I have period date compose by 6 numbers, the first four numbers it’s the year and the last two is the month, example: yyyymm. (202201 )
The problem with this field is that sometimes changes between int and string. How can I change everything to a date format? dd/MM/yyyy
How can I change everything to a date format? dd/MM/yyyy
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I have 2 columns named Fiscal_Year and Fiscal_Month . Fiscal year is integer type and fiscal month is string type . Now I want that visualization should show data for max[fiscal_month] in accordance to max[fiscal_year].For eg if data contains month till sept for year 2021 then data should show only sept month data for year 2021.
Any idea how do we do that ?
First Concat the columns of month and year,Then convert it into date format eg.Date(Concatenate([Month],"/",[Year])),make sure the date format is MM-yyyy which will get you a column with format like 09-2021. Now Create any visualization and go to show/hide section and show only data with max month.
I used <#setting date_format="mm/dd/yyyy"/> to set my date format. However, When I print the dates, it always print 00/xx/xxxx, 0th month.
mm means minutes, not months in year; use MM for that: MM/dd/yyyy. See: https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
I am using fields.Date to enter a particular date to a field. Lets suppose I do not use the date picker and instead choose to enter the date manually, I am encountering following error.
Lets say I input 12/04/17 (mm/dd/yy) it takes it as 12/04/0017 instead of 12/04/2017.
If you want the date (year) to appear as 2 digits, you can change this in the Settings/Translations/Languages - Select Active Language - Date Format.
Change %Y to %y.
If the date is displayed as 2 digits, then entering it in manually as 2 digits appears to work.
Personally, if I try to enter a date manually with the year as 17 (and year displaying as 4 digits) I get an error.
I ran an SQL Query for Oracle which consists of Invoice date and Check date. When these data are copied on to an Excel Spreadsheet as text, it's dispayed as ex: "13-10-31" (Oct 31, 2013). However, when converted to date format, it's displayed as "10/13/1931". I've tried different date types but it always recognizes as the first part of the text as the day, then month, then year. I need these values to be setup as a date format as I need to calculate Days Payable Outstanding and other related ratios.
Is there any way to convert these values so that Excel recognizes the day, month, and year correctly? Would there be a macro that could automate this process for existing data and data that will be added in the future?
Thank you in advance.
Firstly, I hope the data type of your date column is DATE.
Secondly, the date should always have year as YYYY and not just YY. The world has already learned from Y2K bug.
If above two points are met, then while displaying use to_char(date_column, 'mm/dd/yyyy'). Thus, with YYYY format, there won't be any confusion between year and other fields.
In a VBScript, I need to initialise a variable with a date. In my country we usually specify a date with this format: day month year
Here is what I'm trying to do in my VBScript:
Date = #07-06-1973#
MsgBox FormatDateTime(Date, vbLongDate)
but the date I get is July the 6th, where I was expecting June the 7th!
Now, as it seems the first number represents the month, here is what I tried to do:
Date = #13-06-1973#
MsgBox FormatDateTime(Date, vbLongDate)
but now, the first number represents the day! (I get the following date: June the 13th)
I haven't found a way to force the date format, so that there is no more ambiguity.
Strictly speaking, VBScript supports date literals in the US and ISO formats only:
' US format:
Date = #10/19/2009#
' ISO format:
Date = #2009-10-19#
However, the date separators can be different (slash, dash, space etc), and the VBScript engine also recognizes dates containing abbreviated month names (#Oct 19, 2009#) and non-ambiguous dates with swapped date parts (#2009 19 10#). The latter explains why #13-06-1973# in your second example is recognized as June, 13th: the number 13 falls outside the acceptable range of months (1-12) so it's interpreted as the day part.
If you want to specify dates in your regional format (that is, the format specified in your Regional and Language Options), you can use the CDate function to convert date strings, for example:
' Russian format
Date = CDate("19.10.2009")
But using US and ISO date literals are more reliable and preferred.