exe to be run in its own process. This is not a good long term solution, but will give you a temporary solution to your immediate problem.
This is the default behavior of the Scheduled Task system, as it doesn't know that the job is complete until the application actually exits. Therefore, if your application is still open after 24 hours, the next run will simply be skipped because the current run is "still going" as far as the scheduler is concerned.
Personally I would re-visit the way that you handle your job process, as your are setting up a scenario that will be hard to manage long term.
I recommend writing to a log file instead of displaying a UI for any output and/or errors. This way, the application can write, then exit, and you can review the log at your convenience. This is a very common solution for automated processes.

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