How to escape quotes using "echo"? - windows

I am using the Bitwarden CLI.
To pass a JSON to be encoded, it must be done using the command line. In particular, the pipe "|" operator.
On Windows is something like:
echo "password": "defghi" | bw.exe encode
My problem is when there is a quotation mark inside the "password".
For example:
echo "password": "def"ghi" | bw.exe encode
The problem I am having is the output of the previous is as follow:
"password": "def"ghi" | bw.exe encode
And the expected output should look like:
ImFiYyI6ICJkZWZnaGkiIA0K
To share a reproducible example, try the following:
echo "abc": "def"ghi" | FIND "def"
Wrongly I get:
"abc": "def"ghi" | FIND "def"
And expected output should be:
"abc": "def"ghi"
I tried escaping the quotations using ^ and \.
I followed the proposals from this site https://ss64.com/nt/syntax-redirection.html and https://ss64.com/nt/syntax-esc.html
Also tried with:
<nul set /p =""abc": "def"ghi" | FIND "def""
Is there any way to escape the quotation mark inside the password value? Thanks.

Related

how can I query this hash output in bash? [duplicate]

I'm trying to get jq to parse a JSON structure like:
{
"a" : 1,
"b" : 2,
"c" : "{\"id\":\"9ee ...\",\"parent\":\"abc...\"}\n"
}
That is, an element in the JSON is a string with escaped json.
So, I have something along the lines of
$ jq [.c] myFile.json | jq [.id]
But that crashes with jq: error: Cannot index string with string
This is because the output of .c is a string, not more JSON.
How do I get jq to parse this string?
My initial solution is to use sed to replace all the escape chars (\":\", \",\" and \") but that's messy, I assume there's a way built into jq to do this?
Thanks!
edit:
Also, the jq version available here is:
$ jq --version
jq version 1.3
I guess I could update it if required.
jq has the fromjson builtin for this:
jq '.c | fromjson | .id' myFile.json
fromjson was added in version 1.4.
You can use the raw output (-r) that will unescape characters:
jq -r .c myfile.json | jq .id
ADDENDUM: This has the advantage that it works in jq 1.3 and up; indeed, it should work in every version of jq that has the -r option.
Motivation: you want to parse JSON string - you want to escape a JSON object that's wrapped with quotes and represented as a String buffer, and convert it to a valid JSON object. For example:
some JSON unescaped string :
"{\"name\":\"John Doe\",\"position\":\"developer\"}"
the expected result ( a JSON object ):
{"name":"John Doe","position":"developer"}
Solution: In order to escape a JSON string and convert it into a valid JSON object use the sed tool in command line and use regex expressions to remove/replace specific characters:
cat current_json.txt | sed -e 's/\\\"/\"/g' -e 's/^.//g' -e 's/.$//g'
s/\\\"/\"/g replacing all backslashes and quotes ( \" ) into quotes only (")
s/^.//g replacing the first character in the stream to none character
s/.$//g replacing the last character in the stream to none character

How to put single quotes in bash

ABcD!987zyz12388
I'd like to put single quotes around it to handle special character/s. This password is fetched and saved to a variable.
$mypass=`fetchpwd $sourceserver $loginacct`;
$mypass="'$mypass'";
print "My password is: $mypass\n";
The return looks like this
My Password is 'ABcD!987zyz12388
'
The quotes don't belong in the variable itself; they should be added by the printf statement that displays the value.
mypass=$(fetchpwd "$sourceserver" "$logginacct")
printf "My password is: '%s'\n" "$mypass"
If fetchpwd is adding an extra newline you can remove newlines using
mypass=$(fetchpwd "$sourceserver" "$logginacct" | tr -d '\n')

How to access special character like $,# using jq

I am trying to process some string which has special characters in it like abc123#45 or ab$123 or qwe&123.
I am trying to fetch it in shell like:
In json file : foo=qwe$123
foo=`cat tmp_json | jq -r '.keys.foo'`
But it is coming like :
foo=qwe23
JSON input
{
"metadata": {
"name": "xyz",
"version": 7,
"lastUpdated": 1585551422521
},
"keys": {
"abc": "qwe$123",
"foo": "qwe$123"
}
}
When shell strings contain special characters that you do not want to be interpreted specially by the shell, you have to quote them using single quotes, e.g. foo='qwe$123'
Using bash 4.x, the form
x=`...`
does not present any problems with respect to characters such $, #, or &, though it should be noted that the preferred form for such assignments is x=$(...)
However these forms should only be used with great care because of other special characters.
Generally, it would be better to use an idiom such as:
jq -r .... | while -r read line ; do .... ; done
Depending on your requirements, you might also wish to consider jq's #sh filter.

Curl as variable, assign output to variable

I have problem with assigning curl as variable and assign curl's output to variable:
#get results url, format json
URL=$(curl https://api.apifier.com/xy)
#jq is a cli json interpreter
#resultUrl contains the final URL which we want download
OK= "$URL" | jq '.resultsUrl'
#api probably is running
sleep 5
curl "$OK"
Maybe it is trivial, but I don't know where is the problem.
My guess is:
jq '.resultsUrl'
outputs the field resultsUrl with quotes, so curl does not process it correctly. Furthermore, $URL | ... does not work, you would have to use echo or curl directly.
Try
OK=$(curl -s https://api.apifier.com/v1/xHbBnrZ9rxF4CdKjo/crawlers/Example_Alcatraz_Cruises/execute?token=nJ9ohCHZPaJRFEb7nFqtzm76u | jq -r '.resultsUrl')
curl -s "$OK"
which results for me in
[{ "id": 2, "url": "https://www.alcatrazcruises.com/SearchEventDaySpan.aspx?date=02-25-2016&selected=", "loadedUrl": "https://www.alcatrazcruises.com/SearchEventDaySpan.aspx?date=02-25-2016&selected=", "requestedAt": "2016-02-25T23:24:52.611Z", "loadingStartedAt": "2016-02-25T23:24:54.663Z", "loadingFinishedAt": "2016-02-25T23:24:55.642Z", "loadErrorCode": null, "pageFunctionStartedAt": "2016-02-25T23:24:55.839Z", "pageFunctionFinishedAt": "2016-02-25T23:24:55.841Z", "uniqueKey": "https://www.alcatrazcruises.com/SearchEventDaySpan.aspx?date=02-25-2016&selected=", "type": "UserEnqueued", ...
This should be what you expect.
However, sometimes the first API call yields an error:
{
"type": "ALREADY_RUNNING",
"message": "The act is already running and concurrent execution is not allowed"
}
so resultsURL will be null, you will have to handle this error case.
Your line
OK= "$URL" | jq '.resultsURL'
sets the environment variable OK to an empty string, then tries to execute "$URL" as a command and pipe its output to jq. If you want to setOK to the result of a command, you have to use $OK=(...), just like you did when setting URL. The correct syntax is:
OK=$(echo "$URL" | jq '.resultsURL')
And to remove the quotes from the output of .jq, you can do:
OK=$(echo "$URL" | jq '.resultsURL' | tr -d '"')

How to use sed to extract a string [duplicate]

This question already has answers here:
BASH extract value after string in variable Not file [duplicate]
(2 answers)
Closed last year.
I need to extract a number from the output of a command: cmd. The output is type: 1000
So my question is how to execute the command, store its output in a variable and extract 1000 in a shell script. Also how do you store the extracted string in a variable?
This question has been answered in pieces here before, it would be something like this:
line=$(sed -n '2p' myfile)
echo "$line"
if [ `echo $line || grep 'type: 1000' ` ] then;
echo "It's there!";
fi;
Store output of sed into a variable
String contains in Bash
EDIT: sed is very limited, you would need to use bash, perl or awk for what you need.
This is a typical use case for grep:
output=$(cmd | grep -o '[0-9]\+')
You can write the output of a command or even a pipeline of commands into a shell variable using so called command substitution:
variable=$(cmd);
In comments it appeared that the output of cmd contains more lines than the type : 1000. In this case I would suggest sed:
output=$(cmd | sed -n 's/type : \([0-9]\+\)/\1/p;q')
You tagged your question as sed but your question description does not restrict other tools, so here's a solution using awk.
output = `cmd | awk -F':' '/type: [0-9]+/{print $2}'`
Alternatively, you can use the newer $( ) syntax. Some find the newer syntax preferable and it can be conveniently nested, without the need for escaping backtics.
output = $(cmd | awk -F':' '/type: [0-9]+/{print $2}')
If the output is rigidly restricted to "type: " followed by a number, you can just use cut.
var=$(echo 'type: 1000' | cut -f 2 -d ' ')
Obviously you'll have to pipe the output of your command to cut, I'm using echo as a demo.
In addition, I'd use grep and then cut if the string you are searching is more complex. If we assume there can be all kind of numbers in the text, but only one occurrence of "type: " followed by a number, you can use the command:
>> var=$(echo "hello 12 type: 1000 foo 1001" | grep -oE "type: [0-9]+" | cut -f 2 -d ' ')
>> echo $var
1000
You can use the | operator to send the output of one command to another, like so:
echo " 1\n 2\n 3\n" | grep "2"
This sends the string " 1\n 2\n 3\n" to the grep command, which will search for the line containing 2. It sound like you might want to do something like:
cmd | grep "type"
Here is a plain sed solution that uses a regualar expression to find the number in your string:
cmd | sed 's/^.*type: \([0-9]\+\)/\1/g'
^ means from the start
.* can be any character (also none)
\([0-9]\+\) are numbers (minimum one character)
\1 means it takes the first pattern it finds (and only in this case) and uses it as replacement for the whole string

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